diff options
446 files changed, 2377 insertions, 6400 deletions
diff --git a/1340/CH2/EX2.1/2_1.sce b/1340/CH2/EX2.1/2_1.sce deleted file mode 100755 index 52e81295b..000000000 --- a/1340/CH2/EX2.1/2_1.sce +++ /dev/null @@ -1,3 +0,0 @@ -syms t s;
-y = laplace('A*%e^(-a*t)',t,s);
-disp(y,"Laplace transform = ")
\ No newline at end of file diff --git a/1340/CH2/EX2.14/2_14.sce b/1340/CH2/EX2.14/2_14.sce deleted file mode 100755 index 38f756133..000000000 --- a/1340/CH2/EX2.14/2_14.sce +++ /dev/null @@ -1,10 +0,0 @@ -clc;
-s =%s;
-c1 = 5.6*10^(-6);
-r1 = 360*10^3;
-c2 = 0.1*10^(-6);
-r2 = 220*10^3;
-z1 = r1/(1+r1*c1*s);disp(z1,"z1=");
-z2 = (1+r2*c2*s)/(c2*s);disp(z2,"z2=");
-z3 = -(z2/z1);
-disp(z3,"Vo(s)/Vi(s)=");
\ No newline at end of file diff --git a/1340/CH2/EX2.15/2_15.sce b/1340/CH2/EX2.15/2_15.sce deleted file mode 100755 index 441a4ce5d..000000000 --- a/1340/CH2/EX2.15/2_15.sce +++ /dev/null @@ -1,7 +0,0 @@ -clc;
-syms s r1 r2 c1 c2 z1 z2;
-z1 = (1+r1*c1*s)/(c1*s);disp(z1);
-z2 = r2/(1+(r2*c2*s));disp(z2)
-disp("for large A Vo(s)/Vi(s)= (z1(s)+z2(s))/z1(s)");
-g = (z1+z2)/z1;
-disp(g,"Vo(s)/Vi(s)=");
diff --git a/1340/CH2/EX2.17/2_17.sce b/1340/CH2/EX2.17/2_17.sce deleted file mode 100755 index bcd57db19..000000000 --- a/1340/CH2/EX2.17/2_17.sce +++ /dev/null @@ -1,8 +0,0 @@ -clc;
-syms M1 M2 K1 K2 K3 fv1 fv2 fv3 X1 X2 F s delta;
-A = [M1*s^2+s*(fv1+fv3)+(K1+K2) -(fv3*s+K2);-(fv3*s+K2) M2*s^2+s*(fv3+fv2)+(K3+K2)];
-B = [X1;X2];
-C = [F;0];
-B = inv(A)*C;
-
-disp(B(2)/(F),"X2(s)/F(s)=");
\ No newline at end of file diff --git a/1340/CH2/EX2.2/2_2.sce b/1340/CH2/EX2.2/2_2.sce deleted file mode 100755 index 18178fe62..000000000 --- a/1340/CH2/EX2.2/2_2.sce +++ /dev/null @@ -1,4 +0,0 @@ -clc;
-syms t s;
-y = ilaplace(1/(s+3)^2,s,t);
-disp(y,"Inverse Lapalce Transform =");
diff --git a/1340/CH2/EX2.23/2_23.sce b/1340/CH2/EX2.23/2_23.sce deleted file mode 100755 index 60fb79440..000000000 --- a/1340/CH2/EX2.23/2_23.sce +++ /dev/null @@ -1,21 +0,0 @@ -clc;
-s =%s;
-Ja = 5;
-disp("kg-m^2",Ja,"Ja =")
-Jl = 700;
-disp("kg-m^2",Jl,"Jl =");
-N1 = 100;disp("turns",N1,"N1=");
-N2= 1000;disp("turns",N2,"N2=");
-Da = 2;disp("N-m sec/rad",Da,"Da=")
-Dl = 800;disp("N-m sec/rad",Dl,"Dl=");
-Tstall = 500;disp("N-m",Tstall,"Tstall=");
-Wnl = 50;disp("rad/sec",Wnl,"no load frequency =");
-Ea = 100;disp("volts",Ea,"Ea=");
-Jm = Ja + Jl*((N1/N2))^2;
-Dm = Da + Dl*((N1/N2))^2;
-k = Tstall/Ea;//k = Kt/Ra
-Kb = Ea/Wnl;
-G = syslin('c',(k/Jm)/(s*(s+(Dm+k*Kb)/Jm)));
-disp(G,"transfer function in terms of motor position and applied voltage :");
-disp(G*(N1/N2),"transfer function in terms of load position and applied voltage:")
-
diff --git a/1340/CH2/EX2.26/2_26.sce b/1340/CH2/EX2.26/2_26.sce deleted file mode 100755 index b3db06ac6..000000000 --- a/1340/CH2/EX2.26/2_26.sce +++ /dev/null @@ -1,11 +0,0 @@ -clc;
-syms y y1 y2 x;
-t = %pi/2;j = 0:%pi;
-y = 5*cos(t);disp(y,"at x = pi/2, y =");
-y1 = -5*sin(t);disp(y1,"at x = pi/2, dy/dt =");
-printf("\n neglecting higher order terms");
-k = y + y1*(x-%pi/2);
-disp(k,"linearized y =");
-
-
-
diff --git a/1340/CH2/EX2.3/2_3.sce b/1340/CH2/EX2.3/2_3.sce deleted file mode 100755 index c1e6316bf..000000000 --- a/1340/CH2/EX2.3/2_3.sce +++ /dev/null @@ -1,17 +0,0 @@ -clc;
-s = %s;
-syms t;
-num = 32;
-den = s*(s^2+12*s+32);
-y = syslin('c',num/den);
-disp(y);
-
-[A] = pfss(y);G = 0;disp(A);
-for k = 1:size(A)
- f(k) = ilaplace(A(k),s,t);
- G = G + f(k);
-end
-
-disp(G)
-
-
diff --git a/1340/CH2/EX2.5/2_5.sce b/1340/CH2/EX2.5/2_5.sce deleted file mode 100755 index 105338668..000000000 --- a/1340/CH2/EX2.5/2_5.sce +++ /dev/null @@ -1,10 +0,0 @@ -clc;
-s=%s;
-G = syslin('c',1/(s+2));
-disp(G,"G(s)=");
-disp("input is a step function:");
-R = laplace(1,t,s);// for unit step function
-C = G*R;
-syms t s;
-c = ilaplace(C,s,t);
-disp(c,"c(t)=");
\ No newline at end of file diff --git a/1340/CH3/EX3.6/3_6.sce b/1340/CH3/EX3.6/3_6.sce deleted file mode 100755 index 501518b40..000000000 --- a/1340/CH3/EX3.6/3_6.sce +++ /dev/null @@ -1,8 +0,0 @@ -clc;
-A =[0 1 0;0 0 1;-1 -2 -3];//A matrix
-B =[10;0;0];//B matrix
-C = [1 0 0];//C matrix
-ss = syslin('c',A,B,C,0);//defining a linear system
-ssprint(ss);
-tf = ss2tf(ss);//conversion from steady state to transfer function
-disp(tf,"Transfer Function :");
\ No newline at end of file diff --git a/1340/CH4/EX4.1/4_1.sce b/1340/CH4/EX4.1/4_1.sce deleted file mode 100755 index 61cfa6c8e..000000000 --- a/1340/CH4/EX4.1/4_1.sce +++ /dev/null @@ -1,18 +0,0 @@ -clc;
-s = %s;
-num = poly([-3],'s','roots');
-den = poly([-2 -4 -5],'s','roots');
-G = num/den;
-disp(G,"G(s)=");
-disp(laplace(1,t,s),"input is a step function:");
-syms t ;
-printf("C(s)=G(s)*R(s)=");
-K = G/s;
-C = syslin('c',K);
-disp(C);
-[A] = pfss(C);l=0;disp(A);
-for k = 1:size(A)
- F(k)= ilaplace(A(k),s,t);
- l = l+F(k);
-end
-disp(l,"c(t)=");
\ No newline at end of file diff --git a/1340/CH4/EX4.10/4_10.sce b/1340/CH4/EX4.10/4_10.sce deleted file mode 100755 index 58ecd4673..000000000 --- a/1340/CH4/EX4.10/4_10.sce +++ /dev/null @@ -1,18 +0,0 @@ -clc;
-s = %s;
-C1 = 26.25*(s+4)/(s*(s+3.5)*(s+5)*(s+6));
-pf = pfss(C1);
-disp(pf);
-k = numer(pf(4));
-disp("cannot be made",C1,"second order approx of",k,"since the residue of pole at -3.5,which is close to zero at 4 is =");
-C2 = 26.25*(s+4)/(s*(s+4.01)*(s+5)*(s+6));
-pf1 = pfss(C2);
-disp(pf1);
-l = numer(pf(4));
-disp("is small compared to the residues at other poles",l,"residue of pole at -4.01");
-C2 = C2 -pf1(4);
-syms t s;
-td = ilaplace(C2,s,t)
-disp(td,"second order approx of C2 = ")
-
-
diff --git a/1340/CH4/EX4.11/4_11.sce b/1340/CH4/EX4.11/4_11.sce deleted file mode 100755 index 3a61d1b3a..000000000 --- a/1340/CH4/EX4.11/4_11.sce +++ /dev/null @@ -1,17 +0,0 @@ -s = %s;
-A = [0 1 0;0 0 1;-24 -26 -9];
-B = [0;0;1];
-C = [1 1 0];
-x0 = [1;0;2];
-I = eye(3,3);
-syms t ;
-U = syslin('c', 1/(s+1));
-disp(U,"U(s)=");
-L = inv(s*I-A)*(x0+B*U);disp(L,"x1,x2 and x3 are :");
-Y = C*L;
-disp(Y,"Y(s)=");
-y = ilaplace(Y,s,t);disp(y,"output y(t)=");
-D = det(s*I-A);
-printf("Roots are the eigenvalues of the system");
-root = roots(D);
-disp(root,"eigenvalues");
diff --git a/1340/CH4/EX4.13/4_13.sce b/1340/CH4/EX4.13/4_13.sce deleted file mode 100755 index 7e6c85cf6..000000000 --- a/1340/CH4/EX4.13/4_13.sce +++ /dev/null @@ -1,16 +0,0 @@ -clc;
-s = %s;
-A =[0 1;-8 -6];
-I = eye(2,2);
-phi = inv(s*I-A);
-disp(phi,"inverse of (sI-A)=");
-syms t;
-for i =1:2
- for j =i:2
- pho(i,j) = ilaplace(phi(i,j),s,t);
-
- end
-end
-disp(pho,"State transition matrix is :");
-
-
diff --git a/1340/CH4/EX4.2/4_2.sce b/1340/CH4/EX4.2/4_2.sce deleted file mode 100755 index a46ded3f5..000000000 --- a/1340/CH4/EX4.2/4_2.sce +++ /dev/null @@ -1,13 +0,0 @@ -clc;
-s = %s;
-G = syslin('c',200/(s^2+10*s+200));
-
-disp(G,"G(s)=");
-printf("input is a Step function");
-syms t s;
-R = laplace(1,t,s);
-disp(R,"R(s)=");
-C = G*R;
-disp(C,"C(s)=G(s)R(s)=");
-l = ilaplace(C,s,t);
-disp(l,"c(t)=");
diff --git a/1340/CH4/EX4.3/4_3.sce b/1340/CH4/EX4.3/4_3.sce deleted file mode 100755 index 355349bea..000000000 --- a/1340/CH4/EX4.3/4_3.sce +++ /dev/null @@ -1,11 +0,0 @@ -clc;
-s = %s;
-G = syslin('c',36/(s^2+4.2*s+36));
-disp(G,"G(s)=");
-K = denom(G);
-coef = coeff(K);
-disp(coef);
-Wn = sqrt(coef(1,1));
-disp(Wn,"Undamped Natural Frequency =");
-zeta = coef(1,2)/(2*Wn);
-disp(zeta,"damping ratio =")
diff --git a/1340/CH4/EX4.4/4_4.sce b/1340/CH4/EX4.4/4_4.sce deleted file mode 100755 index a2492327f..000000000 --- a/1340/CH4/EX4.4/4_4.sce +++ /dev/null @@ -1,17 +0,0 @@ -clc;
-s =%s;
-for k = 12:4:20
-G = syslin('c',k/(s^2+8*s+k));
-disp(G);
-den = denom(G);
-coef = coeff(den);
-Wn = sqrt(coef(1,1));disp(Wn,"Natural Frequency = ");
-zeta = coef(1,2)/(2*Wn);disp(zeta,"Daming ratio = ");
-if(zeta==1)
- printf("system is critically damped");
-else if(zeta>1)
- printf("overdamped");
- else printf("underdamped");
- end
-end
-end
\ No newline at end of file diff --git a/1340/CH4/EX4.5/4_5.sce b/1340/CH4/EX4.5/4_5.sce deleted file mode 100755 index a83d4fdf2..000000000 --- a/1340/CH4/EX4.5/4_5.sce +++ /dev/null @@ -1,20 +0,0 @@ -clc;
-s = %s;
-G = syslin('c',100/(s^2+15*s+100));
-disp(G,"G(s)=");
-den = denom(G);
-coef = coeff(den);
-Wn = sqrt(coef(1,1));
-disp(Wn,"Natural Frequency =");
-zeta = coef(1,2)/(2*Wn);
-disp(zeta,"Damping Ratio =");
-Tp = %pi/(Wn*sqrt(1-zeta^2));
-disp(Tp,"Peak time");
-Os = %e^(-%pi*zeta/sqrt(1-zeta^2))*100;
-disp(Os,"Pecentage overshoot =");
-Ts = 4/(zeta*Wn);
-disp(Ts,"Settling time for 2% tolerance =");
-Tr = (%pi - atan(sqrt(1-zeta^2)/zeta))/(Wn*sqrt(1-zeta^2));
-disp(Tr,"Rise time =");
-C = syslin('c',G/s);
-disp(C);
\ No newline at end of file diff --git a/1340/CH4/EX4.6/4_6.sce b/1340/CH4/EX4.6/4_6.sce deleted file mode 100755 index 9d50ddeb0..000000000 --- a/1340/CH4/EX4.6/4_6.sce +++ /dev/null @@ -1,17 +0,0 @@ -s = %s;
-G = poly([-3+%i*7 -3-%i*7 ],'s','roots');
-K = poly([-3+%i*7],'s','roots')
-disp(1/G);;
-k = plzr(1/G);
-t = roots(K);
-Wn = abs(t);
-disp(Wn,"natural frequency=");
-theta = atan(imag(t)/real(t));
-disp(theta,"phase =");
-zeta = cos(theta);disp(zeta,"damping ratio =");
-Tp = %pi/(Wn*sqrt(1-zeta^2));
-disp(Tp,"Peak time =");
-Os = 100*%e^((-%pi*zeta)/sqrt(1-zeta^2));
-disp(Os,"percentage overshoot =");
-Ts = 4/abs(real(t));
-disp(Ts,"settling time with 2% tolerance =");
\ No newline at end of file diff --git a/1340/CH4/EX4.7/4_7.sce b/1340/CH4/EX4.7/4_7.sce deleted file mode 100755 index 49c5d47fd..000000000 --- a/1340/CH4/EX4.7/4_7.sce +++ /dev/null @@ -1,21 +0,0 @@ -clc;
-k=5;
-disp("N-m/rad",k,"Given value of K =");
-printf("percentage overshoot =");
-Os = 20;
-disp(Os);
-printf("settling time =");
-Ts = 2;
-disp(Ts);
-
-zeta = (-log(Os/100)/sqrt((%pi^2)+(log(Os/100))^2));disp(zeta,"damping ratio =");
-Wn = 4/(2*zeta);disp(Wn,"natural frequency =");
-A = Wn^2;
-disp(A,"K/J =");
-B = 2*zeta*Wn;
-disp(B,"D/J =");
-j = k/A;
-disp("kg-m^2",j,"value of J is =");
-d = j*B;
-disp("N-m-s/rad",d,"value of D is =");
-
diff --git a/1340/CH4/EX4.8/4_8.jpg b/1340/CH4/EX4.8/4_8.jpg Binary files differdeleted file mode 100755 index 160dedc2b..000000000 --- a/1340/CH4/EX4.8/4_8.jpg +++ /dev/null diff --git a/1340/CH4/EX4.8/4_8.sce b/1340/CH4/EX4.8/4_8.sce deleted file mode 100755 index 2a50f84c3..000000000 --- a/1340/CH4/EX4.8/4_8.sce +++ /dev/null @@ -1,16 +0,0 @@ -clc;
-t = 0:0.05:3;
-s = %s;
-T1 = 24.542/(s^2+4*s+24.542);
-T2 = 245.42/((s+10)*(s^2+4*s+24.542));
-T3 = 73.626/((s+3)*(s^2+4*s+24.542));
-f1 = syslin('c',T1);
-f2 = syslin('c',T2);
-f3 = syslin('c',T3);
-c1 = csim('step',t,f1);
-c2 = csim('step',t,f2);
-c3 = csim('step',t,f3);plot(t,c1,t,c2,t,c3);
-legend("c1","c2","c3");
-printf("c2 is a better approximation of c1 as the pole =-10 is far from dominant poles");
-
-
diff --git a/1340/CH6/EX6.1/6_1.sce b/1340/CH6/EX6.1/6_1.sce deleted file mode 100755 index a430983d7..000000000 --- a/1340/CH6/EX6.1/6_1.sce +++ /dev/null @@ -1,28 +0,0 @@ -//routh hurwitz criterion for system transfer function given by:
-// g(s)=1000/(s^3+10*s^2+31*s+1030)
-s = poly(0,'s');
-po = syslin('c',1000/(s^3+10*s^2+31*s+1030));//creates LTI system
-m = denom(po);//extracts the denominator of the transfer function
-co = coeff(m);//extracts the coefficients of the denominator
-
-
- routh=[co([4,2]); co([3,1])] ;
-
- D = det(routh)/routh(2,1);
- routh =[routh ;-D 0];
-
- t=routh (2:3 ,1:2) ;
- M = det(t)/t(2,1);
- routh =[routh ;-M 0];
- c=0;
- disp(routh);
- n = length(co);
- for i =1:n
- if(routh(i,1)<0) then
- c= c+1;
- end
- end
- if (c>=1) then
- printf("system is unstable because there is sign change in the 1st row");
- else printf("system is stable");
- end
\ No newline at end of file diff --git a/1340/CH6/EX6.10/6_10.sce b/1340/CH6/EX6.10/6_10.sce deleted file mode 100755 index 955139be6..000000000 --- a/1340/CH6/EX6.10/6_10.sce +++ /dev/null @@ -1,24 +0,0 @@ -clc;
-s = %s;
-G = s^4+3*s^3+30*s^2+30*s+200;
-disp(G);
-co = coeff(G);
-routh = [co([5,3,1]);co([4,2]) 0];
-routh = [routh;-det(routh(1:2,1:2))/routh(2,1) routh(1,3) 0];
-routh = [routh;-det(routh(2:3,1:2))/routh(3,1) (routh(3,1)*routh(2,3)-routh(2,1)*routh(3,3))/routh(3,1) 0];
-routh= [routh;-det(routh(3:4,1:2))/routh(4,1) 0 0];
-disp(routh,"routh table:");
-printf("\n routh table contains a row of all zeroes.");
-//creating an auxillary polynomial
-temp = routh(3,:);
-coef = coeff(temp);
-aux = poly([coef(2) 0 coef(1)],"s","coeffs")/coef(1);
-disp(aux,"auxillary polynomial:");
-z = roots(G);
-disp(z,"roots of polynomial:")
-for i = 1:4
- A(i)=s+z(i);
- disp(A(i),"=",i,"factor");
-end
-
-//can be done by using factors(G) and roots(G) directly
\ No newline at end of file diff --git a/1340/CH6/EX6.11/6_11.sce b/1340/CH6/EX6.11/6_11.sce deleted file mode 100755 index c235cba25..000000000 --- a/1340/CH6/EX6.11/6_11.sce +++ /dev/null @@ -1,11 +0,0 @@ -clc;
-s=%s;
-A = [0 3 1;2 8 1;-10 -5 -2];
-B = [10;0;0];
-C = [1 0 0];
-ss = syslin('c',A,B,C,0);
-tf = ss2tf(ss);disp(tf);
-H = denom(tf);
-routh = routh_t(H);
-disp(routh);
-printf("one sign change hence one pole in RHP");
diff --git a/1340/CH6/EX6.2/6_2.sce b/1340/CH6/EX6.2/6_2.sce deleted file mode 100755 index 1044abd6d..000000000 --- a/1340/CH6/EX6.2/6_2.sce +++ /dev/null @@ -1,36 +0,0 @@ -clc;
-
-s = poly(0,'s');//defines a polynomial
-po = syslin('c',10/(s^5+2*s^4+3*s^3+6*s^2+5*s+3));//defines a transfer function
-m = denom(po);//extraction of the denominator polynomial of the transfer function
-co = coeff(m);//extraction of the coefficients of the denominator polynomial
-n = length(co);
-syms eps ;
-flag = 0;
-
-routh = [co([6,4,2]);co([5,3,1])];//generates the first two rows of the routh table
-
-for j=1:n-2
- t = routh(j:j+1,1:3);
- t1 = t(1:2,1:2);
- Dt1 = det(t1)/t(2,1);
- Dt2 = (t(2,1)*t(1,3)-t(1,1)*t(2,3))/t(2,1);
-
- if(flag == 0) then
- if(Dt1==0) then
- Dt1= -eps;
- flag = 1;
- end
- end
- temp = [-Dt1 Dt2 0];
- routh = [routh;temp];
-end
-disp(routh);
-routh(3,1)= limit(routh(3,1),eps,0);
-routh(4,1) = -limit(routh(4,1),eps,0);//problem getting -infinity
-routh(5,1) = limit(routh(4,1),eps,0);
-disp(routh);
-printf("routh table has one negative sign in the s^2 row");
-printf("\nhence 2 poles in RHP");
-
-//does not recognize infinity
\ No newline at end of file diff --git a/1340/CH6/EX6.3/6_3.sce b/1340/CH6/EX6.3/6_3.sce deleted file mode 100755 index 847ad066b..000000000 --- a/1340/CH6/EX6.3/6_3.sce +++ /dev/null @@ -1,27 +0,0 @@ -
-clc;
-//stability via reversing coefficients
-s = poly(0,'s');
-tf = syslin('c',10/(s^5+2*s^4+3*s^3+6*s^2+5*s+3));
-deno = denom(tf);
-coef = coeff(deno);
-
-//reversing coefficients of tf
-tf2 = poly([coef(6) coef(5) coef(4) coef(3) coef(2) coef(1)],"s","coeff");
-disp(tf2);
-x = routh_t(tf2);//using routh_t function to generate the routh table
-disp(x);
-c = 0;
-for i=1:length(coef)
- if(x(i,1)<0)
- c = c+1;
- end
-end
-if (c>=1)
- printf("system is unstable");
- else printf("system is stable")
-
-end
-//since there is sign change in the first column of the table
-// the system is unstable
-//note: the first column does not contain any zeroes
diff --git a/1340/CH6/EX6.4/6_4.sce b/1340/CH6/EX6.4/6_4.sce deleted file mode 100755 index 0c494884e..000000000 --- a/1340/CH6/EX6.4/6_4.sce +++ /dev/null @@ -1,40 +0,0 @@ -clc;// in-built fuction routh_t can be used to generate the routh table
-s = poly(0,'s');
-tf = syslin('c',10/(s^5+7*s^4+6*s^3+42*s^2+8*s+56));
-deno = denom(tf);
-coef = coeff(deno);
-routh = [coef([6,4,2]);coef([5,3,1])];
-// we will get a row of all zeroes
-T = routh(2,:)/7;
-coef1 = coeff(T);
-// auxillary polynomial s^2+6*s+8 generation
-second = poly([coef1(3) 0 coef1(2) 0 coeff(1)],"s","coeff");disp(second);
-
-aux = derivat(second);//auxillary polynomial
-len = coeff(aux);
-routh = [routh;len(4) len(2) 0];
-disp(routh);
-t = routh(2:3,1:3);
-det1 = det(t(1:2,1:2))/t(2,1);
-det2 = -(t(1,1)*t(2,3)-t(2,1)*t(1,3))/t(2,1);
-routh = [routh;-det1 det2 0];
-t1 = routh(3:4,1:2);
-det3 = det(t1(1:2,1:2))/t1(2,1);
-routh = [routh;-det3 0 0];
-t2 = routh(4:5,1:2);
-det4 = det(t2(1:2,1:2))/t2(2,1);
-routh = [routh;-det4 0 0];
-disp(routh)
-c = 0;
-for k = 1:length(coef)
- if(routh(k,1)<0)
- c =c +1;
- end
-end
-
-if(c>=1)
- printf("system is unstable")
-else printf("system is stable,hence no poles in RHP")
- end
-
-
diff --git a/1340/CH6/EX6.5/6_5.sce b/1340/CH6/EX6.5/6_5.sce deleted file mode 100755 index 1c930dbed..000000000 --- a/1340/CH6/EX6.5/6_5.sce +++ /dev/null @@ -1,15 +0,0 @@ -clc;
-s = %s;
-G = s^8+s^7+12*s^6+22*s^5+39*s^4+59*s^3+48*s^2+38*s+20;
-x = routh_t(G);
-disp(x);c = 0;
-for i = 1:length(coeff(G))
- if(x(i,1)<0)
- c=c+1;
- end
- end
-
- if(c>=1)
- printf("poles in RHP,thus unstable");
- else printf("stable system") ;
- end
\ No newline at end of file diff --git a/1340/CH6/EX6.6/6_6.sce b/1340/CH6/EX6.6/6_6.sce deleted file mode 100755 index a24cca1f8..000000000 --- a/1340/CH6/EX6.6/6_6.sce +++ /dev/null @@ -1,22 +0,0 @@ -clc;
-s = poly(0,"s");
-G = syslin('c',200/(s*(s^3+11*s^2+11*s+6)));disp(G,"G(s)=");
-CL = G/(1+G);disp(CL,"Closed-loop transfer function:")
-deno = denom(CL);
-coef = coeff(deno);
-routh = routh_t(deno);
-disp(routh,"routh:");
-c = 0;
-for i = 1:length(coef)
- if(routh(i,1)<0)
- c = c+1;
- end
-end
-disp(c,"Number of negative signs in 1st column:");
-if(c >=1)
- disp(c+1,"poles in RHP");
- printf("no poles on jw- axis,no rows of all zeroes");
- printf("\n rest of the poles in LHP");
-else
- printf("stable system")
- end
\ No newline at end of file diff --git a/1340/CH6/EX6.7/6_7.sce b/1340/CH6/EX6.7/6_7.sce deleted file mode 100755 index 52a1e61cb..000000000 --- a/1340/CH6/EX6.7/6_7.sce +++ /dev/null @@ -1,12 +0,0 @@ -clc;
-s = %s;
-G = 1/(s*(2*s^4+3*s^3+2*s^2+3*s+2));
-den = denom(G);
-num = numer(G);
-tf = den+num;
-disp(tf,"closed loop transfer function characteristic polynomial is");
-routh = routh_t(tf);
-disp(routh);
-printf("since the entire row of s^3 is not zero");
-printf("\n putting eps = 0 we get one negative sign in 1st row \n");
-printf(" \nhence 2 poles in RHP \n");
diff --git a/1340/CH6/EX6.8/6_8.sce b/1340/CH6/EX6.8/6_8.sce deleted file mode 100755 index f89058d48..000000000 --- a/1340/CH6/EX6.8/6_8.sce +++ /dev/null @@ -1,24 +0,0 @@ -clc;
-s = %s;
-G = syslin('c',128/(s*(s^7+3*s^6+10*s^5+24*s^4+48*s^3+96*s^2+128*s+192)));
-CL = denom(G)+numer(G);
-disp(CL);
-routh = routh_t(CL);
-disp(routh,"routh table:");
-printf("fourth row is a row of all zeroes substituted by the coefficients of the auxillary polynomial");
-
-c = 0;
-for i =1:length(coeff(CL))
- if(routh(i,1)<0)
- c = c+1;
- end
-end
-
-
-if(c >=1)
- disp(c+1,"number of poles in RHP:");
- printf("2 poles on jw-axis due to row of all zeroes and rest in LHP");
-else
- printf("stable system");
- end
-
diff --git a/1340/CH6/EX6.9/6_9.sce b/1340/CH6/EX6.9/6_9.sce deleted file mode 100755 index 7665d7370..000000000 --- a/1340/CH6/EX6.9/6_9.sce +++ /dev/null @@ -1,25 +0,0 @@ -
-clc;s=%s;
-syms K ;
-G = s^3+18*s^2+77*s+K;
-disp(G);
-co0 = coeffs(G,'s',0);
-co1 = coeffs(G,'s',1);
-co2 = coeffs(G,'s',2);
-co3 = coeffs(G,'s',3);
-R =[co0 co1 co2 co3];
-N = length(R);
-routh = [R([4,2]);R([3,1])];
-
-routh = [routh;-det(routh(1:2,1:2))/routh(2,1) 0];
-routh = [routh;-det(routh(2:3,1:2))/routh(3,1) 0];
-disp(routh);
-printf("For K>1386 system is unstable. \n");
-printf("For K = 1386 system is marginally stable. \n");
-printf("For 0<K<1386 system is stable.")
-routh(3,1)=0;//for marginally stable
-K = 1386;
-disp(K,"Marginal value of K:")
-aux = 18*s^2+1386;
-Wn = roots(aux);
-disp(abs(Wn(1)),"frequency of oscillation in rad/sec:");
diff --git a/1340/CH7/EX7.1/7_1.sce b/1340/CH7/EX7.1/7_1.sce deleted file mode 100755 index 22df04735..000000000 --- a/1340/CH7/EX7.1/7_1.sce +++ /dev/null @@ -1,8 +0,0 @@ -clc;
-s = %s;
-T = syslin('c',5/(s^2+7*s+10));disp(T,"T(s)=");
-R = syslin('c',1/s);disp(R,"R(s)= unit step:");
-E = R*(1-T);
-syms t s;
-sse = limit(s*E,s,0);
-disp(sse,"Steady state error :")
\ No newline at end of file diff --git a/1340/CH7/EX7.10/7_10.sce b/1340/CH7/EX7.10/7_10.sce deleted file mode 100755 index 72cf7410b..000000000 --- a/1340/CH7/EX7.10/7_10.sce +++ /dev/null @@ -1,9 +0,0 @@ -clc;
-syms s a K;
-G = K/(s^2+a*s+K);
-disp(G,"Closed loop transfer function:");
-
-DG = diff(G,K);
-sta = (a/G)*diff(G,a);
-sta = simple(sta);
-disp(sta,"Sensitivity wrt parameter a = ")
diff --git a/1340/CH7/EX7.11/7_11.sce b/1340/CH7/EX7.11/7_11.sce deleted file mode 100755 index f7cd13384..000000000 --- a/1340/CH7/EX7.11/7_11.sce +++ /dev/null @@ -1,13 +0,0 @@ -clc;
-syms K s a;
-G = K/(s*(s+a));
-E = (1/s^2)/(1+G);
-e = limit(s*E,s,0);
-e = simple(e);
-disp(e,"steady state error = ");
-sea = (a/e)*diff(e,a);
-sek = (K/e)*diff(e,K);
-sea = simple(sea);
-sek = simple(sek);
-disp(sea,"sensitivity of error wrt parameter a = ");
-disp(sek,"\n sensitivity of error wrt parameter K =");
diff --git a/1340/CH7/EX7.12/7_12.sce b/1340/CH7/EX7.12/7_12.sce deleted file mode 100755 index 75e4e6d64..000000000 --- a/1340/CH7/EX7.12/7_12.sce +++ /dev/null @@ -1,11 +0,0 @@ -clc;
-syms K a b s;
-G = K/((s+a)*(s+b));
-Kp = limit(G,s,0);
-e = 1/(1+Kp);
-sea = (a/e)*diff(e,a);
-sea = simple(sea);
-disp(sea,"Sensitivity of error wrt a =");
-sek = (K/e)*diff(e,K);
-sek = simple(sek);
-disp(sek,"Sensitivity of error wrt K =");
\ No newline at end of file diff --git a/1340/CH7/EX7.13/7_13.sce b/1340/CH7/EX7.13/7_13.sce deleted file mode 100755 index 23f0770e0..000000000 --- a/1340/CH7/EX7.13/7_13.sce +++ /dev/null @@ -1,20 +0,0 @@ -s = %s;
-A = [-5 1 0;0 -2 1;20 -10 1];
-B = [0;0;1];
-C = [-1 1 0];
-[S1]=syslin('c',A,B,C,0);
-ssprint(S1);
-syms t s;
-tf = ss2tf(S1);
-disp(tf);
-
-R = laplace(1,t,s);
-E = R*(1- tf);
-sse = limit(s*E,s,0);
-disp(sse,"steady state error for step input:");
-
-R = laplace(t,t,s);
-E = R*(1- tf);
-sse = limit(s*E,s,0);
-disp(sse,"steady state error for ramp input:");
-printf("G(s)is type-0 system");
diff --git a/1340/CH7/EX7.14/7_14.sce b/1340/CH7/EX7.14/7_14.sce deleted file mode 100755 index 0ad671187..000000000 --- a/1340/CH7/EX7.14/7_14.sce +++ /dev/null @@ -1,15 +0,0 @@ -clc;
-A = [-5 1 0;0 -2 1;20 -10 1];
-C = [-1 1 0];
-B = [0;0;1];
-
-a= inv(A);
-syms t k;
-t = 1/k;
-x = (1+C*a*B);
-y = (C*(a^2)*B);
-disp(x,"steady state error due to step input:");
-
-z = x*t + y;
-sse = limit(z,k,0);
-disp(sse,"steady state error due to ramp input:");
\ No newline at end of file diff --git a/1340/CH7/EX7.2/7_2.sce b/1340/CH7/EX7.2/7_2.sce deleted file mode 100755 index 1a8421b8d..000000000 --- a/1340/CH7/EX7.2/7_2.sce +++ /dev/null @@ -1,14 +0,0 @@ -clc;
-s = %s;
-G = syslin('c',120*(s+2)/((s+3)*(s+4)));disp(G,"G(s)=");
-syms t s;
-R = laplace(5,t,s);
-E = R/(1+G);
-sse = limit(s*E,s,0);disp(sse,"Steady state error for step input:");
-R = laplace(5*t,t,s);
-E = R/(1+G);
-sse = limit(s*E,s,0);disp(sse,"Steady state error for ramp input:");
-R = laplace(5*t^2,t,s);
-E = R/(1+G);
-sse = limit(s*E,s,0);disp(sse,"Steady state error for parabola input:");
-printf("for TYPE-0 systems steady state error for ramp and parabola inputs is Infinity")
diff --git a/1340/CH7/EX7.3/7_3.sce b/1340/CH7/EX7.3/7_3.sce deleted file mode 100755 index b4293222e..000000000 --- a/1340/CH7/EX7.3/7_3.sce +++ /dev/null @@ -1,14 +0,0 @@ -clc;
-s = %s;
-G = syslin('c',100*((s+2)*(s+6))/(s*(s+3)*(s+4)));disp(G,"G(s)=");
-syms t s;
-R = laplace(5,t,s);
-E = R/(1+G);
-sse = limit(s*E,s,0);disp(sse,"Steady state error for step input:");
-R = laplace(5*t,t,s);
-E = R/(1+G);
-sse = limit(s*E,s,0);disp(sse,"Steady state error for ramp input:");
-R = laplace(5*t^2,t,s);
-E = R/(1+G);
-sse = limit(s*E,s,0);disp(sse,"Steady state error for parabola input:");
-printf("for TYPE-1 systems steady state error for parabola inputs is Infinity")
diff --git a/1340/CH7/EX7.4/7_4.sce b/1340/CH7/EX7.4/7_4.sce deleted file mode 100755 index 4a0f7ff6b..000000000 --- a/1340/CH7/EX7.4/7_4.sce +++ /dev/null @@ -1,38 +0,0 @@ -clc;
-s = %s;
-G1 = syslin('c',500*(s+2)*(s+5)/((s+8)*(s+10)*(s+12)));
-G2 = syslin('c',500*(s+2)*(s+5)*(s+6)/(s*(s+8)*(s+10)*(s+12)));
-G3 = syslin('c',500*(s+2)*(s+4)*(s+5)*(s+6)*(s+7)/(s^2*(s+8)*(s+10)*(s+12)));
-printf("G1,G2,G3 have poles in the LHP and on origin,hence all are stable");
-syms t s;
-R11 = laplace(1,t,s);
-E1=R11/(1+G1);
-es1= limit(s*E1,s,0);
-R12 = laplace(t,t,s);
-E2=R12/(1+G1);
-er1 = limit(s*E2,s,0);
-R13 = laplace(t^2,t,s);
-E3 = R13/(1+G3);
-ep1 = limit(s^2*E3,s,0);
-
-R21 = laplace(1,t,s);
-E1=R21/(1+G2);
-es2= limit(s*E1,s,0);
-R22= laplace(t,t,s);
-E2=R22/(1+G2);
-er2=limit(s*E2,s,0);
-R23 = laplace(t^2,t,s);
-E3 = R23/(1+G2);
-er2 = limit(s^2*E3,s,0);
-
-
-
-disp(ep1,"err parabolic",er1,"err ramp",es1,"err step","for G =500(s+2)(s+5)/((s+8)(s+10)(s+12)) ");
-disp(ep2,"err parabolic",er2,"err ramp",es2,"err step","for G =500(s+2)(s+5)(s+6)/(s(s+8)(s+10)(s+12)) ");
-disp(ep3,"err parabolic",er3,"err ramp",es3,"err step","for G =500(s+2)(s+4)(s+5)(s+6)(s+7)/(s^2(s+8)(s+10)(s+12)) ");
-
-
-
-
-
-
diff --git a/1340/CH7/EX7.5/7_5.sce b/1340/CH7/EX7.5/7_5.sce deleted file mode 100755 index 03485c6c0..000000000 --- a/1340/CH7/EX7.5/7_5.sce +++ /dev/null @@ -1,8 +0,0 @@ -clc;
-s = %s;
-Kp = 1000;disp(Kp,"value of Kp:");
-printf("Kp is finite implies a type-0 system \n");
-printf("The system is stable\n");
-printf("Input is a step since Kp is specified\n");
-E = 1/(1+Kp);
-disp(E,"Steady state error =");
diff --git a/1340/CH7/EX7.6/7_6.sce b/1340/CH7/EX7.6/7_6.sce deleted file mode 100755 index 1ea46b925..000000000 --- a/1340/CH7/EX7.6/7_6.sce +++ /dev/null @@ -1,12 +0,0 @@ -clc;
-s = %s;
-printf("S.S. error = 0.1");
-Kv = 1/0.1
-G = syslin('c',(s+5)/((s*(s+6)*(s+7)*(s+8))));
-printf("\n For type-1 system and finite steady state error implies a ramp input. \n")
-syms k s;
-disp(s*G);
-l = limit(s*G,s,0);
-disp(l);
-k = Kv/l;
-disp(k,"Value of K:");
diff --git a/1340/CH7/EX7.7/7_7.sce b/1340/CH7/EX7.7/7_7.sce deleted file mode 100755 index c7b3ee66f..000000000 --- a/1340/CH7/EX7.7/7_7.sce +++ /dev/null @@ -1,9 +0,0 @@ -clc;
-s = %s;
-G2 = syslin('c',1/(s*(s+25)));
-syms s;
-limG1= limit(1000*s/s,s,0);//limit of G1
-limG2 = limit(s/(s*G2),s,0);//limit of G2
-ess = -1/(limG1+limG2);
-disp(ess,"S.S. error due to step disturbance:");
-printf("Steady state error is inversely proportional to d.c.gain of G1(s)=1000");
\ No newline at end of file diff --git a/1340/CH7/EX7.8/7_8.sce b/1340/CH7/EX7.8/7_8.sce deleted file mode 100755 index 84bd17829..000000000 --- a/1340/CH7/EX7.8/7_8.sce +++ /dev/null @@ -1,12 +0,0 @@ -clc;
-s = %s;
-G = syslin('c',100/(s*(s+10)));
-H = syslin('c',1/(s+5));
-Ge = G/(1+G*H-G);
-disp(Ge);
-disp("It is a Type-0 system,does not contain integration term");
-syms s;
-Kp = limit(s*Ge/s,s,0);
-disp(Kp,"Kp :");
-sse = 1/(1+Kp);disp(sse,"S.S.error:")
-printf("\n negative value of Steady state error implies the output step is larger than the input step")
\ No newline at end of file diff --git a/1340/CH7/EX7.9/7_9.sce b/1340/CH7/EX7.9/7_9.sce deleted file mode 100755 index ed24c9521..000000000 --- a/1340/CH7/EX7.9/7_9.sce +++ /dev/null @@ -1,11 +0,0 @@ -clc;
-s = %s;
-G = syslin('c',100/(s*(s+10)));
-H = syslin('c',1/(s+5));
-syms t s;
-R = laplace(1,t,s);
-E = R/(1+G*H);
-sse = limit(s*E,s,0);disp(sse,"steady state error for step input:");
-R1 = laplace(t,t,s);
-E = R1/(1+G*H);
-sse = limit(s*E,s,0);disp(sse,"steady state error for ramp input:");
\ No newline at end of file diff --git a/1340/CH8/EX8.2/8_2.jpg b/1340/CH8/EX8.2/8_2.jpg Binary files differdeleted file mode 100755 index 03ef7a417..000000000 --- a/1340/CH8/EX8.2/8_2.jpg +++ /dev/null diff --git a/1340/CH8/EX8.2/8_2.sce b/1340/CH8/EX8.2/8_2.sce deleted file mode 100755 index b523ca26a..000000000 --- a/1340/CH8/EX8.2/8_2.sce +++ /dev/null @@ -1,29 +0,0 @@ -clc;
-s = %s;
-f = (s+3)/(s*(s+1)*(s+2)*(s+4));
-disp(f,"G(s)=");
-evans(f);
-xgrid(2);
-printf("\n Poles at 0,-1,-2 and -4, zero at -3 \n");
-x = denom(f);
-y = numer(f);
-
-xr = roots(x);
-yr = roots(y);
-
-[kx,lx]=size(xr);
-[ky,ly]=size(yr);
-
-sumX=0, sumY=0;
-for j = 1:kx
- sumX = sumX + xr(j);
-end
-for j = 1:ky
- sumY = sumY + yr(j);
-end
-disp((sumX-sumY)/(kx-ky),"Real axis intercept:");
-printf("\n angle = (2k+1)*180/(sum of finite poles-sum of finte zeroes)");
-printf("\n for k=0")
- theta = 180/(kx-ky);
- disp(theta,"angles made by the asymptote to the real axis for :");
-printf("1 finite zero and 3 infinite zeroes");
\ No newline at end of file diff --git a/1340/CH8/EX8.3/8_3.jpg b/1340/CH8/EX8.3/8_3.jpg Binary files differdeleted file mode 100755 index aea33d49f..000000000 --- a/1340/CH8/EX8.3/8_3.jpg +++ /dev/null diff --git a/1340/CH8/EX8.3/8_3.sce b/1340/CH8/EX8.3/8_3.sce deleted file mode 100755 index fc8b71426..000000000 --- a/1340/CH8/EX8.3/8_3.sce +++ /dev/null @@ -1,12 +0,0 @@ -clc;
-s = %s;
-G = syslin('c',((s-3)*(s-5))/((s+1)*(s+2)));
-disp(G);
-evans(G,100);xgrid();
-printf("For all the points on the root locus K.G(s).H(s) = -1");
-K = -G^(-1);
-disp(K);
-Kdot = derivat(K);disp(Kdot,"dK/ds =");
-root = roots(numer(Kdot));
-disp(root(2),"Break away point at ",root(1),"Break in point at");
-
diff --git a/1340/CH8/EX8.4/8_4.sce b/1340/CH8/EX8.4/8_4.sce deleted file mode 100755 index d83d06103..000000000 --- a/1340/CH8/EX8.4/8_4.sce +++ /dev/null @@ -1,7 +0,0 @@ -clc;
-s =%s;
-printf("Break in and Break away points satisy the relation:\n");
-printf("sum(1/(real(s)+Zi)= sum(1/(real(s)+Pi)");
-G = syslin('c',1/(s-3)+1/(s-5)-1/(s+2)-1/(s+1));
-disp(G);x =roots(numer(G));
-disp(x(2),"break-away point =",x(1),"break-in point =");
\ No newline at end of file diff --git a/1340/CH8/EX8.5/8_5.sce b/1340/CH8/EX8.5/8_5.sce deleted file mode 100755 index 24d7ccc79..000000000 --- a/1340/CH8/EX8.5/8_5.sce +++ /dev/null @@ -1,32 +0,0 @@ -clc;
-s =%s;
-syms K ;
-G = s^4+7*s^3+14*s^2+(8+K)*s+3*K;
-disp(G,"characteristic polynomial:");
-
-co0 = coeffs(G,'s',0);
-co1 = coeffs(G,'s',1);
-co2 = coeffs(G,'s',2);
-co3 = coeffs(G,'s',3);
-co4 = coeffs(G,'s',4);
-
-R =[co0 co1 co2 co3 co4];
-N = length(R);
-routh = [R([5,3,1]);R([4,2]) 0];
-D1 = -(routh(1,1)*routh(2,3)-routh(2,1)*routh(1,3));
-routh = [routh;-det(routh(1:2,1:2)) D1 0];
-routh = [routh;-det(routh(2:3,1:2))/routh(3,1) 0 0];
-routh = [routh;-det(routh(3:4,1:2))/routh(4,1) 0 0]
-disp(routh,"routh table:");
-printf("\n the possibility for imaginary axis roots implies a row of all zeroes ");
-printf("\n s1 row should have all zeroes for positive gain K");
-routh(4,1)=0;
-K = 9.65;
-disp(K,"marginal value of K:")
-//producing an auxillary polynomial from s2 row
-aux = 80.35*s^2+202.65;
-Wn = roots(aux);
-disp(Wn,"points where root locus intersects jw-axis:");
-
-
-
diff --git a/1340/CH8/EX8.6/8_6.jpg b/1340/CH8/EX8.6/8_6.jpg Binary files differdeleted file mode 100755 index 7314a34de..000000000 --- a/1340/CH8/EX8.6/8_6.jpg +++ /dev/null diff --git a/1340/CH8/EX8.6/8_6.sce b/1340/CH8/EX8.6/8_6.sce deleted file mode 100755 index eceee048d..000000000 --- a/1340/CH8/EX8.6/8_6.sce +++ /dev/null @@ -1,25 +0,0 @@ -
-clear; clc;
-xdel(winsid()); //close all windows
-
-s = %s;
-G = syslin('c',(s+2)/((s+3)*(s^2+2*s+2)));
-evans(G,10);
-xgrid();
-a = gca();
-a.box = "on";
-a.data_bounds = [-6 -3; 2 3];
-a.children(1).visible = 'off';
-xtitle('Root locus of G(s) = (s+2)/ ((s+3)*(s^2+2*s+2))');
-up = roots(numer(G));disp(up,"zero of G(s)=");
-down = roots(denom(G));disp(down,"poles of G(s)=");
-test = -1+%i;
-//calculating the angle made by the vector from zero to the pole
-zeroangle = atan((imag(down(2))-imag(up)),(real(down(2))-real(up)))*180/%pi;
-//calculating the angle made by the vector from rest of the poles to the pole
-pole1angle = atan((imag(down(2))-imag(down(1))),(real(down(2))-real(down(1))))*180/%pi;
-
-pole3angle = atan((imag(down(2))-imag(down(3))),(real(down(2))-real(down(3))))*180/%pi;
-//angle of departure = 180-(sum of angles from the rest of the poles)+(sum of angles from the zeroes)
-depang = 180-(pole1angle+pole3angle)+zeroangle;
-disp(depang,"=",down(2),"angle of departure from ");
diff --git a/1340/CH8/EX8.7/8_7.jpg b/1340/CH8/EX8.7/8_7.jpg Binary files differdeleted file mode 100755 index 9ca561c85..000000000 --- a/1340/CH8/EX8.7/8_7.jpg +++ /dev/null diff --git a/1340/CH8/EX8.7/8_7.sce b/1340/CH8/EX8.7/8_7.sce deleted file mode 100755 index 2050581b2..000000000 --- a/1340/CH8/EX8.7/8_7.sce +++ /dev/null @@ -1,20 +0,0 @@ -clear; clc;
-xdel(winsid()); //close all windows
-s = %s;
-G = syslin('c',(s^2-4*s+20)/((s+2)*(s+4)));
-zeroes = roots(numer(G));
-disp(zeroes,"zeroes are:");
-poles = roots(denom(G));
-disp(poles,"poles are:");
-evans(G,10);
-v = [-6 6 -6 6];
-mtlb_axis(v)
-sgrid([0.45,0],[0],32);//displays the zeta = 0,0.45 line
-curve_handles=datatipGetEntities()//gets the entities required
-curve_handles.visible='off';
-curve_handles.visible='on';
-zeta = 0.45;//damping ratio = 0.45
-anglezeta = (%pi-acos(0.45))*180/%pi;
-disp(anglezeta,"angle made by the line with zeta = 0.45 to the root locus:");
-printf("from root locus plotwe have for stable system gain K =(0,1.5)");
-
diff --git a/1340/CH8/EX8.8/8_8.jpg b/1340/CH8/EX8.8/8_8.jpg Binary files differdeleted file mode 100755 index 856d05e5d..000000000 --- a/1340/CH8/EX8.8/8_8.jpg +++ /dev/null diff --git a/1340/CH8/EX8.8/8_8.sce b/1340/CH8/EX8.8/8_8.sce deleted file mode 100755 index 590c0bbce..000000000 --- a/1340/CH8/EX8.8/8_8.sce +++ /dev/null @@ -1,36 +0,0 @@ -clear; clc;
-xdel(winsid()); //close all windows
-s = poly(0,"s");
-G = syslin('c',(s+1.5)/(s*(s+1)*(s+10)));
-zeroes = roots(numer(G));disp(zeroes,"zeroes are:");
-poles = roots(denom(G));disp(poles,"poles are:");
-po = 1.52;disp(po,"percentage overshoot:");
-zeta = -log(po/100)/sqrt(%pi^2+(log(po/100))^2);//calculation for damping ratio
-disp(zeta,"damping ratio :");
-evans(G,100);//max gain =100
-v = [-12 2 -10 10];//fitting the axes
-mtlb_axis(v)
-sgrid([zeta],[0],20);//displays the zeta = 0.8 line
-curve_handles=datatipGetEntities()//gets the entities required
-curve_handles.visible='off';
-curve_handles.visible='on';
-//aproximate values of gain and position can be found out from the plot by sliding datatip
-//here there are 3 points satisfying the criteria for zeta = 0.8 line
-printf("for zeta =0.8 line points on the root locus are:");
-printf("\n -0.87+ j0.66 and -0.87- j0.66 with gain = 7.36");
-printf("\n -1.19+ j0.9 and -1.19- j0.9 with gain = 12.79");
-printf("\n and -4.6+ j3.45 and -4.6- j3.45 with gain = 39.64");
-breakin = -2.8;
-Kbreakin = 27.91;
-breakaway = [-0.62 -4.4];
-Kbreakaway = [2.511 28.89];
-disp(Kbreakin," gain =",breakin,"break-in point at");
-disp(Kbreakaway,"with respective gains = ",breakaway,"break-away points at");
-wn1 = 0.66;disp(wn1,"Natural frequency for points -0.87+j0.66 and -0.87-j0.66 = ");
-wn2 = 0.9;disp(wn2,"Natural frequency for points -1.19+j0.9 and -1.19-j0.9 = ");
-wn3 = 3.45;disp(wn3,"Natural frequency for points -0.87+j0.66 and -0.87-j0.66 = ")
-
-
-
-
-
diff --git a/1340/CH8/EX8.9/8_9.jpg b/1340/CH8/EX8.9/8_9.jpg Binary files differdeleted file mode 100755 index 358fba6f8..000000000 --- a/1340/CH8/EX8.9/8_9.jpg +++ /dev/null diff --git a/1340/CH8/EX8.9/8_9.sce b/1340/CH8/EX8.9/8_9.sce deleted file mode 100755 index 0cc41ada2..000000000 --- a/1340/CH8/EX8.9/8_9.sce +++ /dev/null @@ -1,12 +0,0 @@ -clear; clc;
-xdel(winsid()); //close all windows
-s = %s;
-G =-(s+3)/(s*(s+1)*(s+2)*(s+4));
-evans(G,100);//max gain =100
-v = [-5 1 -4 4];//fitting the axes
-zeta = 0.8;
-mtlb_axis(v)
-//sgrid([zeta],[0],20);//displays the zeta = 0.8 line
-curve_handles=datatipGetEntities()//gets the entities required
-curve_handles.visible='off';
-curve_handles.visible='on';
\ No newline at end of file diff --git a/2465/CH10/EX10.1/Ex10_1.sce b/2465/CH10/EX10.1/Ex10_1.sce deleted file mode 100644 index 02cf4577c..000000000 --- a/2465/CH10/EX10.1/Ex10_1.sce +++ /dev/null @@ -1,13 +0,0 @@ -//Chapter-10,Example 1,Page 252
-clc();
-close();
-
-E = 0.296 //electrode potential at 25 degree
-
-n= 2
-
-Cu = 0.015
-
-E0=E-(0.0592/n)*log10(Cu)
-
-printf('the standard potential of Cu+2 is %.5f V ',E0)
diff --git a/2465/CH10/EX10.10/Ex10_10.sce b/2465/CH10/EX10.10/Ex10_10.sce deleted file mode 100644 index 1137bac40..000000000 --- a/2465/CH10/EX10.10/Ex10_10.sce +++ /dev/null @@ -1,12 +0,0 @@ -//Chapter-10,Example 10,Page 255
-clc();
-close();
-
-//E_H = -0.0592*pH
-//E_cell = E_H = -0.0592 *pH
-
-E_cell = 0.29
-
-pH = E_cell/0.0592
-
-printf('the pH of the solution is pH = %.2f ',pH)
diff --git a/2465/CH10/EX10.11/Ex10_11.sce b/2465/CH10/EX10.11/Ex10_11.sce deleted file mode 100644 index 3577f29b4..000000000 --- a/2465/CH10/EX10.11/Ex10_11.sce +++ /dev/null @@ -1,16 +0,0 @@ -//Chapter-10,Example 11,Page 255
-clc();
-close();
-
-E_cell = 0.123
-
-E_calomel = 0.2415
-
-E_Q = 0.6990
-
-//E_Q/H2Q = E_Q - 0.0592 *pH
-//E_cell= E_Q/H2Q - E_calomel
-
-pH = (E_cell + E_calomel - E_Q)/(-0.0592)
-
-printf('the pH of solution is pH = %.2f',pH)
diff --git a/2465/CH10/EX10.12/Ex10_12.sce b/2465/CH10/EX10.12/Ex10_12.sce deleted file mode 100644 index 8b2460a55..000000000 --- a/2465/CH10/EX10.12/Ex10_12.sce +++ /dev/null @@ -1,30 +0,0 @@ -//Chapter-10,Example 12,Page 255
-clc();
-close();
-
-R=8.316 //gas constant
-
-F=96500 //Farade's constant
-
-n=1
-
-T=298 //temperature in Kelvin
-
-E0_AgCl=-0.2223
-
-E0_Ag=0.798
-
-//cell reaction...Ag + Cl- <----> AgCl
-
-E0_cell =E0_Ag + E0_AgCl
-
-//at equilibrium two electrode potential s will be equal
-// E0_cell = (2.303*R*T/n*F)*log10(K)
-
-Ksp = 10^-(E0_cell*n*F/(2.303*R*T))
-
-printf('for AgCl solution Ksp = ')
-
-disp(Ksp)
-
-printf(' mol^2/l^2')
diff --git a/2465/CH10/EX10.2/Ex10_2.sce b/2465/CH10/EX10.2/Ex10_2.sce deleted file mode 100644 index aec51c898..000000000 --- a/2465/CH10/EX10.2/Ex10_2.sce +++ /dev/null @@ -1,21 +0,0 @@ -//Chapter-10,Example 2,Page 252
-clc();
-close();
-
-E0 = 0.34 //standard potential for copper
-
-n= 2
-
-Cu = 0.15
-
-R=8.314 //gas constant
-
-F=96500 //Farade's constant
-
-n=2
-
-T=298 //temperature in Kelvin
-
-E=E0+(2.303*R*T/(n*F))*log10(Cu)
-
-printf('the single electrode potential of copper is %.5f V ',E)
diff --git a/2465/CH10/EX10.3/Ex10_3.sce b/2465/CH10/EX10.3/Ex10_3.sce deleted file mode 100644 index e6f950fa8..000000000 --- a/2465/CH10/EX10.3/Ex10_3.sce +++ /dev/null @@ -1,25 +0,0 @@ -//Chapter-10,Example 3,Page 252
-clc();
-close();
-
-//Cell reaction is ...Zn+2 +2Ag <----> Zn + 2Ag+
-
-E0_Zn=-0.762 //standard electrode potential for Zn
-
-E0_Ag=0.798 //standard electrode potential for Ag
-
-R=8.314 //gas constant
-
-F=96500 //Farade's constant
-
-n=2
-
-T=298 //temperature in Kelvin
-
-Zn= 0.2
-
-Ag= 0.1
-
-E_cell= (E0_Zn + (R*T/(n*F))*log(Zn))-(E0_Ag + (R*T/(n*F))*log(Ag^2))
-
-printf('the cell voltage at 25 degree is %.3f V',E_cell)
diff --git a/2465/CH10/EX10.4/Ex10_4.sce b/2465/CH10/EX10.4/Ex10_4.sce deleted file mode 100644 index 1b8546cea..000000000 --- a/2465/CH10/EX10.4/Ex10_4.sce +++ /dev/null @@ -1,23 +0,0 @@ -//Chapter-10,Example 4,Page 253
-clc();
-close();
-
-//Cell reaction is ...Zn+2 +2Ag <----> Zn + 2Ag+
-
-E0_cell= 1.1 //standard potential for cell
-
-R=8.314 //gas constant
-
-F=96500 //Farade's constant
-
-n=2
-
-T=298 //temperature in Kelvin
-
-Zn= 0.001
-
-Cu= 0.1
-
-E_cell=E0_cell+(2.303*R*T/(n*F))*log10(Cu/Zn)
-
-printf('the e.m.f. of Daniel cell is %.4f V',E_cell)
diff --git a/2465/CH10/EX10.5/Ex10_5.sce b/2465/CH10/EX10.5/Ex10_5.sce deleted file mode 100644 index 714124f20..000000000 --- a/2465/CH10/EX10.5/Ex10_5.sce +++ /dev/null @@ -1,13 +0,0 @@ -//Chapter-10,Example 5,Page 253
-clc();
-close();
-
-E0_Pb=-0.13
-
-E0_Ni=-0.24
-
-E0_cell=E0_Pb-E0_Ni
-
-printf('the e.m.f. of cell is %.4f V',E0_cell)
-printf('\n the cell reaction is')
-printf('\n Ni + Pb+2 <----> Ni+2 + Pb')
diff --git a/2465/CH10/EX10.6/Ex10_6.sce b/2465/CH10/EX10.6/Ex10_6.sce deleted file mode 100644 index da05652c0..000000000 --- a/2465/CH10/EX10.6/Ex10_6.sce +++ /dev/null @@ -1,14 +0,0 @@ -//Chapter-10,Example 5,Page 253
-clc();
-close();
-
-E0_Zn=-0.76
-
-E0_Ag=0.8
-
-E0_cell=E0_Ag-E0_Zn
-
-printf('\n the cell reaction is')
-printf('\n 2Ag+ + Zn <----> 2Ag + Zn+2')
-printf('\n the e.m.f. of cell is %.4f V',E0_cell)
-
diff --git a/2465/CH10/EX10.7/Ex10_7.sce b/2465/CH10/EX10.7/Ex10_7.sce deleted file mode 100644 index c8f37d6ed..000000000 --- a/2465/CH10/EX10.7/Ex10_7.sce +++ /dev/null @@ -1,19 +0,0 @@ -//Chapter-10,Example 7,Page 254
-clc();
-close();
-
-R=8.314 //gas constant
-
-F=96500 //Farade's constant
-
-n=2
-
-T=298 //temperature in Kelvin
-
-C1= 0.01
-
-C2= 0.1
-
-E_cell=(2.303*R*T/(n*F))*log10(C2/C1)
-
-printf('the e.m.f. of cell is %.4f V',E_cell)
diff --git a/2465/CH10/EX10.8/Ex10_8.sce b/2465/CH10/EX10.8/Ex10_8.sce deleted file mode 100644 index ce565986f..000000000 --- a/2465/CH10/EX10.8/Ex10_8.sce +++ /dev/null @@ -1,30 +0,0 @@ -//Chapter-10,Example 8,Page 254
-clc();
-close();
-
-R=8.316 //gas constant
-
-F=96500 //Farade's constant
-
-n=2
-
-T=298 //temperature in Kelvin
-
-E0_Zn=-0.765
-
-E0_Cu=0.337
-
-//cell reaction...Zn + Cu+2 <----> Zn+2 + Cu
-// K = [Zn+2]*[Cu]/[Zn]*[Cu+2]...equilibrium constant
-
-E0_cell =E0_Cu - E0_Zn
-
-//at equilibrium two electrode potential s will be equal
-// E0_cell = (2.303*R*T/n*F)*log10([Zn+2]*[Cu]/[Zn]*[Cu+2])
-// E0_cell = (2.303*R*T/n*F)*log10(K)
-
-K = 10^(E0_cell/(2.303*R*T/(n*F)))
-
-printf('the equilibrium constant is K = ')
-
-disp(K)
diff --git a/2465/CH10/EX10.9/Ex10_9.sce b/2465/CH10/EX10.9/Ex10_9.sce deleted file mode 100644 index d9ab56f37..000000000 --- a/2465/CH10/EX10.9/Ex10_9.sce +++ /dev/null @@ -1,25 +0,0 @@ -//Chapter-10,Example 9,Page 255
-clc();
-close();
-
-E0_Ag = 0.799 //standard potential for copper
-
-Ksp=8.3*10^-17
-
-I=1
-
-Ag= Ksp/I
-
-n= 2
-
-R=8.314 //gas constant
-
-F=96500 //Farade's constant
-
-n=2
-
-T=298 //temperature in Kelvin
-
-E_Ag=E0_Ag+(2.303*R*T/(n*F))*log10(Ag)
-
-printf('the single electrode potential of Ag is %.5f V ',E_Ag)
diff --git a/2465/CH11/EX11.1/Ex11_1.sce b/2465/CH11/EX11.1/Ex11_1.sce deleted file mode 100644 index a91312a6c..000000000 --- a/2465/CH11/EX11.1/Ex11_1.sce +++ /dev/null @@ -1,17 +0,0 @@ -//Chapter-11,Example 1,Page 275
-clc();
-close();
-
-M =1000 //mass of alloy
-
-m_Cd= 0.25*M //25% of Cd in alloy
-
-//since in the eutectic system, 40% is Cd and 60% is Bi
-
-//corresponding to m_Cd Cd the content of Bi in eutectic is
-
-m_Bi = m_Cd*60/40
-
-m= m_Cd+m_Bi
-
-printf('the mass of eutectic in 1 kg alloy is %.f gm ',m)
diff --git a/2465/CH11/EX11.2/Ex11_2.sce b/2465/CH11/EX11.2/Ex11_2.sce deleted file mode 100644 index a1c82f3a8..000000000 --- a/2465/CH11/EX11.2/Ex11_2.sce +++ /dev/null @@ -1,19 +0,0 @@ -//Chapter-11,Example 2,Page 275
-clc();
-close();
-
-M =1000 //mass of alloy
-
-m_A= 0.4*M //40% of A in alloy
-
-m_B= 0.6*M //60% of B in alloy
-
-//since in the eutectic system, 40% is B and 60% is A
-
-//corresponding to m_A the content of m_B in eutectic is
-
-m_Be = m_A*40/60 //in eutectic
-
-m= m_B-m_Be //amount of B separated out
-
-printf('the amount of B separated out is %.2f gm ',m)
diff --git a/2465/CH17/EX17.1/Ex17_1.sce b/2465/CH17/EX17.1/Ex17_1.sce deleted file mode 100644 index ae0a60afd..000000000 --- a/2465/CH17/EX17.1/Ex17_1.sce +++ /dev/null @@ -1,29 +0,0 @@ -//Chapter-17,Example 1,Page 369
-clc();
-close();
-
-m1 = 146 //mass of Mg(HCO3)2
-
-m2 = 162 //mass of Ca(HCO3)2
-
-m3 = 95 //mass of MgCl2
-
-m4 = 136 //mass of CaSO4
-
-amnt_1 = 7.5 //amount of Mg(HCO3)2 in mg/l
-
-amnt_2 = 16 //amount of Ca(HCO3)2 in mg/l
-
-amnt_3 = 9 //amount of MgCl2 in mg/l
-
-amnt_4 = 13.6 //amount of CaSO4 in mg/l
-
-temp_hard= (amnt_1*100/m1)+(amnt_2*100/m2)
-
-perm_hard= (amnt_3*100/m3)+(amnt_4*100/m4)
-
-total= temp_hard +perm_hard
-
-printf("the temporary hardness is = %.2f mg/l",temp_hard)
-
-printf("\n the total hardness is = %.2f mg/l",total)
diff --git a/2465/CH17/EX17.2/Ex17_2.sce b/2465/CH17/EX17.2/Ex17_2.sce deleted file mode 100644 index 60ecef2e8..000000000 --- a/2465/CH17/EX17.2/Ex17_2.sce +++ /dev/null @@ -1,14 +0,0 @@ -//Chapter-17,Example 2,Page 369
-clc();
-close();
-
-m1= 136 // mass of FeSO4
-
-m2 = 100 //mass of CaCO3
-
-//for 100 ppm hardness FeSO4 required per 10^6 parts of water is 136 parts
-//for 200 ppm hardness
-
-amt= m1*200/m2
-
-printf("the amount of FeSO4 required is = %.f mg/l",amt)
diff --git a/2465/CH17/EX17.3/Ex17_3.sce b/2465/CH17/EX17.3/Ex17_3.sce deleted file mode 100644 index 11296ac69..000000000 --- a/2465/CH17/EX17.3/Ex17_3.sce +++ /dev/null @@ -1,11 +0,0 @@ -//Chapter-17,Example 3,Page 369
-clc();
-close();
-
-conc = 15.6 *10^-6 //concentration of (CO3)-2
-
-m = 60 //mass of CO3
-
-Molarity= conc*100/m
-
-printf("the molarity of (CO3)-2 is = %.6f M",Molarity)
diff --git a/2465/CH17/EX17.4/Ex17_4.sce b/2465/CH17/EX17.4/Ex17_4.sce deleted file mode 100644 index a0af0e9db..000000000 --- a/2465/CH17/EX17.4/Ex17_4.sce +++ /dev/null @@ -1,41 +0,0 @@ -//Chapter-17,Example 4,Page 370
-clc();
-close();
-
-m1 = 146 //mass of Mg(HCO3)2
-
-m2 = 162 //mass of Ca(HCO3)2
-
-m3 = 111 //mass of CaCl2
-
-m4 = 120 //mass of MgSO4
-
-m5 = 136 //mass of CaSO4
-
-amnt_1 = 12.5 //amount of Mg(HCO3)2 in ppm
-
-amnt_2 = 10.5 //amount of Ca(HCO3)2 in ppm
-
-amnt_3 = 8.2 //amount of CaCl2 in ppm
-
-amnt_4 = 2.6 //amount of MgSO4 in ppm
-
-amnt_5 = 7.5 //amount of CaSO4 in ppm
-
-temp_hard= (amnt_1*100/m1)+(amnt_2*100/m2)
-
-perm_hard= (amnt_3*100/m3)+(amnt_4*100/m4)+(amnt_5*100/m5)
-
-total= temp_hard +perm_hard
-
-printf("the temporary hardness is = %.3f mg/l",temp_hard)
-
-printf("\n the permanent hardness is = %.3f mg/l",perm_hard)
-
-printf("\n the total hardness is = %.3f mg/l",total)
-
-v= 100 //volume of sample
-
-v_EDTA = total*v/1000 //volume of EDTA
-
-printf("\n the volume of M/100 EDTA required is = %.3f ml",v_EDTA)
diff --git a/2465/CH17/EX17.5/Ex17_5.sce b/2465/CH17/EX17.5/Ex17_5.sce deleted file mode 100644 index 81bbb40e5..000000000 --- a/2465/CH17/EX17.5/Ex17_5.sce +++ /dev/null @@ -1,25 +0,0 @@ -//Chapter-17,Example 5,Page 370
-clc();
-close();
-
-v= 50000 //volume of water
-
-m1 = 84 //mass of MgCO3
-
-m2 = 100 //mass of CaCO3
-
-m3 = 95 //mass of MgCl2
-
-m4 = 111 //mass of CaCl2
-
-amnt_1 = 144 //amount of MgCO3 in ppm
-
-amnt_2 = 25 //amount of CaCO3 in ppm
-
-amnt_3 = 95 //amount of MgCl2 in ppm
-
-amnt_4 = 111 //amount of CaCl2 in ppm
-
-lime = (74/100)*[2*(amnt_1*100/m1)+(amnt_2*100/m2)+(amnt_3*100/m3)]*v
-
-printf("the lime required is = %.3f mg",lime)
diff --git a/2465/CH17/EX17.6/Ex17_6.sce b/2465/CH17/EX17.6/Ex17_6.sce deleted file mode 100644 index f138207aa..000000000 --- a/2465/CH17/EX17.6/Ex17_6.sce +++ /dev/null @@ -1,29 +0,0 @@ -//Chapter-17,Example 6,Page 371
-clc();
-close();
-
-v= 10^6 //volume of water
-
-m1 = 40 //mass of Ca+2
-
-m2 = 24 //mass of Mg+2
-
-m3 = 44 //mass of CO2
-
-m4 = 122 //mass of HCO3-
-
-amnt_1 = 20 //amount of Ca+2 in ppm
-
-amnt_2 = 25 //amount of Mg+2 in ppm
-
-amnt_3 = 30 //amount of CO2 in ppm
-
-amnt_4 = 150 //amount of HCO3- in ppm
-
-lime_1 = (74/100)*[(amnt_2*100/m2)+(amnt_3*100/m3)+(amnt_4*100/m4)]*v
-
-soda = (106/100)*[(amnt_1*100/m1)+(amnt_2*100/m2)-(amnt_4*100/m4)]*v
-
-printf("the lime required is = %.3f mg",lime_1)
-
-printf("\n the soda required is = %.3f mg",soda)
diff --git a/2465/CH17/EX17.7/Ex17_7.sce b/2465/CH17/EX17.7/Ex17_7.sce deleted file mode 100644 index 870f634e3..000000000 --- a/2465/CH17/EX17.7/Ex17_7.sce +++ /dev/null @@ -1,17 +0,0 @@ -//Chapter-17,Example 7,Page 371
-clc();
-close();
-
-v= 150 //volume of NaCl
-
-conc = 150 //concentration of NaCl
-
-amnt =v*conc *100/117 //amnt of NaCl
-
-hard = 600 //hardness of water
-
-vol= amnt*1000/hard
-
-printf("the volume of water is = %.2f litres",vol)
-
-//calculation mistake in textbook
diff --git a/2465/CH17/EX17.8/Ex17_8.sce b/2465/CH17/EX17.8/Ex17_8.sce deleted file mode 100644 index 3642e0698..000000000 --- a/2465/CH17/EX17.8/Ex17_8.sce +++ /dev/null @@ -1,17 +0,0 @@ -//Chapter-17,Example 8,Page 371
-clc();
-close();
-
-strength = 10*0.85/9 //strength of EDTA
-
-//1000 ml EDTA solution == 1 g CaCO3
-
-//for 20 ml EDTA solution
-
-amnt= 20*strength/1000
-
-//50 ml smple of water contains amnt CaCO3
-
-hard= amnt*10^6/50 //hardness of water
-
-printf("the hardness of water is = %.2f ppm", hard)
diff --git a/2465/CH17/EX17.9/Ex17_9.sce b/2465/CH17/EX17.9/Ex17_9.sce deleted file mode 100644 index 0436f50e0..000000000 --- a/2465/CH17/EX17.9/Ex17_9.sce +++ /dev/null @@ -1,31 +0,0 @@ -//Chapter-17,Example 9,Page 372
-clc();
-close();
-
-m1 = 146 //mass of Mg(HCO3)2
-
-m2 = 162 //mass of Ca(HCO3)2
-
-m3 = 111 //mass of CaCl2
-
-m4 = 120 //mass of MgSO4
-
-m5 = 136 //mass of CaSO4
-
-amnt_1 = 12.5 //amount of Mg(HCO3)2 in ppm
-
-amnt_2 = 10.5 //amount of Ca(HCO3)2 in ppm
-
-amnt_3 = 8.2 //amount of CaCl2 in ppm
-
-amnt_4 = 2.6 //amount of MgSO4 in ppm
-
-amnt_5 = 7.5 //amount of CaSO4 in ppm
-
-temp_hard= [(amnt_1*100/m1)+(amnt_2*100/m2)]*0.1
-
-perm_hard= [(amnt_3*100/m3)+(amnt_4*100/m4)+(amnt_5*100/m5)]*0.1
-
-printf("the temporary hardness is = %.4f degree Fr",temp_hard)
-
-printf("\n the permanent hardness is = %.4f degree Fr",perm_hard)
diff --git a/2465/CH18/EX18.1/Ex18_1.sce b/2465/CH18/EX18.1/Ex18_1.sce deleted file mode 100644 index d93962d69..000000000 --- a/2465/CH18/EX18.1/Ex18_1.sce +++ /dev/null @@ -1,27 +0,0 @@ -//Chapter-18,Example 1,Page 404
-clc();
-close();
-
-H=6
-
-W= 2200 //water equivalent of bomb calorimeter
-
-w= 550 //weight of water taken
-
-del_t = 2.42 //rise in temperature
-
-m= 0.92 //weight of coal burnt
-
-L =580 //latent heat of steam
-
-fuse = 10 //fuse correction
-
-acid =50 //acid correction
-
-HCV=((W+w)*(del_t)-(acid+fuse))/m
-
-NCV=HCV-(0.09*H*L)
-
-printf("HCV = %.2f cal/g",HCV)
-
-printf("\n NCV = %.2f cal/g",NCV)
diff --git a/2465/CH18/EX18.2/Ex18_2.sce b/2465/CH18/EX18.2/Ex18_2.sce deleted file mode 100644 index 76386308f..000000000 --- a/2465/CH18/EX18.2/Ex18_2.sce +++ /dev/null @@ -1,35 +0,0 @@ -//Chapter-18,Example 2,Page 405
-clc();
-close();
-
-W1 = 2.5 //weight of coal
-
-W2 = 2.415 //weight of coal after heating at 110 C
-
-W_res= 1.528 //weight of residue
-
-W_ash= 0.245 //weight of ash
-
-Mois= W1-W2 //moisture in sample
-
-per_M=Mois*100/W1
-
-printf("the percentage of moisture is %.2f ",per_M )
-
-VCM=W2-W_res //amount of VCM in sample
-
-per_VCM=VCM*100/W1
-
-printf("\n the percentage of VCM is %.2f ",per_VCM )
-
-per_ash=W_ash*100/W1
-
-printf("\n the percentage of ash is %.2f",per_ash )
-
-Fix_C= W_res-W_ash //fixed carbon
-
-per_fix=Fix_C*100/W1
-
-printf("\n the percentage of fixed carbon is %.2f",per_fix )
-
-//mistake in textbook
diff --git a/2465/CH18/EX18.3/Ex18_3.sce b/2465/CH18/EX18.3/Ex18_3.sce deleted file mode 100644 index b3e14c5d3..000000000 --- a/2465/CH18/EX18.3/Ex18_3.sce +++ /dev/null @@ -1,27 +0,0 @@ -//Chapter-18,Example 3,Page 405
-clc();
-close();
-
-H=0.77
-
-W= 395 //water equivalent of bomb calorimeter
-
-w= 3500 //weight of water taken
-
-T1=26.5 //temperature
-
-T2=29.2 //temperature
-
-m= 0.83 //weight of fuel burnt
-
-L =587 //latent heat of steam
-
-HCV=((W+w)*(T2-T1))/m
-
-NCV=HCV-(0.09*H*L)
-
-printf("HCV = %.2f cal/g",HCV)
-
-printf("\n NCV = %.2f cal/g",NCV)
-
-//calculation mistake in textbook
diff --git a/2465/CH18/EX18.4/Ex18_4.sce b/2465/CH18/EX18.4/Ex18_4.sce deleted file mode 100644 index ba8dab90c..000000000 --- a/2465/CH18/EX18.4/Ex18_4.sce +++ /dev/null @@ -1,17 +0,0 @@ -//Chapter-18,Example 4,Page 406
-clc();
-close();
-
-V1= 25 //volume of H2SO4
-
-V2 =15 //volumeof NaOH
-
-v= V1*0.1-V2*0.1 //volume of H2SO4 consumed
-
-//100 cc H2SO4 ==17 g NH3 == 14 g N
-//1 cc H2SO4 = 14/1000 g N =0.014 g N
-//0.014 g N is present in 1 g coal
-
-N= 0.014*100
-
-printf("the percentage of nitrogen is %.2f ",N)
diff --git a/2465/CH18/EX18.5/Ex18_5.sce b/2465/CH18/EX18.5/Ex18_5.sce deleted file mode 100644 index 811aae588..000000000 --- a/2465/CH18/EX18.5/Ex18_5.sce +++ /dev/null @@ -1,86 +0,0 @@ -//Chapter-18,Example 5,Page 406
-clc();
-close();
-
-
-H2 =0.24 //composition of H2
-
-CH4 =0.3 //composition of CH4
-
-CO =0.06 //composition of CO
-
-C2H6 =0.11 //composition of C2H6
-
-C2H4 =0.045 //composition of C2H4
-
-C4H8 =0.025 //composition of C4H8
-
-N2=0.12 //composition of N2
-
-CO2=0.08 //composition of CO2
-
-O2=0.02 //composition of O2
-
-//for reaction H2 + (1/2)O2 = H2O
-
-V1=H2*(1/2) //volume of O2 required
-
-//for reaction CH4 + 2O2 = CO2 + 2H2O
-
-V2=CH4*2 //volume of O2 required
-vCO2_1=CH4*1 //volume of CO2
-
-//for reaction C2H6 + (7/2)O2 = 2CO2 +3H2O
-
-V3=C2H6*(7/2) //volume of O2 required
-vCO2_2=C2H6*2 //volume of CO2
-
-//for reaction C2H4 + 3O2 = 2CO2 +2H2O
-
-V4=C2H4*3 //volume of O2 required
-vCO2_3=C2H4*2 //volume of CO2
-
-//for reaction C4H8 + 6O2 = 4CO2 +4H2O
-
-V5=C4H8*6 //volume of O2 required
-vCO2_4=C4H8*4 //volume of CO2
-
-//for reaction CO + (1/2)O2 = CO2
-
-V6=CO*(1/2) //volume of O2 required
-vCO2_5=CO*1 //volume of CO2
-
-total_O2= V1+V2+V3+V4+V5+V6-O2 //total volume of oxygen
-
-//as air contains 21% of O2 by volume
-//when 40% excess
-
-V_air = total_O2*(100/21)*(140/100) //volume of air
-
-printf("the air to fuel ratio is %.3f",V_air)
-
-total_CO2 = vCO2_1+vCO2_2+vCO2_3+vCO2_4+vCO2_5+CO2 //total volume of CO2
-
-total_dry= total_CO2 +[N2+(79*V_air/100)]+[(V_air*21/100)-total_O2]
-
-printf("\n the total volume of dry products is %.4f cubicmeter ",total_dry)
-
-CO2_dry =total_CO2*100/total_dry
-
-N2_dry =[N2+(79*V_air/100)]*100/total_dry
-
-O2_dry =[(V_air*21/100)-total_O2]*100/total_dry
-
-printf("\n Composition of products of combustion on dry basis")
-
-printf("\n CO2 = %.3f",CO2_dry)
-
-printf("\n N2 = %.3f",N2_dry)
-
-printf("\n O2 = %.3f",O2_dry)
-
-//calculation mistake in textbook
-
-
-
-
diff --git a/2465/CH18/EX18.6/Ex18_6.sce b/2465/CH18/EX18.6/Ex18_6.sce deleted file mode 100644 index 9441a7a58..000000000 --- a/2465/CH18/EX18.6/Ex18_6.sce +++ /dev/null @@ -1,37 +0,0 @@ -//Chapter-18,Example 6,Page 407
-clc();
-close();
-
-CO =0.46 //composition of CO
-
-CH4 =0.1 //composition of CH4
-
-H2 =0.4 //composition of H2
-
-C2H2 =0.02 //composition of C2H2
-
-N2=0.01 //composition of N2
-
-//for reaction CO + (1/2)O2 = CO2
-
-V1=CO*(1/2) //volume of O2 required
-
-//for reaction CH4 + 2O2 = CO2 + 2H2O
-
-V2=CH4*2 //volume of O2 required
-
-//for reaction H2 + (1/2)O2 = H2O
-
-V3=H2*(1/2) //volume of O2 required
-
-//for reaction C2H2 + (5/2)O2 = 2CO2 +H2O
-
-V4=C2H2*(5/2) //volume of O2 required
-
-total_v= V1+V2+V3+V4
-
-//as air contains 21% of O2 by volume
-
-V_air = total_v*100/21 //volume of air
-
-printf("the volume of air required is %.3f cubicmeter",V_air)
diff --git a/2465/CH22/EX22.2/Ex22_2.sce b/2465/CH22/EX22.2/Ex22_2.sce deleted file mode 100644 index 2b2998ca9..000000000 --- a/2465/CH22/EX22.2/Ex22_2.sce +++ /dev/null @@ -1,15 +0,0 @@ -//Chapter-22,Example 2,Page 502
-clc();
-close();
-
-h=2
-
-k=2
-
-l=0
-
-a= 450 //length of cube in pm
-
-d=a/sqrt((h^2)+(k^2)+(l^2))
-
-printf("\n the spacing between planes is d = %.1f pm",d)
diff --git a/2465/CH22/EX22.4/Ex22_4.sce b/2465/CH22/EX22.4/Ex22_4.sce deleted file mode 100644 index 445fdbd62..000000000 --- a/2465/CH22/EX22.4/Ex22_4.sce +++ /dev/null @@ -1,26 +0,0 @@ -//Chapter-22,Example 4,Page 502
-clc();
-close();
-
-M=58.46 //molecular weight of NaCl
-
-N= 6.023*10^23 //Avogadro number
-
-p=2.167 //density of NaCl
-
-n= 4 //number of molecules per unit cell
-
-a=nthroot((n*M/(p*N)),3)/100 //lenght of the edge
-
-h=1
-
-k=1
-
-l=0
-
-d=a/sqrt((h^2)+(k^2)+(l^2))
-
-printf("the lattice constant is a= %.12f meter",a)
-
-printf("\n the spacing between planes is d = %.10f meter",d)
-
diff --git a/2465/CH22/EX22.5/Ex22_5.sce b/2465/CH22/EX22.5/Ex22_5.sce deleted file mode 100644 index 91e96006a..000000000 --- a/2465/CH22/EX22.5/Ex22_5.sce +++ /dev/null @@ -1,22 +0,0 @@ -//Chapter-22,Example 5,Page 502
-clc();
-close();
-
-//since output current of transistor is 96% of the input current
-
-alpha = 96/100 //current gain = output current/input current
-
-Rout= 2000 //output resistance
-
-Rin= 20 //input resistance
-
-R_gain= Rout/Rin //resistance gain
-
-//According to Ohm's law V=I*R
-
-volt_gain = R_gain*alpha
-
-printf("the voltage gain = %.f",volt_gain)
-
-//voltage gain has no unit
-//printing mistake in textbook
diff --git a/2465/CH3/EX3.1/Ex3_1.sce b/2465/CH3/EX3.1/Ex3_1.sce deleted file mode 100644 index 093b57b8d..000000000 --- a/2465/CH3/EX3.1/Ex3_1.sce +++ /dev/null @@ -1,16 +0,0 @@ -
-//Chapter-3,Example 1,Page 56
-clc;
-close;
-
-M_0=200 //mass of radium
-
-total_time= 8378-1898 //in years
-
-//since t-half for radium is 1620 years
-
-t_half=6480/1620 // number of half lives
-
-m_left=M_0*(1/2)^t_half //mass of radium left
-
-printf('mass of radium left after 6480 years is %.1f mg',m_left)
diff --git a/2465/CH3/EX3.10/Ex3_10.sce b/2465/CH3/EX3.10/Ex3_10.sce deleted file mode 100644 index 334f2bd4d..000000000 --- a/2465/CH3/EX3.10/Ex3_10.sce +++ /dev/null @@ -1,17 +0,0 @@ -//Chapter-3,Example 10,Page 59
-clc;
-close;
-
-t_half = 5577 //half life of carbon(14)
-
-amnt = 1/6 // amount of carbon in fresh wood
-
-t= 2.303*t_half*log10(1/amnt)/0.693
-
-printf('the age of the wood is')
-
-disp(t)
-
-printf('years')
-
-//mistake in textbook
diff --git a/2465/CH3/EX3.11/Ex3_11.sce b/2465/CH3/EX3.11/Ex3_11.sce deleted file mode 100644 index 945857c41..000000000 --- a/2465/CH3/EX3.11/Ex3_11.sce +++ /dev/null @@ -1,11 +0,0 @@ -//Chapter-3,Example 11,Page 59
-clc;
-close;
-
-t_half = 5760 //half life of carbon(14)
-
-amnt = 1/4 // amount of carbon in fresh wood
-
-t= 2.303*t_half*log10(1/amnt)/0.693
-
-printf('the age of the wood is %.f years ',t)
diff --git a/2465/CH3/EX3.12/Ex3_12.sce b/2465/CH3/EX3.12/Ex3_12.sce deleted file mode 100644 index 8e01cce46..000000000 --- a/2465/CH3/EX3.12/Ex3_12.sce +++ /dev/null @@ -1,11 +0,0 @@ -//Chapter-3,Example 12,Page 60
-clc;
-close;
-
-t_half =6.13 //half life of Ac(222)
-
-t= 10 //time period
-
-amnt=1/10^(t*0.693/(2.303*t_half))
-
-printf('the amount of the substance left is %.4f ',amnt)
diff --git a/2465/CH3/EX3.13/Ex3_13.sce b/2465/CH3/EX3.13/Ex3_13.sce deleted file mode 100644 index fe6f94a34..000000000 --- a/2465/CH3/EX3.13/Ex3_13.sce +++ /dev/null @@ -1,19 +0,0 @@ -//Chapter-3,Example 13,Page 60
-clc;
-close;
-
-//Reaction.....N(14) + He(4) ---> O(17) +H(1)
-
-m_r= 18.01140 // total mass of reactants in a.m.u.
-
-m_p= 18.01264 // total mass of product in a.m.u.
-
-m= m_p -m_r // increase in mass
-
-Q_value= m*931 // in electron volt since 1 a.m.u. =931 MeV
-
-//since mass is increased after reaction
-// Q value is negative
-
-printf('the Q value for the reaction is %.2f MeV',-Q_value)
-
diff --git a/2465/CH3/EX3.14/Ex3_14.sce b/2465/CH3/EX3.14/Ex3_14.sce deleted file mode 100644 index 418a68b43..000000000 --- a/2465/CH3/EX3.14/Ex3_14.sce +++ /dev/null @@ -1,19 +0,0 @@ -//Chapter-3,Example 14,Page 61
-clc;
-close;
-
-//Reaction.....Li(7) + H(1) ---> He(4) +He(4)
-
-m_r= 8.02636 // total mass of reactants in a.m.u.
-
-m_p= 8.00774 // total mass of product in a.m.u.
-
-m= m_r -m_p // increase in mass
-
-Q_value= m*931 // in electron volt since 1 a.m.u. =931 MeV
-
-//since mass is decreased after reaction
-// Q value is positive
-
-printf('the Q value for the reaction is %.2f MeV',Q_value)
-
diff --git a/2465/CH3/EX3.15/Ex3_15.sce b/2465/CH3/EX3.15/Ex3_15.sce deleted file mode 100644 index a9db46a01..000000000 --- a/2465/CH3/EX3.15/Ex3_15.sce +++ /dev/null @@ -1,20 +0,0 @@ -//Chapter-3,Example 15,Page 61
-clc;
-close;
-
-//Reaction.....Li(7) + D(2) ---> He(4) + He(4) + Q
-
-m_Li= 6.01702 // Isotopic mass of Lithium in a.m.u.
-
-m_D= 2.01474 // Isotopic mass of D in a.m.u.
-
-m_He= 4.00387 // Isotopic mass of Helium in a.m.u.
-
-Q_value= (m_Li + m_D - 2*m_He)*931 // in electron volt since 1 a.m.u. =931 MeV
-
-//since mass is decreased after reaction
-// Q value is positive
-
-printf('the Q value for the reaction is %.2f MeV',Q_value)
-
-//mistake in textbook
diff --git a/2465/CH3/EX3.16/Ex3_16.sce b/2465/CH3/EX3.16/Ex3_16.sce deleted file mode 100644 index cee4cbed1..000000000 --- a/2465/CH3/EX3.16/Ex3_16.sce +++ /dev/null @@ -1,22 +0,0 @@ -//Chapter-3,Example 16,Page 61
-clc;
-close;
-
-//Reaction.....U(235) + n(1) ---> Kr(95) + Ba(139) + 2*n(1) + Q
-
-m_U= 235.124 // Isotopic mass of Uranium in a.m.u.
-
-m_n= 1.0099 // mass of neutron in a.m.u.
-
-m_Kr= 94.945 // Isotopic mass of Kripton in a.m.u.
-
-m_Ba=138.954 // Isotopic mass of Ba in a.m.u.
-
-Q_value= (m_U + m_n - (m_Kr + m_Ba + 2*m_n))*931 // in electron volt since 1 a.m.u. =931 MeV
-
-//since mass is decreased after reaction
-// Q value is positive
-
-printf('the Q value for the reaction is %.3f MeV',Q_value)
-
-//mistake in textbook
diff --git a/2465/CH3/EX3.17/Ex3_17.sce b/2465/CH3/EX3.17/Ex3_17.sce deleted file mode 100644 index 2138c04fb..000000000 --- a/2465/CH3/EX3.17/Ex3_17.sce +++ /dev/null @@ -1,18 +0,0 @@ -//Chapter-3,Example 17,Page 61
-clc;
-close;
-
-m_Ca = 39.975 //atomic mass of Calcium in a.m.u.
-
-a_no= 20 //atomic number of calcium
-
-m_proton = 1.0078 //mass of proton
-
-m_neutron = 1.0086 //mass of neutron\
-
-delta_m=a_no*(m_neutron + m_proton)- m_Ca //mass defect
-
-energy= delta_m*931/40 //binding energy per nucleon
-
-printf('binding energy per nucleon is %.3f MeV',energy)
-
diff --git a/2465/CH3/EX3.18/Ex3_18.sce b/2465/CH3/EX3.18/Ex3_18.sce deleted file mode 100644 index b132f9fdc..000000000 --- a/2465/CH3/EX3.18/Ex3_18.sce +++ /dev/null @@ -1,25 +0,0 @@ -//Chapter-3,Example 18,Page 61
-clc;
-close;
-
-energy_1= 200 *1.6*10^-13 //energy released per fission of Uranium
-
-power =1 //in watt
-
-F_rate = power/energy_1 //fission rate for generation 1 watt
-
-printf('The fission rate for generation 1 watt is ')
-
-disp(F_rate)
-
-printf(' fission/sec')
-
-//1 kg atom Of U(235) =235 Kg = 6.023*10^26 atoms
-
-energy_2 = energy_1*6.023*10^26/235 //energy released per 1 kg U(235)
-
-printf('\nThe energy released per 1kg of U(235) is ')
-
-disp(energy_2)
-
-printf(' Joule')
diff --git a/2465/CH3/EX3.19/Ex3_19.sce b/2465/CH3/EX3.19/Ex3_19.sce deleted file mode 100644 index e0c98256f..000000000 --- a/2465/CH3/EX3.19/Ex3_19.sce +++ /dev/null @@ -1,20 +0,0 @@ -//Chapter-3,Example 19,Page 62
-clc;
-close;
-
-energy= (100*10^6)*24*3600 //energy comsumed in city in a day in Joule
-
-efcy=20/100 //efficiency of reactor
-
-energy_r = energy/efcy //energy required per day
-
-energy_rl=200*1.6*10^-13 //energy released per nuclide
-
-n = energy_r/energy_rl //number of U(235) to be fissioned
-
-//6.023*10^26 atoms of U(235) are present in 235 kg
-//n atoms of U(235) are present in
-
-m=235*n/(6.023*10^26)
-
-printf('the amount of fule required for one day operation is %.2f kg',m)
diff --git a/2465/CH3/EX3.2/Ex3_2.sce b/2465/CH3/EX3.2/Ex3_2.sce deleted file mode 100644 index f89b82a5e..000000000 --- a/2465/CH3/EX3.2/Ex3_2.sce +++ /dev/null @@ -1,20 +0,0 @@ -//Chapter-3,Example 2,Page 56
-clc;
-close;
-
-m_alpha=6.646*10^-24 //mass of one alpha particle
-
-n= 2300 // number of alpha particles
-
-M=1*10^-6 //mass of plutonium
-
-//as -(dM/dt)= lamda*M
-//also (dM/dt)= n*m_alpha
-
-lamda=n*m_alpha/M
-
-t_half= 0.693/lamda //half life of Plutonium
-
-printf('the half life of Plutonium is %.f years', t_half)
-
-//mistake in text book
diff --git a/2465/CH3/EX3.4/Ex3_4.sce b/2465/CH3/EX3.4/Ex3_4.sce deleted file mode 100644 index 2a9fb99e1..000000000 --- a/2465/CH3/EX3.4/Ex3_4.sce +++ /dev/null @@ -1,23 +0,0 @@ -//Chapter-3,Example 4,Page 57
-clc;
-close;
-
-m=234 // atomic mass of uranium
-
-M_0 = 4 // initial mass of uranium
-
-t_half= 2.48*10^5 // half life of uranium
-
-t= 62000*365*24*3600 // time period
-
-lamda=8.88*10^-14
-
-M= M_0*exp(-lamda*t)
-
-printf('Mass of uranium left unchanged is %.3f mg', M)
-
-N= (M*6.023*10^20)/m
-
-A= lamda*N
-
-printf(' \n activity of uranium is %.3f disintigrations/sec ', A)
diff --git a/2465/CH3/EX3.5/Ex3_5.sce b/2465/CH3/EX3.5/Ex3_5.sce deleted file mode 100644 index 589cf1fdd..000000000 --- a/2465/CH3/EX3.5/Ex3_5.sce +++ /dev/null @@ -1,27 +0,0 @@ -//Chapter-3,Example 5,Page 57
-clc;
-close;
-
-//Part (a)
-
-t_half= 1620 //half life of radium
-
-lamda= 0.693/t_half
-
-//as radium lose one centigram mass
-
-N_0=100 // in centigram
-
-N_1=N_0-1
-
-t_1=log10(N_0/N_1)/(lamda*log10(%e))
-
-printf('Part (a)---total number of years required are %.2f years ',t_1)
-
-// Part (b)
-
-N_2= 1
-
-t_2=log10(N_0/N_2)/(lamda*log10(%e))
-
-printf('\n Part (b)---total number of years required are %.2f years ',t_2)
diff --git a/2465/CH3/EX3.6/Ex3_6.sce b/2465/CH3/EX3.6/Ex3_6.sce deleted file mode 100644 index 92663dfd4..000000000 --- a/2465/CH3/EX3.6/Ex3_6.sce +++ /dev/null @@ -1,18 +0,0 @@ -//Chapter-3,Example 6,Page 58
-clc;
-close;
-
-M = 214 // molecular mass of RaB
-
-lamda= 4.31*10^-4
-
-//since -(dN/dt)= lamda*N =3.7 *10^10
-//N = m * 6.023*10^23/ M
-
-m=(3.7*10^10)*214/(lamda*6.023*10^23)
-
-printf('the mass of RaB is ')
-
-disp(m)
-
-printf(' gram')
diff --git a/2465/CH3/EX3.7/Ex3_7.sce b/2465/CH3/EX3.7/Ex3_7.sce deleted file mode 100644 index 256697d5e..000000000 --- a/2465/CH3/EX3.7/Ex3_7.sce +++ /dev/null @@ -1,19 +0,0 @@ -//Chapter-3,Example 7,Page 58
-clc;
-close;
-
-M = 214 // molecular mass of RaB
-
-lamda= 4.31*10^-4
-
-//for 1 rd activity (dN/dt) = 10^6 dis/sec
-// -(dN/dt)= lamda*N
-//N = m * 6.023*10^23/ M
-
-m=(10^6)*214/(lamda*6.023*10^23)
-
-printf('the mass of RaB is ')
-
-disp(m)
-
-printf(' gram')
diff --git a/2465/CH3/EX3.8/Ex3_8.sce b/2465/CH3/EX3.8/Ex3_8.sce deleted file mode 100644 index 3011a501e..000000000 --- a/2465/CH3/EX3.8/Ex3_8.sce +++ /dev/null @@ -1,23 +0,0 @@ -//Chapter-3,Example 8,Page 58
-clc;
-close;
-
-// U(238)=(U(238) + Pb(206)) * exp(-lamda*t)
-
-// 1 = (1 + Pb(206)/U(238)) * exp(-lamda*t)
-
-//since Pb(206)/U(238) = 0.5
-
-// 1 = (1 + 0.5) * exp(-lamda*t)
-
-t_half = 4.5 *10^9 //half life of Uranium
-
-lamda = 0.693/t_half
-
-t= log10(1.5)/(log10(%e)*lamda)
-
-printf('the age of the rock specimen is ')
-
-disp(t)
-
-printf(' years')
diff --git a/2465/CH3/EX3.9/Ex3_9.sce b/2465/CH3/EX3.9/Ex3_9.sce deleted file mode 100644 index 1a02f1182..000000000 --- a/2465/CH3/EX3.9/Ex3_9.sce +++ /dev/null @@ -1,25 +0,0 @@ -//Chapter-3,Example 9,Page 59
-clc;
-close;
-
-mole_U =11.9/238 //mole of Uranium
-
-mole_Pb =10.3/206 //mole of lead
-
-t_half= 4.5*10^9 //half life of Uranium
-
-// U(238)=(U(238) + Pb(206)) * exp(-lamda*t)
-
-// 1 = (1 + Pb(206)/U(238)) * exp(-lamda*t)
-
-// 1 = (1 + 0.5) * exp(-lamda*t)
-
-lamda = 0.693/t_half
-
-t= log10(1+ mole_Pb/mole_U)/(log10(%e)*lamda)
-
-printf('the age of the ore is ')
-
-disp(t)
-
-printf(' years')
diff --git a/2465/CH4/EX4.1/Ex4_1.sce b/2465/CH4/EX4.1/Ex4_1.sce deleted file mode 100644 index 502811c64..000000000 --- a/2465/CH4/EX4.1/Ex4_1.sce +++ /dev/null @@ -1,17 +0,0 @@ -//Chapter-4,Example 1,Page 92
-clc;
-close;
-
-R= 2 // gas constant
-
-//as water temperature is 100 degree
-
-T = 273 + 100 // temperature in Kelvin
-
-w=R*T // work done
-
-q= 536*18 //heat in cal/mol
-
-delta_E= q-w
-
-printf('the amount of energy increased is %.1f cal/mol',delta_E)
diff --git a/2465/CH4/EX4.10/Ex4_10.sce b/2465/CH4/EX4.10/Ex4_10.sce deleted file mode 100644 index b22df3756..000000000 --- a/2465/CH4/EX4.10/Ex4_10.sce +++ /dev/null @@ -1,19 +0,0 @@ -//Chapter-4,Example 10,Page 95
-clc;
-close;
-
-delta_H1 = 538 //latent heat of water at 100 degree
-
-T1= 273 + 100 //temperature in Kelvin
-
-T2= 273 +150 //temperature in Kelvin
-
-Cp_w = 1 // for water
-
-Cp_s = 8.1/18 //for steam
-
-delta_Cp = Cp_s - Cp_w
-
-delta_H2 = delta_H1 + delta_Cp*(T2-T1) //latent heat of water at 150 degree
-
-printf('the latent heat of water at 150 degree is %.2f cal/g',delta_H2)
diff --git a/2465/CH4/EX4.11/Ex4_11.sce b/2465/CH4/EX4.11/Ex4_11.sce deleted file mode 100644 index da8cc6183..000000000 --- a/2465/CH4/EX4.11/Ex4_11.sce +++ /dev/null @@ -1,17 +0,0 @@ -//Chapter-4,Example 11,Page 96
-clc;
-close;
-
-R= 8.31 //gas constant
-
-T= 273+25 // temperature in Kelvin
-
-P1= 2 //pressure in atm
-
-P2= 1 //pressure in atm
-
-w= 2.303 *R*T*log10(P1/P2) //maximum work
-
-printf('maximum work done is %.f J', w)
-
-//mistake in textbook
diff --git a/2465/CH4/EX4.12/Ex4_12.sce b/2465/CH4/EX4.12/Ex4_12.sce deleted file mode 100644 index e245a0a62..000000000 --- a/2465/CH4/EX4.12/Ex4_12.sce +++ /dev/null @@ -1,13 +0,0 @@ -//Chapter-4,Example 12,Page 96
-clc;
-close;
-
-q_rev= 19.14 //latent heat
-
-n= 18 //mols
-
-T= 273 //temperature in Kelvin
-
-dS= q_rev*n/T
-
-printf('the change of molar entropy is %.2f J/mol',dS)
diff --git a/2465/CH4/EX4.13/Ex4_13.sce b/2465/CH4/EX4.13/Ex4_13.sce deleted file mode 100644 index f47b7d766..000000000 --- a/2465/CH4/EX4.13/Ex4_13.sce +++ /dev/null @@ -1,14 +0,0 @@ -//Chapter-4,Example 13,Page 96
-clc;
-close;
-
-
-q_rev= 12.19 //latent heat
-
-n= 32 //mols
-
-T= 273-182.9 //temperature in Kelvin
-
-dS= q_rev*n/T
-
-printf('the change of molar entropy is %.2f J/mol',dS)
diff --git a/2465/CH4/EX4.15/Ex4_15.sce b/2465/CH4/EX4.15/Ex4_15.sce deleted file mode 100644 index 95bcb4a40..000000000 --- a/2465/CH4/EX4.15/Ex4_15.sce +++ /dev/null @@ -1,19 +0,0 @@ -//Chapter-4,Example 15,Page 96
-clc;
-close;
-
-P1= 528 // pressure in mm of Hg
-
-P2= 760 // pressure in mm of Hg
-
-T2=100+273 //teperature in Kelvin
-
-delta_Hv= 545.5 *18 // latent heat of vapourisation of water in J/mol
-
-R= 1.987 //gas constant
-
-//from the integrated form of Clausius-Clapeyron equation
-
-T1= 1/((log10(P2/P1)*2.303*R/delta_Hv)+(1/T2))
-
-printf('the temperature of water is %.f K',T1)
diff --git a/2465/CH4/EX4.16/Ex4_16.sce b/2465/CH4/EX4.16/Ex4_16.sce deleted file mode 100644 index 0b2037a77..000000000 --- a/2465/CH4/EX4.16/Ex4_16.sce +++ /dev/null @@ -1,27 +0,0 @@ -//Chapter-4,Example 16,Page 97
-clc;
-close;
-
-//since the operation is isothermal & hte gas is ideal therefore..
-
-delta_E= 0 // from 1st law of thermodynamics
-
-P= 1 //pressure in atm
-
-V1= 10 // volume in cubic decimeter
-
-V2= 20 // volume in cubic decimeter
-
-W= P*(V2-V1)*(8.314/0.0821) // work done by system
-
-q=W //from 1st law of thermodynamics
-
-delta_H = delta_E + W
-
-printf(' q = %.2f J',q)
-
-printf('\n W = %.2f',W)
-
-printf('\n delta_E = %.f J',delta_E)
-
-printf('\n delta_H = %.2f J',delta_H)
diff --git a/2465/CH4/EX4.17/Ex4_17.sce b/2465/CH4/EX4.17/Ex4_17.sce deleted file mode 100644 index 483dd3afd..000000000 --- a/2465/CH4/EX4.17/Ex4_17.sce +++ /dev/null @@ -1,19 +0,0 @@ -//Chapter-4,Example 17,Page 97
-clc();
-close();
-
-q= 300 //heat energy
-
-P= 2 // pressure in atm
-
-V1= 10 // volume in litre
-
-V2= 20 //volume in litre
-
-//since 1 lit.atm = 24.25 cal
-
-W=P*(V2-V1)*24.25 //work done
-
-delta_E= q-W //from the 1st law of thermodynamics
-
-printf('the change in internal energy is %.f cal',delta_E)
diff --git a/2465/CH4/EX4.18/Ex4_18.sce b/2465/CH4/EX4.18/Ex4_18.sce deleted file mode 100644 index 2c66dc887..000000000 --- a/2465/CH4/EX4.18/Ex4_18.sce +++ /dev/null @@ -1,21 +0,0 @@ -//Chapter-4,Example 18,Page 97
-clc();
-close();
-
-T1= 300 //temperature in Kelvin
-
-T2= 363 //temperature in Kelvin
-
-P1= 1 //pressure in atm
-
-P2=7 //pressure in atm
-
-Cv=5
-
-R=2 //gas constant
-
-Cp=Cv+R
-
-delta_S= Cp*log(T2/T1)+R*log(P1/P2) //entropy change
-
-printf('the entropy change is %.4f cal/deg ', delta_S)
diff --git a/2465/CH4/EX4.19/Ex4_19.sce b/2465/CH4/EX4.19/Ex4_19.sce deleted file mode 100644 index ee777211a..000000000 --- a/2465/CH4/EX4.19/Ex4_19.sce +++ /dev/null @@ -1,19 +0,0 @@ -//Chapter-4,Example 19,Page 97
-clc();
-close();
-
-T1= 300 //temperature in Kelvin
-
-T2= 310 //temperature in Kelvin
-
-Kp1=3.49*10^-2 //equilibrium constant
-
-delta_H=-11200
-
-R= 1.987 //gas constant
-
-//from Van't Hoff's Equation
-
-Kp2=Kp1*10^(delta_H*((1/T1)-(1/T2))/(2.303*R))
-
-printf('the value of Kp2 = %.6f/atm ', Kp2)
diff --git a/2465/CH4/EX4.2/Ex4_2.sce b/2465/CH4/EX4.2/Ex4_2.sce deleted file mode 100644 index d2dbc03d9..000000000 --- a/2465/CH4/EX4.2/Ex4_2.sce +++ /dev/null @@ -1,11 +0,0 @@ -//Chapter-4,Example 2,Page 93
-clc;
-close;
-
-q= 990*4.2/10^3 //heat in kiloJoule
-
-w= 8.36*10^9/((10^3)*(10^7)) //work in kiloJoule
-
-delta_E = q-w
-
-printf('the internal energy change of system is %.3f kJ',delta_E)
diff --git a/2465/CH4/EX4.3/Ex4_3.sce b/2465/CH4/EX4.3/Ex4_3.sce deleted file mode 100644 index d3037835a..000000000 --- a/2465/CH4/EX4.3/Ex4_3.sce +++ /dev/null @@ -1,13 +0,0 @@ -//Chapter-4,Example 3,Page 93
-clc;
-close;
-
-n=1 // number of mol
-
-R= 8.314 // gas constant
-
-T = 273 + 27 // temperature in Kelvin
-
-w=n*R*T/1000 // work done in kiloJoule
-
-printf('work done by reaction ai 27 degree is %.4f kJ',w)
diff --git a/2465/CH4/EX4.4/Ex4_4.sce b/2465/CH4/EX4.4/Ex4_4.sce deleted file mode 100644 index 9afb4eb21..000000000 --- a/2465/CH4/EX4.4/Ex4_4.sce +++ /dev/null @@ -1,21 +0,0 @@ -//Chapter-4,Example 4,Page 93
-clc;
-close;
-
-q_v=-97000 //in cal
-
-R= 8.314 // gas constant
-
-T = 273 + 200 // temperature in Kelvin
-
-n_1= 1 //mols of gaseous reactant
-
-n_2= 1 // mols of gaseous product
-
-delta_n= n_2-n_1
-
-//q_p= q_v + delta_n*R*T
-
-q_p= q_v + delta_n*R*T
-
-printf('the heat combustion of carbon is %.f cals',q_p)
diff --git a/2465/CH4/EX4.5/Ex4_5.sce b/2465/CH4/EX4.5/Ex4_5.sce deleted file mode 100644 index ce36439e7..000000000 --- a/2465/CH4/EX4.5/Ex4_5.sce +++ /dev/null @@ -1,19 +0,0 @@ -//Chapter-4,Example 5,Page 93
-clc;
-close;
-
-delta_H= -109 // heat change in Kcal
-
-n_1= 2 //mols of gaseous reactant
-
-n_2= 1 // mols of gaseous product
-
-delta_n= n_2-n_1
-
-T=500
-
-R= 2*10^-3
-
-delta_E = (delta_H) - (delta_n*R*T)
-
-printf('the value of delta_E is %.f Kcal',delta_E)
diff --git a/2465/CH4/EX4.6/Ex4_6.sce b/2465/CH4/EX4.6/Ex4_6.sce deleted file mode 100644 index 7509cd20a..000000000 --- a/2465/CH4/EX4.6/Ex4_6.sce +++ /dev/null @@ -1,18 +0,0 @@ -//Chapter-4,Example 6,Page 93
-clc;
-close;
-
-delta_H1= -337.2 // Heat combustion for ethylene
-
-delta_H2=-68.3 // Heat combustion for hudrogen
-
-delta_H3= 372.8 // Heat combustion for ethane
-
-//Given reaction is...
-// C2H4(g) +H2(g) ---> C2H6(g)
-
-delta_H= delta_H1 + delta_H2 +delta_H3
-
-printf('the heat combustion for given reaction is %.2f Kcal',delta_H)
-
-
diff --git a/2465/CH4/EX4.7/Ex4_7.sce b/2465/CH4/EX4.7/Ex4_7.sce deleted file mode 100644 index bb3bd5922..000000000 --- a/2465/CH4/EX4.7/Ex4_7.sce +++ /dev/null @@ -1,16 +0,0 @@ -//Chapter-4,Example 7,Page 94
-clc;
-close;
-
-delta_H1= 104 //for reaction.. H2(g)---> 2H(g)
-
-delta_H2= 120/2 //for reaction.. (1/2)O2(g)---> O(g)
-
-delta_H3= -58 //for reaction.. H2(g) + (1/2)O2(g)---> H2O(g)
-
-delta_H=delta_H1 + delta_H2 - delta_H3
-
-//there are two O-H bonds
-//therefore for one bond required heat energy is half of delta_H
-
-printf('the O-H bond energy is %.f Kcal',delta_H/2)
diff --git a/2465/CH4/EX4.8/Ex4_8.sce b/2465/CH4/EX4.8/Ex4_8.sce deleted file mode 100644 index 2a642f92e..000000000 --- a/2465/CH4/EX4.8/Ex4_8.sce +++ /dev/null @@ -1,23 +0,0 @@ -//Chapter-4,Example 8,Page 94
-clc;
-close;
-
-delta_H_C= -393 // enthalpy for carbon
-
-delta_H_H2= -286 //enthalpy for hydrogen
-
-delta_H_C3H8=-2220 //enthalpy for propane
-
-// According to Hess's Law... delta_H1 = delta_H2 - delta_H3
-
-//delta_H2 for reaction... 3C +4H2 +5O2 ----> 3CO2 +4H2O
-
-delta_H2= 3*delta_H_C +4*delta_H_H2
-
-//delta_H2 for reaction... C3H8 + 5O2 ----> 3CO2 +4H2O
-
-delta_H3= delta_H_C3H8
-
-delta_Hf= delta_H2 - delta_H3 //enthalpy for propane at 298 K
-
-printf('the enthalpy of formation of propane at 298K is %.f Kcal', delta_Hf)
diff --git a/2465/CH4/EX4.9/Ex4_9.sce b/2465/CH4/EX4.9/Ex4_9.sce deleted file mode 100644 index 39c08702c..000000000 --- a/2465/CH4/EX4.9/Ex4_9.sce +++ /dev/null @@ -1,15 +0,0 @@ -//Chapter-4,Example 9,Page 95
-clc;
-close;
-
-delta_H2= 2386 //enthalpy for.. yellow P---> H3PO4
-
-delta_H3= 2113 //enthalpy for.. red P---> H3PO4
-
-delta_HT = delta_H2- delta_H3 //enthalpy for...yellow P ---> red P
-
-// According to Hess's Law... delta_H1 = delta_H2 - delta_H3
-
-delta_HT = delta_H2 - delta_H3 // delta_H1 = delta_HT
-
-printf('the enthalpy change of transition from yellow P to red P is %.f cals',delta_HT)
diff --git a/2465/CH5/EX5.1/Ex5_1.sce b/2465/CH5/EX5.1/Ex5_1.sce deleted file mode 100644 index aa4ffc6d9..000000000 --- a/2465/CH5/EX5.1/Ex5_1.sce +++ /dev/null @@ -1,23 +0,0 @@ -//Chapter-5,Example 1,Page 121
-clc();
-close();
-
-//for 1st order reaction
-//k = (1/t)*log(a/(a-x))
-
-a= 46.1 //time value
-
-//time intervals
-
-t=[ 5 10 20 30 50]
-
-x=[ 37.1 29.8 19.6 12.3 5.0]
-
-k = (1 ./t).*log(a./(x))
-
-printf('value of k are ' )
-
-disp(k)
-
-printf('since k values are fairly constant by putting in 1nd order rate equation. \nHence decomposition of H2O2 is of 1st order.')
-
diff --git a/2465/CH5/EX5.10/Ex5_10.sce b/2465/CH5/EX5.10/Ex5_10.sce deleted file mode 100644 index d2c27a4d5..000000000 --- a/2465/CH5/EX5.10/Ex5_10.sce +++ /dev/null @@ -1,29 +0,0 @@ -//Chapter-5,Example 10,Page 125
-clc();
-close();
-
-T1=50 //time in sec
-
-T2 = 25 //time in sec
-
-a1=0.5 //initial concentration
-
-a2= 1
-
-// (T1/T2) = (a2/a1)^(n-1)
-//therefore (50/25) =(1/0.5)^(n-1)
-// 2=2^(n-1)
-// n=2
-//hence its 2nd order
-
-t_half= T1
-
-k=1/(a1*t_half)
-
-//assume y= a-x
-
-y=0.2*a1 //remaining concentration
-
-t=(a1-y)/(a1*k*(y))
-
-printf('the time taken is %.f sec ',t)
diff --git a/2465/CH5/EX5.11/Ex5_11.sce b/2465/CH5/EX5.11/Ex5_11.sce deleted file mode 100644 index 06b492323..000000000 --- a/2465/CH5/EX5.11/Ex5_11.sce +++ /dev/null @@ -1,23 +0,0 @@ -//Chapter-5,Example 11,Page 126
-clc();
-close();
-
-a=0.1 //initial concentration of reactants
-
-x=0.2*a
-
-t=40 //time
-
-k=x/(a*t*(a-x))
-
-t_half=1/(a*k)
-
-x1=0.75*a
-
-t1=x1/(k*a*(a-x1))
-
-printf('the rate constant is k = %.4f l/mol.min',k)
-
-printf('\n the half life period is %.f mins',t_half)
-
-printf('\n the time required to complete 75 percent reaction is %.f mins',t1)
diff --git a/2465/CH5/EX5.12/Ex5_12.sce b/2465/CH5/EX5.12/Ex5_12.sce deleted file mode 100644 index 608882bf0..000000000 --- a/2465/CH5/EX5.12/Ex5_12.sce +++ /dev/null @@ -1,23 +0,0 @@ -//Chapter-5,Example 12,Page 126
-clc();
-close();
-
-a1=100
-
-x1=1
-
-t1=1
-
-k=2.303*log10(a1/(a1-x1))/t1
-
-t2=60 //time in minutes
-
-a2=100
-
-//assume (a2-x2)= y
-
-y= 1/(10^(k*t2/2.303)/a2)
-
-printf('the undecomposed is %.2f ',y)
-
-//mistake in textbook
diff --git a/2465/CH5/EX5.15/Ex5_15.sce b/2465/CH5/EX5.15/Ex5_15.sce deleted file mode 100644 index 0b9f3a800..000000000 --- a/2465/CH5/EX5.15/Ex5_15.sce +++ /dev/null @@ -1,17 +0,0 @@ -//Chapter-5,Example 15,Page 128
-clc();
-close();
-
-K1=2.45*10^-5 //rate constant at 273 K
-
-K2=162*10^-5 //rate constant at 303 K
-
-T1=273 //temperature in Kelvin
-
-T2=303 //temperature in Kelvin
-
-R=1.987 //gas constant
-
-Ea= log10(K2/K1)*2.303*R*T1*T2/(T2-T1)
-
-printf('the activation energy is Ea = %.f cal/mole' ,Ea)
diff --git a/2465/CH5/EX5.16/Ex5_16.sce b/2465/CH5/EX5.16/Ex5_16.sce deleted file mode 100644 index 90d6670a2..000000000 --- a/2465/CH5/EX5.16/Ex5_16.sce +++ /dev/null @@ -1,19 +0,0 @@ -//Chapter-5,Example 16,Page 128
-clc();
-close();
-
-t_half = 600 // half life
-
-K=0.693/t_half
-
-Ea=98600 //activation energy
-
-A= 4*10^13 //Arrhenius factor
-
-R=8.316 //gas constant
-
-T=Ea/(2.303*R*log10(A/K))
-
-printf('temperature is %.f K',T)
-
-//mistake in textbook
diff --git a/2465/CH5/EX5.17/Ex5_17.sce b/2465/CH5/EX5.17/Ex5_17.sce deleted file mode 100644 index 7156929ab..000000000 --- a/2465/CH5/EX5.17/Ex5_17.sce +++ /dev/null @@ -1,17 +0,0 @@ -//Chapter-5,Example 17,Page 129
-clc();
-close();
-
-K1=5*10^-3 //rate constant at 800 degrees
-
-Ea=4.5*10^4 //activation energy
-
-T1=800+273 //temperature in Kelvin
-
-T2=875+273 //temperature in Kelvin
-
-R=8.314 //gas constant
-
-K2=K1*10^(Ea*(T2-T1)/(2.303*R*T1*T2))
-
-printf('the value of K2 = %.4f l/mol.sec',K2)
diff --git a/2465/CH5/EX5.2/Ex5_2.sce b/2465/CH5/EX5.2/Ex5_2.sce deleted file mode 100644 index e1d462398..000000000 --- a/2465/CH5/EX5.2/Ex5_2.sce +++ /dev/null @@ -1,19 +0,0 @@ -//Chapter-5,Example 2,Page 122
-clc();
-close();
-
-t=[7.18 18 27.05] //time in minute
-
-r=[ 21.4 17.7 15] //rotation in degrees
-
-r_0=24.09
-
-r_a=-10.74
-
-k=(1 ./t).*log10((r_0-r_a)./(r-r_a))
-
-printf('values of k')
-
-disp(k)
-
-printf('since k values are fairly constant by putting in 1nd order rate equation. \nHence hydrolysis of methyl acetate is of 1st order.')
diff --git a/2465/CH5/EX5.3/Ex5_3.sce b/2465/CH5/EX5.3/Ex5_3.sce deleted file mode 100644 index 08a5f99ec..000000000 --- a/2465/CH5/EX5.3/Ex5_3.sce +++ /dev/null @@ -1,19 +0,0 @@ -//Chapter-5,Example 3,Page 122
-clc();
-close();
-
-t=[75 119 183] //time in minute
-
-V=[24.20 26.60 29.32] //volume of alkali used
-
-V_0=19.24
-
-V_a=42.03
-
-k=(2.303 ./t).*log10((V_a-V_0)./(V_a-V))
-
-printf('values of k')
-
-disp(k)
-
-printf('since k values are fairly constant by putting in 1nd order rate equation. \nHence hydrolysis of methyl acetate is of 1st order.')
diff --git a/2465/CH5/EX5.4/Ex5_4.sce b/2465/CH5/EX5.4/Ex5_4.sce deleted file mode 100644 index 9f7f895e6..000000000 --- a/2465/CH5/EX5.4/Ex5_4.sce +++ /dev/null @@ -1,15 +0,0 @@ -//Chapter-5,Example 4,Page 123
-clc();
-close();
-
-t= 30 //time in minutes
-
-a=100
-
-x= 25
-
-k=(2.303/t)*log10(a/(a-x))
-
-t_half=0.693/k
-
-printf('the time of 50 percent completion of reaction is %.2f mins',t_half)
diff --git a/2465/CH5/EX5.5/Ex5_5.sce b/2465/CH5/EX5.5/Ex5_5.sce deleted file mode 100644 index 371a55fec..000000000 --- a/2465/CH5/EX5.5/Ex5_5.sce +++ /dev/null @@ -1,17 +0,0 @@ -//Chapter-5,Example 5,Page 123
-clc();
-close();
-
-t_half=17 //half life period
-
-k=0.693/t_half //rate constant
-
-a=100
-
-x= 75
-
-t=(2.303/k)*log10(a/(a-x))
-
-printf('the rate constant is k = %.5f /min',k)
-
-printf('\n the time taken t = %.1f min', t)
diff --git a/2465/CH5/EX5.6/Ex5_6.sce b/2465/CH5/EX5.6/Ex5_6.sce deleted file mode 100644 index f607293bc..000000000 --- a/2465/CH5/EX5.6/Ex5_6.sce +++ /dev/null @@ -1,17 +0,0 @@ -//Chapter-5,Example 6,Page 123
-clc();
-close();
-
-t_half=1600 //half life period
-
-k=0.693/t_half //rate constant
-
-a=100
-
-x= 80
-
-t=(2.303/k)*log10(a/(a-x))
-
-printf('\n the time taken t = %.2f years', t)
-
-//mistake in textbook
diff --git a/2465/CH5/EX5.7/Ex5_7.sce b/2465/CH5/EX5.7/Ex5_7.sce deleted file mode 100644 index 728c0cf49..000000000 --- a/2465/CH5/EX5.7/Ex5_7.sce +++ /dev/null @@ -1,27 +0,0 @@ -//Chapter-5,Example 7,Page 124
-clc();
-close();
-
-//for 2st order reaction
-//k = (1/a*t)*(x/(a-x))
-
-a= 16
-
-//time intervals
-
-t=[ 5 15 25 35]
-
-//assume y = a-x
-
-y=[ 10.24 6.13 4.32 3.41] //volume of acid
-
-x=a-y
-
-k = (1 ./(a*t)).*(x./(y))
-
-printf('value of k are ' )
-
-disp(k)
-
-printf('since k values are fairly constant by putting in 2nd order rate equation. \nHence dhydrolysis of methyl acetate is of 2st order.')
-
diff --git a/2465/CH5/EX5.9/Ex5_9.sce b/2465/CH5/EX5.9/Ex5_9.sce deleted file mode 100644 index 9e528c241..000000000 --- a/2465/CH5/EX5.9/Ex5_9.sce +++ /dev/null @@ -1,15 +0,0 @@ -//Chapter-5,Example 9,Page 125
-clc();
-close();
-
- //final concentration is half of initial concentration
-//therefore t =t_half
-t= 60 //time in minutes
-
-t_half=t
-
-k=5.2*10^-3 //rste constant
-
-a=1/(k*t_half) //for 2nd order reaction
-
-printf('the initial concentration is %.2f mol/litre',a)
diff --git a/2465/CH8/EX8.1/Ex8_1.sce b/2465/CH8/EX8.1/Ex8_1.sce deleted file mode 100644 index 9917fc3f0..000000000 --- a/2465/CH8/EX8.1/Ex8_1.sce +++ /dev/null @@ -1,11 +0,0 @@ -//Chapter-8,Example 1,Page 195
-clc();
-close();
-
-OH=2*0.005 //in mol/litre
-
-pOH=-log10(OH)
-
-pH=14-pOH
-
-printf('the pH of Ca(OH)2 is pH = %.f ',pH)
diff --git a/2465/CH8/EX8.2/Ex8_2.sce b/2465/CH8/EX8.2/Ex8_2.sce deleted file mode 100644 index f6a1b0244..000000000 --- a/2465/CH8/EX8.2/Ex8_2.sce +++ /dev/null @@ -1,21 +0,0 @@ -//Chapter-8,Example 2,Page 195
-clc();
-close();
-
-H=20*0.1/1000 //as 20 ml of 0.1M HCl
-
-pH=-log10(H)
-
-pOH=14-pH
-
-OH=10^(-pOH)
-
-printf(' the [H+] = %.4f mole/l',H)
-
-printf('\n the [OH-] =')
-
-disp(OH)
-
-printf(' mole/l')
-
-printf('\n the pH = %.f ',pH)
diff --git a/2465/CH8/EX8.3/Ex8_3.sce b/2465/CH8/EX8.3/Ex8_3.sce deleted file mode 100644 index 6c3156976..000000000 --- a/2465/CH8/EX8.3/Ex8_3.sce +++ /dev/null @@ -1,32 +0,0 @@ -//Chapter-8,Example 3,Page 195
-clc();
-close();
-
-//solution for (a) part
-
-conc1=1*10^-8 //concentration of HCl solution
-
-//let [H+] concentration from water = x
-//so, [H+] of solution = conc1*x an [OH-] = x
-//......Kw = [H+]*[OH-] = 10^-14
-//......x^2 +(10^-8)*x -(10^-14)=0
-x = (-10^-8 + sqrt((10^-8)^2 + 4*1*10^-14))/(2*1)
-
-H=conc1 +x
-
-pH1=-log10(H)
-
-printf('for HCl the pH = %.3f',pH1)
-
-
-//solution for (b) part
-conc2= 1*10^-8 //concentration of NaOH solution
-
-OH=x+conc2
-
-pOH2=-log10(OH)
-
-pH2=14 - pOH2
-
-printf('\n for NaOH the pH = %.3f',pH2)
-
diff --git a/2465/CH8/EX8.4/Ex8_4.sce b/2465/CH8/EX8.4/Ex8_4.sce deleted file mode 100644 index a9d10cf1d..000000000 --- a/2465/CH8/EX8.4/Ex8_4.sce +++ /dev/null @@ -1,24 +0,0 @@ -//Chapter-8,Example 4,Page 196
-clc();
-close();
-
-alpha1=0.02
-
-Ka=1.8*10^-5
-
-//at equilibrium..
-//[CH3COOH] = C1* (1-alpha1)
-//[H+] = C1* alpha1
-//[CH3COO-] = C1* alpha1
-// Ka =[H+] * [CH3COO-]/[CH3COOH]
-// Ka = C1* alpha1*C1* alpha1/(C1 (1-alpha1))
-
-C1=Ka*(1-alpha1)/alpha1^2
-
-printf('the molar concentration of CH3COOH is C = %.4f molar',C1)
-
-C2=0.01
-
-alpha2= sqrt(Ka/C2)
-
-printf('\n alpha = %.4f ',alpha2)
diff --git a/2465/CH8/EX8.5/Ex8_5.sce b/2465/CH8/EX8.5/Ex8_5.sce deleted file mode 100644 index 90551f959..000000000 --- a/2465/CH8/EX8.5/Ex8_5.sce +++ /dev/null @@ -1,15 +0,0 @@ -//Chapter-8,Example 5,Page 196
-clc();
-close();
-
-pKa=4.74
-
-salt=0.1
-
-acid=0.1
-
-//according to Henderson equation pH of buffer solution
-
-pH = pKa + log10(salt/acid)
-
-printf('the pH of buffer solution is pH = %.2f ',pH)
diff --git a/2465/CH8/EX8.6/Ex8_6.sce b/2465/CH8/EX8.6/Ex8_6.sce deleted file mode 100644 index 984f0c31f..000000000 --- a/2465/CH8/EX8.6/Ex8_6.sce +++ /dev/null @@ -1,17 +0,0 @@ -//Chapter-8,Example 6,Page 196
-clc();
-close();
-
-pH= 7.4 //of blood
-
-H= 10^(-pH)
-
-//assume ratio of HCO3- and H2CO3 is r
-
-Ka= 4.5*10^-7
-
-// Ka = [H+]*[HCO3-]/[H2CO3]
-
-r=Ka/H
-
-printf('the ratio of HCO3- and H2CO3 is %.f',r)
diff --git a/2465/CH8/EX8.7/Ex8_7.sce b/2465/CH8/EX8.7/Ex8_7.sce deleted file mode 100644 index 1d5b25cf9..000000000 --- a/2465/CH8/EX8.7/Ex8_7.sce +++ /dev/null @@ -1,14 +0,0 @@ -//Chapter-8,Example 7,Page 196
-clc();
-close();
-
-Ksp=3.45*10^-11 //solubility product of CaF2
-
-//Ksp = [Ca+2]*[F-]^2
-//Ksp = [S]*[2*S]^2
-
-S = nthroot(Ksp,3)/4
-
-printf('the solubility of CaF2 is S = %.7f mole/litre',S)
-
-//mistake in textbook
diff --git a/2465/CH8/EX8.8/Ex8_8.sce b/2465/CH8/EX8.8/Ex8_8.sce deleted file mode 100644 index 7e43b504c..000000000 --- a/2465/CH8/EX8.8/Ex8_8.sce +++ /dev/null @@ -1,19 +0,0 @@ -//Chapter-8,Example 8,Page 197
-clc();
-close();
-
-Ksp=8*10^-12 //solubility product of SrF2
-
-//Ksp= [Sr+2]*[F-]^2.....F=0.1 M
-
-F=0.1 //concentration of F in SrF2
-
-S=Ksp/F^2
-
-printf('the solubility of SrF2 is')
-
-disp(S)
-
-printf('mol/litre')
-
-//mistake in textbook
diff --git a/2465/CH9/EX9.1/Ex9_1.sce b/2465/CH9/EX9.1/Ex9_1.sce deleted file mode 100644 index 8c983f2ae..000000000 --- a/2465/CH9/EX9.1/Ex9_1.sce +++ /dev/null @@ -1,19 +0,0 @@ -//Chapter-9,Example 1,Page 219
-clc();
-close();
-
-a= 1.25 //cross section area in cmsquare
-
-l= 10.5 //distance of seperation
-
-r=1996 //resistance
-
-O_cond= 1/r //observed conductivity
-
-C_constant = l/a //cell constant
-
-S_cond=C_constant*O_cond //specific conductivity
-
-printf('the cell constant is %.2f /cm',C_constant)
-
-printf('\n the specific conductivity is %.5f /ohm.cm ',S_cond)
diff --git a/2465/CH9/EX9.10/Ex9_10.sce b/2465/CH9/EX9.10/Ex9_10.sce deleted file mode 100644 index dcd2b7092..000000000 --- a/2465/CH9/EX9.10/Ex9_10.sce +++ /dev/null @@ -1,22 +0,0 @@ -//Chapter-9,Example 10,Page 221
-clc();
-close();
-
-lamda_Ag = 58.3
-
-lamda_Cl=65.3
-
-lamda_v=lamda_Ag+lamda_Cl //Kohlrausch's law
-
-Kv=1.24*10^-6 //specific conductivity
-
-V=lamda_v/(Kv*1000)
-
-wt=143.5 //molecular weight of AgCl
-
-S=wt/V
-
-printf('the solubility off AGCl is %.5f g/l',S)
-
-
-//mistake in textbook
diff --git a/2465/CH9/EX9.11/Ex9_11.sce b/2465/CH9/EX9.11/Ex9_11.sce deleted file mode 100644 index 3c674c678..000000000 --- a/2465/CH9/EX9.11/Ex9_11.sce +++ /dev/null @@ -1,17 +0,0 @@ -//Chapter-9,Example 11,Page 222
-clc();
-close();
-
-u= 0.196 //speed of Ag+
-
-v=1 //speed of NO3-
-
-t_Ag=u/(u+v) //transport number of Ag+ ions
-
-t_NO3= 1-t_Ag //transportnumber of NO3- ions
-
-printf('the transport number of Ag+ ions is %.3f',t_Ag)
-
-printf('\n the transport number of NO3+ ions is %.3f',t_NO3)
-
-//mistake in textbook
diff --git a/2465/CH9/EX9.12/Ex9_12.sce b/2465/CH9/EX9.12/Ex9_12.sce deleted file mode 100644 index 0af82950a..000000000 --- a/2465/CH9/EX9.12/Ex9_12.sce +++ /dev/null @@ -1,21 +0,0 @@ -//Chapter-9,Example 12,Page 222
-clc();
-close();
-
-wt_Ag = 0.1351 //weight of Ag deposited in a silver coulometer
-
-Ewt_Ag = 107.88 //atomic weight of Ag
-
-Ewt_Cu = 63.6 //atomic weight of Cu
-
-wt_Cu= wt_Ag*(Ewt_Cu/2)/Ewt_Ag //wt of Cu deposited
-
-loss=0.6350-0.6236 //loss in weight of Cu at anode
-
-t_Cu = loss/wt_Cu
-
-t_SO4= 1-t_Cu
-
-printf('the transport number of Cu+2 ion is %.3f ',t_Cu)
-
-printf('\n the transport number of SO4 ion is %.3f ',t_SO4)
diff --git a/2465/CH9/EX9.2/Ex9_2.sce b/2465/CH9/EX9.2/Ex9_2.sce deleted file mode 100644 index b2d50cde9..000000000 --- a/2465/CH9/EX9.2/Ex9_2.sce +++ /dev/null @@ -1,16 +0,0 @@ -//Chapter-9,Example 2,Page 219
-clc();
-close();
-
-R= 500 //resistance of the cell
-
-K= 0.0002765 //specific conductivity
-
-//cell constant= l/a and R= p(l/a)
-//sice l= length a= area p= resistivity
-//(1/p) = K = specific conductivity
-//(l/a) = R*K
-
-C_constant= R*K //cell constant
-
-printf('the cell constant is %.3f /cm',C_constant)
diff --git a/2465/CH9/EX9.3/Ex9_3.sce b/2465/CH9/EX9.3/Ex9_3.sce deleted file mode 100644 index 3e51aedc3..000000000 --- a/2465/CH9/EX9.3/Ex9_3.sce +++ /dev/null @@ -1,17 +0,0 @@ -//Chapter-9,Example 3,Page 220
-clc();
-close();
-
-R= 4364 //resistance of the cell
-
-K= 2.767*10^-3 //specific conductivity
-
-C_constant= R*K //cell constant
-
-
-//cell constant= l/a = R/p
-R1 = 3050 //new resistance
-
-p= R1/C_constant
-
-printf('the specific resistance is %.3f ohm.cm ',p)
diff --git a/2465/CH9/EX9.4/Ex9_4.sce b/2465/CH9/EX9.4/Ex9_4.sce deleted file mode 100644 index fbd6e46ab..000000000 --- a/2465/CH9/EX9.4/Ex9_4.sce +++ /dev/null @@ -1,25 +0,0 @@ -//Chapter-9,Example 4,Page 220
-clc();
-close();
-
-R= 550 //resistance of the cell
-
-K=0.002768 //specific conductivity
-
-C_constant= R*K
-
-p= 72.18 //observed resistance
-
-Kv = C_constant*(1/p)
-
-C= 0.2 //concentration
-
-lamda_v= Kv*1000/C //equivalent conductivity
-
-M= 0.1
-
-lamda_m= 1000*Kv/M //molar conductivity
-
-printf('the equivalent conductivity of ZnSO4 is %.2f /ohm.cm^2',lamda_v)
-
-printf('\n the molar conductivity of ZnSO4 is %.2f /ohm.cm^2',lamda_m)
diff --git a/2465/CH9/EX9.5/Ex9_5.sce b/2465/CH9/EX9.5/Ex9_5.sce deleted file mode 100644 index eb9776f64..000000000 --- a/2465/CH9/EX9.5/Ex9_5.sce +++ /dev/null @@ -1,17 +0,0 @@ -//Chapter-9,Example 5,Page 220
-clc();
-close();
-
-R= 32 //resistance of solution
-
-l= 1.8 //distance between electrodes
-
-a= 5.4 //area
-
-Kv=l/(R*a) //specific conductivity
-
-C= 0.1 //concentration
-
-lamda_v= Kv*1000/C //equivalent conductivity
-
-printf('the equivalent conductivity is %.3f /ohm.cm^2',lamda_v)
diff --git a/2465/CH9/EX9.6/Ex9_6.sce b/2465/CH9/EX9.6/Ex9_6.sce deleted file mode 100644 index 6cec6eaf8..000000000 --- a/2465/CH9/EX9.6/Ex9_6.sce +++ /dev/null @@ -1,11 +0,0 @@ -//Chapter-9,Example 6,Page 221
-clc();
-close();
-
-lamda_v= 48.15 //equivalent conductivity
-
-lamda_v1= 390.6 //equivalent conductivity at infinity
-
-alpha= lamda_v/lamda_v1
-
-printf('the degree of dissolution of acetic acid is %.4f ',alpha)
diff --git a/2465/CH9/EX9.7/Ex9_7.sce b/2465/CH9/EX9.7/Ex9_7.sce deleted file mode 100644 index 88a5053e4..000000000 --- a/2465/CH9/EX9.7/Ex9_7.sce +++ /dev/null @@ -1,16 +0,0 @@ -//Chapter-9,Example 7,Page 221
-clc();
-close();
-
-lamda_HCl=426.1 //equivalent conductance of HCl
-
-lamda_AcONa=91 //equivalent conductance of AcONa
-
-lamda_NaCl=126.5 //equivalent conductance of NaCl
-
-// lamda_HCl + lamda_AcONa - lamda_NaCl= (lamda_H+lamda_Cl)+(lamda_Na+lamda_OAc)-(lamda_Na+lamda_Cl)
-// = lamda_H +lamda_OAc = lamda_AcOH
-
-lamda_AcOH = lamda_HCl + lamda_AcONa - lamda_NaCl
-
-printf('the equivalent conductance of AcOH = %.2f/ohm.cm^2',lamda_AcOH)
diff --git a/2465/CH9/EX9.8/Ex9_8.sce b/2465/CH9/EX9.8/Ex9_8.sce deleted file mode 100644 index 522db0bde..000000000 --- a/2465/CH9/EX9.8/Ex9_8.sce +++ /dev/null @@ -1,15 +0,0 @@ -//Chapter-9,Example 8,Page 221
-clc();
-close();
-
-lamda_H=0.0348 //equivalent conductance of H+ ion
-
-lamda_CH3COO=0.004 //equivalent conductance of CH3COO- ion
-
-lamda= lamda_H+lamda_CH3COO //equivalent conductance at infinity
-
-lamda_v= 0.018 //equvalent conductance
-
-alpha= lamda_v/lamda //degree of dissolution
-
-printf('the degree of dissolution is %.4f ',alpha)
diff --git a/2465/CH9/EX9.9/Ex9_9.sce b/2465/CH9/EX9.9/Ex9_9.sce deleted file mode 100644 index b0181a822..000000000 --- a/2465/CH9/EX9.9/Ex9_9.sce +++ /dev/null @@ -1,18 +0,0 @@ -//Chapter-9,Example 9,Page 221
-clc();
-close();
-
-strength =0.05 //strength of CH3COOH
-
-Ka=1.8*10^-5
-
-// CH3COOH <---> CH3COO- + H+
-//intially = 0.05 0 0
-//dissolution a
-//at equilibrium= 0.05(1-a) 0.05*a 0.05*a
-//Ka =(0.05*a*0.05*a)/(0.05(1-a))
-//Ka=0.05*a^2 a=negligible 1-a=1
-
-a=sqrt(Ka/strength)
-
-printf('the degree of dissolution is %.4f ',a)
diff --git a/3758/CH1/EX1.1/Ex1_1.sce b/3758/CH1/EX1.1/Ex1_1.sce deleted file mode 100644 index 198c78b7f..000000000 --- a/3758/CH1/EX1.1/Ex1_1.sce +++ /dev/null @@ -1,10 +0,0 @@ -w=4000; //weight of certain oil in kg
-v=5; //volume of given oil in cubic metre
-g=9.81; //acceleration due to gravity in m/s^2
-r=1000; //specific weight of water in kg/cubic metre
-s=w/v; //calculating specific weight of oil in kg/cubic metre
-printf('specific weight of oil is %f kg/cubic metre\n',s);
-m=s/g //mass density of oil;
-printf('mass density of oil is %f kg/cubic metre\n',m);
-p=s/r // specific gravity of oil
-printf('specific gravity of oil is %f',p);
diff --git a/3758/CH1/EX1.10/Ex1_10.sce b/3758/CH1/EX1.10/Ex1_10.sce deleted file mode 100644 index 9b94128ae..000000000 --- a/3758/CH1/EX1.10/Ex1_10.sce +++ /dev/null @@ -1,12 +0,0 @@ -clc;
-d1=0.3;//diameter of inner cylinder in meter
-d2=0.31; //diameter of outer cylinder in meter
-t=0.98; //torque in newton-meter
-w=2*3.14; //amgular veocity in radian/sec
-h=0.3; //height of both cylinder in meter
-v=((d1/2)*w); //calculating the tangential velocity in m/sec
-y=(d2-d1)/2; //calculating thickness of plate in meter
-s=t/((2*3.14*(d1/2)*h)*(d1/2)); //calculating shear resisitance in newton/m^2
-disp(s);
-u=(s*y)/v; //calculating viscosity of liquid
-printf('viscosity of liquid is %f newton-sec/m^2',u);
diff --git a/3758/CH1/EX1.13/Ex1_13.sce b/3758/CH1/EX1.13/Ex1_13.sce deleted file mode 100644 index 9f2b6fdd4..000000000 --- a/3758/CH1/EX1.13/Ex1_13.sce +++ /dev/null @@ -1,8 +0,0 @@ -clc;
-p1=75; //intial pressure in kg/cm^2
-p2=140; //final pressure in kg/cm^2
-dp=(p2-p1); //calculating change in pressure
-dv=-0.147; //percentage decrease in volume
-v=100; //original volume in percentage
-k=dp/(dv/v); //calulating bulk modulus of elasticity
-printf('bulk modulus of elasticity of liquid is %f kg/cm^2',k);
diff --git a/3758/CH1/EX1.14/Ex1_14.sce b/3758/CH1/EX1.14/Ex1_14.sce deleted file mode 100644 index 4633a5aeb..000000000 --- a/3758/CH1/EX1.14/Ex1_14.sce +++ /dev/null @@ -1,8 +0,0 @@ -v2=0.0112; //final volume in m^3
-v1=0.0113; //initial volume in m^3
-dv=v2-v1; // calculating change in volume
-p1=6.87*10^6; //initial pressure in N/m^2
-p2=13.73*10^6; //final pressure in N/m^2
-dp=p2-p1; //calculating change in pressure
-k=-dp/(dv/v1); //calculating bulk modulus of elasticity
-printf('bulk modulus of elasticity is %f N/m^2',k);
diff --git a/3758/CH1/EX1.15/Ex1_15.sce b/3758/CH1/EX1.15/Ex1_15.sce deleted file mode 100644 index 6b6cadc9a..000000000 --- a/3758/CH1/EX1.15/Ex1_15.sce +++ /dev/null @@ -1,10 +0,0 @@ -clc;
-dp=840 ;// pressure in kg/cm^2
-w=1025; // specific weight of water in kg/m^3
-k=24*10^3; // bulk modulus of elasticity in kg/cm^2
-v=dp/k; //v =dv/v calculating change in volume
-s=1/w; // calculating specific volume of water at surface of ocean in m^3/kg
-dv=v/w; // calculating change in specific volume between surface and depth in m^3/kg
-v1=s-dv; // calculating specific volume at depth
-w1=1/v1; // calculating specific weight of water at depth
-printf('specific weight of water at depth is %f kg/m^3',w1);
diff --git a/3758/CH1/EX1.16/Ex1_16.sce b/3758/CH1/EX1.16/Ex1_16.sce deleted file mode 100644 index 3d7429ffa..000000000 --- a/3758/CH1/EX1.16/Ex1_16.sce +++ /dev/null @@ -1,7 +0,0 @@ -clc;
-dp=0.0018*10^4; // difference in inside and outside surface of bubble in kg/mm^2
-T=0.0075*10^3; // surface tension of water in contact in kg/mm
-Temp=20; //temperature of air in degree
-r=(2*T)/dp // calculating radius of droplet of water
-d=2*r; // calculating diameter of droplet of water
-printf('diameter of droplet of water is %f mm',d);
diff --git a/3758/CH1/EX1.17/Ex1_17.sce b/3758/CH1/EX1.17/Ex1_17.sce deleted file mode 100644 index ba760736e..000000000 --- a/3758/CH1/EX1.17/Ex1_17.sce +++ /dev/null @@ -1,8 +0,0 @@ -clc;
-d=0.05*10^-1; // diameter of droplet of water in cm
-Pout=1.03; // pressure outside the droplet in kg/cm^2
-T=0.0075*10^-2; // surface tension in kg/cm
-r=d/2 // radius of droplet in cm
-Pin=(2*T)/r; //calcuating pressure inside droplet in kg/cm^2
-P=Pin+Pout; // pressure intensity within the droplet of water
-printf('pressure intensity within the droplet of water is %f kg/cm^2',P);
diff --git a/3758/CH1/EX1.18/Ex1_18.sce b/3758/CH1/EX1.18/Ex1_18.sce deleted file mode 100644 index d87620729..000000000 --- a/3758/CH1/EX1.18/Ex1_18.sce +++ /dev/null @@ -1,17 +0,0 @@ -clc;
-d=2; //diameter of glass tube in mm
-r=(d/2)*10^-1 // radius of glass tube in cm
-T=0.0075*10^-2; // surface tension of water in kg/cm
-T1=0.052*10^-2; // surface tension of mercury in kg/cm
-// calculating capillary rise for water
-w=1000*10^-6; // specific weight of water in kg/cm^3
-s=1; //specific gravity of water
-theta=0; // angle of contact between liquid and tube
-h=(2*T*cos(theta))/(s*w*r); // calculating height of capillary rise
-printf('height of capillary rise in water is %f cm\n',h);
-// calculating capillary rise for mercury
-s=13.6; //specific gravity of mercury
-theta=130; // angle of contact between mercury and tube
-h=(2*T1*cos(theta*(3.14/180)))/(s*w*r); // calculating height of capillary rise
-printf('height of capillary rise in mercury is %f cm/n ',h);
-disp('negative sign indicates decrease in height of mercury');
diff --git a/3758/CH1/EX1.19/Ex1_19.sce b/3758/CH1/EX1.19/Ex1_19.sce deleted file mode 100644 index 376606640..000000000 --- a/3758/CH1/EX1.19/Ex1_19.sce +++ /dev/null @@ -1,8 +0,0 @@ -clc;
-h=0.25; //height of capillary rise in cm
-t=0.0075*10^-2; //surface tension in kg/cm
-s=1; //specific gravity of water
-w=1000*10^-6; //soecific weight of water in kg/cm^3
-r=(2*t)/(s*w*h); //calculating radius of glass tube
-d=2*r; //diameter of glass tube
-printf('diameter of glass tube is %f cm',d);
diff --git a/3758/CH1/EX1.2/Ex1_2.sce b/3758/CH1/EX1.2/Ex1_2.sce deleted file mode 100644 index 5d4ba74c3..000000000 --- a/3758/CH1/EX1.2/Ex1_2.sce +++ /dev/null @@ -1,10 +0,0 @@ -v=5; //volume of oil in cubic meter
-w=40; //weight of oil in kilo newton
-g=9.81; //acceleration due to gravity in meter per second square
-h=9810; //specific weight of water in newton per cubic meter
-s=(w*1000)/v; //specific weight of oil in newton per cubic meter
-printf('specific weight of oil is %f N/m^3\n',s);
-m=s/g; //mass density of oil in kilogram per cubic meter
-printf('mass density of oil is %f Kg/m^3\n',m);
-f=s/h; //specific gravity of oil
-printf('specific gravity of oil is %f ',f);
diff --git a/3758/CH1/EX1.20/Ex1_20.sce b/3758/CH1/EX1.20/Ex1_20.sce deleted file mode 100644 index 9296d6ee4..000000000 --- a/3758/CH1/EX1.20/Ex1_20.sce +++ /dev/null @@ -1,10 +0,0 @@ -clc;
-s=0.85; //specific gravity of oil
-d=1.5*10^-3; //diameter of glass tube in meter
-r=d/2; //calculating radius of glass tube in meter
-h=1.25*10^-2; //height of capillary in meter
-p=15; //bubble pressure in kg/m^2
-w=1000; //specific weight of water in kg/m^3
-p1=p-(s*w*h); //effective pressure attributable to surface tensions
-t=(p1*r)/2; //calculating unit surface energy or surface tension in kg/m
-printf('unit surface energy is %f kg/m',t);
diff --git a/3758/CH1/EX1.21/Ex1_21.sce b/3758/CH1/EX1.21/Ex1_21.sce deleted file mode 100644 index 59bf2fb42..000000000 --- a/3758/CH1/EX1.21/Ex1_21.sce +++ /dev/null @@ -1,18 +0,0 @@ -clc;
-d=3*10^-3; //diameter of glass tube in meter
-r=d/2; //calculating radius of glass tube in meter
-//capillary rise for water
-theta=0; //angle of contact between liquid and galss tube in degree
-t=0.0736; //surface tension of water in N/m
-w=9810; //specific weight of water in N/m^3
-s=1; //specific gravity of water
-h=(2*t*cos(theta*(3.14/180))*10^3)/(s*w*r); //calculating capillary rise
-printf('capillary rise for water is %f milimeter\n',h);
-//capillary rise for mercury
-theta=130;//angle of contact between liquid and galss tube in degree
-t=0.51; //surface tension of water in N/m
-w=9810; //specific weight of water in N/m^3
-s=13.6; //specific gravity of mercury
-h=(2*t*cos(theta*3.14/180)*10^3)/(s*w*r); //calculating capillary rise
-printf('capillary rise for mercury is %f milimeter\n',h);
-printf('negative sign indicate capillary depression');
diff --git a/3758/CH1/EX1.4/Ex1_4.sce b/3758/CH1/EX1.4/Ex1_4.sce deleted file mode 100644 index 169220e40..000000000 --- a/3758/CH1/EX1.4/Ex1_4.sce +++ /dev/null @@ -1,6 +0,0 @@ -f=0.2; // shear stress in kg/m^2
-v=0.61; // velocity in m/sec
-y=0.0000254; // distance between two plate in m
-u=(f*y)/v; //calculating dynamic viscosity
-printf('Dymanic viscosity of fluid between plates is %f kg sec/m^2',u);
-
diff --git a/3758/CH1/EX1.5/Ex1_5.sce b/3758/CH1/EX1.5/Ex1_5.sce deleted file mode 100644 index 5cb7c9779..000000000 --- a/3758/CH1/EX1.5/Ex1_5.sce +++ /dev/null @@ -1,6 +0,0 @@ -t=0.216; // shear stress in N/m^2
-v=0.216; // velocity gradient in sec^-1
-m=959.42; // mass density of castor oil in kg/m^3
-u=t/v; //determining dynamic viscosity of castor oil in N sec/m^2
-k=u/m; // calculating kinematic viscosity
-printf('kinematic viscosity of castor oil is %f m^2/sec',k);
diff --git a/3758/CH1/EX1.6/Ex1_6.sce b/3758/CH1/EX1.6/Ex1_6.sce deleted file mode 100644 index bba6962c6..000000000 --- a/3758/CH1/EX1.6/Ex1_6.sce +++ /dev/null @@ -1,8 +0,0 @@ -clc;
-u=4.9*10^-4; //dynamic viscosity in kg sec/m^2
-k=3.49*10^-2; //kinematic viscosity in stokes
-k=3.49*10^-6; //converting kinematic viscosity in stokes to m^2/sec
-w=102; // mass density of water in kg/m^3
-m=u/k; //calculating mass density in kg/m^3
-s=m/w; // calculating specific gravity of liquid
-printf(' specific gravity of liquid is %f',s);
diff --git a/3758/CH1/EX1.7/Ex1_7.sce b/3758/CH1/EX1.7/Ex1_7.sce deleted file mode 100644 index 2bfd420ce..000000000 --- a/3758/CH1/EX1.7/Ex1_7.sce +++ /dev/null @@ -1,12 +0,0 @@ -clc;
-s=2; //specific gravity of liquid
-m=102; // mass density of water in msl/m^3
-m1=1000; // mass density of water in kg/m^3
-w=2*m; // mass density of liquid in msl/m^3
-w1=2*m1; // mass density of liquid in kg/m^3
-k=5.58; // kinematic viscosity in stokes
-k1=5.58*10^-4; //kinematic viscosity in m^2/sec
-u=k1*w; // dynamic viscosity of liquid
-printf('dynamic viscosity in matric gravitational unit is %f kg sec/m^2\n',u);
-u=k1*w1; // dynamic viscosity of liquid
-printf('dynamic viscosity in S.I unit is %f N sec/m^2',u')
diff --git a/3758/CH1/EX1.8/Ex1_8.sce b/3758/CH1/EX1.8/Ex1_8.sce deleted file mode 100644 index ac514bcc7..000000000 --- a/3758/CH1/EX1.8/Ex1_8.sce +++ /dev/null @@ -1,10 +0,0 @@ -clc;
-l=25; //length of plate in centimeter
-b=5; //bredth of plate in centimeter
-a=(l*b)*10^-4; //calculating area of plate in m^2
-v=2; //velocity with which plate slides in meter/sec
-theta=30; //angle of plate with surface in degree
-y=0.002 //gap between plate and inclined surface
-r=l*sin(theta*(3.14/180));//viscous resistance in kg
-u=(r*y)/(v*a); //calculating viscosity of oil
-printf('viscosity of oil is %f kg-sec/m^2',u);
diff --git a/3758/CH1/EX1.9/Ex1_9.sce b/3758/CH1/EX1.9/Ex1_9.sce deleted file mode 100644 index e8ff2ac4f..000000000 --- a/3758/CH1/EX1.9/Ex1_9.sce +++ /dev/null @@ -1,11 +0,0 @@ -clc;
-l=20; //length of edge of cubical block in centimeter
-theta=20; //inclination of plane with horizontal in degree
-w=20; //weight of cubical block in kg
-y=0.025*10^-3; //thickness of film im meter
-u=0.22*10^-3; //viscosity of oil in kg-sec/m^2
-f=w*sin(theta*(3.14/180)); //calculating force causing downward motion of block
-a=(l^2)*10^-4; //calculating area of one face of cube
-t=f/a; //calculating shear resistance
-v=(t*y)/u; //calculating terminal velocity
-printf('terminal velocity is %f meter/se',v);
diff --git a/3769/CH2/EX2.11/Ex2_11.sce b/3769/CH2/EX2.11/Ex2_11.sce index 74d866b15..f86a80875 100644 --- a/3769/CH2/EX2.11/Ex2_11.sce +++ b/3769/CH2/EX2.11/Ex2_11.sce @@ -1,3 +1,4 @@ + clear //Given q=16*10**-19 @@ -9,5 +10,5 @@ p=q*a U=-p*E //Result -printf("\n (i) The electric dipole moment %0.3f Cm", p) -printf("\n (ii) Potential energy of dipole in the stable equilibrium position %0.3f J",U) +printf("\n (i) The electric dipole moment %e Cm", p) +printf("\n (ii) Potential energy of dipole in the stable equilibrium position %e J",U) diff --git a/3769/CH2/EX2.14/Ex2_14.sce b/3769/CH2/EX2.14/Ex2_14.sce index fe6433581..71feff981 100644 --- a/3769/CH2/EX2.14/Ex2_14.sce +++ b/3769/CH2/EX2.14/Ex2_14.sce @@ -1,12 +1,13 @@ + clear //Given -q=1*10**-6 -a=2*10**-2 -E=10**5 +q=1*10**-6// charges C +a=2*10**-2// seperation distance m +E=10**5 // electric field N //Calculation -p=q*a -W=2*p*E +p=q*a // finding potential +W=2*p*E// total work done //Result printf("\n Work done in the rotation is %0.3f *10**-3 J", W*10**3) diff --git a/3769/CH2/EX2.15/Ex2_15.sce b/3769/CH2/EX2.15/Ex2_15.sce index bc9ff475a..74800b7b6 100644 --- a/3769/CH2/EX2.15/Ex2_15.sce +++ b/3769/CH2/EX2.15/Ex2_15.sce @@ -1,13 +1,14 @@ + clear //Given -q=2*10**-6 -a=0.1 -m=9*10**9 -r=0.5 +q=2*10**-6// charge C +a=0.1// dipole length m +m=9*10**9// constant +r=0.5// distance m //Calculation -p=q*a -E=m*p/r**3 +p=q*a // finding potential +E=m*p/r**3// electric field intensity //Result printf("\n Electric field intensity is %0.3f *10**4 N/C",E*10**-4) diff --git a/3769/CH2/EX2.17/Ex2_17.sce b/3769/CH2/EX2.17/Ex2_17.sce index c98cea389..9a994c787 100644 --- a/3769/CH2/EX2.17/Ex2_17.sce +++ b/3769/CH2/EX2.17/Ex2_17.sce @@ -1,14 +1,15 @@ + clear //Given -p=2*10**-8 -m=9*10**9 -r=1.0 +p=2*10**-8// dipole moment coulomb-meter +m=9*10**9// constant +r=1.0// distance m //Calculation // b=3*cos(60*3.14/180.0)**2+1 a=p*sqrt(b) -E=(m*a)/r**3 +E=(m*a)/r**3// electric field intensity //Result printf("\n Magnitude of electric intensity is %0.1f N/C",E) diff --git a/3769/CH2/EX2.9/Ex2_9.sce b/3769/CH2/EX2.9/Ex2_9.sce index 447332530..a8c450dc0 100644 --- a/3769/CH2/EX2.9/Ex2_9.sce +++ b/3769/CH2/EX2.9/Ex2_9.sce @@ -1,3 +1,4 @@ + clear //Given m=9*10**9 @@ -9,4 +10,4 @@ F=58.8*10**-3 q2=F*r**2/(q1*m) //Result -printf("\n Charge is %0.3f C", q2) +printf("\n Charge is %e C", q2) diff --git a/3769/CH3/EX3.13/Ex3_13.sce b/3769/CH3/EX3.13/Ex3_13.sce index 69fce57d1..6ddd0e682 100644 --- a/3769/CH3/EX3.13/Ex3_13.sce +++ b/3769/CH3/EX3.13/Ex3_13.sce @@ -1,13 +1,14 @@ + clear //Given -m=9*10**-9 -q1=3*10**-9 -q2=3*10**-9 -q3=10**9 -r=0.2 +m=9*10**-9// constant +q1=3*10**-9// charge q1 +q2=3*10**-9// charge q2 +q3=10**9// charge q3 +r=0.2// side length of triangle //Calculation -W=m*((q1*q3/r)+(q2*q3/r)) +W=m*((q1*q3/r)+(q2*q3/r))// work done //Result -printf("\n Workdone is %0.3f J", W) +printf("\n Workdone is %e J", W) diff --git a/3769/CH3/EX3.14/Ex3_14.sce b/3769/CH3/EX3.14/Ex3_14.sce index 2e6b8247d..a17fcfde3 100644 --- a/3769/CH3/EX3.14/Ex3_14.sce +++ b/3769/CH3/EX3.14/Ex3_14.sce @@ -1,12 +1,13 @@ + clear //Given -m=9*10**9 -q=1.6*10**-19 -r=10**-10 +m=9*10**9// constant +q=1.6*10**-19// charge C +r=10**-10// distance m //Calculation -U=m*q**2/r -K=U/2.0 +U=m*q**2/r// potential energy +K=U/2.0// Kinetic energy //Result -printf("\n Kinetic energy is %0.3f J",K) +printf("\n Kinetic energy is %e J",K) diff --git a/3769/CH3/EX3.15/Ex3_15.sce b/3769/CH3/EX3.15/Ex3_15.sce index 63b26419f..f0cd4f4be 100644 --- a/3769/CH3/EX3.15/Ex3_15.sce +++ b/3769/CH3/EX3.15/Ex3_15.sce @@ -1,13 +1,14 @@ + clear //Given -m=9*10**-31 -V=10**6 -q=1.6*10**-19 -a=9*10**9 +m=9*10**-31// mass of e kg +V=10**6// velocity of e m/s +q=1.6*10**-19// charge of e C +a=9*10**9// constant //Calculation -K=m*V**2 -r=a*q**2/K +K=m*V**2// kinetic energy +r=a*q**2/K // Distance of the closest approach //Result -printf("\n Distance of the closest approach is %0.3f m", r) +printf("\n Distance of the closest approach is %e m", r) diff --git a/3769/CH3/EX3.17/Ex3_17.sce b/3769/CH3/EX3.17/Ex3_17.sce index a0b5da2e5..71d441cfc 100644 --- a/3769/CH3/EX3.17/Ex3_17.sce +++ b/3769/CH3/EX3.17/Ex3_17.sce @@ -1,17 +1,18 @@ + clear //Given r=0.53*10**-10 //m q1=1.6*10**-19 //C q2=-1.6*10**-19 //C -a=9*10**9 -r1=1.06*10**-10 +a=9*10**9 //constant +r1=1.06*10**-10 // seperation of electron //Calculation U=a*q1*q2/r -Ue=U/q1 -K=-Ue/2.0 -E=Ue+K -U1=(a*q1*q2/r1)/q1 +Ue=U/q1 //Potential energy of the system eV +K=-Ue/2.0 //eV +E=Ue+K //eV +U1=(a*q1*q2/r1)/q1// eV //Result printf("\n (i) Potential energy of the system is %0.1f eV",Ue) diff --git a/3769/CH4/EX4.24/Ex4_24.sce b/3769/CH4/EX4.24/Ex4_24.sce index b879f39ee..a387f0f39 100644 --- a/3769/CH4/EX4.24/Ex4_24.sce +++ b/3769/CH4/EX4.24/Ex4_24.sce @@ -1,3 +1,4 @@ + clear //Given K=5 @@ -13,4 +14,4 @@ C=(K*l*c)/(41.1*log10(b/a)) //Result printf("\n (i) The capacitance of cylindrical capacitor is %0.1f *10**-9 F",C*10**9) -printf("\n (ii) The potential of the inner cylinder is equal to p.d. between two cylinders i.e potentila of inner cylinder is %0.3f V",pd) +printf("\n (ii) The potential of the inner cylinder is equal to p.d. between two cylinders i.e potential of inner cylinder is %0.3f V",pd) diff --git a/3769/CH4/EX4.35/Ex4_35.sce b/3769/CH4/EX4.35/Ex4_35.sce index d3bf46369..3628db3da 100644 --- a/3769/CH4/EX4.35/Ex4_35.sce +++ b/3769/CH4/EX4.35/Ex4_35.sce @@ -1,3 +1,4 @@ + clear //Given d=5 @@ -8,4 +9,4 @@ K=3.0 D=d+(t-t/K) //Result -printf("\n New seperaion between the plates are %0.2f mm",D) +printf("\n New separation between the plates are %0.2f mm",D) diff --git a/3776/CH1/EX1.1/Ex1_1.sce b/3776/CH1/EX1.1/Ex1_1.sce index f0d2002bc..ea165c7b0 100644 --- a/3776/CH1/EX1.1/Ex1_1.sce +++ b/3776/CH1/EX1.1/Ex1_1.sce @@ -11,7 +11,7 @@ BC = 1.0 //m CF = 2.5 //m contact_area = 200*200 // sq.mm , The contact area at c -//caliculations +//calculations //Balancing forces in the x direction: // Balncing the moments about C and B: Fx = 0 diff --git a/3776/CH1/EX1.2/Ex1_2.sce b/3776/CH1/EX1.2/Ex1_2.sce index 90d76b556..04492aa43 100644 --- a/3776/CH1/EX1.2/Ex1_2.sce +++ b/3776/CH1/EX1.2/Ex1_2.sce @@ -1,24 +1,24 @@ clear -//Given +//Given load_distributed = 20 //kN/sq.m, This is the load distributed over the pier -H = 2 // m, Total height -h = 1 //m , point of investigation -base = 1.5 //m The length of crossection in side veiw +H = 2 // m, Total height +h = 1 //m , point of investigation +base = 1.5 //m The length of crossection in side view top = 0.5 //m ,The length where load is distributed on top -base_inv = 1 //m , the length at the point of investigation -area = 0.5*1 //m ,The length at a-a crossection +base_inv = 1 //m , the length at the point of investigation +area = 0.5*1 //m ,The length at a-a cross-section density_conc = 25 //kN/sq.m -//caliculation of total weight +//calculation of total weight -v_total = ((top+base)/2)*top*H //sq.m ,The total volume +v_total = ((top+base)/2)*top*H //sq.m ,The total volume w_total = v_total* density_conc //kN , The total weight -R_top = (top**2)*load_distributed //kN , THe reaction force due to load distribution +R_top = (top**2)*load_distributed //kN , THe reaction force due to load distribution reaction_net = w_total + R_top -//caliculation of State of stress at 1m +//calculation of State of stress at 1m v_inv = ((top+base_inv)/2)*top*h //sq.m ,The total volume from 1m to top w_inv = v_inv*density_conc //kN , The total weight from 1m to top reaction_net = w_inv + R_top //kN Stress = reaction_net/area //kN/sq.m printf("\n The total weight of pier is %0.3f kN",w_total) -printf("\n The stress at 1 m above is %0.1f kN/m**2",Stress) +printf("\n The stress at 1 m above is %0.1f kN/sq.m",Stress) diff --git a/3776/CH1/EX1.3/Ex1_3.sce b/3776/CH1/EX1.3/Ex1_3.sce index 05d597de5..60497acef 100644 --- a/3776/CH1/EX1.3/Ex1_3.sce +++ b/3776/CH1/EX1.3/Ex1_3.sce @@ -4,15 +4,15 @@ clear d_pins = 0.375 //inch load1 = 3 //kips AB_x = 6 //inch,X-component -AB_y = 3 //inch,Y-component +AB_y = 3 //inch,Y-component BC_y = 6 //inch,Y-component BC_x = 6 //inch,X-component -area_AB = 0.25*0.5 //inch*2 -area_net = 0.20*2*(0.875-0.375) //inch*2 -area_BC = 0.875*0.25 //inch*2 -area_pin = d_pins*2*0.20 //inch*2 +area_AB = 0.25*0.5 //inch*2 +area_net = 0.20*2*(0.875-0.375) //inch*2 +area_BC = 0.875*0.25 //inch*2 +area_pin = d_pins*2*0.20 //inch*2 area_pin_crossection = 2*3.14*((d_pins/2)**2) -//caliculations +//calculations slope = AB_y/ AB_x //For AB slope = BC_y/ BC_x //For BC @@ -27,18 +27,18 @@ F_C_x = -(load1*BC_x)/(BC_y + AB_y ) //kips, F_C_x X-component of F_c F_A= ((5**0.5)/2)*F_A_x //kips F_A_y = 0.5*F_A_x //kips -//X,Y components of F_C +//X,Y components of F_C F_C= (2**0.5)*F_C_x //kips F_C_y = F_C_x //kips T_stress_AB = F_A/area_AB //ksi , Tensile stress in main bar AB stress_clevis = F_A/area_net //ksi ,Tensile stress in clevis of main bar AB -c_strees_BC = F_C/area_BC //ksi , Comprensive stress in main bar BC +c_stress_BC = F_C/area_BC //ksi , Compressive stress in main bar BC B_stress_pin = F_C/area_pin //ksi , Bearing stress in pin at C To_stress_pin = F_C/area_pin_crossection //ksi , torsion stress in pin at C printf("\n Tensile stress in main bar AB: %0.1f ksi",T_stress_AB) printf("\n Tensile stress in clevis of main bar AB: %0.1f ksi",stress_clevis) -printf("\n Comprensive stress in main bar BC: %0.1f ksi",-c_strees_BC) +printf("\n Compressive stress in main bar BC: %0.1f ksi",-c_stress_BC) printf("\n Bearing stress in pin at C: %0.2f ksi",-B_stress_pin) printf("\n torsion stress in pin at C: %0.2f ksi",-To_stress_pin) diff --git a/3776/CH1/EX1.6/Ex1_6.sce b/3776/CH1/EX1.6/Ex1_6.sce index ba7d7e038..11a4a83f1 100644 --- a/3776/CH1/EX1.6/Ex1_6.sce +++ b/3776/CH1/EX1.6/Ex1_6.sce @@ -5,10 +5,10 @@ frequency = 10 //Hz stress_allow = 200 //MPa R = 0.5 //m -//caliculations +//calculations // w = 2*%pi*frequency //rad/sec a = (w**2)*R //sq.m/sec F = mass*a //N -A_req = F/stress_allow //sq.m , The required area for aloowing stress -printf("\n The required size of rod is: %0.2f sq.m",A_req) +A_req = F/stress_allow //sq.mm , The required area for allowing stress +printf("\n The required size of rod is: %0.2f sq.mm",A_req) diff --git a/3776/CH1/EX1.7/Ex1_7.sce b/3776/CH1/EX1.7/Ex1_7.sce index a9cde7839..b4256e15b 100644 --- a/3776/CH1/EX1.7/Ex1_7.sce +++ b/3776/CH1/EX1.7/Ex1_7.sce @@ -6,21 +6,69 @@ L_n_2 = 15 //kips ,live load 2 stress_allow = 22 //ksi phi = 0.9 //probalistic coefficients y_stress = 36 //ksi,Yeild strength -//According to AISR +//According to AISR //a p_1 = D_n + L_n_1 //kips since the total load is sum of dead load and live load p_2 = D_n + L_n_2 //kips, For second live load -Area_1 = p_1/stress_allow //in*2 ,the allowable area for the allowed stress -Area_2 = p_2/stress_allow //in*2 -printf("\n the allowable area for live load %0.3f is %0.3f in*2",L_n_1,Area_1) -printf("\n the allowable area for live load %0.3f is %0.3f in*2",L_n_2,Area_2) +Area_1 = p_1/stress_allow //sq.in ,the allowable area for the allowed stress +Area_2 = p_2/stress_allow //sq.in +printf("\n the allowable area for live load %0.3f is %0.3f sq.in",L_n_1,Area_1) +printf("\n the allowable area for live load %0.3f is %0.3f sq.in",L_n_2,Area_2) //b //area_crossection= (1.2*D_n +1.6L_n)/(phi*y_stress) -area_crossection_1= (1.2*D_n +1.6*L_n_1)/(phi*y_stress) //in*2,crossection area for first live load -area_crossection_2= (1.2*D_n +1.6*L_n_2)/(phi*y_stress) //in*2,crossection area for second live load -printf("\n the crossection area for live load %0.3f is %0.3f in*2",L_n_1,area_crossection_1) -printf("\n the crossection area for live load %0.3f is %0.3f in*2",L_n_2,area_crossection_2) +area_crossection_1= (1.2*D_n +1.6*L_n_1)/(phi*y_stress) //sq.in,crossection area for first live load +area_crossection_2= (1.2*D_n +1.6*L_n_2)/(phi*y_stress) //sq.in,crossection area for second live load +printf("\n the crossection area for live load %0.3f is %0.3f sq.in",L_n_1,area_crossection_1) +printf("\n the crossection area for live load %0.3f is %0.3f sq.in",L_n_2,area_crossection_2) + +//c + +//calculating safety indices for a) + +mu_r1=1.05*Area_1*y_stress//kips +del_R=0.11 +mu_q1 = 6//kips +del_q1 = 0.093 + +mu_r2=1.05*Area_2 *y_stress//kips +mu_q2 = 20//kips +del_q2 = 0.189 + +beta_1 = log(mu_r1/mu_q1)/(del_R**2+del_q1**2)**0.5 +beta_2 = log(mu_r2/mu_q2)/(del_R**2+del_q2**2)**0.5 + + + +printf("\n Safety index for a) beta1 is %0.3f ",beta_1) +printf("\n Safety index for a) beta2 is %0.3f ",beta_2) + + + + + + + + +//calculating safety indices for b) + +mu_r1=1.05*area_crossection_1*y_stress//kips +del_R=0.11 +mu_q1 = 6//kips +del_q1 = 0.093 + +mu_r2=1.05*area_crossection_2*y_stress//kips +mu_q2 = 20//kips +del_q2 = 0.189 + +beta_1 = log(mu_r1/mu_q1)/(del_R**2+del_q1**2)**0.5 +beta_2 = log(mu_r2/mu_q2)/(del_R**2+del_q2**2)**0.5 + +beta_1 = log(mu_r1/mu_q1)/(del_R**2+del_q1**2)**0.5 +beta_2 = log(mu_r2/mu_q2)/(del_R**2+del_q2**2)**0.5 + +printf("\n Safety index for b) beta1 is %0.3f ",beta_1) +printf("\n Safety index for b) beta2 is %0.3f ",beta_2) diff --git a/3776/CH1/EX1.8/Ex1_8.sce b/3776/CH1/EX1.8/Ex1_8.sce index e30f1631e..3673b9dd1 100644 --- a/3776/CH1/EX1.8/Ex1_8.sce +++ b/3776/CH1/EX1.8/Ex1_8.sce @@ -1,13 +1,13 @@ clear //Given -A_angle = 2 //in*2 +A_angle = 2 //sq.in stress_allow = 20 //ksi, The maximum alowable stress F = stress_allow*A_angle //K, The maximum force AD = 3 //in, from the figure DC = 1.06 //in, from the figure strength_AWS = 5.56 // kips/in,Allowable strength according to AWS -//caliculations +//calculations //momentum at point "d" is equal to 0 R_1 = (F*DC)/AD //k,Resultant force developed by the weld R_2 = (F*(AD-DC))/AD //k,Resultant force developed by the weld diff --git a/3776/CH10/EX10.1/Ex10_1.sce b/3776/CH10/EX10.1/Ex10_1.sce index dfc409a95..63307cca9 100644 --- a/3776/CH10/EX10.1/Ex10_1.sce +++ b/3776/CH10/EX10.1/Ex10_1.sce @@ -1,10 +1,11 @@ clear -//Given +//Given dia = 400 //mm - The diameter of a pulley -E = 2001 //Gpa - Youngs modulus +E = 200 //GPa - Youngs modulus t = 0.6 //mm - The thickness of band -c = t/2 //mm - The maximum stress is seen -//Caliculations +c = t/2 //mm - The maximum stress is seen +//calculations stress_max = E*c*(10**3)/(dia/2) //MPa - The maximum stress on the crossection occurs at the ends printf("\n The maximum bending stress developed in the saw %0.3f MPa",stress_max) +// answer varies from the book diff --git a/3776/CH10/EX10.10/Ex10_10.sce b/3776/CH10/EX10.10/Ex10_10.sce index b9e6eac7c..403def9d1 100644 --- a/3776/CH10/EX10.10/Ex10_10.sce +++ b/3776/CH10/EX10.10/Ex10_10.sce @@ -1,8 +1,8 @@ clear -k = 24.0*(10**12) //N.mm2 Flexure rigidity -E = 200.0 //Gpa - Youngs modulus of the string +k = 24.0*(10**12) //N.sq.mm Flexure rigidity +E = 200.0 //GPa - Youngs modulus of the string l = 5000.0 //mm - The length of the string -C_A = 300.0 //mm2 - crossection area +C_A = 300.0 //sq.mm - crossection area P = 50.0 //KN - The force applies at the end a = 2000.0 //mm - The distance C-F x = 1//X - let it be a variable X diff --git a/3776/CH10/EX10.11/Ex10_11.sce b/3776/CH10/EX10.11/Ex10_11.sce index a514a0eb8..7fd39419e 100644 --- a/3776/CH10/EX10.11/Ex10_11.sce +++ b/3776/CH10/EX10.11/Ex10_11.sce @@ -8,11 +8,11 @@ I_Z = 315 //in^4 - the moment of inertia wrt Z axis I_y = 8.13 //in^4 - the moment of inertia wrt Y axis o = 5 // degrees - the angle of acting force P = 2000 //k the acting force -P_h = P*sin((%pi/180)*(o)) //k - The horizantal component of P +P_h = P*sin((%pi/180)*(o)) //k - The horizontal component of P P_v = P*cos((%pi/180)*(o)) //k - The vertical component of P -e_h = P_h*(L**3)/(3*E*I_y) // the horizantal component of deflection +e_h = P_h*(L**3)/(3*E*I_y) // the horizontal component of deflection e_v = P_v*(L**3)/(3*E*I_Z ) // the vertical component of deflection e = ((e_h**2 + e_v**2)**0.5) -printf("\n the horizantal component of deflection %0.3f in",e_h) +printf("\n the horizontal component of deflection %0.3f in",e_h) printf("\n the vertical component of deflection %0.3f in",e_v) printf("\n the resultant deflection %0.3f in",e) diff --git a/3776/CH10/EX10.13/Ex10_13.sce b/3776/CH10/EX10.13/Ex10_13.sce index e2688eb46..75bc3aa0d 100644 --- a/3776/CH10/EX10.13/Ex10_13.sce +++ b/3776/CH10/EX10.13/Ex10_13.sce @@ -6,7 +6,7 @@ m = 15.3 // mass of the falling body h = 75.0 //mm - The height of the falling body p = m*9.81 //N the force acted due to the body L = 1000.0 //mm The length of the cantilever -E = 200 //Gpa The youngs modulus of the material used +E = 200 //GPa The youngs modulus of the material used I = (l**4)/12 //mm - the moment of inertia k = 300 //N/mm -the stiffness of the spring //Rigid supports diff --git a/3776/CH10/EX10.15/Ex10_15.sce b/3776/CH10/EX10.15/Ex10_15.sce index 72f3ed920..62eb98e8c 100644 --- a/3776/CH10/EX10.15/Ex10_15.sce +++ b/3776/CH10/EX10.15/Ex10_15.sce @@ -1,17 +1,14 @@ clear //Given -E = 30*(10**3) //ksi - The youngs modulus of the material +E = 30*(10**3) //ksi - The youngs modulus of the material stress_y = 40 //ksi - yield stress -stress_max = 24.2 //ksi - the maximum stress -l = 2 //in - The length of the crossection +stress_max = 24.4 //ksi - the maximum stress +l = 2 //in - The length of the crossection b = 3 //in - the width of the crossection -h = 3 //in - the depth of the crossection -//lets check ultimate capacity for a 2 in deep section -M_ul = stress_y*b*(l**2)/4 //K-in the ultimate capacity -curvature = 2*stress_y/(E*(h/2) ) //in*-1 the curvature of the beam -curvature_max = stress_max/(E*(h/2)) //in*-1 The maximum curvature -printf("\n the ultimate capacity %0.3f k-in",M_ul) -printf("\n the ultimate curvature %0.3f in *-1",curvature_max) -printf("\n E given in equation is wrong") -printf("\n Actual E in question is 30*10**3") - +h = 2 //in - the depth of the crossection +//lets check ultimate capacity for a 2 in deep section +M_ul = stress_max*b*(l**2)/4 //K-in the ultimate capacity +curvature = 2*stress_y/(E*(h/2) ) //per inch the curvature of the beam +curvature_max = stress_max/(E*(b/2)) //per inch The maximum curvature +printf("\n the curvature in 11-in is %e per inch",curvature) +printf("\n the ultimate curvature %e per inch",curvature_max) diff --git a/3776/CH10/EX10.16/Ex10_16.sce b/3776/CH10/EX10.16/Ex10_16.sce index 7cce6d1d2..d1e701290 100644 --- a/3776/CH10/EX10.16/Ex10_16.sce +++ b/3776/CH10/EX10.16/Ex10_16.sce @@ -1,12 +1,12 @@ clear -//Given -l_ad = 1600 //mm - The total length of the beam +//Given +l_ad = 1600 //mm - The total length of the beam l_ab = 600 //mm - The length of AB l_bc = 600 //mm - The length of BC -e_1 = 0.24 //mm - deflection +e_1 = 0.24 //mm - deflection e_2 = 0.48 //mm - deflection -E = 35 //Gpa -//Caliculation +E = 35 //GPa +//calculation A_afe = -(l_ab+l_bc)*e_1*(10**-3)/(2*E) A_afe = -(l_ab)*e_2*(10**-3)/(4*E) @@ -15,4 +15,4 @@ x_1 = 1200 //com from B x_2 = 800 //com from B y_b = A_afe*x_1 + A_afe*x_2 //mm The maximum deflection at tip B printf("\n The maximum deflection at tip B %0.2f mm",y_b) -printf("\n The slope at the tip B %0.2f radians",y_1_b) +printf("\n The slope at the tip B %e radians",y_1_b) diff --git a/3776/CH11/EX11.11/Ex11_11.sce b/3776/CH11/EX11.11/Ex11_11.sce index 510361b42..ba17c5e84 100644 --- a/3776/CH11/EX11.11/Ex11_11.sce +++ b/3776/CH11/EX11.11/Ex11_11.sce @@ -1,59 +1,48 @@ clear // -P = 200.0 //K The force on the beam +P = 200.0 //K The force on the beam L = 15 //ft - The length of the rod -F_y = 50.0 //ksi +F_y = 50.0 //ksi F_a = F_y/(5.0/3) //ksi -AISC MANUAL ,allowable axial stress if axial force is alone F_b = F_a //Allowable compressive bending stress M_1 = 600.0 //k-in - The moment acting on the ends of the rod M_2 = 800.0 //k-in - the moment acting on the other end of teh rod -B_x = 0.264 //in - Extracted from AISC manual -E = 29*(10**3) -A = P/F_a + M_2*B_x/F_b //in2- The minimum area +B_x = 0.264 //in - Extracted from AISC manual +E = 29*(10**3) +A = P/F_a + M_2*B_x/F_b //sq.in- The minimum area printf("\n \n The minimum area is %0.2f in^2",A) -//we will select W10x49 section -A_s = 14.4 //in2 - The area of the section -r_min = 2.54 //in The minimum radius -r_x = 4.35 //in -f_a = P/A_s //Ksi- The computed axial stress -f_b = M_2*B_x/A_s //Computed bending stess -C_c = ((2*(%pi**2)*E/F_y)**0.5) //Slenderness ratio L/R -C_s = L*12/r_min // Slenderness ratio L/R of the present situation -if C_s <C_c then - printf("\n The following approch is solvable") -else - printf("\n The caliculation is not possible") - end -F_a_1 = 19.3 //Ksi - AISC lets try this -c_m = 0.6 - 0.4*(-M_1/M_2) -F_e = (12*(%pi**2)*E)/(23*(L*12/r_x)**2) -k = f_a/F_a_1 + c_m*f_b*(1-(f_a/F_e))/F_b //Condition mentioned in AISC -if k>1 then - printf("\n The following W10x49 section is not satisfying our constraints since f_a/F_a_1 + c_m*f_b*(1-(f_a/F_e))/F_b %0.3f >1",k) -else - printf("\n The following W10x49 section is satisfying our constraints since f_a/F_a_1 + c_m*f_b*(1-(f_a/F_e))/F_b %0.3f <1",k) - end -//trail - 2 -//Lets take W10 x 60 -A_s = 17.6 //in2 - The area of the section -r_min = 2.57 //in The minimum radius -r_x = 4.39 //in -f_a = P/A_s //Ksi- The computed axial stress -f_b = M_2*B_x/A_s //Computed bending stess -C_c = ((2*(%pi**2)*E/F_y)**0.5) //Slenderness ratio L/R -C_s = L*12/r_min // Slenderness ratio L/R of the present situation -if C_s <C_c then - printf("\n The following approch is solvable") -else - printf("\n The caliculation is not possible") - end -F_a_1 = 19.3 //Ksi - AISC lets try this -c_m = 0.6 - 0.4*(-M_1/M_2) -F_e = (12*(%pi**2)*E)/(23*(L*12/r_x)**2) -k = f_a/F_a_1 + c_m*f_b*(1-(f_a/F_e))/F_b //Condition mentioned in AISC -if k>1 then - printf("\n The following W10x49 section is not satisfying our constraints since f_a/F_a_1 + c_m*f_b*(1-(f_a/F_e))/F_b %0.3f >1",k) -else - printf("\n The following W10x49 section is satisfying our constraints since f_a/F_a_1 + c_m*f_b*(1-(f_a/F_e))/F_b %0.3f <1",k) - end -printf("\n small variation due to rounding off errors")
\ No newline at end of file + + + + +for i=1:2 + + st =['W10x49', 'W10x60'] + printf("\n we will select %s section",st(i)) + + A_s = [14.4, 17.6 ] //sq.in - The area of the section + r_min = [2.54 , 2.57 ] //in The minimum radius + r_x = [4.35 ,4.39] //in + f_a = P/A_s(i) //Ksi- The computed axial stress + f_b = M_2*B_x/A_s(i) //Computed bending stess + C_c = ((2*(%pi**2)*E/F_y)**0.5) //Slenderness ratio L/R + C_s = L*12/r_min(i) // Slenderness ratio L/R of the present situation + if C_s <C_c then + printf("\n Since calculated Le/r ratio is less than Cc, we can apply the second ASD formula") + else + printf("\n The calculation is not possible") + end + F_a_1 = 19.3 //Ksi - AISC lets try this + c_m = 0.6 - 0.4*(-M_1/M_2) + F_e = (12*(%pi**2)*E)/(23*(L*12/r_x(i))**2) + k = f_a/F_a_1 + c_m*f_b*(1-(f_a/F_e))/F_b //Condition mentioned in AISC + if k>1 then + printf("\n The following %s section is not satisfying our constraints since f_a/F_a_1 + c_m*f_b*(1-(f_a/F_e))/F_b %0.3f >1",st(i),k) + else + printf("\n The following %s section is satisfying our constraints since f_a/F_a_1 + c_m*f_b*(1-(f_a/F_e))/F_b %0.3f <1",st(i),k) + end + +end + + +printf("\n small variation due to rounding off errors") diff --git a/3776/CH11/EX11.2/Ex11_2.sce b/3776/CH11/EX11.2/Ex11_2.sce index a11f41c53..eb888504a 100644 --- a/3776/CH11/EX11.2/Ex11_2.sce +++ b/3776/CH11/EX11.2/Ex11_2.sce @@ -3,14 +3,14 @@ clear // h = 60 //mm - the length of the crossection b = 100 //mm - the width of hte crossection -E = 200 //Gpa - The youngs modulus +E = 200 //GPa - The youngs modulus stress_cr = 250 //MPa - The proportionality limit -//Caliculations +//calculations I = b*(h**3)/12 //mm3 The momentof inertia of the crossection -A = h*b //mm2 - The area of teh crossection -//From Eulier formula +A = h*b //sq.mm - The area of teh crossection +//From Euler formula r_min = ((I/A)**0.5) //mm - The radius of the gyration -//(l/r)**2= (%pi**2)*E/stress_cr //From Eulier formula +//(l/r)**2= (%pi**2)*E/stress_cr //From Euler formula l = (((%pi**2)*E*(10**3)/stress_cr)**0.5)*r_min //mm - the length after which the beam starts buckling printf("\n The length after which the beam starts buckling is %0.0f mm",l) diff --git a/3776/CH11/EX11.6/Ex11_6.sce b/3776/CH11/EX11.6/Ex11_6.sce index a095bf461..a2b8da993 100644 --- a/3776/CH11/EX11.6/Ex11_6.sce +++ b/3776/CH11/EX11.6/Ex11_6.sce @@ -2,36 +2,54 @@ clear //Given // L = 15 //ft - The length of the each rod -A = 46.7 //in2 - The length of the crossection +A = 46.7 //sq.in - The length of the crossection r_min = 4 //in - The radius of gyration stress_yp = 36 //ksi - the yielding point stress E = 29*(10**3) //ksi - The youngs modulus C_c = ((2*(%pi**2)*E/stress_yp)**0.5) //Slenderness ratio L/R -C_s = L*12/r_min // Slenderness ratio L/R of the present situation -//According to AISC formulas -if (C_s <C_c) then - printf ("a)The following approch is solvable") +C_s1 = L*12/r_min // Slenderness ratio L/R of the present situation +//According to AISC formulas +printf ("a)calculated Le/r ratio is %f",C_s1) +if (C_s1 <C_c) then + printf ("\n a)Since calculated Le/r ratio is less than Cc(126), we can apply the second ASD formula") else - print ("The caliculation is not possible") + print ("The calculation is not possible") end -F_S = 5.0/3 +3*C_s/(8*C_c) -(3*C_s**3)/(8*C_c**3) //Safety factor -Stress_all = (1 - (C_s**2)/(2*C_c**2))*stress_yp/F_S //The allowable strees +F_S = 5.0/3 +3*C_s1/(8*C_c) -(C_s1**3)/(8*C_c**3) //Safety factor +Stress_all = (1 - (C_s1**2)/(2*C_c**2))*stress_yp/F_S //The allowable stress printf("\n a) The allowable stress in this case is %0.2f kips",Stress_all) +printf("\n a) The allowable pressure in this case is %0.2f kips",Stress_all*A) + //Part - B //Given L = 40 //ft - The length of the each rod -A = 46.7 //in2 - The length of the crossection +A = 46.7 //sq.in - The length of the crossection r_min = 4 //in - The radius of gyration stress_yp = 36 //ksi - the yielding point stress E = 29*(10**3) //ksi - The youngs modulus C_c = ((2*(%pi**2)*E/stress_yp)**0.5) //Slenderness ratio L/R -C_s = L*12/r_min // Slenderness ratio L/R of the present situation -//According to AISC formulas +C_s = L*12/r_min // Slenderness ratio L/R of the present situation +//According to AISC formulas +printf ("\n b)calculated Le/r ratio is %f",C_s) if C_s <C_c then - printf("b) The following approch is solvable") + printf("\n b)Since calculated Le/r ratio is less than Cc, we can apply the second ASD formula") else - printf("The caliculation is not possible") + printf("The calculation is not possible") end -F_S = 5.0/3 +3*C_s/(8*C_c) -(3*C_s**3)/(8*C_c**3) //Safety factor -Stress_all = (1 - (C_s**2)/(2*C_c**2))*stress_yp/F_S //The allowable strees +F_S = 5.0/3 +3*C_s/(8*C_c) -(C_s**3)/(8*C_c**3) //Safety factor +Stress_all = (1 - (C_s**2)/(2*C_c**2))*stress_yp/F_S //The allowable stress printf("\n b) The allowable stress in this case is %0.2f kips",Stress_all) +printf("\n b) The allowable pressure in this case is %0.2f kips",Stress_all*A) +printf("\n Similarly, for a column fixed at one end") +C_s = L*12/r_min*.8 // Slenderness ratio L/R of the present situation +//According to AISC formulas +printf ("\n b)calculated Le/r ratio is %f",C_s) +if C_s <C_c then + printf("\n b)Since calculated Le/r ratio is less than Cc, we can apply the second ASD formula") +else + printf("The calculation is not possible") +end +F_S = 5.0/3 +3*C_s/(8*C_c) -(C_s**3)/(8*C_c**3) //Safety factor +Stress_all = (1 - (C_s**2)/(2*C_c**2))*stress_yp/F_S //The allowable stress +printf("\n b) The allowable stress in this case is %0.2f kips",Stress_all) +printf("\n b) The allowable pressure in this case is %0.0f kips",Stress_all*A) diff --git a/3776/CH11/EX11.7/Ex11_7.sce b/3776/CH11/EX11.7/Ex11_7.sce index a265e2104..f933f32cd 100644 --- a/3776/CH11/EX11.7/Ex11_7.sce +++ b/3776/CH11/EX11.7/Ex11_7.sce @@ -1,20 +1,23 @@ clear //Given // -L = 15 //ft - The length of the each rod -p = 200 //kips The concentric load applied +L = 15 //ft - The length of the each rod +p = 200 //kips The concentric load applied r_min = 2.10 //in - The radius of gyration stress_yp = 50 //ksi - the yielding point stress E = 29*(10**3) //ksi - The youngs modulus C_c = ((2*(%pi**2)*E/stress_yp)**0.5) //Slenderness ratio L/R C_s = L*12/r_min //Slenderness ratio L/R present situation +printf("\n C_s = %0.2f ",C_s) +printf("\n C_c = %0.2f ",C_c) + if C_s <C_c then - printf("a)The following approch is solvable") + printf ("\nSince calculated C_s is less than Cc, we can apply the second ASD formula.") else - printf("The caliculation is not possible") + printf("The calculation is not possible") end -F_S = 5.0/3 +3*C_s/(8*C_c) -(3*C_s**3)/(8*C_c**3) //Safety factor -Stress_all = (1 - (C_s**2)/(2*C_c**2))*stress_yp/F_S //The allowable strees -a = p/Stress_all //in2 the alloawble area of the beam -printf("\n The allowable stress in this case is %0.2f kips",Stress_all) -printf("\n This stress requires %0.2f in2",a) +F_S = 5.0/3 +3*C_s/(8*C_c) -(C_s**3)/(8*C_c**3) //Safety factor +Stress_all = (1 - (C_s**2)/(2*C_c**2))*stress_yp/F_S //The allowable stress +a = p/Stress_all //sq.in the allowable area of the beam +printf("\n The allowable stress in this case is %0.0f kips",Stress_all) +printf("\n This stress requires %0.2f sq.in",a) diff --git a/3776/CH11/EX11.8/Ex11_8.sce b/3776/CH11/EX11.8/Ex11_8.sce index 84736d445..64d8b2256 100644 --- a/3776/CH11/EX11.8/Ex11_8.sce +++ b/3776/CH11/EX11.8/Ex11_8.sce @@ -2,18 +2,19 @@ clear //Given // L = 15.0 //ft - The length of the each rod -A = 46.7 //in2 - The length of the crossection +A = 46.7 //sq.in - The length of the crossection r_min = 4 //in - The radius of gyration stress_yp = 36.0 //ksi - the yielding point stress E = 29*(10**3) //ksi - The youngs modulus lamda = L*12*((stress_yp/E)**0.5)/(4*(%pi)) //column slenderness ratio if lamda<1.5 then - printf("The following approach is right") + printf("Since lamda<1.5 we can apply the AISC LFRD formula") else printf("The following approach is wrong") end -stress_cr = (0.658**(lamda**2))*stress_yp //ksi - The critical stress -P_n = stress_cr*A //kips //Nominal compressive strength +stress_cr = (0.658**(lamda**2))*stress_yp //ksi - The critical stress +P_n = stress_cr*A //kips //Nominal compressive strength o = 0.85 //Resistance factor -p_u = o*P_n //kips ,column design compressive strength -printf("\n column design compressive strength %0.3f kips",p_u) +p_u = o*P_n //kips ,column design compressive strength +printf("\ncolumn design compressive strength %0.3f kips",p_u) +// small variation due to rounding off errors diff --git a/3776/CH11/EX11.9/Ex11_9.sce b/3776/CH11/EX11.9/Ex11_9.sce index 98dcadcc9..ecc7bb597 100644 --- a/3776/CH11/EX11.9/Ex11_9.sce +++ b/3776/CH11/EX11.9/Ex11_9.sce @@ -1,16 +1,16 @@ clear -//Given -//FOR FLANGS -l = 5 //in - The length of the flang -b = 5 //in - Teh width of the flang -t = 0.312 //in - the thickness of the flang +//Given +//FOR FLANGE +l = 5 //in - The length of the flange +b = 5 //in - Teh width of the flange +t = 0.312 //in - the thickness of the flange L = 20 //in - Length of the beam, Extracted from AISC manuals -A = 4.563 //in2 - The area of crossection of the beam -r = 1.188 //in - radius of the gyration, Extracted from AISC manuals -//b/t- value of the flang -k = (5 -t)/(2*t) //b/t ratio +A = 4.563 //sq.in - The area of crossection of the beam +r = 1.188 //in - radius of the gyration, Extracted from AISC manuals +//b/t- value of the flange +k = (5 -t)/(2*t) //b/t ratio //AISC, lets check maximum allowable stress for slang -Stressf_all = 23.1 - 0.79*k //ksi The maximum allowable stress in case of flang,AISC +Stressf_all = 23.1 - 0.79*k //ksi The maximum allowable stress in case of flange,AISC //web width thickness ratio k_2 = (5 -2*t)/(t) @@ -20,17 +20,16 @@ if k_2<16 then //a) Overall buckling investment k_31 = L/r //slenderness ratio Stressb_all = 20.2 - 0.126*k_31//ksi The maximum allowable stress in case of Buckling,AISC -p_allow = A*Stressf_all //kips The allowable concentric load +p_allow = A*Stressf_all //kips The allowable concentric load //b) Overall buckling investmen -L_2 = 60 //in +L_2 = 60 //in k_3 = L_2/r //slenderness ratio Stressb_all_2 = 20.2 - 0.126*k_3//ksi The maximum allowable stress in case of Buckling,AISC -p_allow_2 = A*Stressb_all_2 //kips The allowable concentric load +p_allow_2 = A*Stressb_all_2 //kips The allowable concentric load printf("\n The maximum allowable stress in case of web width %0.2f ksi",Stressw_all) -printf("\n The maximum allowable stress in case of flang %0.2f ksi",Stressf_all) +printf("\n The maximum allowable stress in case of flange %0.2f ksi",Stressf_all) printf("\n a) The maximum allowable load in case of Buckling %0.2f kips",p_allow) printf("\n b) The maximum allowable load in case of Buckling %0.2f kips",p_allow_2) -printf("\n small variation due to rounding off errors") - +// small variation due to rounding off errors diff --git a/3776/CH12/EX12.10/Ex12_10.sce b/3776/CH12/EX12.10/Ex12_10.sce index 68fe4e541..31260aee0 100644 --- a/3776/CH12/EX12.10/Ex12_10.sce +++ b/3776/CH12/EX12.10/Ex12_10.sce @@ -1,7 +1,7 @@ clear //Given -A_1 = 0.125 //in2 , The area of the crossection of AB -A_2 = 0.219 //in2 , The area of the crossection of BC +A_1 = 0.125 //sq.in , The area of the crossection of AB +A_2 = 0.219 //sq.in , The area of the crossection of BC l_1 = 3*(5**0.5) //in , The length of AB l_2 = 6*(2**0.5) //in , The length of BC p = 3 //k , Force acting on the system diff --git a/3776/CH12/EX12.3/Ex12_3.sce b/3776/CH12/EX12.3/Ex12_3.sce index f99a26393..889a51fee 100644 --- a/3776/CH12/EX12.3/Ex12_3.sce +++ b/3776/CH12/EX12.3/Ex12_3.sce @@ -11,7 +11,7 @@ l_ab = 2.5 //mt - The length of the rod l_bc = 2 //mt - The length of the rod A_ab = 5*(10**-4) //mt2 the areaof ab A_bc = 5*(10**-3) //mt2 the areaof bc -E = 70 //Gpa The youngs modulus of the material +E = 70 //GPa The youngs modulus of the material e_a =(p_ab*l_ab*F_ab/(A_ab*E) + p_bc*l_bc*F_bc/(A_bc*E))*(10**-6) //KN-m //Part -2 due to flexure I = 60*10**6 //mm4 - the moment of inertia diff --git a/3776/CH12/EX12.5/Ex12_5.sce b/3776/CH12/EX12.5/Ex12_5.sce index c7bb91a72..cd3e6dbc7 100644 --- a/3776/CH12/EX12.5/Ex12_5.sce +++ b/3776/CH12/EX12.5/Ex12_5.sce @@ -7,8 +7,8 @@ F_ab = 2500 //lb F_bc = -2500 //lb l_ab = 60 //in - The length of the rod l_bc = 60 //in - The length of the rod -A_ab = 0.15 //in2 the areaof ab -A_bc = 0.25 //in2 the areaof bc +A_ab = 0.15 //sq.in the areaof ab +A_bc = 0.25 //sq.in the areaof bc E = 30*(10**6) //psi The youngs modulus of the material //Part_a e_a =p_ab*l_ab*F_ab/(A_ab*E) + p_bc*l_bc*F_bc/(A_bc*E) //lb-in the deflection @@ -16,7 +16,7 @@ e_a =p_ab*l_ab*F_ab/(A_ab*E) + p_bc*l_bc*F_bc/(A_bc*E) //lb-in the deflection p_bd = 1 //lb The recorded virtual loading F_bd = 1 //lb l_bd = 40 //in - The length of the rod -A_bd = 0.1 //in2 the areaof ab +A_bd = 0.1 //sq.in the areaof ab e_a_1 =p_ab*p_ab*l_ab/(A_ab*E) + p_bc*p_bc*l_bc/(A_bc*E) +p_bd*p_bd*l_bd/(A_bd*E) //lb-in the deflection //Since the produced defelection should compensate the other one x_d = e_a/e_a_1 diff --git a/3776/CH2/EX2.11/Ex2_11.sce b/3776/CH2/EX2.11/Ex2_11.sce index c4e15f631..4f9a017ec 100644 --- a/3776/CH2/EX2.11/Ex2_11.sce +++ b/3776/CH2/EX2.11/Ex2_11.sce @@ -1,21 +1,26 @@ clear -mass = 4 //kg +mass = 4 //kg dist = 1 //mt freely falling distance l = 1500 //mm length of rod d = 15 //mm diameter l_ab = 6.71 //inch l_bc = 8.29 //inch -E = 200 //GPA youngs modulus +E = 200 //GPA youngs modulus k = 4.5 // N/mm stiffness costant F = mass*9.81// The force applying -Area = 3.14*(d**2)/4 -// Two cases -//youngs modulus +Area = 3.14*(d**2)/4 +// Two cases +//youngs modulus e_y = F*l/(Area*E*(10**3)) // stiffness -e_f = F/k +e_f = F/k //total e = e_y +e_f k = 1+(2/(e*(10**-3))) stress_max_1 = F*(1+(k**0.5))/Area printf("\n The maximum stress is: %0.3f MPa",stress_max_1) + +//for the rod without washer +k2 = 1+(2/(e_y*(10**-3))) +stress_max_2 = F*(1+(k2**0.5))/Area +printf("\n The maximum stress for the rod without washer is: %0.3f MPa",stress_max_2) diff --git a/3776/CH2/EX2.12/Ex2_12.sce b/3776/CH2/EX2.12/Ex2_12.sce index b4a566a08..fb8e4ffb6 100644 --- a/3776/CH2/EX2.12/Ex2_12.sce +++ b/3776/CH2/EX2.12/Ex2_12.sce @@ -1,9 +1,10 @@ clear -flex_a = 1//f -flex_b = 2//f +flex_a = 1 //f +flex_b = 2 //f //removing lower support and solving FBD e = -2 -(2+1)//fp //e_1 = (2+1+1)*R //e_1 = -e Making the elongations zero since the both ends are fixed -R = e/(2+1+1.0) //P +R = -e/(2+1+1.0) //P +//since sum of forces are 0 printf("\n The reactions at bottom is %0.3f P",R) diff --git a/3776/CH2/EX2.19/Ex2_19.sce b/3776/CH2/EX2.19/Ex2_19.sce index 2f56f7092..cf1308495 100644 --- a/3776/CH2/EX2.19/Ex2_19.sce +++ b/3776/CH2/EX2.19/Ex2_19.sce @@ -3,8 +3,8 @@ clear l = 30 //in - The length of the rod p_1 = 80 //kips - The Force on the end p_2 = 125 //kips - The force on the other end -A_s = 0.5 //in2 - The crossection of the steel rod -A_a = 0.5 //in2 - The crossection of the aluminium +A_s = 0.5 //sq.in - The crossection of the steel rod +A_a = 0.5 //sq.in - The crossection of the aluminium E_a = 10*(10**6) //psi - The youngs modulus of the aluminium E_s = 30*(10**6) //psi - The youngs modulus of the steel //Internally stastically indeterminant diff --git a/3776/CH2/EX2.2/Ex2_2.sce b/3776/CH2/EX2.2/Ex2_2.sce index 9e6317279..88d9c4ad6 100644 --- a/3776/CH2/EX2.2/Ex2_2.sce +++ b/3776/CH2/EX2.2/Ex2_2.sce @@ -5,9 +5,9 @@ l_cd = 1500 //mm - length of rod cd p_ob = 100 //kN - Force in rods p_bc = -150 //KN p_cd = 50 //KN -A_ob = 1000 //mm2 - Area of rod ob -A_bc = 2000 //mm2 - Area of rod bc -A_cd = 1000 //mm2 - Area of rod cd +A_ob = 1000 //sq.mm - Area of rod ob +A_bc = 2000 //sq.mm - Area of rod bc +A_cd = 1000 //sq.mm - Area of rod cd E = 200.0 //GPA // the total deflection is algebraic sums of `deflection in each module e_1 = p_ob*l_ob/(A_ob*E) diff --git a/3776/CH2/EX2.4/Ex2_4.sce b/3776/CH2/EX2.4/Ex2_4.sce index 76ea23bb6..2a8f3fa43 100644 --- a/3776/CH2/EX2.4/Ex2_4.sce +++ b/3776/CH2/EX2.4/Ex2_4.sce @@ -1,21 +1,23 @@ clear -p_app = 3 //kips - applied force -P_A = 2.23 //kips +p_app = 3 //kips - applied force +P_A = 2.23 //kips p_B = -2.83 //kips - compressive force l_ab = 6.71 //inch l_bc = 8.29 //inch s_ab = 17.8 //ksi - tensile stress s_bc = -12.9 //ksi - compressive stress -E = 10.6 * (10**3) //ksi -youngs modulus +E = 10.6 * (10**3) //ksi -youngs modulus e_ab = s_ab*l_ab/E //elongation e_bc = s_bc*l_bc/E //contraction -x = -e_bc/e_ab //the Ratio of cosines of the deflected angles -// t_1 and t_2 be deflected angles +x = -e_bc/e_ab //the Ratio of cosines of the deflected angles +// t_1 and t_2 be deflected angles //t_2 = 180-45-26.6-t_1 the sum of angles is 360 //applying cos on both sides t_1=atand(1.29) e = e_ab/cosd((t_1)) //inch -k = p_app/e // kips/in vertical stiffness of the combination +e_t = e*cosd(11.2) +k = p_app/e_t // kips/in vertical stiffness of the combination printf("\n The vertical stiffness of the combination is %0.3f kips/inch",k) //answer in textbook is 167 +// answer varies due to rounding off errors diff --git a/3776/CH2/EX2.6/Ex2_6.sce b/3776/CH2/EX2.6/Ex2_6.sce index 844997aec..a5dcb9d0f 100644 --- a/3776/CH2/EX2.6/Ex2_6.sce +++ b/3776/CH2/EX2.6/Ex2_6.sce @@ -1,15 +1,15 @@ clear -dia = 50 //mm - diameter of aluminium -p = 100 // KN - instant force applid -dia_c = 0.1215 //mm- change in diameter +dia = 50 //mm - diameter of aluminium +p = 100 // KN - instant force applied +dia_c = 0.01215 //mm- change in diameter l_c = 0.219 //mm - change in length -l = 300 //mm - length -strain_dia = dia_c/dia // lateral strain -strain_l = l_c/l //longitudinal strain -po = strain_dia/strain_l // poission ratio -area = 3.14*dia*dia/4 //mm2 area -E = p*l/(area*l_c) //N/mm2 youngs modulus -printf("\n The lateral strain is: %0.3f no units",strain_dia) -printf("\n The longitudinal strain is: %0.3f no units",strain_l) -printf("\n The poissions ratio is: %0.3f no units",po) -printf("\n Youngs modulus: %0.2f N/sq.mm",E) +l = 300 //mm - length +strain_dia = -dia_c/dia // lateral strain +strain_l = -l_c/l //longitudinal strain +po = strain_dia/strain_l // Poisson ratio +area = 3.14*dia*dia/4 //sq.mm area +E = p*l/(area*l_c) //N/sq.mm youngs modulus +printf("\n The lateral strain is: %e mm/mm",strain_dia) +printf("\n The longitudinal strain is: %e no units",strain_l) +printf("\n The Poissons ratio is: %0.3f no units",po) +printf("\n Youngs modulus: %0.2f GPa",E) diff --git a/3776/CH2/EX2.7/Ex2_7.sce b/3776/CH2/EX2.7/Ex2_7.sce index c452c6448..0bfdaefa3 100644 --- a/3776/CH2/EX2.7/Ex2_7.sce +++ b/3776/CH2/EX2.7/Ex2_7.sce @@ -1,15 +1,16 @@ clear T = 12.9*(10**-6) ///F -t = 100.00 // F +t = 100.00 // F l_ab = 6.71 //inch l_bc = 8.49 //inch -e_ab = T*t*l_ab //in-elongation +e_ab = T*t*l_ab //in-elongation e_bc = T*t*l_bc //in-elongation -k = e_ab/e_bc // ratio of cosines of deflected angles -// t_1 and t_2 be deflected angles -//t_2 = 180-45-26.6-t_1 the sum of angles is 360 +k = e_ab/e_bc // ratio of cosines of deflected angles +// t_1 and t_2 be deflected angles +//t_2 = 45+26.6-t_1 the sum of angles is 360 //applying cos on both sides t_1 = atand(0.5) // e = e_bc/cosd(t_1) printf("\n The displacement in point B is : %e in",e ) +printf("\n It forms an angle of %f degrees with vertical",45-t_1 ) diff --git a/3776/CH3/EX3.2/Ex3_2.sce b/3776/CH3/EX3.2/Ex3_2.sce index 8a3a5388c..759864b7f 100644 --- a/3776/CH3/EX3.2/Ex3_2.sce +++ b/3776/CH3/EX3.2/Ex3_2.sce @@ -1,14 +1,14 @@ clear //Given a = 50 //mm - length of a cube -E = 200 // Gpa - the youngs modulus -v = 0.25 // no units- poissions ratio +E = 200 // GPa - the youngs modulus +v = 0.25 // no units- Poissons ratio pressure = 200 // MPa - pressure acting on all sides //pressure is a compressive stress -S_x = -200 // Gpa - The stress in X direction -S_y = -200 // Gpa - The stress in Y direction -S_z = -200 // Gpa - The stress in Z direction -//Caliculations +S_x = -200 // GPa - The stress in X direction +S_y = -200 // GPa - The stress in Y direction +S_z = -200 // GPa - The stress in Z direction +//calculations e = S_x*(10**-3)/E - v*S_y*(10**-3)/E-v*S_z*(10**-3)/E//mm - considering all three directions x = e*a //mmThe change in the dimension between parallel faces diff --git a/3776/CH3/EX3.3/Ex3_3.sce b/3776/CH3/EX3.3/Ex3_3.sce index 655ef3251..a63e8aa67 100644 --- a/3776/CH3/EX3.3/Ex3_3.sce +++ b/3776/CH3/EX3.3/Ex3_3.sce @@ -1,16 +1,16 @@ clear //Given -R = 1000 // mm - radius of the cylinder +R = 1000 // mm - radius of the cylinder t = 10 //mm - thickness of the cylinder -p_in = 0.80 //Mpa- Internal pressure -E = 200 //Mpa- youngs modulus -v = 0.25 // poission ratio -//caliculations +p_in = 0.80 //Mpa- Internal pressure +E = 200 //Mpa- youngs modulus +v = 0.25 // Poisson ratio +//calculations -Stress_1 = p_in*R/t //MPa -Hoop stress //From derived expressions -Stress_2 = p_in*R/(2*t) //Mpa- Longitudinal stress +Stress_1 = p_in*R/t //MPa -Hoop stress //From derived expressions +Stress_2 = p_in*R/(2*t) //Mpa- Longitudinal stress e = Stress_1*(10**-3)/E-v*Stress_2*(10**-3)/E -dia_change = e*R //mm- The change in daimeter of the cylinder -printf("\n The Hoop stress is %0.3f mm",Stress_1) -printf("\n The longitudinal stress is %0.3f",Stress_2) +dia_change = e*R //mm- The change in daimeter of the cylinder +printf("\n The Hoop stress is %0.3f MPa",Stress_1) +printf("\n The longitudinal stress is %0.3f MPa",Stress_2) printf("\n The change in daimeter of the cylinder is %0.3f mm",dia_change) diff --git a/3776/CH3/EX3.4/Ex3_4.sce b/3776/CH3/EX3.4/Ex3_4.sce index 550b6a893..f0d1c0d96 100644 --- a/3776/CH3/EX3.4/Ex3_4.sce +++ b/3776/CH3/EX3.4/Ex3_4.sce @@ -3,10 +3,10 @@ clear R = 1000 //mm - radius of the cylinder th = 10 //mm - thickness of the cylinder E = 200 //Mpa- youngs modulus -v = 0.25 // poission ratio +v = 0.25 // Poisson ratio p_in = 0.80 //Mpa- Internal pressure t = 10 //mm - thickness of the cylinder -//caliculations +//calculations Stress_1 = p_in*R/(2*t) //MPa -Hoop stress //From derived expressions Stress_2 = p_in*R/(2*t) //Mpa- Longitudinal stress diff --git a/3776/CH3/EX3.5/Ex3_5.sce b/3776/CH3/EX3.5/Ex3_5.sce index 4fe17f46f..78714b79b 100644 --- a/3776/CH3/EX3.5/Ex3_5.sce +++ b/3776/CH3/EX3.5/Ex3_5.sce @@ -1,15 +1,15 @@ clear //Given -p_in = 0.7 //MPa - internal pressure -n_bolts = 20 // number of bolts -dia = 650 //mm - bolt circle diameter -stress_allow = 125 //mm Maximum alowable stress +p_in = 0.7 //MPa - internal pressure +n_bolts = 20 // number of bolts +dia = 650 //mm - bolt circle diameter +stress_allow = 125 //MPa Maximum alowable stress Stress_conc = 2 //stress concentration -d = 25 //mm -//caliculations +d = 25 //mm +//calculations F = p_in*3.14*(((dia-2*d)/2)**2)*(10**6) //N F_each = F/n_bolts //N- force per each Bolt -A = Stress_conc*F_each/(stress_allow*(10**6)) //mm2 The bolt area +A = Stress_conc*F_each/(stress_allow*(10**6)) //sq.mm The bolt area Bolt_dia = 2*((A/3.14)**0.5) //mm the bolt daimeter printf("\n The diameter of each bolt is %0.1f mm",Bolt_dia) diff --git a/3776/CH4/EX4.16/Ex4_16.sce b/3776/CH4/EX4.16/Ex4_16.sce index d62fbcd29..0d9997618 100644 --- a/3776/CH4/EX4.16/Ex4_16.sce +++ b/3776/CH4/EX4.16/Ex4_16.sce @@ -1,12 +1,13 @@ clear -//Given +//Given dia_out = 10 //mm- outer diameter of shaft -dia_in = 8 //mm- inner diameter of shaft -c_out = dia_out/2 //mm - outer Radius of shaft -c_in = dia_in/2 //mm - inner radius of shaft -T = 40 //N/mm -Torque in the shaft -//caliculations - +dia_in = 8 //mm- inner diameter of shaft +c_out = dia_out/2 //mm - outer Radius of shaft +c_in = dia_in/2 //mm - inner radius of shaft +T = 40 //N/mm -Torque in the shaft +//calculations +dia_mean = (dia_out+dia_in)/2 +dia_diff = dia_out-dia_in J = 3.14*((dia_out**4)- (dia_in**4))/32 //mm4 shear_T_max = T*c_out*(10**3)/J // The maximum torsion shear in the shaft shear_T_min = T*c_in*(10**3)/J // The maximum torsion shear in the shaft diff --git a/3776/CH4/EX4.3/Ex4_3.sce b/3776/CH4/EX4.3/Ex4_3.sce index 7ad10bbe6..86dcaed1c 100644 --- a/3776/CH4/EX4.3/Ex4_3.sce +++ b/3776/CH4/EX4.3/Ex4_3.sce @@ -1,14 +1,15 @@ clear -//Given +//Given dia_out = 20 //mm- outer diameter of shaft -dia_in = 16 //mm- inner diameter of shaft -c_out = dia_out/2 //mm - outer Radius of shaft -c_in = dia_in/2 //mm - inner radius of shaft -T = 40 //N/mm -Torque in the shaft -//caliculations +dia_in = 16 //mm- inner diameter of shaft +c_out = dia_out/2 //mm - outer Radius of shaft +c_in = dia_in/2 //mm - inner radius of shaft +T = 40 //N/mm -Torque in the shaft +//calculations J = 3.14*((dia_out**4)- (dia_in**4))/32 //mm4 shear_T_max = T*c_out*(10**3)/J // The maximum torsion shear in the shaft shear_T_min = T*c_in*(10**3)/J // The maximum torsion shear in the shaft -printf("\n The maximum shear due to torsion is %0.2f MPa",shear_T_max) +printf("\n The maximum shear due to torsion is %e MPa",shear_T_max) + //answer in textbook is wrong printf("\n The minimum shear due to torsion is %0.0f MPa",shear_T_min) diff --git a/3776/CH4/EX4.4/Ex4_4.sce b/3776/CH4/EX4.4/Ex4_4.sce index 105784f04..d6f4a901b 100644 --- a/3776/CH4/EX4.4/Ex4_4.sce +++ b/3776/CH4/EX4.4/Ex4_4.sce @@ -1,16 +1,15 @@ clear //Given -hp = 10 // horse power of motor -f = 30 // given -shear_T = 55 //MPa - The maximum shearing in the shaft -//caliculations +hp = 10 // horse power of motor +f = 30 // given +shear_T = 55 //MPa - The maximum shear in the shaft +//calculations -T = 119*hp/f // N.m The torsion in the shaft +T = 119*hp/f // N.m The torsion in the shaft //j/c=T/shear_T=K k = T*(10**3)/shear_T //mm3 //c3=2K/3.14 -c = ((2*k/3)**0.33) //mm - The radius of the shaft -diamter = 2*c //mm - The diameter of the shaft -printf("\n The Diameter of the shaft used is %0.2f mm",diamter) +c = ((2*k/3)**0.33) //mm - The radius of the shaft +diameter = 2*c //mm - The diameter of the shaft +printf("\n The Diameter of the shaft used is %0.2f mm",diameter) printf("\n For practical purposes, a 16-mm shaft would probably be selected") - diff --git a/3776/CH4/EX4.5/Ex4_5.sce b/3776/CH4/EX4.5/Ex4_5.sce index 8d033dc9a..edd0d1fe6 100644 --- a/3776/CH4/EX4.5/Ex4_5.sce +++ b/3776/CH4/EX4.5/Ex4_5.sce @@ -1,23 +1,24 @@ clear -//Given +//Given hp = 200 //Horse power stress_sh = 10000 //psi- shear stress -rpm_1 = 20.0 // The rpm at which this shaft1 operates +rpm_1 = 20.0 // The rpm at which this shaft1 operates rpm_2 = 20000.0 // The rpm at which this shaft2 operates T_1= hp*63000.0/rpm_1 //in-lb Torsion due to rpm1 T_2= hp*63000/rpm_2 //in-lb Torsion due to rpm1 -//caliculations +//calculations //j/c=T/shear_T=K -k_1= T_1/stress_sh //mm3 +k_1= T_1/stress_sh //cu.in //c3=2K/3.14 -c_1= ((2*k_1/3)**0.33) //mm - The radius of the shaft -diamter_1 = 2*c_1 //mm - The diameter of the shaft -printf("\n The Diameter of the shaft1 is %0.2f mm",diamter_1) +//c_1= ((2*k_1/3)**0.33) //mm - The radius of the shaft +diamter_1 = (16*k_1/%pi)**(1/3) //mm - The diameter of the shaft +printf("\n The Diameter of the shaft1 is %0.2f in",diamter_1) //j/c=T/shear_T=K k_2= T_2/stress_sh //mm3 //c3=2K/3.14 -c_2= ((2*k_2/3)**0.33) //mm - The radius of the shaft -diamter_2 = 2*c_2 //mm - The diameter of the shaft -printf("\n The Diameter of the shaft2 is %0.3f mm",diamter_2) +//c_2= ((2*k_2/3)**0.33) //mm - The radius of the shaft +diamter_2 = (16*k_2/%pi)**(1/3) //mm - The diameter of the shaft + +printf("\n The Diameter of the shaft2 is %0.3f in",diamter_2) diff --git a/3776/CH4/EX4.7/Ex4_7.sce b/3776/CH4/EX4.7/Ex4_7.sce index 6b437ff50..2aa479f09 100644 --- a/3776/CH4/EX4.7/Ex4_7.sce +++ b/3776/CH4/EX4.7/Ex4_7.sce @@ -10,8 +10,8 @@ l_cd = 300 //mm - length of cd l_de = 500.0 //mm - length of de d_1 = 25 //mm - outer diameter d_2 = 50 //mm - inner diameter -G = 80 //Gpa -shear modulus -//Caliculations +G = 80 //GPa -shear modulus +//calculations J_ab = 3.14*(d_1**4)/32 //mm4 J_bc = 3.14*(d_1**4)/32 //mm4 diff --git a/3776/CH4/EX4.9/Ex4_9.sce b/3776/CH4/EX4.9/Ex4_9.sce index 5260a4497..31b57e941 100644 --- a/3776/CH4/EX4.9/Ex4_9.sce +++ b/3776/CH4/EX4.9/Ex4_9.sce @@ -1,30 +1,30 @@ clear -//given -//its a statistally indeterminant -//we will take of one of the support -//Given -T_ab = 0 //N.m - torsion in AB +//given +//its a statistally indeterminant +//we will take of one of the support +//Given +T_ab = 0 //N.m - torsion in AB T_bc = 150 //N.m - torsion in BC T_cd = 150 //N.m - torsion in CD T_de = 1150 //N.m - torsion in DE l_ab = 250 //mm - length of AB l_bc = 200 //mm - length of BC -l_cd = 300 //mm - length of cd +l_cd = 300 //mm - length of cd l_de = 500.0//mm - length of de -d_1 = 25 //mm - outer diameter +d_1 = 25 //mm - outer diameter d_2 = 50 //mm - inner diameter -//Caliculations +//calculations J_ab = 3.14*(d_1**4)/32 //mm4 J_bc = 3.14*(d_1**4)/32 //mm4 J_cd = 3.14*(d_2**4 - d_1**4)/32 //mm4 J_de = 3.14*(d_2**4 - d_1**4)/32 //mm4 -G = 80 //Gpa -shear modulus -rad = T_ab*l_ab/(J_ab*G)+ T_bc*l_bc/(J_bc*G)+ T_cd*l_cd/(J_cd*G)+ T_de*l_de/(J_de*G) +G = 80 //GPa -shear modulus +rad = T_ab*l_ab/(J_ab*G)+ T_bc*l_bc/(J_bc*G)+ T_cd*l_cd/(J_cd*G)+ T_de*l_de/(J_de*G) //now lets consider T_A then the torsion is only T_A // T_A*(l_ab/(J_ab*G)+ l_bc/(J_bc*G)+ l_cd/(J_cd*G)+ l_de/(J_de*G)) +rad = 0 -// since there will be no displacement -T_A =-rad/(l_ab/(J_ab*G)+ l_bc/(J_bc*G)+ l_cd/(J_cd*G)+ l_de/(J_de*G)) //Torsion at A +// since there will be no displacement +T_A =rad/(l_ab/(J_ab*G)+ l_bc/(J_bc*G)+ l_cd/(J_cd*G)+ l_de/(J_de*G)) //Torsion at A T_B = 1150 - T_A //n-m F_X = 0 torsion at B -printf("\n The Torsion at rigid end A is %0.2f N-m",T_A) -printf("\n The Torsion at rigid end B is %0.2f N-m",T_B) +printf("\n The Torsion at rigid end A is %0.0f N-m",T_A) +printf("\n The Torsion at rigid end B is %d N-m",T_B) diff --git a/3776/CH5/EX5.1/Ex5_1.sce b/3776/CH5/EX5.1/Ex5_1.sce index f223bc45a..7d38e393a 100644 --- a/3776/CH5/EX5.1/Ex5_1.sce +++ b/3776/CH5/EX5.1/Ex5_1.sce @@ -7,7 +7,7 @@ R_1 = 100 //N - The Force acting l_2 = 0.2 //mt -R_1 acting point the distance from 'a' R_2 = 160 //N The Force acting l_3 = 0.3 //mt -R_2 acting point the distance from 'a' -//caliculations +//calculations //F_X = 0 forces in x directions R_A_X = 0 // since there are no forces in X-direction diff --git a/3776/CH5/EX5.2/Ex5_2.sce b/3776/CH5/EX5.2/Ex5_2.sce index 53aac0bc3..d285b7978 100644 --- a/3776/CH5/EX5.2/Ex5_2.sce +++ b/3776/CH5/EX5.2/Ex5_2.sce @@ -2,8 +2,8 @@ clear //Given P_Max = 10 //N - the maximum distribution in a triangular distribution L = 3 //mt the total length of force distribution -L_X = 5 //mt - the horizantal length of the rod -//caliculations +L_X = 5 //mt - the horizontal length of the rod +//calculations F_y = P_Max*L*0.5 //N - The force due to triangular distribition L_com = 2*L /3 //mt - the resultant force acting as a result of distribution acting position diff --git a/3776/CH5/EX5.3/Ex5_3.sce b/3776/CH5/EX5.3/Ex5_3.sce index 44cb6144a..46e8c4366 100644 --- a/3776/CH5/EX5.3/Ex5_3.sce +++ b/3776/CH5/EX5.3/Ex5_3.sce @@ -2,26 +2,26 @@ clear //given F = 5 //K - force acting on the system tan1 = (4/3) // the Tan of the angle of force with x axis -l_ab = 12 //inch - the total length of ab +l_ab = 12 //inch - the total length of ab l = 3 // inch - Distance from 'a' -//caliculation +//calculation F_X = 4 //K F_Y = 3 //k //M_A = 0 momentum at point a is zero -// F_X*l- R_B_Y*l_ab = 0 +// F_X*l- R_B_Y*l_ab = 0 R_B_Y = F_X*l/l_ab //M_B= 0 momentum at point b is zero // R_A_Y*l_ab - F_X*(l_ab - l) R_A_Y = F_X*(l_ab - l)/l_ab - + //F_X = 0 forces in x directions -R_A_X = F_Y + R_B_Y +R_A_X = F_Y + R_B_Y R_B_X = R_B_Y // since the angle is 45 (180/%pi)* -//resultants -R_A = (R_A_X**2 + R_A_Y**2**0.5) -R_B = (R_B_X**2 + R_B_Y**2**0.5) +//resultants +R_A = (R_A_X**2 + R_A_Y**2)**0.5 +R_B = (R_B_X**2 + R_B_Y**2)**0.5 printf("The X,Y components and resultant of reaction force at A is %0.3f, %0.3f,%0.3f N",R_A_X,R_A_Y,R_A) printf("\nThe X,Y components and resultant of reaction force at B is %0.3f, %0.3f,%0.3f N",R_B_X,R_B_Y,R_B) diff --git a/3776/CH5/EX5.4/Ex5_4.sce b/3776/CH5/EX5.4/Ex5_4.sce index 2a3e57db7..2a3235419 100644 --- a/3776/CH5/EX5.4/Ex5_4.sce +++ b/3776/CH5/EX5.4/Ex5_4.sce @@ -2,8 +2,8 @@ clear //Given P_Max = 10 //N - the maximum distribution in a triangular distribution L = 3 //mt the total length of force distribution -L_X = 5 //mt - the horizantal length of the rod -//caliculations +L_X = 5 //mt - the horizontal length of the rod +//calculations F_y = P_Max*L*0.5 //N - The force due to triangular distribition L_com = 2*L /3 //mt - the resultant force acting as a result of distribution acting position diff --git a/3776/CH5/EX5.9/Ex5_9.sce b/3776/CH5/EX5.9/Ex5_9.sce index 245adc229..87a133ed4 100644 --- a/3776/CH5/EX5.9/Ex5_9.sce +++ b/3776/CH5/EX5.9/Ex5_9.sce @@ -2,8 +2,8 @@ clear //Given P_Max = 10 //N - the maximum distribution in a triangular distribution L = 3 //mt the total length of force distribution -L_X = 5 //mt - the horizantal length of the rod -//caliculations +L_X = 5 //mt - the horizontal length of the rod +//calculations F_y = P_Max*L*0.5 //N - The force due to triangular distribition L_com = 2*L /3 //mt - the resultant force acting as a result of distribution acting position diff --git a/3776/CH6/EX6.10/Ex6_10.sce b/3776/CH6/EX6.10/Ex6_10.sce index 43f31cf7d..b81c2de1f 100644 --- a/3776/CH6/EX6.10/Ex6_10.sce +++ b/3776/CH6/EX6.10/Ex6_10.sce @@ -3,7 +3,7 @@ clear l = 50.0 //mm - the length of the beam b = 50.0 //mm - the width of the beam M = 2083 //Nm -A = l*b //mm2 - The area +A = l*b //sq.mm - The area //straight beam I = b*(l**3)/12.0 //mm4 - The moment of inertia of the beam c_1= l/2 // the distance where the stress is maximum diff --git a/3776/CH6/EX6.14/Ex6_14.sce b/3776/CH6/EX6.14/Ex6_14.sce index 6198c1458..3a12216ff 100644 --- a/3776/CH6/EX6.14/Ex6_14.sce +++ b/3776/CH6/EX6.14/Ex6_14.sce @@ -1,12 +1,13 @@ clear -//given +//given //from example 6.9 St_ul = 2500 //psi - ultimate strength -st_yl = 40000 //psi _ yielding strength -b = 10 //in - width from example -A = 2 //in2 The area of the steel -d = 20 +st_yl = 40000 //psi _ yielding strength +b = 10 //in - width from example +A = 2 //sq.in The area of the steel +d = 20 t_ul = st_yl*A //ultimate capasity y = t_ul/(St_ul*b*0.85) //in 0.85 because its customary -M_ul = t_ul*(d-y/2)/12 //ft-lb Plastic moment +M_ul = t_ul*(d-y/2)/12 //ft-lb Plastic moment printf("\n The plastic moment of the system is %0.3f ft-lb",M_ul) + //answer in the textbook is wrong diff --git a/3776/CH6/EX6.15/Ex6_15.sce b/3776/CH6/EX6.15/Ex6_15.sce index ca2df4451..cfbab548a 100644 --- a/3776/CH6/EX6.15/Ex6_15.sce +++ b/3776/CH6/EX6.15/Ex6_15.sce @@ -1,12 +1,12 @@ clear -//Given -//From example 5.8 -W = 4.0 //N/m - The force distribution +//Given +//From example 5.8 +W = 4.0 //N/m - The force distribution L = 3 // m - The length of the force applied M = W*L/8.0 // KN.m The moment due to force distribution -o = 30 // the angle of force applid to horizantal -l = 150.0 //mm length of the crossection -b = 100.0 //mm - width of the crossection +o = 30 // the angle of force applied to horizontal +l = 150.0 //mm length of the crossection +b = 100.0 //mm - width of the crossection // M_z = M*(cos(3.14/6)) M_y = M*(sin(%pi/6)) @@ -14,4 +14,4 @@ I_z = b*(l**3)/12.0 I_y = l*(b**3)/12.0 //tanb = I_z /I_y *tan30 b = atand((I_z*tan(3.14/6.0)/I_y)) -printf("\n The angle at which neutral axis locates is %0.3f degrees",b) +printf("\n The angle at which neutral axis located by is %0.3f degrees",b) diff --git a/3776/CH6/EX6.18/Ex6_18.sce b/3776/CH6/EX6.18/Ex6_18.sce index ccce2e9e8..ae568d544 100644 --- a/3776/CH6/EX6.18/Ex6_18.sce +++ b/3776/CH6/EX6.18/Ex6_18.sce @@ -1,7 +1,7 @@ clear l = 50 //mm - The length of the beam b = 50 //mm - The width of the beam -A = l*b //mm2 - The area of the beam +A = l*b //sq.mm - The area of the beam p = 8.33 //KN - The force applied on the beam stress_max = p*(10**3)/A //MPa After cutting section A--b printf("\n The maximum stress in the beam %0.3f MPa ",stress_max ) diff --git a/3776/CH6/EX6.24/Ex6_24.sce b/3776/CH6/EX6.24/Ex6_24.sce index 1aac53ebb..ba4fa87eb 100644 --- a/3776/CH6/EX6.24/Ex6_24.sce +++ b/3776/CH6/EX6.24/Ex6_24.sce @@ -4,25 +4,25 @@ M = 10 //KN.m - The moment applied I_max = 23.95*(10**6) //mm4 - I_z The moment of inertia I_min = 2.53*(10**6) //mm4 - I_y The moment of inertia o = 14.34 // degress the principle axis rotated -//Coponents of M in Y,Z direction +//Coponents of M in Y,Z direction M_z = M*(10**6)*cos((%pi/180)*(o)) M_y = M*(10**6)*sin((%pi/180)*(o)) //tanb = I_z /I_y *tan14.34 b = atan((I_max*tan((%pi/180)*(o))/I_min )) -B = (180/%pi)*(b) +B = (180/%pi)*(b) y_p = 122.9 // mm - principle axis Y cordinate z_p = -26.95 //mm - principle axis z cordinate stress_B = - M_z*y_p/I_max + M_y*z_p/I_min //MPa - Maximum tensile stress y_f = -65.97 // mm - principle axis Y cordinate z_f = 41.93 //mm - principle axis z cordinate stress_f = - M_z*y_f/I_max + M_y*z_f/I_min //MPa - Maximum compressive stress -//location of nuetral axis To show these stresses are max and minimum +//location of nuetral axis To show these stresses are max and minimum //tanB = MzI_z + MzI_yz/MyI_y +M_YI_yz I_z = 22.64 *(10**6) //mm4 moment of inertia in Z direction I_y = 3.84 *(10**6) //mm4 moment of inertia in Y direction -I_yz =5.14 *(10**6) //mm4 moment of inertia in YZ direction -M_y = M //KN.m bending moment in Y dorection -M_z = M //KN.m bending moment in Y dorection +I_yz =5.14 *(10**6) //mm4 moment of inertia in YZ direction +M_y = M //KN.m bending moment in Y dorection +M_z = M //KN.m bending moment in Y dorection B = atan(( M_z*I_yz)/(M_z*I_y )) //(%pi/180)* location on neutral axis -beta = (180/%pi)*(B) -printf("\n By sketching the line with angle %0.1f degrees The farthest point associated with B and F",beta) +beta1 = (180/%pi)*(B) +printf("\n By sketching the line with angle %0.1f degrees The farthest point associated with B and F",beta1) diff --git a/3776/CH6/EX6.3/Ex6_3.sce b/3776/CH6/EX6.3/Ex6_3.sce index 857811d33..19291d887 100644 --- a/3776/CH6/EX6.3/Ex6_3.sce +++ b/3776/CH6/EX6.3/Ex6_3.sce @@ -1,18 +1,18 @@ clear -//Given -//Entire area - hallow area +//Given +//Entire area - hollow area l_e = 60.0 //mm - length of the entire area b_e = 40 //mm - width of the entire area -l_h = 30 //mm - length of the hallow area -b_h = 20 //mm - width of the hallow area -A_e = l_e*b_e //mm2 - The entire area -A_h = -l_h*b_h //mm2 - The hallow area '-' because its hallow -A_re = A_e + A_h //mm2 resultant area -y_e = l_e/2 // mm com from bottom -y_h = 20+l_h/2 //mm com from bottom -y_com = (A_e*y_e + A_h*y_h)/A_re +l_h = 30 //mm - length of the hollow area +b_h = 20 //mm - width of the hollow area +A_e = l_e*b_e //sq.mm - The entire area +A_h = -l_h*b_h //sq.mm - The hollow area +A_re = A_e + A_h //sq.mm resultant area +y_e = l_e/2 // mm com from bottom +y_h = 20+l_h/2 //mm com from bottom +y_com = (A_e*y_e + A_h*y_h)/A_re //moment of inertia caliculatins - bh3/12 +ad2 -I_e = b_e*(l_e**3)/12 + A_e*((y_e-y_com)**2) //Parallel axis theorm -I_h = b_h*(l_h**3)/12 - A_h*((y_h-y_com)**2) //Parallel axis theorm +I_e = b_e*(l_e**3)/12 + A_e*((y_e-y_com)**2) //Parallel axis theorem +I_h = b_h*(l_h**3)/12 - A_h*((y_h-y_com)**2) //Parallel axis theorem I_total = I_e - I_h printf("\n The moment of inertia of total system is %e mm^4",I_total) diff --git a/3776/CH6/EX6.4/Ex6_4.sce b/3776/CH6/EX6.4/Ex6_4.sce index 99f0edaa9..98157a320 100644 --- a/3776/CH6/EX6.4/Ex6_4.sce +++ b/3776/CH6/EX6.4/Ex6_4.sce @@ -5,7 +5,7 @@ b = 300 //mm - breath F = 20 //KN _ the force applied on the beam F_d = 0.75 //KN-m - The force distribution d = 2 //mt - the point of interest from the free end -//caliculations +//calculations //From moment diagram M = F*d - F_d*d*1 I = b*(l**3)/12 //mm4 - Bending moment diagram diff --git a/3776/CH6/EX6.5/Ex6_5.sce b/3776/CH6/EX6.5/Ex6_5.sce index 551491f53..6e8121ffb 100644 --- a/3776/CH6/EX6.5/Ex6_5.sce +++ b/3776/CH6/EX6.5/Ex6_5.sce @@ -7,17 +7,17 @@ l_1 = 1 //in l_2 = 3 //in b_1 = 4 //in b_2 = 1 //in -A_1 = l_1* b_1 //in2 - area of part_1 +A_1 = l_1* b_1 //sq.in - area of part_1 y_1 = 0.5 //in com distance from ab -A_2 =l_2*b_2 //in2 - area of part_1 +A_2 =l_2*b_2 //sq.in - area of part_1 y_2 = 2.5 //in com distance from ab -A_3 = l_2*b_2 //in2 - area of part_1 +A_3 = l_2*b_2 //sq.in - area of part_1 y_3 = 2.5 //in com distance from ab y_net = (A_1*y_1 +A_2*y_2 + A_3*y_3)/(A_1+A_2+A_3) //in - The com of the whole system c_max = (4-y_net) //in - The maximum distace from com to end c_min = y_net //in - the minimum distance from com to end -I_1 = b_1*(l_1**3)/12 + A_1*((y_1-y_net)**2) //Parallel axis theorm +I_1 = b_1*(l_1**3)/12 + A_1*((y_1-y_net)**2) //Parallel axis theorem I_2 = b_2*(l_2**3)/12 + A_2*((y_2-y_net)**2) I_3 = b_2*(l_2**3)/12 + A_2*((y_2-y_net)**2) I_net = I_1 + I_2 + I_3 //in^4 - the total moment of inertia diff --git a/3776/CH6/EX6.8/Ex6_8.sce b/3776/CH6/EX6.8/Ex6_8.sce index 244deb69e..51d04bb08 100644 --- a/3776/CH6/EX6.8/Ex6_8.sce +++ b/3776/CH6/EX6.8/Ex6_8.sce @@ -2,20 +2,20 @@ clear //Given //Given //We will divide this into two parts -E_w = 10.0 //Gpa - Youngs modulus of wood -E_s = 200.0 //Gpa - Youngs modulus of steel +E_w = 10.0 //GPa - Youngs modulus of wood +E_s = 200.0 //GPa - Youngs modulus of steel M = 30.0 //K.N-m _ applied bending moment n = E_s/E_w l_1 = 250 //mm l_2 = 10 //mm b_1 = 150.0 //mm b_2 = 150.0*n //mm -A_1 = l_1* b_1 //mm2 - area of part_1 +A_1 = l_1* b_1 //sq.mm - area of part_1 y_1 = 125.0 //mm com distance from top -A_2 =l_2*b_2 //mm2 - area of part_1 +A_2 =l_2*b_2 //sq.mm - area of part_1 y_2 = 255.0 //mm com distance from top y_net = (A_1*y_1 +A_2*y_2)/(A_1+A_2) //mm - The com of the whole system from top -I_1 = b_1*(l_1**3)/12.0 + A_1*((y_1-y_net)**2) //Parallel axis theorm +I_1 = b_1*(l_1**3)/12.0 + A_1*((y_1-y_net)**2) //Parallel axis theorem I_2 = b_2*(l_2**3)/12.0 + A_2*((y_2-y_net)**2) I_net = I_1 + I_2 //mm4 - the total moment of inertia c_s= y_net // The maximum distance in steel diff --git a/3776/CH6/EX6.9/Ex6_9.sce b/3776/CH6/EX6.9/Ex6_9.sce index 74d9c8acf..1c99a03a6 100644 --- a/3776/CH6/EX6.9/Ex6_9.sce +++ b/3776/CH6/EX6.9/Ex6_9.sce @@ -1,12 +1,12 @@ clear -//Given +//Given M = 50000 //ft-lb , positive bending moment applied -N = 9 // number of steel bars -n = 15 // The ratio of steel to concrete -A_s = 30 //in2 area of steel in concrete +N = 9 // number of steel bars +n = 15 // The ratio of steel to concrete +A_s = 30 //sq.in area of steel in concrete //(10*y)*(y/2) = 30*(20-y) //y**2 + 6*y -120 -//solving quadractic equation +//solving quadractic equation // a = 1 @@ -21,16 +21,16 @@ sol2 = (-b+sqrt(d))/(2*a) y = sol2 // Nuetral axis is found l_1 = y //in- the concrete below nuetral axis is not considered b_1 = 10 //in - width -A_1 = l_1* b_1 //in2 - area of concrete -y_1 = y/2 //in com of the concrete -y_2 = 20-y //in com of the transformed steel -I_1 = b_1*(l_1**3)/12.0 + A_1*((y_1-y)**2) //in^4 parallel axis theorm +A_1 = l_1* b_1 //sq.in - area of concrete +y_1 = y/2 //in com of the concrete +y_2 = 20-y //in com of the transformed steel +I_1 = b_1*(l_1**3)/12.0 + A_1*((y_1-y)**2) //in^4 parallel axis theorem I_2 = A_s*((y_2)**2) //in^4 first part is neglected I_net = I_1 + I_2 //in^4 - the total moment of inertia -c_c= y //in The maximum distance in concrete -stress_concrete = M*12*c_c/I_net //psi - The maximum stress in concrete -c_s= 20- y -stress_steel =n*M*12*c_s/I_net //psi - The maximum stress in concrete +c_c= y //in The maximum distance in concrete +stress_concrete = M*12*c_c/I_net //psi - The maximum stress in concrete +c_s= 20- y +stress_steel =n*M*12*c_s/I_net //psi - The maximum stress in concrete printf("\n The maximum stress in concrete %0.2f psi",stress_concrete) // printf("\n The stress in steel %0.2f psi",stress_steel) -printf("\n answer varies due to rounding off errors")
\ No newline at end of file +// answer varies due to rounding off errors diff --git a/3776/CH7/EX7.1/Ex7_1.sce b/3776/CH7/EX7.1/Ex7_1.sce index 22b3a758c..4e1d1ef6f 100644 --- a/3776/CH7/EX7.1/Ex7_1.sce +++ b/3776/CH7/EX7.1/Ex7_1.sce @@ -7,14 +7,14 @@ l_1 = 50.0 //mm l_2 = 200.0 //mm b_1 = 200.0 //mm b_2 = 50.0 //mm -A_1 = l_1* b_1 //mm2 - area of part_1 +A_1 = l_1* b_1 //sq.mm - area of part_1 y_1 = 25.0 //mm com distance -A_2 =l_2*b_2 //mm2 - area of part_1 +A_2 =l_2*b_2 //sq.mm - area of part_1 y_2 = 150.0 //in com distance y_net = (A_1*y_1 +A_2*y_2)/(A_1+A_2) //mm - The com of the whole system c_max = (4-y_net) //mm - The maximum distace from com to end c_min = y_net //mm - the minimum distance from com to end -I_1 = b_1*(l_1**3)/12 + A_1*((y_1-y_net)**2) //Parallel axis theorm +I_1 = b_1*(l_1**3)/12 + A_1*((y_1-y_net)**2) //Parallel axis theorem I_2 = b_2*(l_2**3)/12 + A_2*((y_2-y_net)**2) I_net = I_1 + I_2 //mm4 - the total moment of inertia Q = A_1*(-y_1+y_net) //mm3 diff --git a/3776/CH7/EX7.2/Ex7_2.sce b/3776/CH7/EX7.2/Ex7_2.sce index 71c8e8755..9f6d25ae4 100644 --- a/3776/CH7/EX7.2/Ex7_2.sce +++ b/3776/CH7/EX7.2/Ex7_2.sce @@ -6,15 +6,15 @@ R_a = l*p/2 //KN -The reaction at a, Since the system is symmetry R_b = l*p/2 //KN -The reaction at b l_s = 10 //mm - The length of the screw shear_al = 2 //KN - The maximum load the screw can take -I = 2.36*(10**9) //mm2 The moment of inertia of the whole system +I = 2.36*(10**9) //sq.mm The moment of inertia of the whole system //We will divide this into two parts l_1 = 50.0 //mm l_2 = 50.0 //mm b_1 = 100.0 //mm b_2 = 200.0 //mm -A_1 = l_1* b_1 //in2 - area of part_1 +A_1 = l_1* b_1 //sq.in - area of part_1 y_1 = 200.0 //mm com distance -A_2 =l_2*b_2 //mm2 - area of part_1 +A_2 =l_2*b_2 //sq.mm - area of part_1 y_2 = 225.0 //in com distance Q = 2*A_1*y_1 + A_2*y_2 // mm**3 For the whole system q = R_a*Q*(10**3)/I //N/mm The shear flow diff --git a/3776/CH7/EX7.6/Ex7_6.sce b/3776/CH7/EX7.6/Ex7_6.sce index 89fca203f..7253fc27d 100644 --- a/3776/CH7/EX7.6/Ex7_6.sce +++ b/3776/CH7/EX7.6/Ex7_6.sce @@ -4,7 +4,7 @@ clear l = 10.0 // in - The height t = 0.1 // in - The width b = 5.0 //mm- The width of the above part -A = t* b //in2 - area of part +A = t* b //sq.in - area of part y_net = l/2 // The com of the system y_1 = l // The position of teh com of part_2 I_1 = t*(l**3)/12 //in^4 The moment of inertia of part 1 diff --git a/3776/CH7/EX7.8/Ex7_8.sce b/3776/CH7/EX7.8/Ex7_8.sce index 67646ba58..f39579fa7 100644 --- a/3776/CH7/EX7.8/Ex7_8.sce +++ b/3776/CH7/EX7.8/Ex7_8.sce @@ -2,7 +2,7 @@ clear //Given dia = 10.0 //mm - The diameter of the cylinder c = dia/2 //mm - the radius of the cylinder -A = 3.14*(c**2) //mm2 The area of the crossection +A = 3.14*(c**2) //sq.mm The area of the crossection y = 4*c/(3*3.14) //mm The com of cylinder I = 3.14*(c**4)/4 //mm4 - The moment of inertia of the cylinder j = 3.14*(dia**4)/32 //mm4 diff --git a/3776/CH7/EX7.9/Ex7_9.sce b/3776/CH7/EX7.9/Ex7_9.sce index 4822c44e0..2f8b342e6 100644 --- a/3776/CH7/EX7.9/Ex7_9.sce +++ b/3776/CH7/EX7.9/Ex7_9.sce @@ -2,8 +2,8 @@ clear //Given dia = 15 //mm - The diameter of the rod h = 0.5 //mt - The freely falling height -A = 3.14*(dia**2)/4 //mm2 The area of the crossection -E = 200 //Gpa -Youngs modulus +A = 3.14*(dia**2)/4 //sq.mm The area of the crossection +E = 200 //GPa -Youngs modulus L = 750 //mm - The total length of the rod G = 80 //gpa - Shear modulus N = 10 //number of live coils diff --git a/3776/CH8/EX8.1/Ex8_1.sce b/3776/CH8/EX8.1/Ex8_1.sce index 2510958ab..2fd755047 100644 --- a/3776/CH8/EX8.1/Ex8_1.sce +++ b/3776/CH8/EX8.1/Ex8_1.sce @@ -3,9 +3,9 @@ clear // // o = 22.5 //degrees , The angle of infetisimal wedge -A = 1 //mm2 The area of the element -A_ab = 1*(cos((%pi/180)*(o))) //mm2 - The area corresponds to AB -A_bc = 1*(sin((%pi/180)*(o))) //mm2 - The area corresponds to BC +A = 1 //sq.mm The area of the element +A_ab = 1*(cos((%pi/180)*(o))) //sq.mm - The area corresponds to AB +A_bc = 1*(sin((%pi/180)*(o))) //sq.mm - The area corresponds to BC S_1 = 3 //MN The stresses applying on the element S_2 = 2 //MN S_3 = 2 //MN diff --git a/3776/CH8/EX8.3/Ex8_3.sce b/3776/CH8/EX8.3/Ex8_3.sce index 6172f655f..9bda8dc65 100644 --- a/3776/CH8/EX8.3/Ex8_3.sce +++ b/3776/CH8/EX8.3/Ex8_3.sce @@ -1,16 +1,15 @@ clear -//Given +//Given // // S_x = -2 //MPa _ the noraml stress in x direction S_y = 4 //MPa _ the noraml stress in Y direction -c = (S_x + S_y)/2 //MPa - The centre of the mohr circle -point_x = -2 //The x coordinate of a point on mohr circle +c = (S_x + S_y)/2 //MPa - The centre of the mohr circle +point_x = 3 //The x coordinate of a point on mohr circle point_y = 4 //The y coordinate of a point on mohr circle -Radius = ((point_x-c)**2 + point_y**2**0.5) // The radius of the mohr circle +Radius = ((point_x)**2 + point_y**2)**0.5 // The radius of the mohr circle S_1 = Radius +1//MPa The principle stress S_2 = -Radius +1 //MPa The principle stress S_xy_max = Radius //MPa The maximum shear stress -printf("\n The principle stresses are %0.3f MPa %0.3f MPa",S_1,S_2) +printf("\n The principle stresses are %0.3f MPa, %0.3f MPa",S_1,S_2) printf("\n The maximum shear stress %0.3f MPa",S_xy_max) -printf("\n The maximum tensile stress which is the result of all stresses must act as shown in the figure") diff --git a/3776/CH8/EX8.4/Ex8_4.sce b/3776/CH8/EX8.4/Ex8_4.sce index 75a4498ff..fb3b4c6ff 100644 --- a/3776/CH8/EX8.4/Ex8_4.sce +++ b/3776/CH8/EX8.4/Ex8_4.sce @@ -3,18 +3,17 @@ clear // S_x = 3.0 //MPa _ the noraml stress in x direction S_y = 1.0 //MPa _ the noraml stress in Y direction -c = (S_x + S_y)/2 //MPa - The centre of the mohr circle +c = (S_x + S_y)/2 //MPa - The centre of the mohr circle point_x = 1 //The x coordinate of a point on mohr circle point_y = 3 //The y coordinate of a point on mohr circle -//Caliculations +//calculations -Radius = ((point_x-c)**2 + point_y**2**0.5) // The radius of the mohr circle -//22.5 degrees line is drawn -o = 22.5 //degrees -a = 71.5 - 2*o //Degrees, from diagram -stress_n = c + Radius*sin((180/%pi)*(o)) //MPa The normal stress on the plane -stress_t = Radius*cos((180/%pi)*(o)) //MPa The tangential stress on the plane +Radius = ((point_x)**2 + point_y**2)**0.5 // The radius of the mohr circle +//22.5 degrees line is drawn +o = 22.5 //degrees +a = 71.57 - 2*o //Degrees, from diagram +stress_n = c + Radius*sin((180/%pi)*(o)) //MPa The normal stress on the plane +ang = sind((-a)) +stress_t = Radius*ang //MPa The tangential stress on the plane printf("\n The normal stress on the 22 1/2 plane %0.2f MPa",stress_n) printf("\n The tangential stress on the 22 1/2 plane %0.2f MPa",stress_t) -printf("\n answer varies due to rounding off errors") - diff --git a/3776/CH8/EX8.7/Ex8_7.sce b/3776/CH8/EX8.7/Ex8_7.sce index a497ec56a..8013fda4e 100644 --- a/3776/CH8/EX8.7/Ex8_7.sce +++ b/3776/CH8/EX8.7/Ex8_7.sce @@ -3,7 +3,7 @@ clear e_x = -500 //10-6 m/m The contraction in X direction e_y = 300 //10-6 m/m The contraction in Y direction e_xy = -600 //10-6 m/m discorted angle -centre = (e_x + e_y)/2 //10-6 m/m +centre = (e_x + e_y)/2 //10-6 m/m point_x = -500 //The x coordinate of a point on mohr circle point_y = 300 //The y coordinate of a point on mohr circle Radius = 500 //10-6 m/m - from mohr circle @@ -11,5 +11,5 @@ e_1 = Radius +centre //MPa The principal strain e_2 = -Radius +centre //MPa The principal strain k = atan(300.0/900) // from geometry k_1 = (180/%pi)*(k) -printf("\n The principal strains are %0.3f um/m %0.3f um/m",e_1,e_2) +printf("\n The principal strains are %0.3f micro m/m %0.3f micro m/m",e_1,e_2) printf("\n The angle of principal plane %0.2f degrees",k_1) diff --git a/3776/CH8/EX8.8/Ex8_8.sce b/3776/CH8/EX8.8/Ex8_8.sce index 0c8fd0488..57bd71918 100644 --- a/3776/CH8/EX8.8/Ex8_8.sce +++ b/3776/CH8/EX8.8/Ex8_8.sce @@ -1,24 +1,25 @@ clear //Given -e_0 = -500 //10-6 m/m -e_45 = 200 //10-6 m/m +e_0 = -500 //10-6 m/m +e_45 = 200 //10-6 m/m e_90 = 300 //10-6 m/m -E = 200 //Gpa - youngs modulus of steel -v = 0.3 // poissions ratio -//Caliculations +E = 200 //GPa - youngs modulus of steel +v = 0.3 // Poissons ratio +//calculations e_xy = 2*e_45 - (e_0 +e_90 ) //10-6 m/m from equation 8-40 in text // from example 8.7 e_x = -500 //10-6 m/m The contraction in X direction e_y = 300 //10-6 m/m The contraction in Y direction e_xy = -600 //10-6 m/m discorted angle -centre = (e_x + e_y)/2 //10-6 m/m +centre = (e_x + e_y)/2 //10-6 m/m point_x = -500 //The x coordinate of a point on mohr circle point_y = 300 //The y coordinate of a point on mohr circle Radius = 500 //10-6 m/m - from mohr circle e_1 = Radius +centre //MPa The principle strain e_2 = -Radius +centre //MPa The principle strain -stress_1 = E*(10**-3)*(e_1+v*e_2)/(1-v**2) //MPa the stress in this direction -stress_2 = E*(10**-3)*(e_2+v*e_1)/(1-v**2) //MPa the stress in this direction +stress_1 = E*(10**-3)*(e_1+v*e_2)/(1-v**2) //MPa the stress in this direction +stress_2 = E*(10**-3)*(e_2+v*e_1)/(1-v**2) //MPa the stress in this direction printf("\n The principle stresses are %0.2f MPa %0.2f MPa",stress_1,stress_2) +// answer in textbook is wrong diff --git a/3776/CH9/EX9.4/Ex9_4.sce b/3776/CH9/EX9.4/Ex9_4.sce index f645233f8..1b4944c45 100644 --- a/3776/CH9/EX9.4/Ex9_4.sce +++ b/3776/CH9/EX9.4/Ex9_4.sce @@ -1,13 +1,13 @@ clear -//Given +//Given // b = 40.0 //mm - The width of the beam crossection -h = 300.0 //mm - The length of the beam crossection +h = 300.0 //mm - The length of the beam crossection V = 40.0 //KN - The shear stress in teh crossection -M = 10.0 //KN-m - The bending moment on K----K crossection +M = 10.0 //KN-m - The bending moment on K----K crossection c = h/2 //mm -The position at which maximum stress occurs on the crossection -I = b*(h**3)/12 //mmm4 - the moment of inertia -//Caliculations +I = b*(h**3)/12 //mmm4 - the moment of inertia +//calculations stress_max_1 = M*c*(10**6)/I //The maximum stress occurs at the end stress_max_2 = -M*c*(10**6)/I //The maximum stress occurs at the end @@ -16,13 +16,13 @@ n = y/(c) // The ratio of the distances from nuetral axis t stress_L_1 = n*stress_max_1 //The normal stress on elements L--L stress_L_2 = -n*stress_max_1 //The normal stress on elements L--L x = 10 //mm The length of the element -A = b*x //mm3 The area of the element +A = b*x //mm3 The area of the element y_1 = y+x/2 // the com of element from com of whole system -stress_xy = V*A*y_1*(10**3)/(I*b) //MPa - The shear stress on the element -//stresses acting in plane 30 degrees +stress_xy = V*A*y_1*(10**3)/(I*b) //MPa - The shear stress on the element +//stresses acting in plane 30 degrees o = 60 //degrees - the plane angle stress_theta = stress_L_1/2 + stress_L_1*(cos((%pi/180)*(o)))/2 - stress_xy*(sin((%pi/180)*(o))) //MPa by direct application of equations stress_shear = -stress_L_1*(sin((%pi/180)*(o)))/2 - stress_xy*(cos((%pi/180)*(o))) //MPa Shear stress - + printf("\n a)The principle stresses are %0.2f MPa %0.2f MPa",stress_max_1,stress_max_2) -printf("\n b)The stresses on inclines plane %0.2f MPa noraml, %0.2f MPa shear ",stress_theta,stress_shear) +printf("\n b)The stresses on inclined plane %0.2f MPa normal, %0.2f MPa shear ",stress_theta,stress_shear) diff --git a/3776/CH9/EX9.5/Ex9_5.sce b/3776/CH9/EX9.5/Ex9_5.sce index ee3f65e4e..432d3df4b 100644 --- a/3776/CH9/EX9.5/Ex9_5.sce +++ b/3776/CH9/EX9.5/Ex9_5.sce @@ -1,23 +1,24 @@ clear //Given M = 10 //KN-m moment -v = 8.0 //KN - shear Stress +v = 8.0 //KN - shear Stress stress_allow = 8 //MPa - The maximum allowable stress shear_allow_per = 1.4 //MPa - The allowable stress perpendicular to grain stress_allow_shear = 0.7 //MPa - The maximum allowable shear stress -//Caliculations +//calculations -S = M*(10**6)/stress_allow //mm3 +S = M*(10**6)/stress_allow //mm3 //lets arbitarly assume h = 2b //S = b*(h**2)/6 -h = (12*S**0.333) //The depth of the beam +h = (1.25*(10**6)*12)**(1/3) //The depth of the beam b = h/2 //mm The width of the beam -A = h*b //mm2 The area of the crossection , assumption -stress_shear = 3*v*(10**3)/(2*A) //MPa The strear stress +A = 140*240 //sq.mm The area of the crossection , assumption +stress_shear = 3*v*(10**3)/(2*A) //MPa The strear stress if stress_shear<stress_allow_shear then - printf("The stress developed %0.2f is in allowable ranges for %0.2f mm2 area",stress_shear,A) + printf("The stress developed %0.2f is in allowable ranges for %0.2f sq.mm area",stress_shear,A) else printf("The stress developed %0.3f is in non allowable ranges %0.3f area",stress_shear,A) end Area_allow = v*(10**3)/shear_allow_per //mm - the allowable area -printf("\n The minimum area is %0.3f mm2",Area_allow ) +printf("\n The minimum area is %0.3f sq.mm",Area_allow ) +//answer varies due to rounding off errors diff --git a/3776/CH9/EX9.6/Ex9_6.sce b/3776/CH9/EX9.6/Ex9_6.sce index a8a78e3ed..20e5c1797 100644 --- a/3776/CH9/EX9.6/Ex9_6.sce +++ b/3776/CH9/EX9.6/Ex9_6.sce @@ -9,11 +9,11 @@ A = l*w R_A = 6.4 //k - The reaction at A R_B = 25.6 //k - the reaction at B v_max = R_B-l*w //kips the maximum stress, from diagram -//W8x24 is used from the appendix table 3 and 4 +//W8x24 is used from the appendix table 3 and 4 l =0.245 //in - W8x24 crossesction length -//Caliculations +//calculations -stress_xy = v_max/A //ksi the approximate shear stress +stress_xy = v_max/A //ksi the approximate shear stress if stress_xy < stress_allow_shear then printf("W8x24 gives the allowable ranges of shear stress") else: @@ -24,7 +24,7 @@ k = 7.0/8 //in the distance from the outer face of the flange to the webfillet //a1t+2kt should not exceed 0.75 of yeild stress Stress_yp = 36 //ksi - The yeild stress t = 0.245 //in thickness of the web -//support a +//support a a = R_A/(0.75*Stress_yp*t)-k //in lengths of the bearings //support b a_1 = R_B/(0.75*Stress_yp*t)-2*k //in lengths of the bearings diff --git a/3776/CH9/EX9.8/Ex9_8.sce b/3776/CH9/EX9.8/Ex9_8.sce index b986095ec..f7b27f51e 100644 --- a/3776/CH9/EX9.8/Ex9_8.sce +++ b/3776/CH9/EX9.8/Ex9_8.sce @@ -4,8 +4,8 @@ hp = 63000 //horse power T = hp*20*(10**-3)/63 //k-in the torsion implies due to horse power stress_allow_shear = 6 //ksi- The maximum allowable shear stress M_ver = 6.72/2 //k-in the vertical component of the moment -M_hor = 9.10 //k-in the horizantal component of the moment -//Caliculations +M_hor = 9.10 //k-in the horizontal component of the moment +//calculations M = (((M_ver**2)+(M_hor**2))**0.5) //K-in The resultant d = ((16*(((M**2)+(T**2))**0.5)/(stress_allow_shear*3.14))**0.333) //in** The suggested diameter from derivation diff --git a/3819/CH1/EX1.15/Ex1_15.sce b/3819/CH1/EX1.15/Ex1_15.sce index b813781a2..eb5cc0d90 100644 --- a/3819/CH1/EX1.15/Ex1_15.sce +++ b/3819/CH1/EX1.15/Ex1_15.sce @@ -7,12 +7,13 @@ dist=20/100
u_vertex=120/100
visc=8.5/10
-y=poly(0,"y")
-a=poly(0,"a")
-b=poly(0,"b")
-c=poly(0,"c")
-c=2
-a=2
-b-2
-u=a*y^2+b*y+c
-s=poly(0,'s')
+//Assuming u=a*y^2+b*y+c applying all three boundary conditions , we get the y vector and velocity vector as below;
+y_vector=[0 0 1;400 20 1;40 1 0]
+vel_vector=[0;-120;0]
+[constants]=linsolve(y_vector,vel_vector)
+//1) Velocity grdient =2ay+b
+//For y=0, 10, 20 cm
+y=[0,10,20]
+du_dy=2*constants(1)*y+constants(2);
+ss=visc*du_dy;
+printf("The shear stress at y=%d,%d,%d cm are %f,%f,and %fN/m^2",y(1),y(2),y(3),ss(1),ss(2),ss(3));
diff --git a/3819/CH2/EX2.16/Ex2_16.sce b/3819/CH2/EX2.16/Ex2_16.sce index fed514567..c310ce216 100644 --- a/3819/CH2/EX2.16/Ex2_16.sce +++ b/3819/CH2/EX2.16/Ex2_16.sce @@ -12,12 +12,10 @@ dens2=sg2*1000 //calculations
pA=1*10^4*g
pB=1.8*10^4*g
-//pressure above X-X in left limb is;
-p_left=13.6*1000*g*h+dens1*g*(2+3)+pA
-p_right=dens2*g*(h+2)+pB
+//pressure above X-X in left limb is p_left=13.6*1000*g*h+dens1*g*(2+3)+pA and p_right=dens2*g*(h+2)+p
function [f]=F(h)
f=13.6*1000*g*h+dens1*g*(2+3)+pA-(dens2*g*(h+2)+pB)
endfunction
-h=10;
-h=fsolve(h,F)
+h0=10;
+h=fsolve(h0,F)
mprintf("\nTHE DIFFERENCE IN MERCURY LEVELS IS %f cm\n",h*100)
diff --git a/3819/CH3/EX3.19/Ex3_19.sce b/3819/CH3/EX3.19/Ex3_19.sce index 790f78ed9..1fd7b5dd8 100644 --- a/3819/CH3/EX3.19/Ex3_19.sce +++ b/3819/CH3/EX3.19/Ex3_19.sce @@ -1,24 +1,22 @@ // A Textbook of Fluid Mecahnics and Hydraulic Machines - By R K Bansal
// Chapter 3-Hydrostatic Forces on surfaces
// Problem 3.19
-
//Data given in the Problem
-theta=60
-AC=h/sin(theta*%pi/180)
-s=sin(theta/180*%pi)
-h=poly(0,"h")
-H=h/2
-b=1
-d=AC
-A=AC
-IG=b*d^3/12
+theta=60;
+s=sin(theta/180*%pi);
+hh=poly(0,"hh");
+AC=hh/s;
+H=hh/2;
+b=1;
+d=AC;
+IG=b*d^3/12;
//COP=(IG/(A*H)+H)
//COP=(h/sin(theta/180*%pi)^3/12/(h/sin(theta*%pi/180)/(h/2)+h/2
//We know that COP is equal to (h-3),THAT IS ,the depth of centre of pressure
//hence
-function f=F(h)
-f=((h/s)^3/12*s^2/(h/s*h/2))+(h/2)-(h-3);
+function f=F(hh)
+f=((hh/s)^3/12*s^2/(hh/s*hh/2))+(hh/2)-(hh-3);
endfunction
-h=100;
-y=fsolve(h,F)
-mprintf("The height of wahter for tipping the gate is %f m",y)
+hh=100;
+y=fsolve(hh,F);
+mprintf("The height of water for tipping the gate is %f m",y)
diff --git a/3819/CH3/EX3.3/Ex3_3.sce b/3819/CH3/EX3.3/Ex3_3.sce index 77c07a745..1828a98fa 100644 --- a/3819/CH3/EX3.3/Ex3_3.sce +++ b/3819/CH3/EX3.3/Ex3_3.sce @@ -3,19 +3,12 @@ // Problem 3.3
//Data given in the Problem
-//d=depth
-//d=width
-//Centroid is 'p' metres below
-b=poly(0,"b")
-d=poly(0,"d")
-p=poly(0,"p")
+//depth of gate=d m
+//width of gate=b m
+//depth of CG from surface=p m
-//Proof
-h=p //Depth of COP from the surface
-I_G=horner(b,d)
-I_G=b*d^2/12
-A=horner(b,d)
-A=b*d //Area
-H=horner(I_G,A,h))
-H=I_G/(A*h)+h //H is the depth of the centre of the pressure from the free surface
-mprintf("The depth of the COP from free surface is found to be %p",H)
+//solution:
+//Depth of COP from free surface=(I/(A*h_CG))+h_gate
+//Since I=(b*d^3)/12;
+//h_COP=(b*d^3/12/b/d/p)+p=d^2/12+p
+disp("The depth of centre of pressure from free surface is (d^2/12)+p ")
diff --git a/3819/CH3/EX3.4/Ex3_4.sce b/3819/CH3/EX3.4/Ex3_4.sce index 63fc40385..e2f7a0b8a 100644 --- a/3819/CH3/EX3.4/Ex3_4.sce +++ b/3819/CH3/EX3.4/Ex3_4.sce @@ -7,11 +7,11 @@ d=3 A=%pi*d^2/4
h=4
g=9.81
-
+dens=1000
//Calculations
//1)Force on disc
F=dens*g*A*h
-mprintf("The force on the disc is %f kN\n",10^-3*F)
+mprintf("The Force on the disc is %f kN\n",10^-3*F)
//2)Torque required
IG=%pi/64*d^4
diff --git a/3841/CH8/EX8.28.2/Ex8_2.sce b/3841/CH8/EX8.28.2/Ex8_2.sce deleted file mode 100644 index f778ba349..000000000 --- a/3841/CH8/EX8.28.2/Ex8_2.sce +++ /dev/null @@ -1,10 +0,0 @@ -clear -//given -// -//find the piston speed of enigne running -N=1200. -x=5**(0.5) -y=4**(0.5) -//setting equations -Ps=(N*x)/(6.) -printf("\n \n piston speed %.2f ft",Ps*2.46) diff --git a/3841/CH8/EX8.28.28.2/Ex8_2.sce b/3841/CH8/EX8.28.28.2/Ex8_2.sce deleted file mode 100644 index f778ba349..000000000 --- a/3841/CH8/EX8.28.28.2/Ex8_2.sce +++ /dev/null @@ -1,10 +0,0 @@ -clear -//given -// -//find the piston speed of enigne running -N=1200. -x=5**(0.5) -y=4**(0.5) -//setting equations -Ps=(N*x)/(6.) -printf("\n \n piston speed %.2f ft",Ps*2.46) diff --git a/3843/CH3/EX3.3/Ex3_7.sce b/3843/CH3/EX3.3/Ex3_7.sce deleted file mode 100644 index db644a72e..000000000 --- a/3843/CH3/EX3.3/Ex3_7.sce +++ /dev/null @@ -1,20 +0,0 @@ -// Example 3_7
-clc;funcprot(0);
-// Given data
-d=50*10^-3;// The distance in m
-K=2500;// N/m
-m=50;// kg
-d_p=10/100;// m
-P_atm=100;// The atmospheric pressure in kPa
-g=9.81;// m/s^2
-
-// Calculation
-W=m*g;// The weight in N
-A=(%pi*d_p^2)/4;// m^2
-P_1=((P_atm*10^3*A)+W)/A;// The pressure in the cylinder in Pa
-W_1=(P_1*A)*d;// J
-x_1=0;// m
-x_2=d;// m
-W_2=(1/2)*K*((x_2^2)-(x_1^2));// The work required to compress in J
-W_total=W_1+W_2;// The total work in J
-printf("\nThe total work,W_total=%2.2f J",W_total);
diff --git a/3843/CH4/EX4.9/Ex4_9.sce b/3843/CH4/EX4.9/Ex4_9.sce index 32dcb3fff..5aa74f3f9 100644 --- a/3843/CH4/EX4.9/Ex4_9.sce +++ b/3843/CH4/EX4.9/Ex4_9.sce @@ -20,3 +20,4 @@ v_2=v_1;// m^3/kg u_2=((0.6203-0.6181)/(0.6181-0.5601))*(3661-3476);// kJ/kg
Q=m*(u_2-u_1);// kJ
printf("\nThe heat transfer,Q=%4.0f kJ",Q);
+// The answer provided in the textbook is wrong
diff --git a/3845/CH11/EX11.8/Ex11_8.sce b/3845/CH11/EX11.8/Ex11_8.sce index b6e117260..7af6434d3 100644 --- a/3845/CH11/EX11.8/Ex11_8.sce +++ b/3845/CH11/EX11.8/Ex11_8.sce @@ -10,7 +10,7 @@ w_w=m_w*g;//Weight of water displaced (N) F_B=w_w;//Buoyant force (N)
printf('a.Buoyant force = %0.1e N',F_B)
-V_w1=1*10^5;//Volume of water displaced
+V_w1=1*10^5;//Volume of water displaced (m^3)
m_w1=rho_w*V_w1;//Mass of water displaced (kg)
w_w1=m_w1*g;//Weight of water displaced (N)
F_B1=w_w1;//Buoyant force (N)
diff --git a/3845/CH13/EX13.6/Ex13_6.sce b/3845/CH13/EX13.6/Ex13_6.sce index 30e1f2c2e..344ad031d 100644 --- a/3845/CH13/EX13.6/Ex13_6.sce +++ b/3845/CH13/EX13.6/Ex13_6.sce @@ -4,7 +4,7 @@ T_0=T_0+273;//Initial temperature (K) T_f=35;//Final temperature (C)
T_f=T_f+273;//Final temperature (K)
P_0=7*10^5;//Initial pressure (Pa)
-P_f=P_0*T_f/T_0;//Final presssure (after derivation)(Pa)
+P_f=P_0*T_f/T_0;//Final pressure (after derivation)(Pa)
printf('Pressure after temperature rise = %0.2e Pa',P_f)
//Openstax - College Physics
//Download for free at http://cnx.org/content/col11406/latest
diff --git a/3856/CH11/EX11.5/Ex11_5.sce b/3856/CH11/EX11.5/Ex11_5.sce index 150d241e3..751cef6e4 100644 --- a/3856/CH11/EX11.5/Ex11_5.sce +++ b/3856/CH11/EX11.5/Ex11_5.sce @@ -1,3 +1,4 @@ +
//Describe how you would prepare a phosphate buffer with a pH of seven point four
//Example 11.5
@@ -6,21 +7,21 @@ clc; clear;
-Ka1=7.5*10^-3; //Equilibrium consatnt for H3PO4= H+ +H2PO4-
+Ka1=7.5*10^-3; //Equilibrium constant for H3PO4= H+ +H2PO4-
pKa1=-log10(Ka1); //minus logerithm of Ka1
-Ka2=6.2*10^-8; //Equilibrium consatnt for H2PO4-= H+ +HPO4--
+Ka2=6.2*10^-8; //Equilibrium constant for H2PO4-= H+ +HPO4--
-pKa2=-log10(Ka2); //minus logerithm of Ka2
+pKa2=-log10(Ka2); //minus logarithm of Ka2
-Ka3=4.8*10^-13; //Equilibrium consatnt for HPO4-- = H+ +PO3---
+Ka3=4.8*10^-13; //Equilibrium constant for HPO4-- = H+ +PO3---
-pKa3=-log10(Ka3); //minus logerithm of Ka3
+pKa3=-log10(Ka3); //minus logarithm of Ka3
pH=7.40; //pH of the required buffer solution
-C1=10^(pH-pKa2); //Concentratin of required solution to prepare buffer solution of pH of 7.40
+C1=10^(pH-pKa2); //Concentration of required solution to prepare buffer solution of pH of 7.40
C=C1/1.0; //Ratio of the required solution to prepare buffer solution of pH of 7.40
diff --git a/3856/CH2/EX2.1/Ex2_1.sce b/3856/CH2/EX2.1/Ex2_1.sce index 0698b6d31..e02a051e3 100644 --- a/3856/CH2/EX2.1/Ex2_1.sce +++ b/3856/CH2/EX2.1/Ex2_1.sce @@ -1,4 +1,5 @@ -//Calucate the number of oxygen molecules
+
+//Calculate the number of oxygen molecules
//Example 2.1
clc;
diff --git a/3856/CH3/EX3.2/Ex3_2.sce b/3856/CH3/EX3.2/Ex3_2.sce index 9b2c6f939..95c5b641b 100644 --- a/3856/CH3/EX3.2/Ex3_2.sce +++ b/3856/CH3/EX3.2/Ex3_2.sce @@ -1,3 +1,4 @@ +
//Calculate the Collision frequency Binary Collision Number and Mean free path of Nitrogen
//Example 3.2
@@ -28,5 +29,5 @@ printf("\nBinary collision number = %.1f*10^28 collisions cm^-3 s^-1",Z11*10^-28 lambda=Cbar/Z1; //Mean free path of Nitrogen in A/collision
-printf("\nMean free path of Nirogen = %.0f* A/collision",lambda*10^8);
+printf("\nMean free path of Nitrogen = %.0f* A/collision",lambda*10^8);
diff --git a/3856/CH4/EX4.3/Ex4_3.sce b/3856/CH4/EX4.3/Ex4_3.sce index 68096b6b5..e98e95874 100644 --- a/3856/CH4/EX4.3/Ex4_3.sce +++ b/3856/CH4/EX4.3/Ex4_3.sce @@ -1,3 +1,4 @@ +
//Calculate the value of change in Internal energy and change in Enthalpy for the combution of Benzoic acid
//Example 4.3
@@ -20,7 +21,7 @@ m=0.4089; //Mass of sample of Benzoic acid in g delU=-(C*delT*M)/(m*1000); //Change in Enternal enegy in kJ mol^-1
-printf("Change in Enternal energy = %.0f kJ mol^-1",delU);(The answer vary due to round off error)
+printf("Change in Internal energy = %.0f kJ mol^-1",delU);//(The answer vary due to round off error)
R=8.314; //Gas constant in J K^-1 mol^-1
diff --git a/3856/CH4/EX4.3/Ex4_3.txt b/3856/CH4/EX4.3/Ex4_3.txt index e78d682c7..6340e6b26 100644 --- a/3856/CH4/EX4.3/Ex4_3.txt +++ b/3856/CH4/EX4.3/Ex4_3.txt @@ -1,2 +1,3 @@ - Change in Enternal energy = -3225 kJ mol^-1
+ + Change in Internal energy = -3225 kJ mol^-1
Change in Enthalpy = -3226 kJ mol^-1
\ No newline at end of file diff --git a/3856/CH5/EX5.6/Ex5_6.sce b/3856/CH5/EX5.6/Ex5_6.sce index ae39f051f..63838ea4f 100644 --- a/3856/CH5/EX5.6/Ex5_6.sce +++ b/3856/CH5/EX5.6/Ex5_6.sce @@ -1,4 +1,5 @@ -//Calculate the Increase in Entropy at consant pressure
+
+//Calculate the Increase in Entropy at constant pressure
//Example 5.6
@@ -12,7 +13,7 @@ M=18.02; //Molar mass of water in g mol^-1 n=m/M; //Number of moles of water present in mol
-t1=10; //Initial temperature of water in degree celcious
+t1=10; //Initial temperature of water in degree Celius
T1=10+273; //Initial temperature of water in K
@@ -20,8 +21,8 @@ t2=20; //Final temperature of water in degree celcious T2=20+273; //Final temperature of water in K
-delCpbar=75.3; //Molar heat capacity of water at consant pressure in J K^-1
+delCpbar=75.3; //Molar heat capacity of water at constant pressure in J K^-1
-delS=(n*delCpbar)*log(T2/T1); //Encrease in Entropy at constant pressure in J K^-1
+delS=(n*delCpbar)*log(T2/T1); //Increase in Entropy at constant pressure in J K^-1
printf("Encrease in Entropy = %.1f J K^-1",delS);
diff --git a/3856/CH8/EX8.8/Ex8_8.sce b/3856/CH8/EX8.8/Ex8_8.sce index 3f3aa9453..bc7df7837 100644 --- a/3856/CH8/EX8.8/Ex8_8.sce +++ b/3856/CH8/EX8.8/Ex8_8.sce @@ -1,3 +1,4 @@ +
//Write Expression for the activities of Pottasium Chloride Sodium Chromate and Aluminium sulphate
//Example 8.8
@@ -12,11 +13,11 @@ vneg1=1; //Number of anion of KCl v1=vpos1+vneg1; //Total number of ions of KCl
-m1=(1*vpos1*1*vneg1)^1/v1; //Mean ionic molality of KCl
+m1=(1*vpos1+1*vneg1)*(1/v1); //Mean ionic molality of KCl
a1=m1; //Mean ionic activity ofelectrolyte
-printf("mu KCl = ",a1);
+printf("mu KCl = %f ",a1);
printf("(m^%.1f)",v1);
diff --git a/3856/CH8/EX8.8/Ex8_8.txt b/3856/CH8/EX8.8/Ex8_8.txt index a42d58327..cb968087f 100644 --- a/3856/CH8/EX8.8/Ex8_8.txt +++ b/3856/CH8/EX8.8/Ex8_8.txt @@ -1,3 +1,4 @@ - mu KCl = (m^2.0)*(gamma^2.0)
+ + mu KCl = 1.000 (m^2.0)*(gamma^2.0)
mu Na2CrO4 = 4*(m^3.000000)*(gamma^3.0)
mu Al2(SO4)3 = 108*(m^5.0)*(gamma^5.0)
\ No newline at end of file diff --git a/3866/CH1/EX2.1/Ex2_1.sce b/3866/CH1/EX2.1/Ex2_1.sce deleted file mode 100644 index 122fa491e..000000000 --- a/3866/CH1/EX2.1/Ex2_1.sce +++ /dev/null @@ -1,9 +0,0 @@ -clear; close; clc;
-
-kc=1.380*(10^(-23));//constant
-te=300;//room_temp_in_kelvin
-qe=1.602*(10^(-19));//electron_charge
-ni=1.45*(10^10);
-p=3*(10^17);
-deg=2*kc*te*abs(log(ni/p))/qe;
-disp(deg,'degree of band bending(in volt):');
diff --git a/3873/CH1/EX1.1/Ex2_1.sce b/3873/CH1/EX1.1/Ex2_1.sce deleted file mode 100644 index 8a8a52897..000000000 --- a/3873/CH1/EX1.1/Ex2_1.sce +++ /dev/null @@ -1,18 +0,0 @@ -errcatch(-1,"stop");mode(2);// A Textbook of Fluid Mecahnics and Hydraulic Machines - By R K Bansal
-// Chapter 2 - Pressure and its measurements
-// Problem 2.1
-
-//Given Data Set in the Problem
-D=30/100
-d=4.5/100
-F=500
-
-//Calculations
-A_ram=%pi/4*D^2 //Area of ram
-A_plunger=%pi/4*d^2 //Area pof plunger
-P_plunger=F/A_plunger
- //Pressure is transmitted equally in all directions ,thus,
-W_ram=P_plunger*A_ram
-mprintf("The Weight of the ram is %f kN",W_ram/1000);
- -exit(); diff --git a/3875/CH1/EX1.1/1_1.txt b/3875/CH1/EX1.1/1_1.txt index 6d1ee2ec9..8b15a9380 100644 --- a/3875/CH1/EX1.1/1_1.txt +++ b/3875/CH1/EX1.1/1_1.txt @@ -1,2 +1,2 @@ -Resistive force = 2.31e-03 newton/s/meter
+Resistive force = 2.31e-03 newton-s/meter
Relaxation time = 86.56 s
\ No newline at end of file diff --git a/3875/CH1/EX1.1/Ex1_1.sce b/3875/CH1/EX1.1/Ex1_1.sce index c20e0ced8..e017a533a 100644 --- a/3875/CH1/EX1.1/Ex1_1.sce +++ b/3875/CH1/EX1.1/Ex1_1.sce @@ -9,5 +9,5 @@ damp_omega=log(2)/60 //amplitude of damped oscillator for A/C = 1/2 in rad/s c= 2*m*damp_omega
tau= 1/damp_omega
-mprintf("Resistive force = %0.2e newton/s/meter \n",c)
+mprintf("Resistive force = %0.2e newton-s/meter \n",c)
mprintf("Relaxation time = %2.2f s",tau) //The answer provided in the textbook is wrong.
diff --git a/3875/CH1/EX1.2/Ex1_2.sce b/3875/CH1/EX1.2/Ex1_2.sce index 44e020473..c8b805dbc 100644 --- a/3875/CH1/EX1.2/Ex1_2.sce +++ b/3875/CH1/EX1.2/Ex1_2.sce @@ -12,20 +12,20 @@ c=m*2*damp_omega omega_n=sqrt(K/m)
//for (c)
-damping_ratio=damp_omega/omega_n
-Q=1/(2*damping_ratio)
-omega_d=omega_n*sqrt(1-damping_ratio^2) //in radian/s
+eta=damp_omega/omega_n
+Q=1/(2*eta)
+omega_d=omega_n*sqrt(1-eta^2) //in radian/s
//for (d)
-fract_change=0.5*(damping_ratio^2) //fractional change in frequency
+fract_change=0.5*(eta^2) //fractional change in frequency
percent_change=fract_change*(10^2)
mprintf("\n(a)\n")
-mprintf("Resistive force constant c = %.0e newton/s/meter\n",c)
+mprintf("Resistive force constant c = %.0e newton-s/meter\n",c)
mprintf("(b)\n")
mprintf("Natural angular frequency omega_n = %d rad/s\n",omega_n)
mprintf("(c)\n")
-mprintf("Damping ratio damping_ratio = %.0e\n",damping_ratio)
+mprintf("Damping ratio eta = %.0e\n",eta)
mprintf("Q factor = %d\n",Q)
mprintf("(d)\n")
mprintf("percent change in frequency = %.0e\n",percent_change)
diff --git a/3875/CH1/EX1.5/1_5.txt b/3875/CH1/EX1.5/1_5.txt index 7f12ea8f5..e6a92eb5e 100644 --- a/3875/CH1/EX1.5/1_5.txt +++ b/3875/CH1/EX1.5/1_5.txt @@ -1,2 +1,2 @@ Resistance is = 19 ohm
-Capacitance is = 3.33e-05 F
+Capacitance is = 33.3 mF
diff --git a/3875/CH1/EX1.5/Ex1_5.sce b/3875/CH1/EX1.5/Ex1_5.sce index 95bf614ca..e40506873 100644 --- a/3875/CH1/EX1.5/Ex1_5.sce +++ b/3875/CH1/EX1.5/Ex1_5.sce @@ -14,4 +14,4 @@ L_omega=L*omega //in ohm C=1/((L_omega-R)*omega)
mprintf("Resistance is = %d ohm\n",R) //The answers vary due to round off error
-mprintf("Capacitance is = %2.2e F\n",C)
+mprintf("Capacitance is = %2.1f mF\n",C/10^-6) //converting from F to mF dividing by 10^-6
diff --git a/3875/CH1/EX1.7/1_7.txt b/3875/CH1/EX1.7/1_7.txt index f4d6f09b8..a1371ee47 100644 --- a/3875/CH1/EX1.7/1_7.txt +++ b/3875/CH1/EX1.7/1_7.txt @@ -1,5 +1,5 @@ -(i)Impedance = 12.4 ohm
+ (i)Impedance = 12.4 ohm
(ii)Current = 19.41 A
-(iii)Power Factor = 0.65 (Lead)
+(iii)Power Factor = 0.65 (lag)
(iv)Power Consumed = 3015 W
-(v)The value of capacitance is = 0.000169 F or 169 micro-F
+(v)The value of capacitance is = 168 mF
diff --git a/3875/CH1/EX1.7/Ex1_7.sce b/3875/CH1/EX1.7/Ex1_7.sce index a567e7324..2c8a1f3b9 100644 --- a/3875/CH1/EX1.7/Ex1_7.sce +++ b/3875/CH1/EX1.7/Ex1_7.sce @@ -21,6 +21,6 @@ C=1/(omega*reactance_C) mprintf("(i)Impedance = %2.1f ohm\n",Z) //The answer varies due to round off error
mprintf("(ii)Current = %1.2f A\n",I) //The answers varies due to round off error
-mprintf("(iii)Power Factor = %1.2f (Lead)\n",pf)
+mprintf("(iii)Power Factor = %1.2f (lag)\n",pf)
mprintf("(iv)Power Consumed = %d W\n",P) //The provided in the textbook is wrong.
-mprintf("(v)The value of capacitance is = %f F or 169 micro-F\n",C)
+mprintf("(v)The value of capacitance is = %d mF\n",C/10^-6)//The answers varies due to round off error
diff --git a/3875/CH1/EX1.9/1_9.txt b/3875/CH1/EX1.9/1_9.txt index 8c60f25c0..d260f74f6 100644 --- a/3875/CH1/EX1.9/1_9.txt +++ b/3875/CH1/EX1.9/1_9.txt @@ -1,3 +1,3 @@ -(a) The capacitance of the circuit is 8e-06 F
+(a) The capacitance of the circuit is 8 microF
(b) The value of current is = 0.3 A
\ No newline at end of file diff --git a/3875/CH1/EX1.9/Ex1_9.sce b/3875/CH1/EX1.9/Ex1_9.sce index 7ac8c7fff..dab401ed1 100644 --- a/3875/CH1/EX1.9/Ex1_9.sce +++ b/3875/CH1/EX1.9/Ex1_9.sce @@ -11,7 +11,7 @@ inductance_l=2*%pi*f*L //in ohm Z=sqrt(R^2+inductance_l^2) //in ohm
C=L/Z^2
-mprintf("\n(a) The capacitance of the circuit is %0.0e F\n",C)
+mprintf("\n(a) The capacitance of the circuit is %d microF\n",C/10^-6) //converting from F to mF dividing by 10^-6
//for(b)
diff --git a/3875/CH10/EX10.13/10_13.sce b/3875/CH10/EX10.13/10_13.sce index 366e8ace0..d926d115f 100644 --- a/3875/CH10/EX10.13/10_13.sce +++ b/3875/CH10/EX10.13/10_13.sce @@ -8,19 +8,20 @@ W=4.2 //work function in Joule c=3*10^8 //velocity of light in m/s
//calculation
-E=(h*v)/(lambda)//energy in J
+E=(h*c)/(lambda)//energy in J
E_v=E/e //energy in eV
//case (1)
+//(a)
E_k=E_v-W
-mprintf("\nThe kinetic energy of the fastest electrons is = %d eV\n",E_k)
+mprintf("The kinetic energy of the fastest electrons is = %d eV\n",E_k)
+
+//(b)
+mprintf("The kinetic energy of slowest electrons is zero. As the emitted electrons have all possible energies from 0 to certain maximun value is E_k = %d eV \n",E_k)
//case(2)
-mprintf("\nThe kinetic energy of slowest electrons is zero.As the emitted electrons have all possible energies from 0 to certain maximun value is E_k\n")
+mprintf("If V_s is the stopping potential then E_k=e*V_s.Since the electrons have a maximum kinetic energy of %d eV,the stopping potential is also E_k = %d eV \n",E_k,E_k)
//case(3)
-mprintf("If V_s is the stopping potential then E_k=e*V_s.Since the electrons have a maximum kinetoc energy of 2eV,the stopping potential is 2V.\n")
-
-//case(4)
lambda_0=(h*c)/(W*e)
-mprintf("The cut off wavelength for aluminium is %1.2e m",lambda_0) //The answer provided in the textbook is wrong.
+mprintf("The cut off wavelength for aluminium is %1.1e m",lambda_0)
diff --git a/3875/CH10/EX10.15/10_15.sce b/3875/CH10/EX10.15/10_15.sce index e871bae41..32babe3a3 100644 --- a/3875/CH10/EX10.15/10_15.sce +++ b/3875/CH10/EX10.15/10_15.sce @@ -1,14 +1,14 @@ clc;
clear;
-lambda1=400 //wavelength in nm
-lambda2=300 //wavelength in nm
+lambda1=400*10^-9 //wavelength in m
+lambda2=300*10^-9 //wavelength in m
V1=0.82 //stopping potential in V
V2=1.85 //stopping potential in V
c=3*10^8 //velocity of light in m/s
e=1.6*10^-19 //charge in C
//calculation
-h=(e*(V1-V2)*(lambda1*10^-9)*(lambda2*10^-9))/(c*(lambda2-lambda1)*10^-9)
+h=(e*(V1-V2)*(lambda1)*(lambda2))/(c*(lambda2-lambda1))
mprintf("\nThe Plancks constant is = %1.3e J-s\n",h)
mprintf("The photoelectric current will not be obtained as the stopping potential does not depend on the intensity of light")
diff --git a/3875/CH10/EX10.31/10_31.sce b/3875/CH10/EX10.31/10_31.sce index cfeff01cb..a3e2a4cd5 100644 --- a/3875/CH10/EX10.31/10_31.sce +++ b/3875/CH10/EX10.31/10_31.sce @@ -8,4 +8,4 @@ m=1.675*10^-27 //mass in kg p_min=h/(4*%pi*delta_x) //minimum momentum in kg-m/s
E_min=((p_min)^2/(2*m))
-mprintf("The minimum kinetic energy of the nucleon is = %1.2e J or 0.33*10^-15 J",E_min)
+mprintf("The minimum kinetic energy of the nucleon is = %0.2e J",E_min)
diff --git a/3875/CH10/EX10.9/10_9.sce b/3875/CH10/EX10.9/10_9.sce index 04a390b8f..283855b74 100644 --- a/3875/CH10/EX10.9/10_9.sce +++ b/3875/CH10/EX10.9/10_9.sce @@ -13,12 +13,12 @@ d_lambda2=1*10^-9 //range of wavelength in m //case (a) when the range of wavelength is between 1-1.1 mm
E=exp((h*c)/(lambda1*k_B*T)) //calculating the exponential term of the eqn
U_lambda1=((8*%pi*h*c*d_lambda1)/(lambda1^5*(E-1)))
-mprintf("The energy density is = %1.2e J/m^3.\n",U_lambda1)
+mprintf("The energy density for wavelength in range 1-1.1 mm is = %1.2e J/m^3.\n",U_lambda1)
//case (b) when the range of wavelength is between 100-101 nm
E1=exp((h*c)/(lambda2*k_B*T)) //calculating the exponential term of the eqn
U_lambda2=((8*%pi*h*c*d_lambda2)/(lambda2^5*(E1-1)))
-mprintf("The energy density is = %1.2e J/m^3.",U_lambda2)
+mprintf("The energy density for wavelength in range 100-101 mm is = %1.2e J/m^3.",U_lambda2)
//The answer provided in the textbook is wrong.
mprintf("\nThus for shorter wavelengths the energy densities predicted by Rayleigh-Jeans law and Planks law are considerably different while for longer wavelengths the energy densites predicted are same.")
diff --git a/3875/CH10/EX10.9/10_9.txt b/3875/CH10/EX10.9/10_9.txt index dd4ecf59d..bbdfa1efd 100644 --- a/3875/CH10/EX10.9/10_9.txt +++ b/3875/CH10/EX10.9/10_9.txt @@ -1,3 +1,3 @@ -The energy density is = 3.44e-11 J/m^3.
-The energy density is = 1.27e-60 J/m^3.
-Thus for shorter wavelengths the energy densities predicted by Rayleigh-Jeans law and Planks law are considerably different while for longer wavelengths the energy densites predicted are same.
\ No newline at end of file +The energy density for wavelength in range 1-1.1 mm is = 3.44e-11 J/m^3.
+The energy density for wavelength in range 100-101 mm is = 1.27e-60 J/m^3.
+Thus for shorter wavelengths the energy densities predicted by Rayleigh-Jeans law and Planks law are considerably different while for longer wavelengths the energy densites predicted are same.s
\ No newline at end of file diff --git a/3875/CH11/EX11.13/11_13.sce b/3875/CH11/EX11.13/11_13.sce index f6607a95f..cf6a35ac2 100644 --- a/3875/CH11/EX11.13/11_13.sce +++ b/3875/CH11/EX11.13/11_13.sce @@ -8,7 +8,7 @@ n=1 //first order reflection tetha=58 //Braggs angle in degree
//calculation
-lambda=(h/sqrt(2*m*e*V_0))
+lambda=(h/sqrt(2*m*e*V_0)) //wavelength in m
d=((n*lambda)/(2*sind(tetha)))
-mprintf("The interplanar spacing is = %1.2e m or 0.249e-10 m",d)
+mprintf("The interplanar spacing is = %1.2e m",d)
//The answer varies due to round off error.
diff --git a/3875/CH11/EX11.15/11_15.sce b/3875/CH11/EX11.15/11_15.sce index 3f4a3e518..9c20a7091 100644 --- a/3875/CH11/EX11.15/11_15.sce +++ b/3875/CH11/EX11.15/11_15.sce @@ -8,7 +8,7 @@ k=0 //lattice parameter for y axis l=0 //lattice parameter for z axis
//calculations
-sin_square_theta=sind(theta)^2
+sin_square_theta=sind(theta)^2 //angle in degrees
alpha=(lambda/2)*((h^2+k^2+l^2)/sqrt(sin_square_theta))
-mprintf("alpha = %d pm",ceil(alpha))
+mprintf("The lattice constant is alpha = %d pm",ceil(alpha))
diff --git a/3875/CH11/EX11.16/11_16.sce b/3875/CH11/EX11.16/11_16.sce index 799cd889e..35db1e508 100644 --- a/3875/CH11/EX11.16/11_16.sce +++ b/3875/CH11/EX11.16/11_16.sce @@ -6,10 +6,11 @@ theta2=29 //angle in degree h=1 //x intercept of parallel plane
k=1 //y intercept of parallel plane
l=0 //z intercept of parallel plane
+
//calculation
ratio=sind(theta1)^2/sind(theta2)^2 //ratio of sin^2 theta values of first and second angles
alpha=(lambda/2)*sqrt((sqrt(h^2+k^2+l^2))/sind(theta1)^2)
mprintf("The crystal structure is bcc since the ratio is %1.1f\n",ratio)
-mprintf("lattice constant alpha = %0.3f nm\n",alpha) // The answer provided in the textbook is wrong
-mprintf("The element is tungsten since this lattice constant of %0.3f nm and crystallizes in the bcc structure",alpha) //The answer provided in the textbook is wrong
+mprintf("The lattice constant alpha is = %0.3f nm\n",alpha) // The answer provided in the textbook is wrong
+mprintf("The element is tungsten since this lattice constant of %0.3f nm and crystallizes in the bcc structure",alpha) //The answer provided in the textbook is wrong.Since there is no predefined method to determine the element,hence we do not know the element after answer varies.
diff --git a/3875/CH11/EX11.17/11_17.sce b/3875/CH11/EX11.17/11_17.sce index 855296229..5353c3479 100644 --- a/3875/CH11/EX11.17/11_17.sce +++ b/3875/CH11/EX11.17/11_17.sce @@ -12,5 +12,5 @@ d_400=(lambda/(2*sind(theta))) //interplanar distance in nm alpha=d_400*(sqrt(h^2+k^2+l^2))
mprintf("The crystal structure is bcc due to corresponding (hkl) values\n")
-mprintf("lattice constant of peak no.1 is (110)\n")
+mprintf("lattice constant of peak no.1 is (%d%d%d)\n",h,k,l)
mprintf("The element is tungsten since this lattice constant of %0.4f nm and crystallizes in the bcc structure",alpha) //The answer provided in the textbook is wrong
diff --git a/3875/CH11/EX11.21/11_21.txt b/3875/CH11/EX11.21/11_21.txt index 3dbc1e074..84c2091af 100644 --- a/3875/CH11/EX11.21/11_21.txt +++ b/3875/CH11/EX11.21/11_21.txt @@ -1,5 +1,12 @@ -The lattice parameter is = 0.242 nm
-The lattice parameter is = 0.2960 nm
-The lattice parameters are not equal,hence metal is not bcc
-We assume that the metal is fcc,lattice parameter is consistent at value=0.296 nm
+The lattice parameter for Bragg reflections from plane 110 is = 0.242 nm
+
+The lattice parameter for Bragg reflections from plane 200 is = 0.296 nm
+
+The lattice parameters 0.242 nm and 0.296 nm are not equal,hence metal is not bcc.
+
+The lattice parameter for Bragg reflections from plane 111 is = 0.296 nm
+
+The lattice parameter for Bragg reflections from plane 200 is = 0.296 nm
+
+The lattice parameters 0.296 nm and 0.296 nm are equal,hence metal is fcc.
The atomic diameter is = 0.2093 nm
\ No newline at end of file diff --git a/3875/CH11/EX11.21/Ex11_21.sce b/3875/CH11/EX11.21/Ex11_21.sce index 79417d726..59b22ab07 100644 --- a/3875/CH11/EX11.21/Ex11_21.sce +++ b/3875/CH11/EX11.21/Ex11_21.sce @@ -4,28 +4,47 @@ lambda=0.171 //wavelength of X-ray in nm tetha_1=30 //Braggs angle in degree
tetha_2_degrees=35 //part of Braggs angle in degrees
tetha_2_minutes=17 //part of Braggs angle in minutes
+
+//calculation
+//case(1)((Assuming metal is bcc for plane 111))
h=1 //x intercept of the parallel plane
k=1 //y intercept of the parallel plane
l=0 //z intercept of the parallel plane
+d1_110=lambda/(2*sind(tetha_1)) //distance in nm
+a1=d1_110*sqrt(h^2+k^2+l^2)
+mprintf("The lattice parameter for Bragg reflections from plane %d%d%d is = %1.3f nm\n",h,k,l,a1)
+
+//case(2)(Assuming metal is bcc for plane 200)
+h=2 //x intercept of the parallel plane
+k=0 //y intercept of the parallel plane
+l=0 //z intercept of the parallel plane
+tetha_2_decdeg=tetha_2_degrees+(tetha_2_minutes/60)
+d1_200=lambda/(2*sind(tetha_2_decdeg))
+a2=d1_200*sqrt(h^2+k^2+l^2)
+mprintf("The lattice parameter for Bragg reflections from plane %d%d%d is = %1.3f nm\n",h,k,l,a2)
+mprintf("The lattice parameters %1.3f nm and %1.3f nm are not equal,hence metal is not bcc.\n",a1,a2)
+
+
+//case(3)(Assuming metal is fcc for plane 111)
+h=1 //x intercept of the parallel plane
+k=1 //y intercept of the parallel plane
+l=1 //z intercept of the parallel plane
+d2_111=lambda/(2*sind(tetha_1))
+a3=d2_111*sqrt(h^2+k^2+l^2)
+mprintf("The lattice parameter for Bragg reflections from plane %d%d%d is = %1.3f nm\n",h,k,l,a3)
-//calculation
-//case(A)
-d_110=lambda/(2*sind(tetha_1))
-a=d_110*sqrt(h^2+k^2+l^2)
-mprintf("The lattice parameter is = %1.3f nm\n",a)
-//case(B)
+//case(4)(Assuming metal is fcc for plane 222)
h=2 //x intercept of the parallel plane
k=0 //y intercept of the parallel plane
l=0 //z intercept of the parallel plane
tetha_2_decdeg=tetha_2_degrees+(tetha_2_minutes/60)
-d_110=lambda/(2*sind(tetha_2_decdeg))
-a=d_110*sqrt(h^2+k^2+l^2)
-mprintf("The lattice parameter is = %1.4f nm\n",a)
-mprintf("The lattice parameters are not equal,hence metal is not bcc\n")
-mprintf("We assume that the metal is fcc,lattice parameter is consistent at value=0.296 nm\n") //by multiplying d_110 by sqrt(3) and d_200 by sqrt(4)
+d2_200=lambda/(2*sind(tetha_2_decdeg))
+a4=d2_200*sqrt(h^2+k^2+l^2)
+mprintf("The lattice parameter for Bragg reflections from plane %d%d%d is = %1.3f nm\n",h,k,l,a4)
+mprintf("The lattice parameters %1.3f nm and %1.3f nm are equal,hence metal is fcc.\n",a3,a4)
//for atomice diameter we have
-a=0.296 //lattice parameter in nm
-D=a/sqrt(2)
+a3=0.296 //lattice parameter in nm
+D=a3/sqrt(2) //since a3 and a4 are the same values
mprintf("The atomic diameter is = %1.4f nm",D)
diff --git a/3875/CH11/EX11.22/11_22.txt b/3875/CH11/EX11.22/11_22.txt index 719ecb5b0..3ffcc2d31 100644 --- a/3875/CH11/EX11.22/11_22.txt +++ b/3875/CH11/EX11.22/11_22.txt @@ -1,3 +1,3 @@ -The sum total of the intercepts of the parallel plane h^2+k^2+l^2 should be less than 13.988
-The highest possible values of hkl are (222) as the sum total of h^2+k^2+l^2 is less than or equal to 13.98.
+The sum total of the intercepts of the parallel plane h^2+k^2+l^2 should be less than 13.99
+The highest possible values of hkl are (222) as the sum total of h^2+k^2+l^2 is less than or equal to 13.99
Braggs reflection will occur from the first planes including (222)
\ No newline at end of file diff --git a/3875/CH11/EX11.22/Ex11_22.sce b/3875/CH11/EX11.22/Ex11_22.sce index 59593c68b..e4be3d620 100644 --- a/3875/CH11/EX11.22/Ex11_22.sce +++ b/3875/CH11/EX11.22/Ex11_22.sce @@ -6,6 +6,6 @@ D=0.2494 //diameter in D //calculation
d=lambda/2 //interplanar distance in nm
hkl_parameters=((2*D)/(d*sqrt(3)))^2
-mprintf("The sum total of the intercepts of the parallel plane h^2+k^2+l^2 should be less than %1.3f\n",hkl_parameters)
-mprintf("The highest possible values of hkl are (222) as the sum total of h^2+k^2+l^2 is less than or equal to 13.98.\n")
+mprintf("The sum total of the intercepts of the parallel plane h^2+k^2+l^2 should be less than %1.2f\n",hkl_parameters)//The answer varies dur to round off error
+mprintf("The highest possible values of hkl are (222) as the sum total of h^2+k^2+l^2 is less than or equal to %1.2f\n",hkl_parameters)//The answer varies dur to round off error
mprintf("Braggs reflection will occur from the first planes including (222)")
diff --git a/3875/CH11/EX11.3/11_3.sce b/3875/CH11/EX11.3/11_3.sce index d3e675c34..289afcab9 100644 --- a/3875/CH11/EX11.3/11_3.sce +++ b/3875/CH11/EX11.3/11_3.sce @@ -5,13 +5,18 @@ tetha=45 //glancing angle in degree //calculation
//case(1) when intensity maxima is 3
-n=3
-lambda=(2*d*sind(tetha))/n
-mprintf("\nThe wavelength is = %1.3f pm\n",lambda)
+n1=3
+lambda=(2*d*sind(tetha))/n1
+disp("case (1)")
+mprintf("The wavelength for n = %d is = %d pm\n",n1,ceil(lambda))
//case(2) when intensity maxima is 4
-n=4
-lambda=(2*d*sind(tetha))/n
-mprintf("The wavelength is = %1.3f pm",lambda)
-mprintf("Only for n=3 and n=4,the value of lambda lies within the range 95 pm to 140 pm")
-//The answer varies due to round off error.
+n2=4
+lambda=(2*d*sind(tetha))/n2
+disp("case (2)")
+mprintf("The wavelength for n = %d is = %1.1f pm\n",n2,lambda)
+////The answer varies due to round off error.
+
+
+mprintf("Only for n=%d and n=%d,the value of lambda lies within the range 95 pm to 140 pm. Hence Bragg reflections are observed only for these two wavelengths",n1,n2)
+
diff --git a/3875/CH12/EX12.3/Ex12_3.sce b/3875/CH12/EX12.3/Ex12_3.sce index bba9994ea..e81e4e45c 100644 --- a/3875/CH12/EX12.3/Ex12_3.sce +++ b/3875/CH12/EX12.3/Ex12_3.sce @@ -6,5 +6,5 @@ h=6.63*10^-34 //Plancks constant in J-s //calculation
delta_p=h/(4*%pi*delta_x)
-mprintf("The uncertainity in momentum of the electron is = %1.2e kgms^-1",delta_p)
+mprintf("The uncertainity in momentum of the electron is greater than or equal to %1.1e kgms^-1",delta_p)
//The answer provided in the textbook is wrong.
diff --git a/3875/CH12/EX12.6/Ex12_6.sce b/3875/CH12/EX12.6/Ex12_6.sce index 62e884fe1..9dff0194b 100644 --- a/3875/CH12/EX12.6/Ex12_6.sce +++ b/3875/CH12/EX12.6/Ex12_6.sce @@ -8,7 +8,7 @@ alpha=0.3*10^-9 //width of potental barrier in m e=1.6*10^-19 //charge in C
//calculation
-Gamma=((sqrt(2*m*(V_0-E)))*1.6*10^-19)/h //in m^-1
-T=(16*E*(V_0-E)*exp(-2*Gamma*alpha))/V_0^2
-mprintf("The tunneling probability is = %1.2f",T)
+Gamma=(2*%pi*(sqrt(2*m*(V_0-E)))*e)/h //in m^-1
+T=((16*E*(V_0-E)/V_0^2)*exp(-2*(Gamma)*alpha))
+mprintf("The tunneling probability is = %1.2e",T)
//The answer provided in the textbook is wrong.
diff --git a/3875/CH2/EX2.1/2_1.txt b/3875/CH2/EX2.1/2_1.txt index 0dbba33b7..254c90fc4 100644 --- a/3875/CH2/EX2.1/2_1.txt +++ b/3875/CH2/EX2.1/2_1.txt @@ -1 +1 @@ - Total absorption in hall = 1012.5 m^2 sabine
\ No newline at end of file +Total absorption in hall = 1012.5 sq-m sabine
\ No newline at end of file diff --git a/3875/CH2/EX2.1/Ex2_1.sce b/3875/CH2/EX2.1/Ex2_1.sce index 031f10443..46a43a15e 100644 --- a/3875/CH2/EX2.1/Ex2_1.sce +++ b/3875/CH2/EX2.1/Ex2_1.sce @@ -6,4 +6,4 @@ T=1.2 //time in seconds //calculations
A=(0.162*V)/T
-mprintf("Total absorption in hall = %0.1f m^2 sabine",A)
+mprintf("Total absorption in hall = %0.1f sq-m sabine",A)
diff --git a/3875/CH2/EX2.2/Ex2_2.sce b/3875/CH2/EX2.2/Ex2_2.sce index 824d5b8c8..7eeae716b 100644 --- a/3875/CH2/EX2.2/Ex2_2.sce +++ b/3875/CH2/EX2.2/Ex2_2.sce @@ -19,21 +19,21 @@ c_Audience=0.4367 -//calcultion
-Absorption_plastered_wall=Area_plastered_wall*c_plastered_wall //in m^2 sabine
-Absorption_wooden_floor=Area_woodem_floor*c_woodem_floor //in m^2 sabine
-Absorption_plastered_ceiling=Area_plastered_ceiling*c_plastered_ceiling //in m^2 sabine
-Absorption_wooden_doors=Area_wooden_doors*c_wooden_doors //in m^2 sabine
-Absorption_cushioned_chairs=Area_cushioned_chairs*c_cushioned_chairs //in m^2 sabine
-Total_absorption1 = Absorption_plastered_wall+Absorption_wooden_floor+Absorption_plastered_ceiling+Absorption_wooden_doors+Absorption_cushioned_chairs //in m^2 sabine
+//calculation
+Abs_plastered_wall=Area_plastered_wall*c_plastered_wall //in m^2 sabine
+Abs_wooden_floor=Area_woodem_floor*c_woodem_floor //in m^2 sabine
+Abs_plastered_ceiling=Area_plastered_ceiling*c_plastered_ceiling //in m^2 sabine
+Abs_wooden_doors=Area_wooden_doors*c_wooden_doors //in m^2 sabine
+Abs_cushioned_chairs=Area_cushioned_chairs*c_cushioned_chairs //in m^2 sabine
+Total_absorption1 = Abs_plastered_wall+Abs_wooden_floor+Abs_plastered_ceiling+Abs_wooden_doors+Abs_cushioned_chairs //in m^2 sabine
//Case (i)
T1=(0.162*V)/Total_absorption1
//case (ii)
-Absorption_Audience=Area_Audience*c_Audience //in m^2 sabine when hall at full capacity
-Total_absorption2 = Absorption_plastered_wall+Absorption_wooden_floor+Absorption_plastered_ceiling+Absorption_wooden_doors+Absorption_cushioned_chairs+Absorption_Audience //in m^2 sabine
+Abs_Audience=Area_Audience*c_Audience //in m^2 sabine when hall at full capacity
+Total_absorption2 = Abs_plastered_wall+Abs_wooden_floor+Abs_plastered_ceiling+Abs_wooden_doors+Abs_cushioned_chairs+Abs_Audience //in m^2 sabine
T2=(0.162*V)/Total_absorption2
-mprintf("Reveberation time when hall empty = %1.2f s\n",T1)
-mprintf("Reveberation time when hall at full capacity = %1.2f s",T2) //The answer provided in the textbook is wrong
+mprintf("Reverbertion time when hall empty = %1.2f s\n",T1)
+mprintf("Reverbertion time when hall at full capacity = %1.2f s",T2) //The answer provided in the textbook is wrong
diff --git a/3875/CH2/EX2.3/Ex2_3.sce b/3875/CH2/EX2.3/Ex2_3.sce index c05390b85..4cd85a417 100644 --- a/3875/CH2/EX2.3/Ex2_3.sce +++ b/3875/CH2/EX2.3/Ex2_3.sce @@ -13,7 +13,7 @@ c_floor=0.06 //Value given in the sum is wrong which is 0.60 c_seat=0.64
-//calcultion
+//calculation
A1=2*((b*h)+(l*h))*c_wall //in m^2
A2=(l*b)*c_ceiling //in m^2
A3=(l*b)*c_floor //in m^2
diff --git a/3875/CH4/EX4.14/4_13.txt b/3875/CH4/EX4.14/4_13.txt deleted file mode 100644 index 55b42f247..000000000 --- a/3875/CH4/EX4.14/4_13.txt +++ /dev/null @@ -1 +0,0 @@ -The refractive index of oil is = 1.375
\ No newline at end of file diff --git a/3875/CH4/EX4.14/Ex4_13.sce b/3875/CH4/EX4.14/Ex4_13.sce deleted file mode 100644 index 697284dfd..000000000 --- a/3875/CH4/EX4.14/Ex4_13.sce +++ /dev/null @@ -1,13 +0,0 @@ -clc;
-clear;
-vol=0.2 //volume of a drop of oil in cubic centimeter
-area=100*100 //area in cm^2
-lambda=5.5*10^-5 //wavelength in m
-r=0 //angle of incidence in degree
-n=1 //number of dark band
-
-//calculation
-d=vol/area //thickness of the film of oil in cm
-myu=(n*lambda)/(2*d*cosd(0))
-
-mprintf("The refractive index of oil is = %1.3f",myu)
diff --git a/3875/CH4/EX4.16/4_16.txt b/3875/CH4/EX4.16/4_16.txt index 31d5d83cd..e8d5b6826 100644 --- a/3875/CH4/EX4.16/4_16.txt +++ b/3875/CH4/EX4.16/4_16.txt @@ -1 +1 @@ - The distance at which the 10th fringe will be obtained from the edge of the wedge is =2.85e-08 m
\ No newline at end of file + The distance at which the 10th fringe will be obtained from the edge of the wedge is = 2.85e-04 m
\ No newline at end of file diff --git a/3875/CH4/EX4.16/Ex4_16.sce b/3875/CH4/EX4.16/Ex4_16.sce index fca7af854..e4882cfef 100644 --- a/3875/CH4/EX4.16/Ex4_16.sce +++ b/3875/CH4/EX4.16/Ex4_16.sce @@ -5,7 +5,6 @@ lambda=6000*10^-10 //wavelength in m n=10 //the fringe observed
//calculation
-x=((2*n-1)*lambda)/4*alpha
+x=((2*n-1)*lambda)/(4*alpha)
-mprintf("The distance at which the 10th fringe will be obtained from the edge of the wedge is =%1.2e m",x)
-//The answer provided in the textbook is wrong.
+mprintf("The distance at which the 10th fringe will be obtained from the edge of the wedge is = %1.2e m",x)
diff --git a/3875/CH4/EX4.17/Ex4_17.sce b/3875/CH4/EX4.17/Ex4_17.sce index df7f1f6e7..65446a8b8 100644 --- a/3875/CH4/EX4.17/Ex4_17.sce +++ b/3875/CH4/EX4.17/Ex4_17.sce @@ -1,13 +1,14 @@ clc;
clear;
-f=4 //focal length of lens in m
+f=400 //focal length of lens in cm
myu=1.50 //refractive index
-lambda=5460*10^-10 //wavelength in m
+lambda=5460*10^-6 //wavelength in cm
n=5 //fifth bright ring
//calculation
R=(myu-1)*2*f //radius of curvature in cm
-D5=sqrt(2*(2*n-1)*lambda*R)
-mprintf("The diameter of the fifth bright ring is = %1.5f cm",D5)
+D5=sqrt(2*((2*n)-1)*lambda*R)
+
+mprintf("The diameter of the fifth bright ring is = %1.2f cm",D5)
//The answer provided in the textbook is wrong.
diff --git a/3875/CH4/EX4.20/Ex4_20.sce b/3875/CH4/EX4.20/Ex4_20.sce index d7db69871..5d462a526 100644 --- a/3875/CH4/EX4.20/Ex4_20.sce +++ b/3875/CH4/EX4.20/Ex4_20.sce @@ -3,8 +3,12 @@ clear; R=100 //radius of curvature in cm
D_5=0.3 //diameter of the 5th dark ring in cm
D_25=0.8 //diameter of the 25th dark ring in cm
-p=20 //difference in no of fringes
+n5=5 //fifth dark ring
+n25=25 //twenty fifth ring
//calculation
-lambda=(D_25^2-D_5^2)/(4*p*R)
+p = n25 - n5 //difference in no of fringes
+lambda=((D_25^2)-(D_5^2))/(4*p*R)
+
mprintf("The wavelength of light used is = %1.2e cm",lambda)
+//The answer provided in the textbook is wrong.
diff --git a/3875/CH4/EX4.21/Ex4_21.sce b/3875/CH4/EX4.21/Ex4_21.sce index e57549561..c0b88ce7f 100644 --- a/3875/CH4/EX4.21/Ex4_21.sce +++ b/3875/CH4/EX4.21/Ex4_21.sce @@ -1,9 +1,10 @@ clc;
clear;
-X2_minus_X1=0.05896*10^-3 //displacement of mirror in m
+disp_X=0.05896*10^-3 //displacement of mirror in m
n=200 //no of fringes
//calculation
-lambda=(2*X2_minus_X1)/n
+lambda=(2*disp_X)/n
+
mprintf("The wavelength of the light is = %1.3e m",lambda)
//The answer provided in the textbook is wrong.
diff --git a/3875/CH4/EX4.4/Ex4_4.sce b/3875/CH4/EX4.4/Ex4_4.sce index 2c723e8f2..392885aab 100644 --- a/3875/CH4/EX4.4/Ex4_4.sce +++ b/3875/CH4/EX4.4/Ex4_4.sce @@ -6,8 +6,8 @@ d1=4.05*10^-3 //distance between two images of the slit in m in first case d2=2.90*10^-3 //distance between two images of the slit in m in second case
//calculation
-d=sqrt(d1*d2)
-disp(d)
+d=sqrt(d1*d2) //distance between the slits in m
Beta=(lambda*D)/d
mprintf("The distance between interference fringes is %1.2e m",Beta)
+//The answer provided in the textbook is wrong.
diff --git a/3875/CH5/EX5.4/5_4.txt b/3875/CH5/EX5.4/5_4.txt index c7124740e..8a08b5341 100644 --- a/3875/CH5/EX5.4/5_4.txt +++ b/3875/CH5/EX5.4/5_4.txt @@ -1,2 +1,3 @@ As the total number of lines required for the just resolution in the first order is 982 and the total number of lines on the grating is 850, the lines will not be resolved
-As the total number of lines required for the just resolution in the first order is 491 and the total number of lines on the grating is 850, the lines will appear resolved in second order
\ No newline at end of file +
+As the total number of lines required is 491 and the given grating has a total of 850 lines, the lines will appear resolved in second order
diff --git a/3875/CH5/EX5.4/Ex5_4.sce b/3875/CH5/EX5.4/Ex5_4.sce index 559e5b52a..d7ea9e484 100644 --- a/3875/CH5/EX5.4/Ex5_4.sce +++ b/3875/CH5/EX5.4/Ex5_4.sce @@ -1,13 +1,15 @@ clc;
clear;
lambda=5890*10^-8 //wavelength in cm
-k1=1
-k2=2
+k1=1 //first order of wavelength
+k2=2 //second order of wavelength
N=425 // grating lines per cm
d_lambda=(5896 - 5890)*10^-8 //grating width in cm
d=2 //grating width in cm
//calculation
+Total_lines = N*2 //Total no. of lines on the grating
+
//for the first order
N1=ceil(lambda/(k1*d_lambda)) //No. of grating lines
@@ -15,5 +17,5 @@ N1=ceil(lambda/(k1*d_lambda)) //No. of grating lines N2=ceil(lambda/(k2*d_lambda)) //No. of grating lines
-printf("\nAs the total number of lines required for the just resolution in the first order is %d and the total number of lines on the grating is 850, the lines will not be resolved\n",N1)
-printf("\nAs the total number of lines required for the just resolution in the first order is %d and the total number of lines on the grating is 850, the lines will appear resolved in second order\n",N2)
+printf("\nAs the total number of lines required for the just resolution in the first order is %d and the total number of lines on the grating is %d, the lines will not be resolved\n",N1,Total_lines)
+printf("\nAs the total number of lines required is %d and the given grating has a total of %d lines, the lines will appear resolved in second order\n",N2,Total_lines)
diff --git a/3875/CH9/EX9.2/Ex9_2.sce b/3875/CH9/EX9.2/Ex9_2.sce index 68d3e7d4d..1a9d85d31 100644 --- a/3875/CH9/EX9.2/Ex9_2.sce +++ b/3875/CH9/EX9.2/Ex9_2.sce @@ -5,10 +5,11 @@ L1=2 //distance in km L2=6 //distance in km
//calculation
-//Case(a):when distance is 2km
-It_by_I0=10^-((alpha*L1)/10)
-mprintf("\nThe fraction of intial intensity that will remain after 2km is = %1.3f\n",It_by_I0)
+//Case(a):when distance L = 2km
+It_by_I0_1=10^-((alpha*L1)/10)
-//Case(b):when distance is 6km
-It_by_I0=10^-((alpha*L2)/10)
-mprintf("\nThe fraction of intial intensity that will remain after 2km is = %1.3f",It_by_I0) //The answer varies due to round off error.
+//Case(b):when distance L = 6km
+It_by_I0_2=10^-((alpha*L2)/10)
+
+mprintf("\nThe fraction of intial intensity that will remain after 2km is = %1.3f\n",It_by_I0_1) //The answer varies due to round off error.
+mprintf("\nThe fraction of intial intensity that will remain after 6km is = %1.3f",It_by_I0_2) //The answer varies due to round off error.
diff --git a/3875/CH9/EX9.5/Ex9_5.sce b/3875/CH9/EX9.5/Ex9_5.sce index 6b178a2fc..3b5210027 100644 --- a/3875/CH9/EX9.5/Ex9_5.sce +++ b/3875/CH9/EX9.5/Ex9_5.sce @@ -5,7 +5,7 @@ I_0=7.5*10^-6 //input power in Watt I_t=8.6*10^-6 //output power in Watt
//calculation
-alpha=-(10/0.5)*log10(I_0/I_t)
+alpha=-(10/L)*log10(I_0/I_t)
-mprintf("The loss specification of the fibre is = %1.1f dB/km",alpha)
+mprintf("The loss specification of the fibre is = -%1.1f dB/km",alpha)
//The answer varies dur to round off error.
diff --git a/3876/CH13/EX13.3/Ex13_3.sce b/3876/CH13/EX13.3/Ex13_3.sce index 1e0354360..99a48673b 100644 --- a/3876/CH13/EX13.3/Ex13_3.sce +++ b/3876/CH13/EX13.3/Ex13_3.sce @@ -1,3 +1,4 @@ + //Chapter 13 Thermodynamics Entropy and Free Energy clc; diff --git a/3878/CH1/EX1.8/Ex1_8.sce b/3878/CH1/EX1.8/Ex1_8.sce index d7c640331..26ba8e4cd 100644 --- a/3878/CH1/EX1.8/Ex1_8.sce +++ b/3878/CH1/EX1.8/Ex1_8.sce @@ -1,5 +1,5 @@ clear -// Variable declartion +// Variable declaration t=225// The wall thickness in mm k=0.60// Thermal conductivity in W/(m K) L=10// Length in m diff --git a/806/CH1/EX1.1/11.sce b/806/CH1/EX1.1/11.sce deleted file mode 100644 index 00e0f8766..000000000 --- a/806/CH1/EX1.1/11.sce +++ /dev/null @@ -1,14 +0,0 @@ -clc
-pathname=get_absolute_file_path('11.sce')
-filename=pathname+filesep()+'11.sci'
-exec(filename)
-diary('C:\users\Bhavesh\desktop\scilab\11.txt')
-disp("a liquid has a viscosity of 0.005kg/m.s and density of 850kg/cm^3,calculate the kinematic viscosity in (a)SI units (b)USC units and (c)viscosity in USC units")
-disp("Solution:")
-v=u/p//kinematic viscosity
-V=v*(1/.3048)^2//kinematic viscosity in USC units
-U=u/47.9//viscosity in USC units
-disp("m^2/s",v,"Kinematic viscosity in SI units=")
-disp("ft^2/s",V,"Kinematic viscosity in USC units=")
-disp("slug/ft.s",U,"viscosity in USC units")
-diary(0)
\ No newline at end of file diff --git a/806/CH1/EX1.1/11.txt b/806/CH1/EX1.1/11.txt deleted file mode 100644 index 978fca8ef..000000000 --- a/806/CH1/EX1.1/11.txt +++ /dev/null @@ -1,22 +0,0 @@ -
- a liquid has a viscosity of 0.005kg/m.s and density of 850kg/cm^3,calculate the kinematic viscosity in (a)SI units (b)USC units and (c)viscosity in USC units
-
- Solution:
-
- Kinematic viscosity in SI units=
-
- 0.0000059
-
- m^2/s
-
- Kinematic viscosity in USC units=
-
- 0.0000633
-
- ft^2/s
-
- viscosity in USC units
-
- 0.0001044
-
- slug/ft.s
diff --git a/806/CH1/EX1.2/12.sce b/806/CH1/EX1.2/12.sce deleted file mode 100644 index 310088f85..000000000 --- a/806/CH1/EX1.2/12.sce +++ /dev/null @@ -1,12 +0,0 @@ -clc
-pathname=get_absolute_file_path('12.sce')
-filename=pathname+filesep()+'12.sci'
-exec(filename)
-diary('C:\users\Bhavesh\desktop\scilab\12.txt')
-disp("A lubricated shaft rotates inside a concentric sleeve bearing at 1200rpm,the clearance is smaal with respect to the radius and hence a linear distribution velocity distribution may be assumed.What are the power requirements to rotate the shaft?R=2cm , L=6cm , dy=0.1mm , and u=0.2N.s/m^2.")
-disp("Solution:")
-t=u*du/dy*2*%pi/60*R*1000/100//shear stress in N/m^2
-T=t*2*%pi*R*L*R/1000000//torque in Nm
-P=T*du*2*%pi/60//Power in Watts
-disp("W",P,"Power required to rotate the shaft =")
-diary(0)
\ No newline at end of file diff --git a/806/CH1/EX1.2/12.txt b/806/CH1/EX1.2/12.txt deleted file mode 100644 index 5a0ff5871..000000000 --- a/806/CH1/EX1.2/12.txt +++ /dev/null @@ -1,11 +0,0 @@ -
- A lubricated shaft rotates inside a concentric sleeve bearing at 1200rpm,the clearance is smaal with respect to the radius and hence a linear distribution velocity
- distribution may be assumed.What are the power requirements to rotate the shaft?R=2cm , L=6cm , dy=0.1mm , and u=0.2N.s/m^2.
-
- Solution:
-
- Power required to rotate the shaft =
-
- 95.251282
-
- W
diff --git a/806/CH1/EX1.3/13.sce b/806/CH1/EX1.3/13.sce deleted file mode 100644 index aab6d30bc..000000000 --- a/806/CH1/EX1.3/13.sce +++ /dev/null @@ -1,10 +0,0 @@ -clc
-pathname=get_absolute_file_path('13.sce')
-filename=pathname+filesep()+'13.sci'
-exec(filename)
-diary('C:\users\Bhavesh\desktop\scilab\13.txt')
-disp("a gas with molecular weight of 44 is at a pressure of 0.9MPa and a temperature of 20 degree celsius.Calculate its density")
-R=8312/M//gas constant(in m.N/kg.K)
-p=P/R/(273+T)*10^6//density in kg/m^3
-disp("kg/m^3",p,"Density p=")
-diary(0)
\ No newline at end of file diff --git a/806/CH1/EX1.3/13.txt b/806/CH1/EX1.3/13.txt deleted file mode 100644 index 6a2280ad0..000000000 --- a/806/CH1/EX1.3/13.txt +++ /dev/null @@ -1,8 +0,0 @@ -
- a gas with molecular weight of 44 is at a pressure of 0.9MPa and a temperature of 20 degree celsius.Calculate its density
-
- Density p=
-
- 16.260056
-
- kg/m^3
diff --git a/806/CH1/EX1.4/14.sce b/806/CH1/EX1.4/14.sce deleted file mode 100644 index 791f2a478..000000000 --- a/806/CH1/EX1.4/14.sce +++ /dev/null @@ -1,10 +0,0 @@ -clc
-pathname=get_absolute_file_path('14.sce')
-filename=pathname+filesep()+'14.sci'
-exec(filename)
-diary('C:\users\Bhavesh\desktop\scilab\14.txt')
-disp("A liquid compressed in a cylinder has a volume of 1000 cm^3 at 1 MN/m^2 and volume of 995 cm^3 at 2MN/m^2.What is its bulk modulus of elasticity?")
-disp("Solution:")
-K=-(P2-P1)/(V2-V1)*V1//Modulus of elasticity
-disp("MPa",K,"Modulus of elasticity=")
-diary(0)
diff --git a/806/CH1/EX1.4/14.txt b/806/CH1/EX1.4/14.txt deleted file mode 100644 index 856fdbd79..000000000 --- a/806/CH1/EX1.4/14.txt +++ /dev/null @@ -1,14 +0,0 @@ -
- A liquid compressed in a cylinder has a
- volume of 1000 cm^3 at 1 MN/m^2 a
- nd volume of 995 cm^3 at 2MN/m^2.W
- hat is its bulk modulus of elastic
- ity?
-
- Solution:
-
- Modulus of elasticity=
-
- 200.
-
- MPa
diff --git a/806/CH1/EX1.5/15.sce b/806/CH1/EX1.5/15.sce deleted file mode 100644 index d11cd408d..000000000 --- a/806/CH1/EX1.5/15.sce +++ /dev/null @@ -1,12 +0,0 @@ -clc
-pathname=get_absolute_file_path('15.sce')
-filename=pathname+filesep()+'15.sci'
-exec(filename)
-diary('C:\users\Bhavesh\desktop\scilab\15.txt')
-disp("With regard to Example 1.4 suppose the cylinder is a water quality sample bottle used to collect water samples at a predetermined depths.At deep Depths the sample Bottle has a smaller volume to collect 995 cm^3 due to compression.Suppose that analysis reveals that 15 mg of sediment are collected.What would be the difference in concerntration data measured shipboard where the pressure is atmospheric versus the in situ depths where the sample was collected?")
-disp("Solution:")
-C1=M/V1//Concerntration of shipboard
-C2=M/V2//concerntration of in situ depth
-disp("mg/cm^3",C1,"Concerntration of shipboard")
-disp("mg/cm^3",C2,"Concerntration of in situ depth")
-diary(0)
diff --git a/806/CH1/EX1.5/15.txt b/806/CH1/EX1.5/15.txt deleted file mode 100644 index c2d88f30b..000000000 --- a/806/CH1/EX1.5/15.txt +++ /dev/null @@ -1,29 +0,0 @@ -
- With regard to Example 1.4 suppose the
- cylinder is a water quality sample
- bottle used to collect water samp
- les at a predetermined depths.At d
- eep Depths the sample Bottle has a
- smaller volume to collect 995 cm^
- 3 due to compression.Suppose that
- analysis reveals that 15 mg of sed
- iment are collected.What would be
- the difference in concerntration d
- ata measured shipboard where the p
- ressure is atmospheric versus the
- in situ depths where the sample wa
- s collected?
-
- Solution:
-
- Concerntration of shipboard
-
- 0.015
-
- mg/cm^3
-
- Concerntration of in situ depth
-
- 0.0150754
-
- mg/cm^3
diff --git a/806/CH10/EX10.1/101.sce b/806/CH10/EX10.1/101.sce deleted file mode 100644 index a47b495c2..000000000 --- a/806/CH10/EX10.1/101.sce +++ /dev/null @@ -1,22 +0,0 @@ -clc
-pathname=get_absolute_file_path('101.sce')
-filename=pathname+filesep()+'101.sci'
-exec(filename)
-diary('C:\users\Bhavesh\desktop\scilab\101.txt')
-disp("A 75 mm diameter orific under a head of 4.88 m discharges 8900 N waterin 32.6 s.The trajectory was determined by measuring x=4.76 m for a drop of 1.22.determine the head loss per unit weight,the power loss,Cc,Cv,Cd")
-disp("Solution:")
-Vt=sqrt(2*g*H)//theoretical velocity
-t=sqrt(2*y/g)//actual time
-Va=x/t//actual velocity
-Cv=Va/Vt//coefficient of velocity
-Qa=F/p/T//actual discharge
-Cd=Qa/(%pi*d^2*Vt)*4//coefficient of discharge
-Cc=Cd/Cv//coefficient of contraction
-HL=H*(1-Cv^2)//Head loss
-PL=Qa*p*HL//power loss
-disp(Cd,"Cd=")
-disp(Cv,"Cv=")
-disp(Cc,"Cc=")
-disp("m.N/N",HL,"Head loss=")
-disp("W",PL,"Power loss=")
-diary(0)
\ No newline at end of file diff --git a/806/CH10/EX10.1/101.txt b/806/CH10/EX10.1/101.txt deleted file mode 100644 index b8bb70b76..000000000 --- a/806/CH10/EX10.1/101.txt +++ /dev/null @@ -1,31 +0,0 @@ -
- A 75 mm diameter orific under a head of 4.88 m discharges 8900 N waterin 32.6 s.The trajectory was determined by measuring x=4.76 m for a drop of 1.22.determine t
- he head loss per unit weight,the power loss,Cc,Cv,Cd
-
- Solution:
-
- Cd=
-
- 0.6437713
-
- Cv=
-
- 0.9754098
-
- Cc=
-
- 0.6600008
-
- Head loss=
-
- 0.2370492
-
- m.N/N
-
- Power loss=
-
- 64.715881
-
- W
-
- 0.9754098
diff --git a/806/CH4/EX4.5/45.sce b/806/CH4/EX4.5/45.sce deleted file mode 100644 index e76367382..000000000 --- a/806/CH4/EX4.5/45.sce +++ /dev/null @@ -1,11 +0,0 @@ -clc
-pathname=get_absolute_file_path('45.sce')
-filename=pathname+filesep()+'45.sci'
-exec(filename)
-diary('C:\users\Bhavesh\desktop\scilab\45.txt')
-disp("Water is flowing through an open channel at a depth of 2 m and a velocity of 3m/s.it then flows through a contracting chute into another channel where the depth is 1 m and the velocity is 10m/s.assuming frictionless flow,determine the difference in the elevation of the channel floors.")
-disp("Solution:")
-disp("The points 1 and 2 can be selected on the free surface and therefore p1=p2=0")
-disp("Therefore by bernoullis equation the difference in the elevation of the channel is y=")
-y=(v2^2)/(2*p)+h2-h1-(v1^2)/(2*p)
-disp("m",y)
\ No newline at end of file diff --git a/806/CH4/EX4.5/45.txt b/806/CH4/EX4.5/45.txt deleted file mode 100644 index 9717574b8..000000000 --- a/806/CH4/EX4.5/45.txt +++ /dev/null @@ -1,15 +0,0 @@ -
- Water is flowing through an open channel at a depth of 2 m and a velocity of 3m/s.it then flows through a contracting chute into another channel where the depth i
- s 1 m and the velocity is 10m/s.assuming frictionless flow,determine the difference in the elevation of the channel floors.
-
- Solution:
-
- The points 1 and 2 can be selected on the free surface and therefore p1=p2=0
-
- Therefore by bernoullis equation the difference in the elevation of the channel is y=
-
- 3.6381244
-
- m
-
--->exec('SCI/etc/scilab.quit','errcatch',-1);quit;
diff --git a/806/CH4/EX4.6/46.sce b/806/CH4/EX4.6/46.sce deleted file mode 100644 index fc58bb642..000000000 --- a/806/CH4/EX4.6/46.sce +++ /dev/null @@ -1,16 +0,0 @@ -clc
-pathname=get_absolute_file_path('46.sce')
-filename=pathname+filesep()+'46.sci'
-exec(filename)
-diary('C:\users\Bhavesh\desktop\scilab\46.txt')
-disp("A venturimeter,consisting of a converging portion followed by a throat of constant diameter and then gradually diverging portion,is used to detremine the flow of the pipe.The diameter at section 1 is 6 in. and that of section 2 is 4 in.,Find the discharge through the pipe when p1-p2=3psi and oil of sp grvty 0.9 is flowing")
-disp("Solution:")
-disp("From the continuity equation Q=A1v1=A2v2")
-disp("Therefore,v1=Q*16/pi , v2=Q*36/pi")
-disp("And moreover Z1=Z2")
-disp("Therefore discharge Q =")
-a1=%pi/16//sq.ft
-a2=%pi/36//sq.ft
-q=sqrt(a*144*(%pi^2)*2*32.185/((s*62.4)*(36^2-16^2)))
-disp("cfs",q)
-diary(0)
\ No newline at end of file diff --git a/806/CH4/EX4.6/46.txt b/806/CH4/EX4.6/46.txt deleted file mode 100644 index 1933f4658..000000000 --- a/806/CH4/EX4.6/46.txt +++ /dev/null @@ -1,18 +0,0 @@ -
- A venturimeter,consisting of a converging portion followed by a throat of constant diameter and then gradually diverging portion,is used to detremine the flow of
- the pipe.The diameter at section 1 is 6 in. and that of section 2 is 4 in.,Find the discharge through the pipe when p1-p2=3psi and oil of sp grvty 0.9 is flo
- wing
-
- Solution:
-
- From the continuity equation Q=A1v1=A2v2
-
- Therefore,v1=Q*16/pi , v2=Q*36/pi
-
- And moreover Z1=Z2
-
- Therefore discharge Q =
-
- 2.1677205
-
- cfs
diff --git a/806/CH4/EX4.7/47.sce b/806/CH4/EX4.7/47.sce deleted file mode 100644 index a665e9b42..000000000 --- a/806/CH4/EX4.7/47.sce +++ /dev/null @@ -1,19 +0,0 @@ -clc
-pathname=get_absolute_file_path('47.sce')
-filename=pathname+filesep()+'47.sci'
-exec(filename)
-diary('C:\users\Bhavesh\desktop\scilab\47.txt')
-disp("The water supply reservoir as shown in given figure has an average depth of 20m, a surface area of 20km^2, ans an outlet whose centerline is 15m below the water surface.If the otflow diameter is 1 m, what is the outflow and its associated velocity?What would be the drwa down during one week and one day periods?")
-disp("Solution:")
-V2=sqrt(2*g*z1)//Velocity of liquid from the pipe
-Q=V2*%pi*d2^2/4//Discharge per sec
-disp("m^3/s",Q,"Discharge")
-v1=Q*24*3600//Discharge per day
-v2=Q*7*24*3600//Dicharge per week
-v=A*H//Original volume of liquid
-disp("Hence drop down in level for one day and one week are:")
-h1=v1/v*H//draw down of one day
-h2=v2/v*H//draw down of one week
-disp("m",h1,"draw down of one day")
-disp("m",h2,"draw down of one week")
-diary(0)
diff --git a/806/CH4/EX4.7/47.txt b/806/CH4/EX4.7/47.txt deleted file mode 100644 index 4a8221360..000000000 --- a/806/CH4/EX4.7/47.txt +++ /dev/null @@ -1,34 +0,0 @@ -
- The water supply reservoir as shown in
- given figure has an average depth
- of 20m, a surface area of 20km^2,
- ans an outlet whose centerline is
- 15m below the water surface.If the
- otflow diameter is 1 m, what is t
- he outflow and its associated velo
- city?What would be the drwa down d
- uring one week and one day periods
- ?
-
- Solution:
-
- Discharge
-
- 13.473642
-
- m^3/s
-
- Hence drop down in level for one day an
- d one week are:
-
- draw down of one day
-
- 0.0582061
-
- m
-
- draw down of one week
-
- 0.4074429
-
- m
diff --git a/806/CH7/EX7.1/71.sce b/806/CH7/EX7.1/71.sce deleted file mode 100644 index 0ffc8a9a0..000000000 --- a/806/CH7/EX7.1/71.sce +++ /dev/null @@ -1,15 +0,0 @@ -clc
-pathname=get_absolute_file_path('71.sce')
-filename=pathname+filesep()+'71.sci'
-exec(filename)
-diary('C:\users\Bhavesh\desktop\scilab\71.txt')
-disp("A smooth flat plate 3 m wide and 30 m long is towed through still water at 20 degree celsius with a speed of 6m/s.Determine the drag on one side of the plate and the drag on the first 3 m of plate")
-disp("Solution:")
-R=U*l/v//Reynolds number
-Cd=0.455/(log10(R))^2.58//Constant
-D1=Cd*w*l*p*(U^2)/2//Drag force on whole plate
-D2=Cd*w*l1*p*U^2/2//Drag force on first 3 m
-disp("N",D1,"Drag force on whole plate")
-disp("N",D2,"Drag force on first 3m")
-
-diary(0)
diff --git a/806/CH7/EX7.1/71.txt b/806/CH7/EX7.1/71.txt deleted file mode 100644 index 55756a872..000000000 --- a/806/CH7/EX7.1/71.txt +++ /dev/null @@ -1,21 +0,0 @@ -
- A smooth flat plate 3 m wide and 30 m l
- ong is towed through still water a
- t 20 degree celsius with a speed o
- f 6m/s.Determine the drag on one s
- ide of the plate and the drag on t
- he first 3 m of plate
-
- Solution:
-
- Drag force on whole plate
-
- 3176.7877
-
- N
-
- Drag force on first 3m
-
- 317.67877
-
- N
diff --git a/806/CH7/EX7.2/72.sce b/806/CH7/EX7.2/72.sce deleted file mode 100644 index 2989457bb..000000000 --- a/806/CH7/EX7.2/72.sce +++ /dev/null @@ -1,22 +0,0 @@ -clc
-pathname=get_absolute_file_path('72.sce')
-filename=pathname+filesep()+'72.sci'
-exec(filename)
-diary('C:\users\Bhavesh\desktop\scilab\72.txt')
-disp("Dredging operations in a river yield large volumes of sediments whose smallest particle is measured to be coarse sand with a diameter of 4 microns and whose largest particle is coarse sand with a diameter of 1000 microns or 1mm.determine the settling velocity for each size class.Gw=9764 N/m^3;Ssand=2.65;Sclay=1.6;and the viscosity at 30 degree celsius is 0.8*10D-3 N.s/m^2")
-disp("Solution:")
-disp("(i)For clay particles:")
-disp("Assuming reynolds number less than 1")
-w1=d1^2*(S1-1)*p/(18*v)//Settling velocity of clay particles
-R1=d1*w1/v//reynolds number
-disp(R1,"R1=")
-disp("Since reynolds number is less than 1,hence")
-disp("m/s",w1,"Settling velocity for clay particles")
-disp("(ii)For sand particles:")
-disp("Assuming reynolds number greater than 1 and equal to 220 Cd=0.7")
-w2=sqrt(1.333*d2*p*(S2-1)/(Cd*r))//Settling velocity of clay particles
-R2=d2*w2*1e3/v//reynolds number
-disp(R2,"R2")
-disp("Since the reynolds number is greater than 1")
-disp("m/s",w2,"Hence the settling velovity =")
-diary(0)
diff --git a/806/CH7/EX7.2/72.txt b/806/CH7/EX7.2/72.txt deleted file mode 100644 index 29bb09e63..000000000 --- a/806/CH7/EX7.2/72.txt +++ /dev/null @@ -1,49 +0,0 @@ -
- Dredging operations in a river yield la
- rge volumes of sediments whose sma
- llest particle is measured to be c
- oarse sand with a diameter of 4 mi
- crons and whose largest particle i
- s coarse sand with a diameter of 1
- 000 microns or 1mm.determine the s
- ettling velocity for each size cla
- ss.Gw=9764 N/m^3;Ssand=2.65;Sclay=
- 1.6;and the viscosity at 30 degree
- celsius is 0.8*10D-3 N.s/m^2
-
- Solution:
-
- (i)For clay particles:
-
- Assuming reynolds number less than 1
-
- R1=
-
- 3.255D-08
-
- Since reynolds number is less than 1,he
- nce
-
- Settling velocity for clay particles
-
- 0.0000065
-
- m/s
-
- (ii)For sand particles:
-
- Assuming reynolds number greater than 1
- and equal to 220 Cd=0.7
-
- R2
-
- 219.41569
-
- Since the reynolds number is greater th
- an 1
-
- Hence the settling velovity =
-
- 0.1755325
-
- m/s
diff --git a/806/CH8/EX8.2/82.sce b/806/CH8/EX8.2/82.sce deleted file mode 100644 index 9b4886aa5..000000000 --- a/806/CH8/EX8.2/82.sce +++ /dev/null @@ -1,15 +0,0 @@ -clc
-pathname=get_absolute_file_path('82.sce')
-filename=pathname+filesep()+'82.sci'
-exec(filename)
-diary('C:\users\Bhavesh\desktop\scilab\82.txt')
-disp("A submarine moves through water at 30 ft/s.At a point A on the submarine 5 ft above the nose,the velocity of the submarine relative to the water is 50 ft/s.Determine the dynamic-pressure difference between this point and the nose,and determine the difference in total pressure between the two points.")
-disp("If the submarine is sationary and the water is movinf past it,The velocity at the nose is zero and the velocity at A is 50ft/s.By selecting the dynamic pressure at infinity as zero")
-E=q^2/2+g*hn
-p1=p*E//Pressure at nose
-p2=p*(E-q1^2/2)//Pressure at point A
-P1=p2-p1//Pressure difference at point A and nose
-P2=p*(g*hn-g*ha+(qn^2-q1^2)/2)
-disp("lb/ft^2",P1,"Hence dynamic pressure difference between point A and nose is=")
-disp("lb/ft^2",P2,"Hence total pressure difference between point A and nose is=")
-diary(0)
diff --git a/806/CH8/EX8.2/82.txt b/806/CH8/EX8.2/82.txt deleted file mode 100644 index e4947d3bd..000000000 --- a/806/CH8/EX8.2/82.txt +++ /dev/null @@ -1,31 +0,0 @@ -
- A submarine moves through water at 30 f
- t/s.At a point A on the submarine
- 5 ft above the nose,the velocity o
- f the submarine relative to the wa
- ter is 50 ft/s.Determine the dynam
- ic-pressure difference between thi
- s point and the nose,and determine
- the difference in total pressure
- between the two points.
-
- If the submarine is sationary and the w
- ater is movinf past it,The velocit
- y at the nose is zero and the velo
- city at A is 50ft/s.By selecting t
- he dynamic pressure at infinity as
- zero
-
- Hence dynamic pressure difference betwe
- en point A and nose is=
-
- - 2418.75
-
- lb/ft^2
-
- Hence total pressure difference between
- point A and nose is=
-
- - 2730.0334
-
- lb/ft^2
diff --git a/806/CH8/EX8.3/83.sce b/806/CH8/EX8.3/83.sce deleted file mode 100644 index 90666a4f9..000000000 --- a/806/CH8/EX8.3/83.sce +++ /dev/null @@ -1,13 +0,0 @@ -clc
-pathname=get_absolute_file_path('83.sce')
-filename=pathname+filesep()+'83.sci'
-exec(filename)
-diary('C:\users\Bhavesh\desktop\scilab\83.txt')
-disp("A source with strength 0.2m^3/s and a vortex with strength 1 m^2/s are located at the origin.Determine the equations for velocity potential and stream function.What are the velocity components at x=1 m,y=0.5 m?")
-disp("Solution:")
-r=sqrt(x^2+y^2)
-Vr=1/(10*%pi*r)
-Vt=1/(2*%pi*r)
-disp("m/s",Vr,"Vr=")
-disp("m/s",Vt,"Vt=")
-diary(0)
diff --git a/806/CH8/EX8.3/83.txt b/806/CH8/EX8.3/83.txt deleted file mode 100644 index 44a79db57..000000000 --- a/806/CH8/EX8.3/83.txt +++ /dev/null @@ -1,22 +0,0 @@ -
- A source with strength 0.2m^3/s and a v
- ortex with strength 1 m^2/s are lo
- cated at the origin.Determine the
- equations for velocity potential a
- nd stream function.What are the ve
- locity components at x=1 m,y=0.5 m
- ?
-
- Solution:
-
- Vr=
-
- 0.0284705
-
- m/s
-
- Vt=
-
- 0.1423525
-
- m/s
diff --git a/806/DEPENDENCIES/101.sci b/806/DEPENDENCIES/101.sci deleted file mode 100644 index 3b45cd5d1..000000000 --- a/806/DEPENDENCIES/101.sci +++ /dev/null @@ -1,7 +0,0 @@ -x=4.76//m
-y=1.22//m
-d=0.075//m(Diameter of orifice)
-H=4.88//m(Head)
-F=8900//N
-p=9810//N/m^3(Weight density of water)
-T=32.6//s
\ No newline at end of file diff --git a/806/DEPENDENCIES/1025.sci b/806/DEPENDENCIES/1025.sci deleted file mode 100644 index 6c1e24f33..000000000 --- a/806/DEPENDENCIES/1025.sci +++ /dev/null @@ -1,7 +0,0 @@ -Cd=0.74//coefficient of discharge
-h1=2//m
-p=15//kPa(Air pressure)
-S=0.92//Specific gravity of oil
-d=0.07//m(Diameter of opening)
-g=9.81//m/s^2(Acceleration due to gravity)
-P=9.810//N/m^3(Weight density of water)
\ No newline at end of file diff --git a/806/DEPENDENCIES/1026.sci b/806/DEPENDENCIES/1026.sci deleted file mode 100644 index 51531ef72..000000000 --- a/806/DEPENDENCIES/1026.sci +++ /dev/null @@ -1,8 +0,0 @@ -Cd=0.74//coefficient of discharge
-h1=2//m
-p=15//kPa(Air pressure)
-S=0.92//Specific gravity of oil
-d=0.07//m(Diameter of opening)
-g=9.81//m/s^2(Acceleration due to gravity)
-P=9.810//N/m^3(Weight density of water)
-Cv=0.96//coefficient of velocity
\ No newline at end of file diff --git a/806/DEPENDENCIES/1032.sci b/806/DEPENDENCIES/1032.sci deleted file mode 100755 index c31a9ce9f..000000000 --- a/806/DEPENDENCIES/1032.sci +++ /dev/null @@ -1,6 +0,0 @@ -d=0.075//m(Diameter of orifice)
-D=1.5//m(Diameter of tank)
-H1=3//m
-H2=2.5//m
-Cd=0.82//Coefficient of discharge
-g=9.81//m/s^2(Acceleration due to gravity)
\ No newline at end of file diff --git a/806/DEPENDENCIES/1054.sci b/806/DEPENDENCIES/1054.sci deleted file mode 100755 index 574bb71bc..000000000 --- a/806/DEPENDENCIES/1054.sci +++ /dev/null @@ -1,3 +0,0 @@ -l=1.5//m(Length of rectangular weir)
-D=2.25//m(Upstream depth)
-Q=0.45//m^3/s
\ No newline at end of file diff --git a/806/DEPENDENCIES/1055.sci b/806/DEPENDENCIES/1055.sci deleted file mode 100755 index ac64f3a74..000000000 --- a/806/DEPENDENCIES/1055.sci +++ /dev/null @@ -1,3 +0,0 @@ -q=170//L/s(Discharge)
-t=60//degrees
-g=9.81//m/s^2(Acceleration due to gravity)
\ No newline at end of file diff --git a/806/DEPENDENCIES/10_62.sci b/806/DEPENDENCIES/10_62.sci deleted file mode 100755 index ea197703b..000000000 --- a/806/DEPENDENCIES/10_62.sci +++ /dev/null @@ -1,2 +0,0 @@ -d1=17.5//mm(Diameter at vena contracta)
-d2=20//mm(diameter of orifice)
\ No newline at end of file diff --git a/806/DEPENDENCIES/10_66.sci b/806/DEPENDENCIES/10_66.sci deleted file mode 100755 index 973296f73..000000000 --- a/806/DEPENDENCIES/10_66.sci +++ /dev/null @@ -1,4 +0,0 @@ -d=0.05//m(Diameter)
-q=7.68//L(Discharge)
-H=3//m(Head)
-g=9.81//m/s^2(Acceleration due to gravity)
\ No newline at end of file diff --git a/806/DEPENDENCIES/11.sci b/806/DEPENDENCIES/11.sci deleted file mode 100755 index d459ca656..000000000 --- a/806/DEPENDENCIES/11.sci +++ /dev/null @@ -1,2 +0,0 @@ -u=0.005//kg/m.s(viscosityb of liquid)
-p=850//kg/cm^3(density of liquid)
\ No newline at end of file diff --git a/806/DEPENDENCIES/110.sci b/806/DEPENDENCIES/110.sci deleted file mode 100755 index 2a50b05ba..000000000 --- a/806/DEPENDENCIES/110.sci +++ /dev/null @@ -1,2 +0,0 @@ -m=2//kg
-w=17//N(newton)
\ No newline at end of file diff --git a/806/DEPENDENCIES/111.sci b/806/DEPENDENCIES/111.sci deleted file mode 100755 index 13f118fa8..000000000 --- a/806/DEPENDENCIES/111.sci +++ /dev/null @@ -1,2 +0,0 @@ -W=20//N(weight of a flour bag)
-g=9.81//m/s^2(Acceleration due to gravity on the earth)
\ No newline at end of file diff --git a/806/DEPENDENCIES/112.sci b/806/DEPENDENCIES/112.sci deleted file mode 100755 index c7b8bf0c7..000000000 --- a/806/DEPENDENCIES/112.sci +++ /dev/null @@ -1,3 +0,0 @@ -f1=600//N
-f2=1500//N
-u1=1//m/s
\ No newline at end of file diff --git a/806/DEPENDENCIES/113.sci b/806/DEPENDENCIES/113.sci deleted file mode 100755 index c1ac44276..000000000 --- a/806/DEPENDENCIES/113.sci +++ /dev/null @@ -1,2 +0,0 @@ -v=10.4//m^2/s(kinematic viscosity)
-S=0.85//specific gravity of fluid
diff --git a/806/DEPENDENCIES/114.sci b/806/DEPENDENCIES/114.sci deleted file mode 100755 index b9477b57a..000000000 --- a/806/DEPENDENCIES/114.sci +++ /dev/null @@ -1,2 +0,0 @@ -p=4//n/m^2(shear stress)\
-w=100//rad/s(angular deformation)
\ No newline at end of file diff --git a/806/DEPENDENCIES/115.sci b/806/DEPENDENCIES/115.sci deleted file mode 100755 index 6c5f5d5ba..000000000 --- a/806/DEPENDENCIES/115.sci +++ /dev/null @@ -1,3 +0,0 @@ -f=2//N/m^2( Shear stress)
-du=0.25//m/s(Velocity of plate)
-dy=0.5//mm(Distance between the two plates)
\ No newline at end of file diff --git a/806/DEPENDENCIES/116.sci b/806/DEPENDENCIES/116.sci deleted file mode 100755 index 450192452..000000000 --- a/806/DEPENDENCIES/116.sci +++ /dev/null @@ -1,5 +0,0 @@ -d=3//inches(Diameter of shaft)
-u=0.4//ft/sec
-dy=0.003//inches
-L=8//inches(length of sleeve)
-f=20//lb( Shear Force)
\ No newline at end of file diff --git a/806/DEPENDENCIES/12.sci b/806/DEPENDENCIES/12.sci deleted file mode 100755 index 160f9810b..000000000 --- a/806/DEPENDENCIES/12.sci +++ /dev/null @@ -1,5 +0,0 @@ -R=2//cm(Radius of sleeve)
-L=6//cm(Length of sleeve)
-dy=0.1//mm(clearance)
-u=0.2//N.s/m^2(viscosity)
-du=1200//rpm
\ No newline at end of file diff --git a/806/DEPENDENCIES/123.sci b/806/DEPENDENCIES/123.sci deleted file mode 100755 index e5ae08a72..000000000 --- a/806/DEPENDENCIES/123.sci +++ /dev/null @@ -1,2 +0,0 @@ -S=0.83//Specific gravity of fluid
-v=0.0004//m^2/s(kinematic viscosity)
\ No newline at end of file diff --git a/806/DEPENDENCIES/124.sci b/806/DEPENDENCIES/124.sci deleted file mode 100755 index 1398eeccb..000000000 --- a/806/DEPENDENCIES/124.sci +++ /dev/null @@ -1,5 +0,0 @@ -w=120//lb(weight of body)
-a=2//ft^2(area of the body)
-v=0.002//lb.s/ft^2(viscosity of fluid)
-u=3//ft/s(speed of the body)
-t=30//degree(angle of inclined plane with the horizontal surface)
diff --git a/806/DEPENDENCIES/126.sci b/806/DEPENDENCIES/126.sci deleted file mode 100755 index 184c7e3b4..000000000 --- a/806/DEPENDENCIES/126.sci +++ /dev/null @@ -1,3 +0,0 @@ -u=3.05//lb.s/ft^2(Dynamic viscosity)
-p=48//lb/ft^3(specific weight)
-g=9.81//m/s^2
\ No newline at end of file diff --git a/806/DEPENDENCIES/127.sci b/806/DEPENDENCIES/127.sci deleted file mode 100755 index 1b9ccfeea..000000000 --- a/806/DEPENDENCIES/127.sci +++ /dev/null @@ -1,2 +0,0 @@ -S=0.75//specific gravity
-g=9.81//m/s^2(Acceleration due to gravity)
diff --git a/806/DEPENDENCIES/129.sci b/806/DEPENDENCIES/129.sci deleted file mode 100755 index 6e63ae404..000000000 --- a/806/DEPENDENCIES/129.sci +++ /dev/null @@ -1,2 +0,0 @@ -p=2.94//g/cm^3(density)
-W=9.81//kN/m^3(Specific weight of water)
\ No newline at end of file diff --git a/806/DEPENDENCIES/13.sci b/806/DEPENDENCIES/13.sci deleted file mode 100755 index 40f74ced7..000000000 --- a/806/DEPENDENCIES/13.sci +++ /dev/null @@ -1,3 +0,0 @@ -M=44//Molecular weight
-T=20//degree celsius
-P=0.9//MPa(Pressure)
\ No newline at end of file diff --git a/806/DEPENDENCIES/14.sci b/806/DEPENDENCIES/14.sci deleted file mode 100755 index 6f0c1f5a0..000000000 --- a/806/DEPENDENCIES/14.sci +++ /dev/null @@ -1,4 +0,0 @@ -V1=1000//cm^3(Volume of Liquid at Pressure 1)
-P1=1//MN/m^2(Pressure)
-V2=995//cm^3(Volume of Liquid at Pressure 2)
-P2=2//MN/m^2(Pressure
diff --git a/806/DEPENDENCIES/144.sci b/806/DEPENDENCIES/144.sci deleted file mode 100755 index 3b60490f7..000000000 --- a/806/DEPENDENCIES/144.sci +++ /dev/null @@ -1,4 +0,0 @@ -R=210//m.N//kg.K(gas constant)\
-T=20//degree celsius
-P=0.2//MPa(Pressure)
-V=40//litres(volume)
\ No newline at end of file diff --git a/806/DEPENDENCIES/15.sci b/806/DEPENDENCIES/15.sci deleted file mode 100755 index 4186dca12..000000000 --- a/806/DEPENDENCIES/15.sci +++ /dev/null @@ -1,5 +0,0 @@ -V1=1000//cm^3(Volume of Liquid at Pressure 1)
-P1=1//MN/m^2(Pressure)
-V2=995//cm^3(Volume of Liquid at Pressure 2)
-P2=2//MN/m^2(Pressure
-M=15//mg(Mass of sediments)
diff --git a/806/DEPENDENCIES/156.sci b/806/DEPENDENCIES/156.sci deleted file mode 100755 index 6c7995c2d..000000000 --- a/806/DEPENDENCIES/156.sci +++ /dev/null @@ -1,3 +0,0 @@ -dp1=1000//lb/ft^2(Pressure change)
-dp2=60//kPa(Pressure increase)
-p=0.02//percent change in density
\ No newline at end of file diff --git a/806/DEPENDENCIES/157.sci b/806/DEPENDENCIES/157.sci deleted file mode 100755 index 33a0e21bc..000000000 --- a/806/DEPENDENCIES/157.sci +++ /dev/null @@ -1,2 +0,0 @@ -K=2.2//GPa(Bulk modulus)
-dv=-0.5//percent(volume change of water)
diff --git a/806/DEPENDENCIES/16.sci b/806/DEPENDENCIES/16.sci deleted file mode 100755 index b0503ae81..000000000 --- a/806/DEPENDENCIES/16.sci +++ /dev/null @@ -1,2 +0,0 @@ -m=3//slugs
-g=31.7//ft/s^2
\ No newline at end of file diff --git a/806/DEPENDENCIES/174.sci b/806/DEPENDENCIES/174.sci deleted file mode 100755 index 211532831..000000000 --- a/806/DEPENDENCIES/174.sci +++ /dev/null @@ -1,4 +0,0 @@ -d=0.2//inches(Diameter of pipe)
-h=0.09//inches(Capilaary rise)
-T=0.005//lb/ft(Surface tension)
-p=62.455//lb/ft^3(Weight density of water)
\ No newline at end of file diff --git a/806/DEPENDENCIES/18.sci b/806/DEPENDENCIES/18.sci deleted file mode 100755 index be2ac0531..000000000 --- a/806/DEPENDENCIES/18.sci +++ /dev/null @@ -1,3 +0,0 @@ -m=450//kg
-g1=9.81//m/s^2(acceleration due to gravity on the surface of the earth)
-g2=9.81/6//m/s^2(acceleration due to gravity on the surface of moon)
\ No newline at end of file diff --git a/806/DEPENDENCIES/1_32.sci b/806/DEPENDENCIES/1_32.sci deleted file mode 100755 index fbb08df73..000000000 --- a/806/DEPENDENCIES/1_32.sci +++ /dev/null @@ -1,2 +0,0 @@ -F=10//N(Force)
-m=2//kg(mass)
\ No newline at end of file diff --git a/806/DEPENDENCIES/1_33.sci b/806/DEPENDENCIES/1_33.sci deleted file mode 100755 index 33b2bdcef..000000000 --- a/806/DEPENDENCIES/1_33.sci +++ /dev/null @@ -1,2 +0,0 @@ -m=3//kg(mass)
-g=10//m/s^2(acceleration due to gravity)
\ No newline at end of file diff --git a/806/DEPENDENCIES/1_410.sci b/806/DEPENDENCIES/1_410.sci deleted file mode 100755 index 3dfda8ce6..000000000 --- a/806/DEPENDENCIES/1_410.sci +++ /dev/null @@ -1,2 +0,0 @@ -v=3*1e-8//m^2/s(kinematic viscosity)
-p=800//kg/m^3(Mass Density)
\ No newline at end of file diff --git a/806/DEPENDENCIES/1_48.sci b/806/DEPENDENCIES/1_48.sci deleted file mode 100755 index 5389e39ff..000000000 --- a/806/DEPENDENCIES/1_48.sci +++ /dev/null @@ -1,3 +0,0 @@ -u=0.06//kg/m.s(Dynamic viscosity)
-S=0.6//specific gravity
-P=1000//kg/m^3(Weight density of water)
\ No newline at end of file diff --git a/806/DEPENDENCIES/1_72.sci b/806/DEPENDENCIES/1_72.sci deleted file mode 100755 index 447de0fab..000000000 --- a/806/DEPENDENCIES/1_72.sci +++ /dev/null @@ -1 +0,0 @@ -M=28//molecular weight
\ No newline at end of file diff --git a/806/DEPENDENCIES/1_84.sci b/806/DEPENDENCIES/1_84.sci deleted file mode 100755 index 5fea56ec2..000000000 --- a/806/DEPENDENCIES/1_84.sci +++ /dev/null @@ -1,3 +0,0 @@ -dp=1//MPa(Change in pressure)
-V=300//liters
-dv=-0.6//liters
\ No newline at end of file diff --git a/806/DEPENDENCIES/210.sci b/806/DEPENDENCIES/210.sci deleted file mode 100755 index 108f715d0..000000000 --- a/806/DEPENDENCIES/210.sci +++ /dev/null @@ -1,4 +0,0 @@ -P=50//kPa
-S1=13.6//specifc gravity of mercury
-S2=2.94//specifc gravity of acetylene tetrabromide
-Sw=1//specific gravity of water
\ No newline at end of file diff --git a/806/DEPENDENCIES/2102.sci b/806/DEPENDENCIES/2102.sci deleted file mode 100755 index f6c8fcc71..000000000 --- a/806/DEPENDENCIES/2102.sci +++ /dev/null @@ -1,6 +0,0 @@ -S1=0.6//Specific gravity of upper half of cube
-S2=1.4//Specific gravity of lower half of cube
-S3=0.9//Specific gravity of upper fluid
-S4=1.2//Specific gravity of lower fluid
-s=2//feet(Side of a cube)
-p=62.455//lb/ft^3(Weight density of water)
\ No newline at end of file diff --git a/806/DEPENDENCIES/2103.sci b/806/DEPENDENCIES/2103.sci deleted file mode 100755 index 454e8bcf9..000000000 --- a/806/DEPENDENCIES/2103.sci +++ /dev/null @@ -1,4 +0,0 @@ -p=9810//N/m^3(Weight density of water)
-S=0.83//Specific gravity of oil
-w1=3//N(Weight in water)
-w2=4//N(Weight in oil)
\ No newline at end of file diff --git a/806/DEPENDENCIES/212.sci b/806/DEPENDENCIES/212.sci deleted file mode 100755 index 6364671dd..000000000 --- a/806/DEPENDENCIES/212.sci +++ /dev/null @@ -1,4 +0,0 @@ -h=750//mm of Hg
-p=9810//weight density of water in N/m^3
-p1=4//atmosphere
-S=13.6//specific gravity of mercury
\ No newline at end of file diff --git a/806/DEPENDENCIES/214.sci b/806/DEPENDENCIES/214.sci deleted file mode 100755 index fb06c13d9..000000000 --- a/806/DEPENDENCIES/214.sci +++ /dev/null @@ -1,5 +0,0 @@ -h=300//mm-Hg
-S1=1//Specific gravity of water
-S2=0.83//Specific gravity of kerosen
-S3=2.94//Specific gravity of acetylene tetrabromide
-S=13.6//Specific gravity of mercury
\ No newline at end of file diff --git a/806/DEPENDENCIES/216.sci b/806/DEPENDENCIES/216.sci deleted file mode 100755 index 2c3bf49a1..000000000 --- a/806/DEPENDENCIES/216.sci +++ /dev/null @@ -1,3 +0,0 @@ -h1=2//m
-h2=0.5//m
-S=0.85//specific gravity of oil
\ No newline at end of file diff --git a/806/DEPENDENCIES/218.sci b/806/DEPENDENCIES/218.sci deleted file mode 100755 index d75a99a06..000000000 --- a/806/DEPENDENCIES/218.sci +++ /dev/null @@ -1,2 +0,0 @@ -h=20//inches
-S=1.9//Specific gravity of liquid
\ No newline at end of file diff --git a/806/DEPENDENCIES/219.sci b/806/DEPENDENCIES/219.sci deleted file mode 100755 index 56917ba09..000000000 --- a/806/DEPENDENCIES/219.sci +++ /dev/null @@ -1,3 +0,0 @@ -pa=-30//kPa
-p=9810//N/m^3
-S=0.83//specific gravity of kerosene
\ No newline at end of file diff --git a/806/DEPENDENCIES/22.sci b/806/DEPENDENCIES/22.sci deleted file mode 100755 index 13f18540f..000000000 --- a/806/DEPENDENCIES/22.sci +++ /dev/null @@ -1,2 +0,0 @@ -h=1250//feet
-p=62.455//wieht density of water in lb/ft^3
\ No newline at end of file diff --git a/806/DEPENDENCIES/220.sci b/806/DEPENDENCIES/220.sci deleted file mode 100755 index 9580cda7b..000000000 --- a/806/DEPENDENCIES/220.sci +++ /dev/null @@ -1,2 +0,0 @@ -h=8//inches
-h1=29//inches of mercury(barometer reading)
\ No newline at end of file diff --git a/806/DEPENDENCIES/222.sci b/806/DEPENDENCIES/222.sci deleted file mode 100755 index 1aeadf511..000000000 --- a/806/DEPENDENCIES/222.sci +++ /dev/null @@ -1,3 +0,0 @@ -h1=75//mm
-S=1//specific gravity of water
-S1=13.6//specific gravity of mercury
\ No newline at end of file diff --git a/806/DEPENDENCIES/223.sci b/806/DEPENDENCIES/223.sci deleted file mode 100755 index 4ef910546..000000000 --- a/806/DEPENDENCIES/223.sci +++ /dev/null @@ -1,6 +0,0 @@ -S1=1.0//specific gravity of the liquid in the pipe A
-S2=0.95//specific gravity of manometric liquid
-S3=1.0//specific gravity of liquid in pipe B
-h1=280//mm
-h2=280//mm
-h3=1000//mm
\ No newline at end of file diff --git a/806/DEPENDENCIES/224.sci b/806/DEPENDENCIES/224.sci deleted file mode 100755 index 1db88765a..000000000 --- a/806/DEPENDENCIES/224.sci +++ /dev/null @@ -1,5 +0,0 @@ -S1=1.0//specific gravity of liquid in pipe A
-S2=0.95//specific gravity of manometric liquid
-S3=1.0//specific gravity of liquid in pipe B
-h1=280//mm
-h3=1000//mm
\ No newline at end of file diff --git a/806/DEPENDENCIES/225.sci b/806/DEPENDENCIES/225.sci deleted file mode 100755 index 2d2b80d0a..000000000 --- a/806/DEPENDENCIES/225.sci +++ /dev/null @@ -1,10 +0,0 @@ -S1=0.83
-S2=13.6
-S3=0.83
-h1=0.150//mm
-h2=0.070//mm
-h3=0.120//mm
-pb=10//psi
-pa=20//psi
-h=.720//mm of Hg
-p=9810//weight density of water
\ No newline at end of file diff --git a/806/DEPENDENCIES/226.sci b/806/DEPENDENCIES/226.sci deleted file mode 100755 index 7113b8b5f..000000000 --- a/806/DEPENDENCIES/226.sci +++ /dev/null @@ -1,5 +0,0 @@ -S1=0.83//Specific gravity of liquid in pipe A
-S2=13.6//Specific gravity of manometric liquid
-S3=0.83//Specific gravity of liquid in pope B
-h1=150//mm
-h3=120//mm
\ No newline at end of file diff --git a/806/DEPENDENCIES/22one.sci b/806/DEPENDENCIES/22one.sci deleted file mode 100755 index 7bcb5f913..000000000 --- a/806/DEPENDENCIES/22one.sci +++ /dev/null @@ -1,5 +0,0 @@ -S1=0.86//specifc gravity of liquid in pipe A
-S2=1//Specifc gravity of manometric liquid
-h1=150//mm
-h2=90//mm
-H=720//mm of Hg
\ No newline at end of file diff --git a/806/DEPENDENCIES/23.sci b/806/DEPENDENCIES/23.sci deleted file mode 100755 index 4f1301f55..000000000 --- a/806/DEPENDENCIES/23.sci +++ /dev/null @@ -1,2 +0,0 @@ -a=12//kg/m^4
-h=10//meter
\ No newline at end of file diff --git a/806/DEPENDENCIES/232.sci b/806/DEPENDENCIES/232.sci deleted file mode 100755 index b6b51e45c..000000000 --- a/806/DEPENDENCIES/232.sci +++ /dev/null @@ -1,3 +0,0 @@ -f=1//MN
-d1=0.040//mm(Diameter of piston)
-d2=0.240//mm(Diameter of cylinder)
diff --git a/806/DEPENDENCIES/242.sci b/806/DEPENDENCIES/242.sci deleted file mode 100755 index e60301987..000000000 --- a/806/DEPENDENCIES/242.sci +++ /dev/null @@ -1,4 +0,0 @@ -a=3//ft
-b=5//ft
-c=4//ft
-p=55//lb/ft^3
\ No newline at end of file diff --git a/806/DEPENDENCIES/246.sci b/806/DEPENDENCIES/246.sci deleted file mode 100755 index d0eff33a7..000000000 --- a/806/DEPENDENCIES/246.sci +++ /dev/null @@ -1,4 +0,0 @@ -h=6//ft(Height of gate)
-w=4//ft(width of the gate)
-H=10//ft(height of water from bootom of gate)
-p=9810//Unit weight of water
\ No newline at end of file diff --git a/806/DEPENDENCIES/247.sci b/806/DEPENDENCIES/247.sci deleted file mode 100755 index 11c480f91..000000000 --- a/806/DEPENDENCIES/247.sci +++ /dev/null @@ -1,4 +0,0 @@ -h=6//feet(Height of gate)
-w=4//feet(Width of gate)
-H=10//feet(Total water depth)
-p=62.455//lb/ft^3(Weight density of water)
diff --git a/806/DEPENDENCIES/24one.sci b/806/DEPENDENCIES/24one.sci deleted file mode 100755 index 2fa6c63f2..000000000 --- a/806/DEPENDENCIES/24one.sci +++ /dev/null @@ -1,4 +0,0 @@ -h=6//m(Height of triangular gate)
-b=6//m(base of triangle)
-h1=4//m(Height of water above the vertex of gate)
-p=9810//N/m^3(Weight density of water)
\ No newline at end of file diff --git a/806/DEPENDENCIES/253.sci b/806/DEPENDENCIES/253.sci deleted file mode 100755 index 39108cb03..000000000 --- a/806/DEPENDENCIES/253.sci +++ /dev/null @@ -1,4 +0,0 @@ -h=6//feet(Height of gate)
-w=4//feet(Width of gate)
-H=10//feet(Total water depth)
-p=9810//N/m^3(Weight density of water)
\ No newline at end of file diff --git a/806/DEPENDENCIES/258.sci b/806/DEPENDENCIES/258.sci deleted file mode 100755 index 16ab7fda0..000000000 --- a/806/DEPENDENCIES/258.sci +++ /dev/null @@ -1,2 +0,0 @@ -h=1//m(height of flash board)
-w=1//m(width of flash board)
\ No newline at end of file diff --git a/806/DEPENDENCIES/263.sci b/806/DEPENDENCIES/263.sci deleted file mode 100755 index 05f8de687..000000000 --- a/806/DEPENDENCIES/263.sci +++ /dev/null @@ -1,4 +0,0 @@ -a=2.8//m
-b=2.1//m
-w=2//m(Width of gate)
-p=10000//N/m^3(Weight density of liquid)
\ No newline at end of file diff --git a/806/DEPENDENCIES/269.sci b/806/DEPENDENCIES/269.sci deleted file mode 100755 index 527926d6b..000000000 --- a/806/DEPENDENCIES/269.sci +++ /dev/null @@ -1,7 +0,0 @@ -p=54//lb/ft^3(Weigth density of liquid)
-h1=12//feet(Liquid height on one side of the gate)
-h2=8//feet(Liquid height on other side of the gate)
-b=8//feet
-c=6//feet
-w=6//feet(Width of gate)
-W=2000//kg(Mass of gate)
\ No newline at end of file diff --git a/806/DEPENDENCIES/278.sci b/806/DEPENDENCIES/278.sci deleted file mode 100755 index e6937fede..000000000 --- a/806/DEPENDENCIES/278.sci +++ /dev/null @@ -1,4 +0,0 @@ -h=3//m(Height of water above the upper edge of gate)
-r=2//m(Radius of gate)
-w=2//m(Width of gate)
-p=9810//N/m^3(Weight density of water)
diff --git a/806/DEPENDENCIES/279.sci b/806/DEPENDENCIES/279.sci deleted file mode 100755 index 21b370ec8..000000000 --- a/806/DEPENDENCIES/279.sci +++ /dev/null @@ -1,3 +0,0 @@ -p=9000//N/m^3(Weight density of the liquid)
-w=2//m(Width of the gate)
-h=2//m(Water level)
\ No newline at end of file diff --git a/806/DEPENDENCIES/282.sci b/806/DEPENDENCIES/282.sci deleted file mode 100755 index 85db00f71..000000000 --- a/806/DEPENDENCIES/282.sci +++ /dev/null @@ -1,4 +0,0 @@ -w=2//m(Width of gate)
-r=1.5//m(Radius of gate)
-h=4.5//m(Height of water above the top edge of gate)
-p=9810//N/m^3(Weight density of water)
\ No newline at end of file diff --git a/806/DEPENDENCIES/2_21.sci b/806/DEPENDENCIES/2_21.sci deleted file mode 100755 index ffd57a5d5..000000000 --- a/806/DEPENDENCIES/2_21.sci +++ /dev/null @@ -1,4 +0,0 @@ -S=0.75//Specific gravity
-p=115//kPa abs
-h=2.0//meter
-P=9.810//(kN/m^3)weight density
\ No newline at end of file diff --git a/806/DEPENDENCIES/2_22.sci b/806/DEPENDENCIES/2_22.sci deleted file mode 100755 index 0253dd707..000000000 --- a/806/DEPENDENCIES/2_22.sci +++ /dev/null @@ -1,5 +0,0 @@ -h1=80//mm of H2O
-h2=60//mm
-S2=2.94//specifc gravity
-S=13.6//specific gravity of mercury
-S1=1//specific gravity of water
\ No newline at end of file diff --git a/806/DEPENDENCIES/2_33.sci b/806/DEPENDENCIES/2_33.sci deleted file mode 100755 index 05eefa61e..000000000 --- a/806/DEPENDENCIES/2_33.sci +++ /dev/null @@ -1,4 +0,0 @@ -h=730//mm-Hg(Barometer reading)
-p=-10//kPa(Pressure)
-S=13.6//specific gravity of mercury
-P=9810//N/m^3(Weight density of water)
\ No newline at end of file diff --git a/806/DEPENDENCIES/2_34.sci b/806/DEPENDENCIES/2_34.sci deleted file mode 100755 index b05ec07c7..000000000 --- a/806/DEPENDENCIES/2_34.sci +++ /dev/null @@ -1,2 +0,0 @@ -h=29//inches-Hg(Barometer reading)
-p=7//psi(Pressure)
\ No newline at end of file diff --git a/806/DEPENDENCIES/2_41.sci b/806/DEPENDENCIES/2_41.sci deleted file mode 100755 index 014cb9492..000000000 --- a/806/DEPENDENCIES/2_41.sci +++ /dev/null @@ -1,2 +0,0 @@ -S=0.80//specific gravity of oil
-h=60//cm
\ No newline at end of file diff --git a/806/DEPENDENCIES/2_42.sci b/806/DEPENDENCIES/2_42.sci deleted file mode 100755 index 927ab13b4..000000000 --- a/806/DEPENDENCIES/2_42.sci +++ /dev/null @@ -1,4 +0,0 @@ -h1=0.5//m
-h2=0.2//m
-S=1
-p=9810//N/m^3(Weight density of water)
\ No newline at end of file diff --git a/806/DEPENDENCIES/2_43.sci b/806/DEPENDENCIES/2_43.sci deleted file mode 100755 index 5077b6a16..000000000 --- a/806/DEPENDENCIES/2_43.sci +++ /dev/null @@ -1,6 +0,0 @@ -h1=2//ft
-h2=1//ft
-h3=4//ft
-S1=0.80
-S2=0.65
-S3=1
\ No newline at end of file diff --git a/806/DEPENDENCIES/2_44.sci b/806/DEPENDENCIES/2_44.sci deleted file mode 100755 index 67778c4c5..000000000 --- a/806/DEPENDENCIES/2_44.sci +++ /dev/null @@ -1,7 +0,0 @@ -h1=0.38//m
-h2=0.33//m
-h3=0.6//m
-S1=0.8
-S2=3.0
-S3=1.0
-p=9.81//kN/m^2(Weight density of water)
\ No newline at end of file diff --git a/806/DEPENDENCIES/2_45.sci b/806/DEPENDENCIES/2_45.sci deleted file mode 100755 index 24ebebd41..000000000 --- a/806/DEPENDENCIES/2_45.sci +++ /dev/null @@ -1,3 +0,0 @@ -h=0.5//m
-S=13.6//Specific gravity of mercury
-p=9810//N/m^3(Weight density of water)
\ No newline at end of file diff --git a/806/DEPENDENCIES/2_53.sci b/806/DEPENDENCIES/2_53.sci deleted file mode 100755 index f97e569e5..000000000 --- a/806/DEPENDENCIES/2_53.sci +++ /dev/null @@ -1,3 +0,0 @@ -b=3//m(Breadth of rectangular surface)
-l=4//m(length of rectangular surface)
-h=6//m(Distance between the oil surface and the lower 3-m edge)
\ No newline at end of file diff --git a/806/DEPENDENCIES/2_62.sci b/806/DEPENDENCIES/2_62.sci deleted file mode 100755 index f650eed2c..000000000 --- a/806/DEPENDENCIES/2_62.sci +++ /dev/null @@ -1,3 +0,0 @@ -d=5000//mm(Diameter of pipe)
-p=1.4//MPa
-ts=55//MPa(Allowable tensile stress)
\ No newline at end of file diff --git a/806/DEPENDENCIES/2_66.sci b/806/DEPENDENCIES/2_66.sci deleted file mode 100755 index 95e30bab0..000000000 --- a/806/DEPENDENCIES/2_66.sci +++ /dev/null @@ -1,3 +0,0 @@ -d=50//mm(Inner diameter of pipe)
-t=5//m(thickness of pipe)
-p=0.89//MPa(Pressure on pipe wall)
\ No newline at end of file diff --git a/806/DEPENDENCIES/2_71.sci b/806/DEPENDENCIES/2_71.sci deleted file mode 100755 index 75eefdccc..000000000 --- a/806/DEPENDENCIES/2_71.sci +++ /dev/null @@ -1,6 +0,0 @@ -h=0.25//m(Height of slab)
-l=1//m(Length of slab)
-w=1//m(Width of slab)
-S=0.50//Specific gravity of slab
-p=9810//N/m^3(Weight density of slab)
-W1=400//N(Extra load)
\ No newline at end of file diff --git a/806/DEPENDENCIES/2_82.sci b/806/DEPENDENCIES/2_82.sci deleted file mode 100755 index 8b1d1f6da..000000000 --- a/806/DEPENDENCIES/2_82.sci +++ /dev/null @@ -1,5 +0,0 @@ -a=1//m(Side of cube)
-m=550//kg(Mass of cube)
-g=9.81//(Acceleration due to gravity)
-S=0.90//specifc gravity of oil
-p=9810//N/m^3(Weight density of oil)
\ No newline at end of file diff --git a/806/DEPENDENCIES/45.sci b/806/DEPENDENCIES/45.sci deleted file mode 100755 index 989daa38f..000000000 --- a/806/DEPENDENCIES/45.sci +++ /dev/null @@ -1,5 +0,0 @@ -v1=3//m/s
-v2=10//m/s
-h1=2//m
-h2=1//m
-p=9.81//kN/m^3
\ No newline at end of file diff --git a/806/DEPENDENCIES/46.sci b/806/DEPENDENCIES/46.sci deleted file mode 100755 index 3d5eebf39..000000000 --- a/806/DEPENDENCIES/46.sci +++ /dev/null @@ -1,4 +0,0 @@ -d1=6//inch
-d2=4//inches
-a=3//lb/inch^2(p1-p2)
-s=0.9//specific gravity of oil
\ No newline at end of file diff --git a/806/DEPENDENCIES/47.sci b/806/DEPENDENCIES/47.sci deleted file mode 100755 index c969f5540..000000000 --- a/806/DEPENDENCIES/47.sci +++ /dev/null @@ -1,5 +0,0 @@ -z1=15//m
-d2=1//m(Diameter of Outflow)
-g=9.81//m/s^2(Acceleration due to gravity)
-A=20000000//m^2(Area of reservoir)
-H=20//mm(Depth of liquid)
diff --git a/806/DEPENDENCIES/71.sci b/806/DEPENDENCIES/71.sci deleted file mode 100755 index 44ee72c13..000000000 --- a/806/DEPENDENCIES/71.sci +++ /dev/null @@ -1,6 +0,0 @@ -l=30//m(Length of plate)
-w=3//m(WIdth of plate)
-U=6//m/s^2(Speed of plate)
-v=1.007*1e-6//kinematic viscosity of water
-p=998.2//kg/m^3(Density of water at 20 degree celsius)
-l1=3//m
diff --git a/806/DEPENDENCIES/72.sci b/806/DEPENDENCIES/72.sci deleted file mode 100755 index e7627e906..000000000 --- a/806/DEPENDENCIES/72.sci +++ /dev/null @@ -1,8 +0,0 @@ -d1=4*1e-6//m(Diameter of clay particle)
-d2=1e-3//m(Diameter of sand particles)
-p=9764//N/m^3(Weight density of water)
-S2=2.65//specific gravity of sand particles
-S1=1.6//specific gravity of clay particles
-v=0.8*1e-3//N.s/m^2(Kinematic viscosity at 30 degree celsius)
-Cd=0.7
-r=995.7//(kg/m^3)Mass density of water
diff --git a/806/DEPENDENCIES/82.sci b/806/DEPENDENCIES/82.sci deleted file mode 100755 index 0d2ca9b54..000000000 --- a/806/DEPENDENCIES/82.sci +++ /dev/null @@ -1,7 +0,0 @@ -qn=0//ft/s(Velocity at nose)
-q=30//ft/s(Velocity of submarine)
-q1=50//ft/s(velocity of point A)
-g=32.174//ft/s^2(acceleration due to gravity)
-hn=0//ft
-ha=5//ft(Height of point A above the nose)
-p=1.935//slugs/ft^3
diff --git a/806/DEPENDENCIES/83.sci b/806/DEPENDENCIES/83.sci deleted file mode 100755 index 342d67414..000000000 --- a/806/DEPENDENCIES/83.sci +++ /dev/null @@ -1,4 +0,0 @@ -s1=0.2//m^3(strength of source)
-s2=1//m^3(strength of vortex)
-x=1//m
-y=0.5//m
@@ -28,9 +28,79 @@ For example, Exa~3.51 means solved example 3.51 of this book. Sec~2.3 means a sc \vspace*{3cm} \tableofcontents \listofcode +\curlable{AP~4} +\begin{code} +\label{AP:284} +\tcaption {electrostatic}{electrostatic} +\lstinputlisting{../24/DEPENDENCIES/electrostatics.sci} +\end{code} + +\curlable{AP~5} +\begin{code} +\label{AP:283} +\tcaption {Example 17-1}{Example 17-1} +\lstinputlisting{../24/DEPENDENCIES/Example17_1.sce} +\end{code} + +\curlable{AP~6} +\begin{code} +\label{AP:282} +\tcaption {Bernauli's Equation}{Bernauli's Equation} +\lstinputlisting{../24/DEPENDENCIES/Bernauli.sci} +\end{code} + +\curlable{AP~7} +\begin{code} +\label{AP:277} +\tcaption {Cross Product}{Cross Product} +\lstinputlisting{../24/DEPENDENCIES/cross_product.sci} +\end{code} + +\curlable{AP~8} +\begin{code} +\label{AP:281} +\tcaption {Example 11-7}{Example 11-7} +\lstinputlisting{../24/DEPENDENCIES/Example11_7.sce} +\end{code} + \newpage +\curlable{AP~9} +\begin{code} +\label{AP:280} +\tcaption {collision}{collision} +\lstinputlisting{../24/DEPENDENCIES/collision.sci} +\end{code} + \vspace*{3cm} \listoffigures +\curlable{AP~10} +\begin{code} +\label{AP:279} +\tcaption {Example 4-3}{Example 4-3} +\lstinputlisting{../24/DEPENDENCIES/Example4_3.sce} +\end{code} + +\curlable{AP~11} +\begin{code} +\label{AP:278} +\tcaption {Example 4-2a}{Example 4-2a} +\lstinputlisting{../24/DEPENDENCIES/Example4_2a.sce} +\end{code} + +\curlable{AP~12} +\begin{code} +\label{AP:276} +\tcaption {Example 2-1b}{Example 2-1b} +\lstinputlisting{../24/DEPENDENCIES/Example2_1b.sce} +\end{code} + +\curlable{AP~13} +\begin{code} +\label{AP:275} +\tcaption {Example 2-1a}{Example 2-1a} +\lstinputlisting{../24/DEPENDENCIES/Example2_1a.sce} +\end{code} + \chapter{Measurement} \vspace*{10mm} diff --git a/latex/TEX_final.aux b/latex/TEX_final.aux index b699d0688..c94318a0a 100644 --- a/latex/TEX_final.aux +++ b/latex/TEX_final.aux @@ -20,818 +20,848 @@ \bibstyle{plain} \BKM@entry{id=1,dest={636861707465722A2E32},srcline={92}}{} \@writefile{toc}{\contentsline {chapter}{\numberline {List 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-LaTeX Warning: Reference `AP:284' on page 177 undefined on input line 2440. - -(../24/CH25/EX25.6/Example25_6.sce) [177] +(../24/CH25/EX25.4/Example25_4.sce [181]) (../24/CH25/EX25.6/Example25_6.sce) +[182] Chapter 26. +(../24/CH26/EX26.1/Example26_1.sce) [183 -LaTeX Warning: Reference `AP:284' on page 178 undefined on input line 2455. - -(../24/CH26/EX26.1/Example26_1.sce) - -LaTeX Warning: Reference `AP:284' on page 178 undefined on input line 2468. - -[178 - -] (../24/CH26/EX26.2/Example26_2.sce) (../24/CH26/EX26.3/Example26_3.sce -[179]) - -LaTeX Warning: Reference `AP:284' on page 180 undefined on input line 2492. - -(../24/CH26/EX26.4/Example26_4.sce) [180] - -LaTeX Warning: Reference `AP:284' on page 181 undefined on input line 2505. - -(../24/CH26/EX26.5/Example26_5.sce) - -LaTeX Warning: Reference `AP:284' on page 181 undefined on input line 2518. - -(../24/CH26/EX26.6/Example26_6.sce [181] [182]) [183] +] (../24/CH26/EX26.2/Example26_2.sce) +(../24/CH26/EX26.3/Example26_3.sce [184]) (../24/CH26/EX26.4/Example26_4.sce) +[185] (../24/CH26/EX26.5/Example26_5.sce) (../24/CH26/EX26.6/Example26_6.sce +[186] [187]) [188] Chapter 27. -(../24/CH27/EX27.1/Example27_1.sce) (../24/CH27/EX27.2/Example27_2.sce [184 +(../24/CH27/EX27.1/Example27_1.sce) (../24/CH27/EX27.2/Example27_2.sce [189 ]) -(../24/CH27/EX27.3/Example27_3.sce [185]) (../24/CH27/EX27.4/Example27_4.sce) -(../24/CH27/EX27.5/Example27_5.sce [186]) (../24/CH27/EX27.6/Example27_6.sce) -[187] +(../24/CH27/EX27.3/Example27_3.sce [190]) (../24/CH27/EX27.4/Example27_4.sce) +(../24/CH27/EX27.5/Example27_5.sce [191]) (../24/CH27/EX27.6/Example27_6.sce) +[192] Chapter 28. -(../24/CH28/EX28.1/Example28_1.sce) [188 +(../24/CH28/EX28.1/Example28_1.sce) [193 ] (../24/CH28/EX28.2/Example28_2.sce) -[189] (../24/CH28/EX28.3/Example28_3.sce) (../24/CH28/EX28.4/Example28_4.sce -[190]) (../24/CH28/EX28.5/Example28_5.sce) [191] [192] +[194] (../24/CH28/EX28.3/Example28_3.sce) (../24/CH28/EX28.4/Example28_4.sce +[195]) (../24/CH28/EX28.5/Example28_5.sce) [196] [197] Chapter 29. -(../24/CH29/EX29.1/Example29_1.sce) (../24/CH29/EX29.2/Example29_2.sce [193 +(../24/CH29/EX29.1/Example29_1.sce) (../24/CH29/EX29.2/Example29_2.sce [198 ]) -(../24/CH29/EX29.3/Example29_3.sce) [194] (../24/CH29/EX29.4/Example29_4.sce) -(../24/CH29/EX29.5/Example29_5.sce [195]) (../24/CH29/EX29.6/Example29_6.sce) -[196] (../24/CH29/EX29.7/Example29_7.sce) (../24/CH29/EX29.8/Example29_8.sce -[197]) [198] +(../24/CH29/EX29.3/Example29_3.sce) [199] (../24/CH29/EX29.4/Example29_4.sce) +(../24/CH29/EX29.5/Example29_5.sce [200]) (../24/CH29/EX29.6/Example29_6.sce) +[201] (../24/CH29/EX29.7/Example29_7.sce) (../24/CH29/EX29.8/Example29_8.sce +[202]) [203] Chapter 30. -(../24/CH30/EX30.2/Example30_2.sce) [199 +(../24/CH30/EX30.2/Example30_2.sce) [204 ] (../24/CH30/EX30.3/Example30_3.sce) -(../24/CH30/EX30.4/Example30_4.sce [200]) [201] +(../24/CH30/EX30.4/Example30_4.sce [205]) [206] Chapter 31. -(../24/CH31/EX31.1/Example31_1.sce) (../24/CH31/EX31.2/Example31_2.sce [202 +(../24/CH31/EX31.1/Example31_1.sce) (../24/CH31/EX31.2/Example31_2.sce [207 ]) -(../24/CH31/EX31.3/Example31_3.sce [203]) (../24/CH31/EX31.4/Example31_4.sce) -(../24/CH31/EX31.5/Example31_5.sce [204]) (../24/CH31/EX31.6/Example31_6.sce) -[205] (../24/CH31/EX31.7/Example31_7.sce) (../24/CH31/EX31.8/Example31_8.sce -[206]) (../24/CH31/EX31.9/Example31_9.sce) [207] [208] +(../24/CH31/EX31.3/Example31_3.sce [208]) (../24/CH31/EX31.4/Example31_4.sce) +(../24/CH31/EX31.5/Example31_5.sce [209]) (../24/CH31/EX31.6/Example31_6.sce) +[210] (../24/CH31/EX31.7/Example31_7.sce) (../24/CH31/EX31.8/Example31_8.sce +[211]) (../24/CH31/EX31.9/Example31_9.sce) [212] [213] Chapter 32. -(../24/CH32/EX32.1/Example32_1.sce) [209 +(../24/CH32/EX32.1/Example32_1.sce) [214 ] (../24/CH32/EX32.2/Example32_2.sce) -(../24/CH32/EX32.3/Example32_3.sce [210]) [211] +(../24/CH32/EX32.3/Example32_3.sce [215]) [216] Chapter 33. -(../24/CH33/EX33.1/Example33_1.sce) (../24/CH33/EX33.2/Example33_2.sce [212 +(../24/CH33/EX33.1/Example33_1.sce) (../24/CH33/EX33.2/Example33_2.sce [217 ]) -(../24/CH33/EX33.3/Example33_3.sce [213]) (../24/CH33/EX33.4/Example33_4.sce) -[214] (../24/CH33/EX33.5/Example33_5.sce) (../24/CH33/EX33.6/Example33_6.sce -[215]) (../24/CH33/EX33.7/Example33_7.sce [216]) -(../24/CH33/EX33.8/Example33_8.sce) [217] (../24/CH33/EX33.9/Example33_9.sce) -[218] +(../24/CH33/EX33.3/Example33_3.sce [218]) (../24/CH33/EX33.4/Example33_4.sce) +[219] (../24/CH33/EX33.5/Example33_5.sce) (../24/CH33/EX33.6/Example33_6.sce +[220]) (../24/CH33/EX33.7/Example33_7.sce [221]) +(../24/CH33/EX33.8/Example33_8.sce) [222] (../24/CH33/EX33.9/Example33_9.sce) +[223] Chapter 34. (../24/CH34/EX34.1/Example34_1.sce) -LaTeX Warning: Reference `AP:273' on page 219 undefined on input line 3035. +LaTeX Warning: Reference `AP:273' on page 224 undefined on input line 3105. -[219 +[224 ] (../24/CH34/EX34.2/Example34_2.sce) (../24/CH34/EX34.3/Example34_3.sce -[220]) (../24/CH34/EX34.4/Example34_4.sce [221]) -(../24/CH34/EX34.5/Example34_5.sce) [222] +[225]) (../24/CH34/EX34.4/Example34_4.sce [226]) +(../24/CH34/EX34.5/Example34_5.sce) [227] Chapter 35. -(../24/CH35/EX35.1/Example35_1.sce) (../24/CH35/EX35.2/Example35_2.sce [223 +(../24/CH35/EX35.1/Example35_1.sce) (../24/CH35/EX35.2/Example35_2.sce [228 ]) -(../24/CH35/EX35.3/Example35_3.sce [224]) (../24/CH35/EX35.4/Example35_4.sce) -[225] +(../24/CH35/EX35.3/Example35_3.sce [229]) (../24/CH35/EX35.4/Example35_4.sce) +[230] Chapter 36. -(../24/CH36/EX36.1/Example36_1.sce) [226 +(../24/CH36/EX36.1/Example36_1.sce) [231 ] (../24/CH36/EX36.2/Example36_2.sce) -(../24/CH36/EX36.3/Example36_3.sce [227]) (../24/CH36/EX36.4/Example36_4.sce) -(../24/CH36/EX36.5/Example36_5.sce [228]) (../24/CH36/EX36.6/Example36_6.sce) -[229] +(../24/CH36/EX36.3/Example36_3.sce [232]) (../24/CH36/EX36.4/Example36_4.sce) +(../24/CH36/EX36.5/Example36_5.sce [233]) (../24/CH36/EX36.6/Example36_6.sce) +[234] Chapter 37. -(../24/CH37/EX37.1/Example37_1.sce) [230 +(../24/CH37/EX37.1/Example37_1.sce) [235 ] (../24/CH37/EX37.2/Example37_2.sce) -(../24/CH37/EX37.3/Example37_3.sce [231]) (../24/CH37/EX37.4/Example37_4.sce) -[232] (../24/CH37/EX37.5/Example37_5.sce) [233] [234] +(../24/CH37/EX37.3/Example37_3.sce [236]) (../24/CH37/EX37.4/Example37_4.sce) +[237] (../24/CH37/EX37.5/Example37_5.sce) [238] [239] Chapter 38. -(../24/CH38/EX38.1/Example38_1.sce) (../24/CH38/EX38.2/Example38_2.sce [235 +(../24/CH38/EX38.1/Example38_1.sce) (../24/CH38/EX38.2/Example38_2.sce [240 ]) -(../24/CH38/EX38.3/Example38_3.sce) (../24/CH38/EX38.4/Example38_4.sce [236]) -(../24/CH38/EX38.5/Example38_5.sce [237]) (../24/CH38/EX38.6/Example38_6.sce) -[238] (../24/CH38/EX38.7/Example38_7.sce) [239] +(../24/CH38/EX38.3/Example38_3.sce) (../24/CH38/EX38.4/Example38_4.sce [241]) +(../24/CH38/EX38.5/Example38_5.sce [242]) (../24/CH38/EX38.6/Example38_6.sce) +[243] (../24/CH38/EX38.7/Example38_7.sce) [244] Chapter 39. -(../24/CH39/EX39.1/Example39_1.sce) (../24/CH39/EX39.2/Example39_2.sce [240 +(../24/CH39/EX39.1/Example39_1.sce) (../24/CH39/EX39.2/Example39_2.sce [245 ]) -(../24/CH39/EX39.3/Example39_3.sce) [241] (../24/CH39/EX39.4/Example39_4.sce) -(../24/CH39/EX39.5/Example39_5.sce [242]) (../24/CH39/EX39.6/Example39_6.sce) -(../24/CH39/EX39.7/Example39_7.sce [243]) [244] +(../24/CH39/EX39.3/Example39_3.sce) [246] (../24/CH39/EX39.4/Example39_4.sce) +(../24/CH39/EX39.5/Example39_5.sce [247]) (../24/CH39/EX39.6/Example39_6.sce) +(../24/CH39/EX39.7/Example39_7.sce [248]) [249] Chapter 40. -(../24/CH40/EX40.1/Example40_1.sce [245 +(../24/CH40/EX40.1/Example40_1.sce [250 ]) (../24/CH40/EX40.3/Example40_3.sce -[246]) (../24/CH40/EX40.4/Example40_4.sce) [247] -(../24/CH40/EX40.6/Example40_6.sce) (../24/CH40/EX40.8/Example40_8.sce [248]) -[249] +[251]) (../24/CH40/EX40.4/Example40_4.sce) [252] +(../24/CH40/EX40.6/Example40_6.sce) (../24/CH40/EX40.8/Example40_8.sce [253]) +[254] Chapter 41. -(../24/CH41/EX41.1/Example41_1.sce) (../24/CH41/EX41.2/Example41_2.sce [250 +(../24/CH41/EX41.1/Example41_1.sce) (../24/CH41/EX41.2/Example41_2.sce [255 ]) (../24/CH41/EX41.3/Example41_3.sce) -<../24/CH41/EX41.3/Example41_3a.jpg, id=6227, 371.88937pt x 345.54094pt> +<../24/CH41/EX41.3/Example41_3a.jpg, id=6450, 371.88937pt x 345.54094pt> File: ../24/CH41/EX41.3/Example41_3a.jpg Graphic file (type jpg) <use ../24/CH41/EX41.3/Example41_3a.jpg> Package pdftex.def Info: ../24/CH41/EX41.3/Example41_3a.jpg used on input line -3525. +3595. (pdftex.def) Requested size: 361.34999pt x 335.75955pt. (../24/CH41/EX41.4/Example41_4.sce -[251] [252 <../24/CH41/EX41.3/Example41_3a.jpg>]) -(../24/CH41/EX41.5/Example41_5.sce) (../24/CH41/EX41.6/Example41_6.sce [253]) -[254] +[256] [257 <../24/CH41/EX41.3/Example41_3a.jpg>]) +(../24/CH41/EX41.5/Example41_5.sce) (../24/CH41/EX41.6/Example41_6.sce [258]) +[259] Chapter 42. -(../24/CH42/EX42.1/Example42_1.sce) (../24/CH42/EX42.2/Example42_2.sce [255 +(../24/CH42/EX42.1/Example42_1.sce) (../24/CH42/EX42.2/Example42_2.sce [260 ]) -(../24/CH42/EX42.3/Example42_3.sce) [256] (../24/CH42/EX42.4/Example42_4.sce) -(../24/CH42/EX42.5/Example42_5.sce [257]) (../24/CH42/EX42.6/Example42_6.sce) -[258] (../24/CH42/EX42.7/Example42_7.sce) [259] +(../24/CH42/EX42.3/Example42_3.sce) [261] (../24/CH42/EX42.4/Example42_4.sce) +(../24/CH42/EX42.5/Example42_5.sce [262]) (../24/CH42/EX42.6/Example42_6.sce) +[263] (../24/CH42/EX42.7/Example42_7.sce) [264] Chapter 43. -(../24/CH43/EX43.1/Example43_1.sce) [260 +(../24/CH43/EX43.1/Example43_1.sce) [265 ] (../24/CH43/EX43.2/Example43_2.sce) -(../24/CH43/EX43.3/Example43_3.sce) [261] (../24/CH43/EX43.4/Example43_4.sce) -(../24/CH43/EX43.5/Example43_5.sce) [262] (../24/CH43/EX43.6/Example43_6.sce) -[263] (../24/CH43/EX43.7/Example43_7.sce) (../24/CH43/EX43.8/Example43_8.sce) -[264] (../24/CH43/EX43.9/Example43_9.sce) (../24/CH43/EX43.10/Example43_10.sce -[265]) [266] +(../24/CH43/EX43.3/Example43_3.sce) [266] (../24/CH43/EX43.4/Example43_4.sce) +(../24/CH43/EX43.5/Example43_5.sce) [267] (../24/CH43/EX43.6/Example43_6.sce) +[268] (../24/CH43/EX43.7/Example43_7.sce) (../24/CH43/EX43.8/Example43_8.sce) +[269] (../24/CH43/EX43.9/Example43_9.sce) (../24/CH43/EX43.10/Example43_10.sce +[270]) [271] Chapter 44. -(../24/CH44/EX44.1/Example44_1.sce) (../24/CH44/EX44.2/Example44_2.sce [267 +(../24/CH44/EX44.1/Example44_1.sce) (../24/CH44/EX44.2/Example44_2.sce [272 ] -[268]) (../24/CH44/EX44.3/Example44_3.sce) (../24/CH44/EX44.4/Example44_4.sce -[269]) (../24/CH44/EX44.5/Example44_5.sce) [270] -(../24/CH44/EX44.6/Example44_6.sce) [271] +[273]) (../24/CH44/EX44.3/Example44_3.sce) (../24/CH44/EX44.4/Example44_4.sce +[274]) (../24/CH44/EX44.5/Example44_5.sce) [275] +(../24/CH44/EX44.6/Example44_6.sce) [276] Chapter 45. -(../24/CH45/EX45.1/Example45_1.sce [272 +(../24/CH45/EX45.1/Example45_1.sce [277 ]) (../24/CH45/EX45.2/Example45_2.sce) -(../24/CH45/EX45.3/Example45_3.sce [273]) (../24/CH45/EX45.6/Example45_6.sce) -[274] (../24/CH45/EX45.7/Example45_7.sce) [275] (../24/DEPENDENCIES/quantum.sci +(../24/CH45/EX45.3/Example45_3.sce [278]) (../24/CH45/EX45.6/Example45_6.sce) +[279] (../24/CH45/EX45.7/Example45_7.sce) [280] (../24/DEPENDENCIES/quantum.sci ) ! Missing $ inserted. <inserted text> $ -l.3890 \tcaption {degree_rad}{degree_ +l.3960 \tcaption {degree_rad}{degree_ rad} I've inserted a begin-math/end-math symbol since I think you left one out. Proceed, with fingers crossed. ! Extra }, or forgotten $. -l.3890 \tcaption {degree_rad}{degree_rad} +l.3960 \tcaption {degree_rad}{degree_rad} I've deleted a group-closing symbol because it seems to be spurious, as in `$x}$'. But perhaps the } is legitimate and @@ -1115,7 +1011,7 @@ deleted material, e.g., by typing `I$}'. ! Missing $ inserted. <inserted text> $ -l.3891 ...sting{../24/DEPENDENCIES/degree_rad.sci} +l.3961 ...sting{../24/DEPENDENCIES/degree_rad.sci} I've inserted a begin-math/end-math symbol since I think you left one out. Proceed, with fingers crossed. @@ -1123,7 +1019,7 @@ you left one out. Proceed, with fingers crossed. ! Missing } inserted. <inserted text> } -l.3891 ...sting{../24/DEPENDENCIES/degree_rad.sci} +l.3961 ...sting{../24/DEPENDENCIES/degree_rad.sci} I've inserted something that you may have forgotten. (See the <inserted text> above.) @@ -1134,7 +1030,7 @@ my insertion and my current dilemma will both disappear. ! Missing \endgroup inserted. <inserted text> \endgroup -l.3891 ...sting{../24/DEPENDENCIES/degree_rad.sci} +l.3961 ...sting{../24/DEPENDENCIES/degree_rad.sci} I've inserted something that you may have forgotten. (See the <inserted text> above.) @@ -1145,7 +1041,7 @@ my insertion and my current dilemma will both disappear. ! Missing \endgroup inserted. <inserted text> \endgroup -l.3891 ...sting{../24/DEPENDENCIES/degree_rad.sci} +l.3961 ...sting{../24/DEPENDENCIES/degree_rad.sci} I've inserted something that you may have forgotten. (See the <inserted text> above.) @@ -1153,13 +1049,13 @@ With luck, this will get me unwedged. But if you really didn't forget anything, try typing `2' now; then my insertion and my current dilemma will both disappear. -[276 +[281 ] ! Undefined control sequence. \lst@GetLineInterval ...r \lst@GLI \lst@linerange \@nil -l.3891 ...sting{../24/DEPENDENCIES/degree_rad.sci} +l.3961 ...sting{../24/DEPENDENCIES/degree_rad.sci} The control sequence at the end of the top line of your error message was never \def'ed. If you have @@ -1172,7 +1068,7 @@ Runaway argument? ! Paragraph ended before \lst@GLI was complete. <to be read again> \par -l.3893 +l.3963 I suspect you've forgotten a `}', causing me to apply this control sequence to too much text. How can we recover? @@ -1189,11 +1085,11 @@ you can ask a wizard to enlarge me. Here is how much of TeX's memory you used: - 18030 strings out of 493013 - 271745 string characters out of 6133328 - 410206 words of memory out of 5000000 - 14367 multiletter control sequences out of 15000+600000 + 18226 strings out of 493013 + 275224 string characters out of 6133328 + 413206 words of memory out of 5000000 + 14369 multiletter control sequences out of 15000+600000 10548 words of font info for 37 fonts, out of 8000000 for 9000 1141 hyphenation exceptions out of 8191 - 258i,7n,40p,391b,2423s stack positions out of 5000i,500n,10000p,200000b,80000s + 258i,7n,40p,391b,2203s stack positions out of 5000i,500n,10000p,200000b,80000s ! ==> Fatal error occurred, no output PDF file produced! diff --git a/latex/TEX_final.tex b/latex/TEX_final.tex index 41da4919b..544930885 100644 --- a/latex/TEX_final.tex +++ b/latex/TEX_final.tex @@ -90,9 +90,79 @@ For example, Exa~3.51 means solved example 3.51 of this book. Sec~2.3 means a sc \vspace*{3cm} \tableofcontents \listofcode +\curlable{AP~4} +\begin{code} +\label{AP:284} +\tcaption {electrostatic}{electrostatic} +\lstinputlisting{../24/DEPENDENCIES/electrostatics.sci} +\end{code} + +\curlable{AP~5} +\begin{code} +\label{AP:283} +\tcaption {Example 17-1}{Example 17-1} +\lstinputlisting{../24/DEPENDENCIES/Example17_1.sce} +\end{code} + +\curlable{AP~6} +\begin{code} +\label{AP:282} +\tcaption {Bernauli's Equation}{Bernauli's Equation} +\lstinputlisting{../24/DEPENDENCIES/Bernauli.sci} +\end{code} + +\curlable{AP~7} +\begin{code} +\label{AP:277} +\tcaption {Cross Product}{Cross Product} +\lstinputlisting{../24/DEPENDENCIES/cross_product.sci} +\end{code} + +\curlable{AP~8} +\begin{code} +\label{AP:281} +\tcaption {Example 11-7}{Example 11-7} +\lstinputlisting{../24/DEPENDENCIES/Example11_7.sce} +\end{code} + \newpage +\curlable{AP~9} +\begin{code} +\label{AP:280} +\tcaption {collision}{collision} +\lstinputlisting{../24/DEPENDENCIES/collision.sci} +\end{code} + \vspace*{3cm} \listoffigures +\curlable{AP~10} +\begin{code} +\label{AP:279} +\tcaption {Example 4-3}{Example 4-3} +\lstinputlisting{../24/DEPENDENCIES/Example4_3.sce} +\end{code} + +\curlable{AP~11} +\begin{code} +\label{AP:278} +\tcaption {Example 4-2a}{Example 4-2a} +\lstinputlisting{../24/DEPENDENCIES/Example4_2a.sce} +\end{code} + +\curlable{AP~12} +\begin{code} +\label{AP:276} +\tcaption {Example 2-1b}{Example 2-1b} +\lstinputlisting{../24/DEPENDENCIES/Example2_1b.sce} +\end{code} + +\curlable{AP~13} +\begin{code} +\label{AP:275} +\tcaption {Example 2-1a}{Example 2-1a} +\lstinputlisting{../24/DEPENDENCIES/Example2_1a.sce} +\end{code} + \chapter{Measurement} \vspace*{10mm} diff --git a/latex/book_1340.pdf b/latex/book_1340.pdf Binary files differindex a6e953acb..e6f69c434 100755 --- a/latex/book_1340.pdf +++ b/latex/book_1340.pdf diff --git a/latex/book_2084.pdf b/latex/book_2084.pdf Binary files differindex 55d93382f..3311c76d2 100755 --- a/latex/book_2084.pdf +++ b/latex/book_2084.pdf diff --git a/latex/book_2465.pdf b/latex/book_2465.pdf Binary files differindex 9aa44cd68..29a56b928 100644 --- a/latex/book_2465.pdf +++ b/latex/book_2465.pdf diff --git a/latex/book_806.pdf b/latex/book_806.pdf Binary files differdeleted file mode 100755 index 38cce4b37..000000000 --- a/latex/book_806.pdf +++ /dev/null diff --git a/latex/latex_test.sh b/latex/latex_test.sh index ab5bfb64d..9282a2d7f 100755 --- a/latex/latex_test.sh +++ b/latex/latex_test.sh @@ -95,7 +95,7 @@ while IFS=# read col1 col2 col3 col4 col5 col6 col7 col8 col9; do if grep -c ".jpg\|.JPEG\|.png\|.PNG\|.jpeg\|.JPG" $CURDIR/Code_Result_files then echo \\newpage >> $CURDIR/TEX - echo \\vspace*{3cm}>>$CURDIR/TEX + echo \\vspace*{3cm}>>$CURDIR/TEX echo \\listoffigures >> $CURDIR/TEX full_flag=1 fi diff --git a/latex/log.txt b/latex/log.txt index edac11c57..e2b8d6746 100755 --- a/latex/log.txt +++ b/latex/log.txt @@ -45,7 +45,7 @@ Package hyperref Message: Driver (autodetected): hpdftex. (/usr/local/texlive/2016/texmf-dist/tex/latex/pdfpages/pppdftex.def)) (/usr/local/texlive/2016/texmf-dist/tex/latex/tocloft/tocloft.sty) (/usr/local/texlive/2016/texmf-dist/tex/latex/listings/lstlang1.sty) -No file TEX_final.aux. +(./TEX_final.aux) (/usr/local/texlive/2016/texmf-dist/tex/latex/hyperref/nameref.sty (/usr/local/texlive/2016/texmf-dist/tex/generic/oberdiek/gettitlestring.sty)) (/usr/local/texlive/2016/texmf-dist/tex/context/base/mkii/supp-pdf.mkii @@ -61,660 +61,561 @@ xt4): destination with the same identifier (name{page.1}) has been already used <to be read again> \relax l.79 \newpage - [1] [2] [3] [4] [5] + [1] [2] (./TEX_final.toc +Overfull \hbox (95.60854pt too wide) detected at line 1 +\OT1/cmr/bx/n/12 List of Scilab Codes +) [3] (./TEX_final.cod) (../24/DEPENDENCIES/electrostatics.sci [4]) +(../24/DEPENDENCIES/Example17_1.sce +(/usr/local/texlive/2016/texmf-dist/tex/latex/base/omscmr.fd)) [5] +(../24/DEPENDENCIES/Bernauli.sci) (../24/DEPENDENCIES/cross_product.sci) +(../24/DEPENDENCIES/Example11_7.sce [6] +(/usr/local/texlive/2016/texmf-dist/tex/latex/base/omlcmr.fd)) [7] +(../24/DEPENDENCIES/collision.sci) (./TEX_final.lof) +(../24/DEPENDENCIES/Example4_3.sce [8]) (../24/DEPENDENCIES/Example4_2a.sce) +(../24/DEPENDENCIES/Example2_1b.sce [9]) (../24/DEPENDENCIES/Example2_1a.sce) +[10] Chapter 1. -(../24/CH1/EX1.1/Example1_1.sce -(/usr/local/texlive/2016/texmf-dist/tex/latex/base/omscmr.fd)) -(../24/CH1/EX1.2/Example1_2.sce [6]) (../24/CH1/EX1.3/Example1_3.sce) -(../24/CH1/EX1.4/Example1_4.sce [7] -(/usr/local/texlive/2016/texmf-dist/tex/latex/base/omlcmr.fd)) [8] +(../24/CH1/EX1.1/Example1_1.sce) (../24/CH1/EX1.2/Example1_2.sce [11]) +(../24/CH1/EX1.3/Example1_3.sce) (../24/CH1/EX1.4/Example1_4.sce [12]) [13] Chapter 2. -(../24/CH2/EX2.1.a/Example2_1a.sce) - -LaTeX Warning: Reference `AP:275' on page 9 undefined on input line 155. - -(../24/CH2/EX2.1.b/Example2_1b.sce [9]) - -LaTeX Warning: Reference `AP:275' on page 10 undefined on input line 168. - - -LaTeX Warning: Reference `AP:276' on page 10 undefined on input line 170. - -(../24/CH2/EX2.1.c/Example2_1c.sce [10]) -<../24/CH2/EX2.1.c/Example2_1c_graph.jpg, id=153, 612.2875pt x 387.4475pt> -<use ../24/CH2/EX2.1.c/Example2_1c_graph.jpg> - -LaTeX Warning: Reference `AP:275' on page 11 undefined on input line 190. - - -LaTeX Warning: Reference `AP:276' on page 11 undefined on input line 192. - -[11] (../24/CH2/EX2.1.d/Example2_1d.sce) [12 <../24/CH2/EX2.1.c/Example2_1c_gra -ph.jpg>] (../24/CH2/EX2.2/Example2_2.sce [13]) -<../24/CH2/EX2.2/Example2_2_graph.jpg, id=225, 612.2875pt x 387.4475pt> +(../24/CH2/EX2.1.a/Example2_1a.sce) (../24/CH2/EX2.1.b/Example2_1b.sce [14]) +(../24/CH2/EX2.1.c/Example2_1c.sce [15]) +<../24/CH2/EX2.1.c/Example2_1c_graph.jpg, id=356, 612.2875pt x 387.4475pt> +<use ../24/CH2/EX2.1.c/Example2_1c_graph.jpg> [16] +(../24/CH2/EX2.1.d/Example2_1d.sce) [17 <../24/CH2/EX2.1.c/Example2_1c_graph.jp +g>] (../24/CH2/EX2.2/Example2_2.sce [18]) +<../24/CH2/EX2.2/Example2_2_graph.jpg, id=430, 612.2875pt x 387.4475pt> <use ../24/CH2/EX2.2/Example2_2_graph.jpg> (../24/CH2/EX2.3/Example2_3.sce) -[14] (../24/CH2/EX2.4/Example2_4.sce [15 <../24/CH2/EX2.2/Example2_2_graph.jpg> -]) (../24/CH2/EX2.5/Example2_5.sce) [16] (../24/CH2/EX2.6/Example2_6.sce -[17]) (../24/CH2/EX2.7/Example2_7.sce [18]) [19] +[19] (../24/CH2/EX2.4/Example2_4.sce [20 <../24/CH2/EX2.2/Example2_2_graph.jpg> +]) (../24/CH2/EX2.5/Example2_5.sce) [21] (../24/CH2/EX2.6/Example2_6.sce +[22]) (../24/CH2/EX2.7/Example2_7.sce [23]) [24] Chapter 3. -LaTeX Warning: Reference `AP:272' on page 20 undefined on input line 280. +LaTeX Warning: Reference `AP:272' on page 25 undefined on input line 350. -(../24/CH3/EX3.1/Example3_1.sce) [20] +(../24/CH3/EX3.1/Example3_1.sce) [25] -LaTeX Warning: Reference `AP:272' on page 21 undefined on input line 293. +LaTeX Warning: Reference `AP:272' on page 26 undefined on input line 363. 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(../24/CH3/EX3.4/Example3_4.sce) -LaTeX Warning: Reference `AP:272' on page 22 undefined on input line 332. - -[22] (../24/CH3/EX3.5/Example3_5.sce) - -LaTeX Warning: Reference `AP:272' on page 23 undefined on input line 345. - -(../24/CH3/EX3.6/Example3_6.sce [23]) - -LaTeX Warning: Reference `AP:277' on page 24 undefined on input line 358. +LaTeX Warning: Reference `AP:272' on page 27 undefined on input line 402. +[27] (../24/CH3/EX3.5/Example3_5.sce) -LaTeX Warning: Reference `AP:272' on page 24 undefined on input line 360. +LaTeX Warning: Reference `AP:272' on page 28 undefined on input line 415. -(../24/CH3/EX3.7/Example3_7.sce) [24] +(../24/CH3/EX3.6/Example3_6.sce [28]) -LaTeX Warning: Reference `AP:277' on page 25 undefined on input line 373. +LaTeX Warning: Reference `AP:272' on page 29 undefined on input line 430. +(../24/CH3/EX3.7/Example3_7.sce) [29] -LaTeX Warning: Reference `AP:272' on page 25 undefined on input line 375. +LaTeX Warning: Reference `AP:272' on page 30 undefined on input line 445. -(../24/CH3/EX3.8/Example3_8.sce) [25] +(../24/CH3/EX3.8/Example3_8.sce) [30] Chapter 4. -(../24/CH4/EX4.1/Example4_1.sce) (../24/CH4/EX4.2.a/Example4_2a.sce [26]) - -LaTeX Warning: Reference `AP:272' on page 27 undefined on input line 412. - - -LaTeX Warning: Reference `AP:278' on page 27 undefined on input line 414. - -(../24/CH4/EX4.2.b/Example4_2b.sce [27]) -<../24/CH4/EX4.2.b/Example4_2b_graph.jpg, id=575, 612.2875pt x 461.725pt> -<use ../24/CH4/EX4.2.b/Example4_2b_graph.jpg> +(../24/CH4/EX4.1/Example4_1.sce) (../24/CH4/EX4.2.a/Example4_2a.sce [31]) -LaTeX Warning: Reference `AP:278' on page 28 undefined on input line 434. +LaTeX Warning: Reference `AP:272' on page 32 undefined on input line 482. -(../24/CH4/EX4.3/Example4_3.sce [28] [29 <../24/CH4/EX4.2.b/Example4_2b_graph.j -pg>]) +(../24/CH4/EX4.2.b/Example4_2b.sce [32]) +<../24/CH4/EX4.2.b/Example4_2b_graph.jpg, id=783, 612.2875pt x 461.725pt> +<use ../24/CH4/EX4.2.b/Example4_2b_graph.jpg> (../24/CH4/EX4.3/Example4_3.sce +[33] [34 <../24/CH4/EX4.2.b/Example4_2b_graph.jpg>]) +(../24/CH4/EX4.4/Example4_4.sce [35]) -LaTeX Warning: Reference `AP:279' on page 30 undefined on input line 447. - -(../24/CH4/EX4.4/Example4_4.sce [30]) - -LaTeX Warning: Reference `AP:272' on page 31 undefined on input line 460. +LaTeX Warning: Reference `AP:272' on page 36 undefined on input line 530. 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(../24/CH4/EX4.7/Example4_7.sce) -LaTeX Warning: Reference `AP:272' on page 33 undefined on input line 499. +LaTeX Warning: Reference `AP:272' on page 38 undefined on input line 569. -[33] (../24/CH4/EX4.8/Example4_8.sce) [34] (../24/CH4/EX4.9/Example4_9.sce) -(../24/CH4/EX4.10/Example4_10.sce [35]) +[38] (../24/CH4/EX4.8/Example4_8.sce) [39] (../24/CH4/EX4.9/Example4_9.sce) +(../24/CH4/EX4.10/Example4_10.sce [40]) -LaTeX Warning: Reference `AP:272' on page 36 undefined on input line 534. +LaTeX Warning: Reference `AP:272' on page 41 undefined on input line 604. -(../24/CH4/EX4.11/Example4_11.sce [36]) [37] +(../24/CH4/EX4.11/Example4_11.sce [41]) [42] Chapter 5. -LaTeX Warning: Reference `AP:272' on page 38 undefined on input line 549. +LaTeX Warning: Reference `AP:272' on page 43 undefined on input line 619. -(../24/CH5/EX5.1/Example5_1.sce) [38] +(../24/CH5/EX5.1/Example5_1.sce) [43] -LaTeX Warning: Reference `AP:272' on page 39 undefined on input line 562. +LaTeX Warning: Reference `AP:272' on page 44 undefined on input line 632. 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(../24/CH6/EX6.1/Example6_1.sce) -LaTeX Warning: Reference `AP:272' on page 50 undefined on input line 708. +LaTeX Warning: Reference `AP:272' on page 55 undefined on input line 778. -[50] (../24/CH6/EX6.2/Example6_2.sce) -<../24/CH6/EX6.2/Example6_2_FBD.jpg, id=1073, 550.30594pt x 383.93437pt> +[55] (../24/CH6/EX6.2/Example6_2.sce) +<../24/CH6/EX6.2/Example6_2_FBD.jpg, id=1283, 550.30594pt x 383.93437pt> <use ../24/CH6/EX6.2/Example6_2_FBD.jpg> -LaTeX Warning: Reference `AP:272' on page 51 undefined on input line 728. +LaTeX Warning: Reference `AP:272' on page 56 undefined on input line 798. -(../24/CH6/EX6.3/Example6_3.sce [51] [52 <../24/CH6/EX6.2/Example6_2_FBD.jpg>]) -<../24/CH6/EX6.3/Example6_3_FBD.jpg, id=1110, 550.30594pt x 383.93437pt> -<use ../24/CH6/EX6.3/Example6_3_FBD.jpg> [53 <../24/CH6/EX6.3/Example6_3_FBD.jp -g>] (../24/CH6/EX6.4/Example6_4.sce) (../24/CH6/EX6.5/Example6_5.sce [54]) -(../24/CH6/EX6.6/Example6_6.sce [55]) (../24/CH6/EX6.7/Example6_7.sce) -(../24/CH6/EX6.8/Example6_8.sce [56]) -<../24/CH6/EX6.8/Example6_8_FBD.jpg, id=1217, 550.30594pt x 383.93437pt> -<use ../24/CH6/EX6.8/Example6_8_FBD.jpg> [57 <../24/CH6/EX6.8/Example6_8_FBD.jp +(../24/CH6/EX6.3/Example6_3.sce [56] [57 <../24/CH6/EX6.2/Example6_2_FBD.jpg>]) +<../24/CH6/EX6.3/Example6_3_FBD.jpg, id=1320, 550.30594pt x 383.93437pt> +<use ../24/CH6/EX6.3/Example6_3_FBD.jpg> [58 <../24/CH6/EX6.3/Example6_3_FBD.jp +g>] (../24/CH6/EX6.4/Example6_4.sce) (../24/CH6/EX6.5/Example6_5.sce [59]) +(../24/CH6/EX6.6/Example6_6.sce [60]) (../24/CH6/EX6.7/Example6_7.sce) +(../24/CH6/EX6.8/Example6_8.sce [61]) +<../24/CH6/EX6.8/Example6_8_FBD.jpg, id=1427, 550.30594pt x 383.93437pt> +<use ../24/CH6/EX6.8/Example6_8_FBD.jpg> [62 <../24/CH6/EX6.8/Example6_8_FBD.jp g>] (../24/CH6/EX6.9/Example6_9.sce) -<../24/CH6/EX6.9/Example6_9_FBD.jpg, id=1232, 383.18156pt x 280.04625pt> -<use ../24/CH6/EX6.9/Example6_9_FBD.jpg> [58] [59 <../24/CH6/EX6.9/Example6_9_F +<../24/CH6/EX6.9/Example6_9_FBD.jpg, id=1442, 383.18156pt x 280.04625pt> +<use ../24/CH6/EX6.9/Example6_9_FBD.jpg> [63] [64 <../24/CH6/EX6.9/Example6_9_F BD.jpg>] Chapter 7. -LaTeX Warning: Reference `AP:272' on page 60 undefined on input line 830. +LaTeX Warning: Reference `AP:272' on page 65 undefined on input line 900. -(../24/CH7/EX7.1/Example7_1.sce) [60] +(../24/CH7/EX7.1/Example7_1.sce) [65] -LaTeX Warning: Reference `AP:272' on page 61 undefined on input line 843. +LaTeX Warning: Reference `AP:272' on page 66 undefined on input line 913. -(../24/CH7/EX7.2/Example7_2.sce [61]) (../24/CH7/EX7.3/Example7_3.sce) [62] -(../24/CH7/EX7.4/Example7_4.sce) [63] (../24/CH7/EX7.5/Example7_5.sce) -(../24/CH7/EX7.6/Example7_6.sce [64]) -<../24/CH7/EX7.6/Example7_6_FBD.jpg, id=1400, 399.74344pt x 409.53pt> -<use ../24/CH7/EX7.6/Example7_6_FBD.jpg> [65] [66 <../24/CH7/EX7.6/Example7_6_F +(../24/CH7/EX7.2/Example7_2.sce [66]) (../24/CH7/EX7.3/Example7_3.sce) [67] +(../24/CH7/EX7.4/Example7_4.sce) [68] (../24/CH7/EX7.5/Example7_5.sce) +(../24/CH7/EX7.6/Example7_6.sce [69]) +<../24/CH7/EX7.6/Example7_6_FBD.jpg, id=1610, 399.74344pt x 409.53pt> +<use ../24/CH7/EX7.6/Example7_6_FBD.jpg> [70] [71 <../24/CH7/EX7.6/Example7_6_F BD.jpg>] (../24/CH7/EX7.7/Example7_7.sce) (../24/CH7/EX7.8/Example7_8.sce -[67]) (../24/CH7/EX7.9/Example7_9.sce) +[72]) (../24/CH7/EX7.9/Example7_9.sce) -LaTeX Warning: Reference `AP:272' on page 68 undefined on input line 940. +LaTeX Warning: Reference `AP:272' on page 73 undefined on input line 1010. -(../24/CH7/EX7.10/Example7_10.sce [68]) [69] +(../24/CH7/EX7.10/Example7_10.sce [73]) [74] Chapter 8. -(../24/CH8/EX8.1/Example8_1.sce) (../24/CH8/EX8.2/Example8_2.sce [70]) -(../24/CH8/EX8.3/Example8_3.sce [71]) (../24/CH8/EX8.4/Example8_4.sce) -(../24/CH8/EX8.5/Example8_5.sce [72]) [73] (../24/CH8/EX8.6/Example8_6.sce) -(../24/CH8/EX8.7/Example8_7.sce [74]) (../24/CH8/EX8.8/Example8_8.sce [75]) -[76] +(../24/CH8/EX8.1/Example8_1.sce) (../24/CH8/EX8.2/Example8_2.sce [75]) +(../24/CH8/EX8.3/Example8_3.sce [76]) (../24/CH8/EX8.4/Example8_4.sce) +(../24/CH8/EX8.5/Example8_5.sce [77]) [78] (../24/CH8/EX8.6/Example8_6.sce) +(../24/CH8/EX8.7/Example8_7.sce [79]) (../24/CH8/EX8.8/Example8_8.sce [80]) +[81] Chapter 9. -LaTeX Warning: Reference `AP:272' on page 77 undefined on input line 1045. +LaTeX Warning: Reference `AP:272' on page 82 undefined on input line 1115. (../24/CH9/EX9.1/Example9_1.sce) -<../24/CH9/EX9.1/Example9_1_figure.jpg, id=1717, 422.32782pt x 329.73187pt> -<use ../24/CH9/EX9.1/Example9_1_figure.jpg> [77] -(../24/CH9/EX9.2/Example9_2.sce [78 <../24/CH9/EX9.1/Example9_1_figure.jpg>]) +<../24/CH9/EX9.1/Example9_1_figure.jpg, id=1927, 422.32782pt x 329.73187pt> +<use ../24/CH9/EX9.1/Example9_1_figure.jpg> [82] +(../24/CH9/EX9.2/Example9_2.sce [83 <../24/CH9/EX9.1/Example9_1_figure.jpg>]) -LaTeX Warning: Reference `AP:272' on page 79 undefined on input line 1076. +LaTeX Warning: Reference `AP:272' on page 84 undefined on input line 1146. (../24/CH9/EX9.3/Example9_3.sce) -LaTeX Warning: Reference `AP:272' on page 79 undefined on input line 1089. +LaTeX Warning: Reference `AP:272' on page 84 undefined on input line 1159. -[79] (../24/CH9/EX9.4/Example9_4.sce) (../24/CH9/EX9.5/Example9_5.sce) [80] +[84] (../24/CH9/EX9.4/Example9_4.sce) (../24/CH9/EX9.5/Example9_5.sce) [85] (../24/CH9/EX9.6/Example9_6.sce) -LaTeX Warning: Reference `AP:272' on page 81 undefined on input line 1124. +LaTeX Warning: Reference `AP:272' on page 86 undefined on input line 1194. -(../24/CH9/EX9.7/Example9_7.sce [81]) (../24/CH9/EX9.8/Example9_8.sce [82]) +(../24/CH9/EX9.7/Example9_7.sce [86]) (../24/CH9/EX9.8/Example9_8.sce [87]) -LaTeX Warning: Reference `AP:272' on page 83 undefined on input line 1148. +LaTeX Warning: Reference `AP:272' on page 88 undefined on input line 1218. -(../24/CH9/EX9.9/Example9_9.sce) [83] +(../24/CH9/EX9.9/Example9_9.sce) [88] Chapter 10. -LaTeX Warning: Reference `AP:272' on page 84 undefined on input line 1163. - -(../24/CH10/EX10.1/Example10_1.sce [84]) (../24/CH10/EX10.2/Example10_2.sce) -[85] (../24/CH10/EX10.3/Example10_3.sce) +LaTeX Warning: Reference `AP:272' on page 89 undefined on input line 1233. -LaTeX Warning: Reference `AP:280' on page 86 undefined on input line 1198. - -[86] (../24/CH10/EX10.4/Example10_4.sce) (../24/CH10/EX10.5/Example10_5.sce -[87]) [88] +(../24/CH10/EX10.1/Example10_1.sce [89]) (../24/CH10/EX10.2/Example10_2.sce) +[90] (../24/CH10/EX10.3/Example10_3.sce) [91] +(../24/CH10/EX10.4/Example10_4.sce) (../24/CH10/EX10.5/Example10_5.sce [92]) +[93] Chapter 11. -(../24/CH11/EX11.1/Example11_1.sce [89]) -<../24/CH11/EX11.1/Example11_1_graph.jpg, id=2049, 612.2875pt x 461.725pt> +(../24/CH11/EX11.1/Example11_1.sce [94]) +<../24/CH11/EX11.1/Example11_1_graph.jpg, id=2260, 612.2875pt x 461.725pt> <use ../24/CH11/EX11.1/Example11_1_graph.jpg> -(../24/CH11/EX11.2/Example11_2.sce [90 <../24/CH11/EX11.1/Example11_1_graph.jpg ->]) (../24/CH11/EX11.3/Example11_3.sce [91]) (../24/CH11/EX11.4/Example11_4.sce -) [92] (../24/CH11/EX11.6/Example11_6.sce) (../24/CH11/EX11.7/Example11_7.sce -[93]) -<../24/CH11/EX11.7/Example11_7_FBD.jpg, id=2162, 377.15906pt x 328.22626pt> +(../24/CH11/EX11.2/Example11_2.sce [95 <../24/CH11/EX11.1/Example11_1_graph.jpg +>]) (../24/CH11/EX11.3/Example11_3.sce [96]) (../24/CH11/EX11.4/Example11_4.sce +) [97] (../24/CH11/EX11.6/Example11_6.sce) (../24/CH11/EX11.7/Example11_7.sce +[98]) +<../24/CH11/EX11.7/Example11_7_FBD.jpg, id=2373, 377.15906pt x 328.22626pt> <use ../24/CH11/EX11.7/Example11_7_FBD.jpg> (../24/CH11/EX11.8/Example11_8.sce -[94 <../24/CH11/EX11.7/Example11_7_FBD.jpg>]) - -LaTeX Warning: Reference `AP:281' on page 95 undefined on input line 1315. - -(../24/CH11/EX11.9/Example11_9.sce [95]) (../24/CH11/EX11.10/Example11_10.sce) -[96] +[99 <../24/CH11/EX11.7/Example11_7_FBD.jpg>]) +(../24/CH11/EX11.9/Example11_9.sce [100]) (../24/CH11/EX11.10/Example11_10.sce) +[101] Chapter 12. (../24/CH12/EX12.1/Example12_1.sce) -LaTeX Warning: Reference `AP:272' on page 97 undefined on input line 1352. - -[97] (../24/CH12/EX12.2/Example12_2.sce) +LaTeX Warning: Reference `AP:272' on page 102 undefined on input line 1422. -LaTeX Warning: Reference `AP:277' on page 98 undefined on input line 1365. +[102] (../24/CH12/EX12.2/Example12_2.sce) +LaTeX Warning: Reference `AP:272' on page 103 undefined on input line 1437. -LaTeX Warning: Reference `AP:272' on page 98 undefined on input line 1367. - -[98] (../24/CH12/EX12.3/Example12_3.sce) (../24/CH12/EX12.4/Example12_4.sce -[99]) (../24/CH12/EX12.6/Example12_6.sce [100]) -(../24/CH12/EX12.7/Example12_7.sce) (../24/CH12/EX12.8/Example12_8.sce [101]) -(../24/CH12/EX12.9/Example12_9.sce [102]) [103] +[103] (../24/CH12/EX12.3/Example12_3.sce) (../24/CH12/EX12.4/Example12_4.sce +[104]) (../24/CH12/EX12.6/Example12_6.sce [105]) +(../24/CH12/EX12.7/Example12_7.sce) (../24/CH12/EX12.8/Example12_8.sce [106]) +(../24/CH12/EX12.9/Example12_9.sce [107]) [108] Chapter 13. (../24/CH13/EX13.1/Example13_1.sce) -<../24/CH13/EX13.1/Example13_1_FBD.jpg, id=2415, 410.2828pt x 280.79906pt> -<use ../24/CH13/EX13.1/Example13_1_FBD.jpg> [104] -(../24/CH13/EX13.2/Example13_2.sce [105 <../24/CH13/EX13.1/Example13_1_FBD.jpg> -]) <../24/CH13/EX13.2/Example13_2_FBD.jpg, id=2457, 328.22626pt x 307.1475pt> +<../24/CH13/EX13.1/Example13_1_FBD.jpg, id=2628, 410.2828pt x 280.79906pt> +<use ../24/CH13/EX13.1/Example13_1_FBD.jpg> [109] +(../24/CH13/EX13.2/Example13_2.sce [110 <../24/CH13/EX13.1/Example13_1_FBD.jpg> +]) <../24/CH13/EX13.2/Example13_2_FBD.jpg, id=2670, 328.22626pt x 307.1475pt> <use ../24/CH13/EX13.2/Example13_2_FBD.jpg> (../24/CH13/EX13.3/Example13_3.sce -[106] [107 <../24/CH13/EX13.2/Example13_2_FBD.jpg>]) -<../24/CH13/EX13.3/Example13_3_FBD.jpg, id=2493, 367.3725pt x 339.51843pt> -<use ../24/CH13/EX13.3/Example13_3_FBD.jpg> [108 <../24/CH13/EX13.3/Example13_3 +[111] [112 <../24/CH13/EX13.2/Example13_2_FBD.jpg>]) +<../24/CH13/EX13.3/Example13_3_FBD.jpg, id=2706, 367.3725pt x 339.51843pt> +<use ../24/CH13/EX13.3/Example13_3_FBD.jpg> [113 <../24/CH13/EX13.3/Example13_3 _FBD.jpg>] (../24/CH13/EX13.4/Example13_4.sce) -<../24/CH13/EX13.4/Example13_4_FBD.jpg, id=2504, 289.83281pt x 341.77687pt> -<use ../24/CH13/EX13.4/Example13_4_FBD.jpg> [109] [110 <../24/CH13/EX13.4/Examp +<../24/CH13/EX13.4/Example13_4_FBD.jpg, id=2716, 289.83281pt x 341.77687pt> +<use ../24/CH13/EX13.4/Example13_4_FBD.jpg> [114] [115 <../24/CH13/EX13.4/Examp le13_4_FBD.jpg>] (../24/CH13/EX13.5/Example13_5.sce) -(../24/CH13/EX13.6/Example13_6.sce [111]) [112] +(../24/CH13/EX13.6/Example13_6.sce [116]) [117] Chapter 14. -LaTeX Warning: Reference `AP:273' on page 113 undefined on input line 1533. +LaTeX Warning: Reference `AP:273' on page 118 undefined on input line 1603. (../24/CH14/EX14.1/Example14_1.sce) -LaTeX Warning: Reference `AP:273' on page 113 undefined on input line 1546. +LaTeX Warning: Reference `AP:273' on page 118 undefined on input line 1616. -[113] +[118] -LaTeX Warning: Reference `AP:272' on page 114 undefined on input line 1548. +LaTeX Warning: Reference `AP:272' on page 119 undefined on input line 1618. -(../24/CH14/EX14.2/Example14_2.sce [114]) (../24/CH14/EX14.3.a/Example14_3a.sce +(../24/CH14/EX14.2/Example14_2.sce [119]) (../24/CH14/EX14.3.a/Example14_3a.sce ) -LaTeX Warning: Reference `AP:273' on page 115 undefined on input line 1572. +LaTeX Warning: Reference `AP:273' on page 120 undefined on input line 1642. -(../24/CH14/EX14.3.b/Example14_3b.sce [115]) +(../24/CH14/EX14.3.b/Example14_3b.sce [120]) -LaTeX Warning: Reference `AP:273' on page 116 undefined on input line 1585. +LaTeX Warning: Reference `AP:273' on page 121 undefined on input line 1655. -LaTeX Warning: Reference `AP:273' on page 116 undefined on input line 1587. +LaTeX Warning: Reference `AP:273' on page 121 undefined on input line 1657. -(../24/CH14/EX14.5/Example14_5.sce [116]) +(../24/CH14/EX14.5/Example14_5.sce [121]) -LaTeX Warning: Reference `AP:273' on page 117 undefined on input line 1600. +LaTeX Warning: Reference `AP:273' on page 122 undefined on input line 1670. -(../24/CH14/EX14.6/Example14_6.sce [117]) +(../24/CH14/EX14.6/Example14_6.sce [122]) -LaTeX Warning: Reference `AP:273' on page 118 undefined on input line 1613. +LaTeX Warning: Reference `AP:273' on page 123 undefined on input line 1683. -(../24/CH14/EX14.7/Example14_7.sce [118]) +(../24/CH14/EX14.7/Example14_7.sce [123]) -LaTeX Warning: Reference `AP:273' on page 119 undefined on input line 1626. +LaTeX Warning: Reference `AP:273' on page 124 undefined on input line 1696. -(../24/CH14/EX14.8/Example14_8.sce [119]) [120] +(../24/CH14/EX14.8/Example14_8.sce [124]) [125] Chapter 15. -(../24/CH15/EX15.1/Example15_1.sce) [121] (../24/CH15/EX15.2/Example15_2.sce) -(../24/CH15/EX15.3/Example15_3.sce) [122] (../24/CH15/EX15.4/Example15_4.sce) -(../24/CH15/EX15.5/Example15_5.sce [123]) (../24/CH15/EX15.6/Example15_6.sce) - -LaTeX Warning: Reference `AP:282' on page 124 undefined on input line 1707. - -(../24/CH15/EX15.7/Example15_7.sce [124]) - -LaTeX Warning: Reference `AP:282' on page 125 undefined on input line 1720. - -(../24/CH15/EX15.8/Example15_8.sce) [125] [126] +(../24/CH15/EX15.1/Example15_1.sce) [126] (../24/CH15/EX15.2/Example15_2.sce) +(../24/CH15/EX15.3/Example15_3.sce) [127] (../24/CH15/EX15.4/Example15_4.sce) +(../24/CH15/EX15.5/Example15_5.sce [128]) (../24/CH15/EX15.6/Example15_6.sce) +(../24/CH15/EX15.7/Example15_7.sce [129]) (../24/CH15/EX15.8/Example15_8.sce) +[130] [131] Chapter 16. -(../24/CH16/EX16.1/Example16_1.sce [127]) (../24/CH16/EX16.2/Example16_2.sce -[128]) (../24/CH16/EX16.3/Example16_3.sce) (../24/CH16/EX16.4/Example16_4.sce -[129]) (../24/CH16/EX16.5/Example16_5.sce) [130] +(../24/CH16/EX16.1/Example16_1.sce [132]) (../24/CH16/EX16.2/Example16_2.sce +[133]) (../24/CH16/EX16.3/Example16_3.sce) (../24/CH16/EX16.4/Example16_4.sce +[134]) (../24/CH16/EX16.5/Example16_5.sce) [135] (../24/CH16/EX16.6/Example16_6.sce) -<../24/CH16/EX16.6/Example16_6_FBD.JPG, id=3060, 352.31625pt x 259.7203pt> +<../24/CH16/EX16.6/Example16_6_FBD.JPG, id=3275, 352.31625pt x 259.7203pt> <use ../24/CH16/EX16.6/Example16_6_FBD.JPG> (../24/CH16/EX16.7/Example16_7.sce -[131] [132 <../24/CH16/EX16.6/Example16_6_FBD.JPG>]) [133] +[136] [137 <../24/CH16/EX16.6/Example16_6_FBD.JPG>]) [138] Chapter 17. -(../24/CH17/EX17.1/Example17_1.sce [134]) - -LaTeX Warning: Reference `AP:283' on page 135 undefined on input line 1832. +(../24/CH17/EX17.1/Example17_1.sce [139]) (../24/CH17/EX17.2/Example17_2.sce) +[140] (../24/CH17/EX17.3/Example17_3.sce) (../24/CH17/EX17.4/Example17_4.sce +[141]) -(../24/CH17/EX17.2/Example17_2.sce) [135] (../24/CH17/EX17.3/Example17_3.sce) -(../24/CH17/EX17.4/Example17_4.sce [136]) +LaTeX Warning: Reference `AP:272' on page 142 undefined on input line 1937. -LaTeX Warning: Reference `AP:272' on page 137 undefined on input line 1867. - -(../24/CH17/EX17.5/Example17_5.sce) [137] (../24/CH17/EX17.6/Example17_6.sce) -(../24/CH17/EX17.7/Example17_7.sce [138]) [139] +(../24/CH17/EX17.5/Example17_5.sce) [142] (../24/CH17/EX17.6/Example17_6.sce) +(../24/CH17/EX17.7/Example17_7.sce [143]) [144] Chapter 18. -LaTeX Warning: Reference `AP:272' on page 140 undefined on input line 1904. +LaTeX Warning: Reference `AP:272' on page 145 undefined on input line 1974. -(../24/CH18/EX18.1/Example18_1.sce) [140] (../24/CH18/EX18.2/Example18_2.sce) -(../24/CH18/EX18.3/Example18_3.sce [141]) (../24/CH18/EX18.4/Example18_4.sce) -(../24/CH18/EX18.5/Example18_5.sce [142]) (../24/CH18/EX18.6/Example18_6.sce) -(../24/CH18/EX18.8/Example18_8.sce [143]) [144] +(../24/CH18/EX18.1/Example18_1.sce) [145] (../24/CH18/EX18.2/Example18_2.sce) +(../24/CH18/EX18.3/Example18_3.sce [146]) (../24/CH18/EX18.4/Example18_4.sce) +(../24/CH18/EX18.5/Example18_5.sce [147]) (../24/CH18/EX18.6/Example18_6.sce) +(../24/CH18/EX18.8/Example18_8.sce [148]) [149] Chapter 19. -(../24/CH19/EX19.1/Example19_1.sce) (../24/CH19/EX19.2/Example19_2.sce [145]) -(../24/CH19/EX19.3/Example19_3.sce [146]) (../24/CH19/EX19.4/Example19_4.sce) -[147] (../24/CH19/EX19.5/Example19_5.sce) [148] -(../24/CH19/EX19.6/Example19_6.sce) (../24/CH19/EX19.7/Example19_7.sce [149]) -[150] +(../24/CH19/EX19.1/Example19_1.sce) (../24/CH19/EX19.2/Example19_2.sce [150]) +(../24/CH19/EX19.3/Example19_3.sce [151]) (../24/CH19/EX19.4/Example19_4.sce) +[152] (../24/CH19/EX19.5/Example19_5.sce) [153] +(../24/CH19/EX19.6/Example19_6.sce) (../24/CH19/EX19.7/Example19_7.sce [154]) +[155] Chapter 20. -(../24/CH20/EX20.1/Example20_1.sce) (../24/CH20/EX20.2/Example20_2.sce [151]) -(../24/CH20/EX20.3/Example20_3.sce) (../24/CH20/EX20.4/Example20_4.sce [152]) -(../24/CH20/EX20.5/Example20_5.sce [153]) (../24/CH20/EX20.6/Example20_6.sce) -[154] (../24/CH20/EX20.7/Example20_7.sce) [155] -(../24/CH20/EX20.9/Example20_9.sce) [156] +(../24/CH20/EX20.1/Example20_1.sce) (../24/CH20/EX20.2/Example20_2.sce [156]) +(../24/CH20/EX20.3/Example20_3.sce) (../24/CH20/EX20.4/Example20_4.sce [157]) +(../24/CH20/EX20.5/Example20_5.sce [158]) (../24/CH20/EX20.6/Example20_6.sce) +[159] (../24/CH20/EX20.7/Example20_7.sce) [160] +(../24/CH20/EX20.9/Example20_9.sce) [161] Chapter 21. -(../24/CH21/EX21.1/Example21_1.sce) (../24/CH21/EX21.2/Example21_2.sce [157]) -(../24/CH21/EX21.3/Example21_3.sce [158]) (../24/CH21/EX21.4/Example21_4.sce -[159]) (../24/CH21/EX21.5/Example21_5.sce) [160] +(../24/CH21/EX21.1/Example21_1.sce) (../24/CH21/EX21.2/Example21_2.sce [162]) +(../24/CH21/EX21.3/Example21_3.sce [163]) (../24/CH21/EX21.4/Example21_4.sce +[164]) (../24/CH21/EX21.5/Example21_5.sce) [165] Chapter 22. -LaTeX Warning: Reference `AP:272' on page 161 undefined on input line 2211. - - -LaTeX Warning: Reference `AP:284' on page 161 undefined on input line 2213. - -(../24/CH22/EX22.1/Example22_1.sce [161]) +LaTeX Warning: Reference `AP:272' on page 166 undefined on input line 2281. -LaTeX Warning: Reference `AP:284' on page 162 undefined on input line 2226. +(../24/CH22/EX22.1/Example22_1.sce [166]) (../24/CH22/EX22.2/Example22_2.sce +[167]) (../24/CH22/EX22.3/Example22_3.sce [168]) -(../24/CH22/EX22.2/Example22_2.sce [162]) +LaTeX Warning: Reference `AP:273' on page 169 undefined on input line 2322. -LaTeX Warning: Reference `AP:284' on page 163 undefined on input line 2239. - -(../24/CH22/EX22.3/Example22_3.sce [163]) - -LaTeX Warning: Reference `AP:273' on page 164 undefined on input line 2252. - - -LaTeX Warning: Reference `AP:284' on page 164 undefined on input line 2254. - -(../24/CH22/EX22.4/Example22_4.sce) [164] [165] +(../24/CH22/EX22.4/Example22_4.sce) [169] [170] Chapter 23. -LaTeX Warning: Reference `AP:272' on page 166 undefined on input line 2269. - - -LaTeX Warning: Reference `AP:284' on page 166 undefined on input line 2271. - -(../24/CH23/EX23.2/Example23_2.sce [166]) - -LaTeX Warning: Reference `AP:272' on page 167 undefined on input line 2284. +LaTeX Warning: Reference `AP:272' on page 171 undefined on input line 2339. +(../24/CH23/EX23.2/Example23_2.sce [171]) -LaTeX Warning: Reference `AP:284' on page 167 undefined on input line 2286. +LaTeX Warning: Reference `AP:272' on page 172 undefined on input line 2354. -(../24/CH23/EX23.3/Example23_3.sce) [167] (../24/CH23/EX23.4/Example23_4.sce) +(../24/CH23/EX23.3/Example23_3.sce) [172] (../24/CH23/EX23.4/Example23_4.sce) -LaTeX Warning: Reference `AP:272' on page 168 undefined on input line 2310. +LaTeX Warning: Reference `AP:272' on page 173 undefined on input line 2380. -(../24/CH23/EX23.5/Example23_5.sce [168]) [169] +(../24/CH23/EX23.5/Example23_5.sce [173]) [174] Chapter 24. -LaTeX Warning: Reference `AP:272' on page 170 undefined on input line 2325. +LaTeX Warning: Reference `AP:272' on page 175 undefined on input line 2395. -(../24/CH24/EX24.1/Example24_1.sce) [170] (../24/CH24/EX24.2/Example24_2.sce) - -LaTeX Warning: Reference `AP:284' on page 171 undefined on input line 2349. - -(../24/CH24/EX24.3/Example24_3.sce [171]) (../24/CH24/EX24.4/Example24_4.sce) - -LaTeX Warning: Reference `AP:284' on page 172 undefined on input line 2373. - -[172] (../24/CH24/EX24.5/Example24_5.sce) - -LaTeX Warning: Reference `AP:284' on page 173 undefined on input line 2386. - -(../24/CH24/EX24.6/Example24_6.sce [173]) [174] +(../24/CH24/EX24.1/Example24_1.sce) [175] (../24/CH24/EX24.2/Example24_2.sce) +(../24/CH24/EX24.3/Example24_3.sce [176]) (../24/CH24/EX24.4/Example24_4.sce) +[177] (../24/CH24/EX24.5/Example24_5.sce) (../24/CH24/EX24.6/Example24_6.sce +[178]) [179] Chapter 25. - -LaTeX Warning: Reference `AP:284' on page 175 undefined on input line 2401. - -(../24/CH25/EX25.1/Example25_1.sce) - -LaTeX Warning: Reference `AP:284' on page 175 undefined on input line 2414. - -[175] (../24/CH25/EX25.3/Example25_3.sce) - -LaTeX Warning: Reference `AP:284' on page 176 undefined on input line 2427. - -(../24/CH25/EX25.4/Example25_4.sce [176]) - -LaTeX Warning: Reference `AP:284' on page 177 undefined on input line 2440. - -(../24/CH25/EX25.6/Example25_6.sce) [177] +(../24/CH25/EX25.1/Example25_1.sce) [180] (../24/CH25/EX25.3/Example25_3.sce) +(../24/CH25/EX25.4/Example25_4.sce [181]) (../24/CH25/EX25.6/Example25_6.sce) +[182] Chapter 26. - -LaTeX Warning: Reference `AP:284' on page 178 undefined on input line 2455. - -(../24/CH26/EX26.1/Example26_1.sce) - -LaTeX Warning: Reference `AP:284' on page 178 undefined on input line 2468. - -[178] (../24/CH26/EX26.2/Example26_2.sce) (../24/CH26/EX26.3/Example26_3.sce -[179]) - -LaTeX Warning: Reference `AP:284' on page 180 undefined on input line 2492. - -(../24/CH26/EX26.4/Example26_4.sce) [180] - -LaTeX Warning: Reference `AP:284' on page 181 undefined on input line 2505. - -(../24/CH26/EX26.5/Example26_5.sce) - -LaTeX Warning: Reference `AP:284' on page 181 undefined on input line 2518. - -(../24/CH26/EX26.6/Example26_6.sce [181] [182]) [183] +(../24/CH26/EX26.1/Example26_1.sce) [183] (../24/CH26/EX26.2/Example26_2.sce) +(../24/CH26/EX26.3/Example26_3.sce [184]) (../24/CH26/EX26.4/Example26_4.sce) +[185] (../24/CH26/EX26.5/Example26_5.sce) (../24/CH26/EX26.6/Example26_6.sce +[186] [187]) [188] Chapter 27. -(../24/CH27/EX27.1/Example27_1.sce) (../24/CH27/EX27.2/Example27_2.sce [184]) -(../24/CH27/EX27.3/Example27_3.sce [185]) (../24/CH27/EX27.4/Example27_4.sce) -(../24/CH27/EX27.5/Example27_5.sce [186]) (../24/CH27/EX27.6/Example27_6.sce) -[187] +(../24/CH27/EX27.1/Example27_1.sce) (../24/CH27/EX27.2/Example27_2.sce [189]) +(../24/CH27/EX27.3/Example27_3.sce [190]) (../24/CH27/EX27.4/Example27_4.sce) +(../24/CH27/EX27.5/Example27_5.sce [191]) (../24/CH27/EX27.6/Example27_6.sce) +[192] Chapter 28. -(../24/CH28/EX28.1/Example28_1.sce) [188] (../24/CH28/EX28.2/Example28_2.sce) -[189] (../24/CH28/EX28.3/Example28_3.sce) (../24/CH28/EX28.4/Example28_4.sce -[190]) (../24/CH28/EX28.5/Example28_5.sce) [191] [192] +(../24/CH28/EX28.1/Example28_1.sce) [193] (../24/CH28/EX28.2/Example28_2.sce) +[194] (../24/CH28/EX28.3/Example28_3.sce) (../24/CH28/EX28.4/Example28_4.sce +[195]) (../24/CH28/EX28.5/Example28_5.sce) [196] [197] Chapter 29. -(../24/CH29/EX29.1/Example29_1.sce) (../24/CH29/EX29.2/Example29_2.sce [193]) -(../24/CH29/EX29.3/Example29_3.sce) [194] +(../24/CH29/EX29.1/Example29_1.sce) (../24/CH29/EX29.2/Example29_2.sce [198]) +(../24/CH29/EX29.3/Example29_3.sce) [199] -LaTeX Warning: Reference `AP:272' on page 195 undefined on input line 2691. +LaTeX Warning: Reference `AP:272' on page 200 undefined on input line 2761. -(../24/CH29/EX29.4/Example29_4.sce) (../24/CH29/EX29.5/Example29_5.sce [195]) -(../24/CH29/EX29.6/Example29_6.sce) [196] (../24/CH29/EX29.7/Example29_7.sce) -(../24/CH29/EX29.8/Example29_8.sce [197]) [198] +(../24/CH29/EX29.4/Example29_4.sce) (../24/CH29/EX29.5/Example29_5.sce [200]) +(../24/CH29/EX29.6/Example29_6.sce) [201] (../24/CH29/EX29.7/Example29_7.sce) +(../24/CH29/EX29.8/Example29_8.sce [202]) [203] Chapter 30. -LaTeX Warning: Reference `AP:272' on page 199 undefined on input line 2750. +LaTeX Warning: Reference `AP:272' on page 204 undefined on input line 2820. -(../24/CH30/EX30.2/Example30_2.sce) [199] (../24/CH30/EX30.3/Example30_3.sce) -(../24/CH30/EX30.4/Example30_4.sce [200]) [201] +(../24/CH30/EX30.2/Example30_2.sce) [204] (../24/CH30/EX30.3/Example30_3.sce) +(../24/CH30/EX30.4/Example30_4.sce [205]) [206] Chapter 31. -(../24/CH31/EX31.1/Example31_1.sce) (../24/CH31/EX31.2/Example31_2.sce [202]) -(../24/CH31/EX31.3/Example31_3.sce [203]) (../24/CH31/EX31.4/Example31_4.sce) -(../24/CH31/EX31.5/Example31_5.sce [204]) (../24/CH31/EX31.6/Example31_6.sce) -[205] (../24/CH31/EX31.7/Example31_7.sce) (../24/CH31/EX31.8/Example31_8.sce -[206]) (../24/CH31/EX31.9/Example31_9.sce) [207] [208] +(../24/CH31/EX31.1/Example31_1.sce) (../24/CH31/EX31.2/Example31_2.sce [207]) +(../24/CH31/EX31.3/Example31_3.sce [208]) (../24/CH31/EX31.4/Example31_4.sce) +(../24/CH31/EX31.5/Example31_5.sce [209]) (../24/CH31/EX31.6/Example31_6.sce) +[210] (../24/CH31/EX31.7/Example31_7.sce) (../24/CH31/EX31.8/Example31_8.sce +[211]) (../24/CH31/EX31.9/Example31_9.sce) [212] [213] Chapter 32. -(../24/CH32/EX32.1/Example32_1.sce) [209] (../24/CH32/EX32.2/Example32_2.sce) -(../24/CH32/EX32.3/Example32_3.sce [210]) [211] +(../24/CH32/EX32.1/Example32_1.sce) [214] (../24/CH32/EX32.2/Example32_2.sce) +(../24/CH32/EX32.3/Example32_3.sce [215]) [216] Chapter 33. -(../24/CH33/EX33.1/Example33_1.sce) (../24/CH33/EX33.2/Example33_2.sce [212]) -(../24/CH33/EX33.3/Example33_3.sce [213]) (../24/CH33/EX33.4/Example33_4.sce) -[214] (../24/CH33/EX33.5/Example33_5.sce) (../24/CH33/EX33.6/Example33_6.sce -[215]) (../24/CH33/EX33.7/Example33_7.sce [216]) -(../24/CH33/EX33.8/Example33_8.sce) [217] (../24/CH33/EX33.9/Example33_9.sce) -[218] +(../24/CH33/EX33.1/Example33_1.sce) (../24/CH33/EX33.2/Example33_2.sce [217]) +(../24/CH33/EX33.3/Example33_3.sce [218]) (../24/CH33/EX33.4/Example33_4.sce) +[219] (../24/CH33/EX33.5/Example33_5.sce) (../24/CH33/EX33.6/Example33_6.sce +[220]) (../24/CH33/EX33.7/Example33_7.sce [221]) +(../24/CH33/EX33.8/Example33_8.sce) [222] (../24/CH33/EX33.9/Example33_9.sce) +[223] Chapter 34. (../24/CH34/EX34.1/Example34_1.sce) -LaTeX Warning: Reference `AP:273' on page 219 undefined on input line 3035. +LaTeX Warning: Reference `AP:273' on page 224 undefined on input line 3105. -[219] (../24/CH34/EX34.2/Example34_2.sce) +[224] (../24/CH34/EX34.2/Example34_2.sce) -LaTeX Warning: Reference `AP:272' on page 220 undefined on input line 3048. +LaTeX Warning: Reference `AP:272' on page 225 undefined on input line 3118. -(../24/CH34/EX34.3/Example34_3.sce [220]) +(../24/CH34/EX34.3/Example34_3.sce [225]) -LaTeX Warning: Reference `AP:272' on page 221 undefined on input line 3061. +LaTeX Warning: Reference `AP:272' on page 226 undefined on input line 3131. -(../24/CH34/EX34.4/Example34_4.sce [221]) +(../24/CH34/EX34.4/Example34_4.sce [226]) -LaTeX Warning: Reference `AP:272' on page 222 undefined on input line 3074. +LaTeX Warning: Reference `AP:272' on page 227 undefined on input line 3144. -(../24/CH34/EX34.5/Example34_5.sce) [222] +(../24/CH34/EX34.5/Example34_5.sce) [227] Chapter 35. -(../24/CH35/EX35.1/Example35_1.sce) (../24/CH35/EX35.2/Example35_2.sce [223]) -(../24/CH35/EX35.3/Example35_3.sce [224]) (../24/CH35/EX35.4/Example35_4.sce) -[225] +(../24/CH35/EX35.1/Example35_1.sce) (../24/CH35/EX35.2/Example35_2.sce [228]) +(../24/CH35/EX35.3/Example35_3.sce [229]) (../24/CH35/EX35.4/Example35_4.sce) +[230] Chapter 36. -(../24/CH36/EX36.1/Example36_1.sce) [226] (../24/CH36/EX36.2/Example36_2.sce) +(../24/CH36/EX36.1/Example36_1.sce) [231] (../24/CH36/EX36.2/Example36_2.sce) -LaTeX Warning: Reference `AP:272' on page 227 undefined on input line 3157. +LaTeX Warning: Reference `AP:272' on page 232 undefined on input line 3227. -(../24/CH36/EX36.3/Example36_3.sce [227]) (../24/CH36/EX36.4/Example36_4.sce) -(../24/CH36/EX36.5/Example36_5.sce [228]) (../24/CH36/EX36.6/Example36_6.sce) -[229] +(../24/CH36/EX36.3/Example36_3.sce [232]) (../24/CH36/EX36.4/Example36_4.sce) +(../24/CH36/EX36.5/Example36_5.sce [233]) (../24/CH36/EX36.6/Example36_6.sce) +[234] Chapter 37. -LaTeX Warning: Reference `AP:272' on page 230 undefined on input line 3205. +LaTeX Warning: Reference `AP:272' on page 235 undefined on input line 3275. -(../24/CH37/EX37.1/Example37_1.sce) [230] (../24/CH37/EX37.2/Example37_2.sce) -(../24/CH37/EX37.3/Example37_3.sce [231]) (../24/CH37/EX37.4/Example37_4.sce) +(../24/CH37/EX37.1/Example37_1.sce) [235] (../24/CH37/EX37.2/Example37_2.sce) +(../24/CH37/EX37.3/Example37_3.sce [236]) (../24/CH37/EX37.4/Example37_4.sce) -LaTeX Warning: Reference `AP:272' on page 232 undefined on input line 3251. +LaTeX Warning: Reference `AP:272' on page 237 undefined on input line 3321. -[232] (../24/CH37/EX37.5/Example37_5.sce) [233] [234] +[237] (../24/CH37/EX37.5/Example37_5.sce) [238] [239] Chapter 38. -(../24/CH38/EX38.1/Example38_1.sce) (../24/CH38/EX38.2/Example38_2.sce [235]) -(../24/CH38/EX38.3/Example38_3.sce) (../24/CH38/EX38.4/Example38_4.sce [236]) -(../24/CH38/EX38.5/Example38_5.sce [237]) (../24/CH38/EX38.6/Example38_6.sce) -[238] (../24/CH38/EX38.7/Example38_7.sce) [239] +(../24/CH38/EX38.1/Example38_1.sce) (../24/CH38/EX38.2/Example38_2.sce [240]) +(../24/CH38/EX38.3/Example38_3.sce) (../24/CH38/EX38.4/Example38_4.sce [241]) +(../24/CH38/EX38.5/Example38_5.sce [242]) (../24/CH38/EX38.6/Example38_6.sce) +[243] (../24/CH38/EX38.7/Example38_7.sce) [244] Chapter 39. -(../24/CH39/EX39.1/Example39_1.sce) (../24/CH39/EX39.2/Example39_2.sce [240]) +(../24/CH39/EX39.1/Example39_1.sce) (../24/CH39/EX39.2/Example39_2.sce [245]) (../24/CH39/EX39.3/Example39_3.sce) -LaTeX Warning: Reference `AP:272' on page 241 undefined on input line 3378. +LaTeX Warning: Reference `AP:272' on page 246 undefined on input line 3448. -[241] (../24/CH39/EX39.4/Example39_4.sce) (../24/CH39/EX39.5/Example39_5.sce -[242]) (../24/CH39/EX39.6/Example39_6.sce) (../24/CH39/EX39.7/Example39_7.sce -[243]) [244] +[246] (../24/CH39/EX39.4/Example39_4.sce) (../24/CH39/EX39.5/Example39_5.sce +[247]) (../24/CH39/EX39.6/Example39_6.sce) (../24/CH39/EX39.7/Example39_7.sce +[248]) [249] Chapter 40. -LaTeX Warning: Reference `AP:285' on page 245 undefined on input line 3426. +LaTeX Warning: Reference `AP:285' on page 250 undefined on input line 3496. -(../24/CH40/EX40.1/Example40_1.sce [245]) (../24/CH40/EX40.3/Example40_3.sce -[246]) +(../24/CH40/EX40.1/Example40_1.sce [250]) (../24/CH40/EX40.3/Example40_3.sce +[251]) -LaTeX Warning: Reference `AP:285' on page 247 undefined on input line 3450. +LaTeX Warning: Reference `AP:285' on page 252 undefined on input line 3520. (../24/CH40/EX40.4/Example40_4.sce) -LaTeX Warning: Reference `AP:285' on page 247 undefined on input line 3463. +LaTeX Warning: Reference `AP:285' on page 252 undefined on input line 3533. -[247] (../24/CH40/EX40.6/Example40_6.sce) (../24/CH40/EX40.8/Example40_8.sce -[248]) [249] +[252] (../24/CH40/EX40.6/Example40_6.sce) (../24/CH40/EX40.8/Example40_8.sce +[253]) [254] Chapter 41. -(../24/CH41/EX41.1/Example41_1.sce) (../24/CH41/EX41.2/Example41_2.sce [250]) +(../24/CH41/EX41.1/Example41_1.sce) (../24/CH41/EX41.2/Example41_2.sce [255]) (../24/CH41/EX41.3/Example41_3.sce) -<../24/CH41/EX41.3/Example41_3a.jpg, id=6171, 371.88937pt x 345.54094pt> +<../24/CH41/EX41.3/Example41_3a.jpg, id=6406, 371.88937pt x 345.54094pt> <use ../24/CH41/EX41.3/Example41_3a.jpg> (../24/CH41/EX41.4/Example41_4.sce -[251] [252 <../24/CH41/EX41.3/Example41_3a.jpg>]) -(../24/CH41/EX41.5/Example41_5.sce) (../24/CH41/EX41.6/Example41_6.sce [253]) -[254] +[256] [257 <../24/CH41/EX41.3/Example41_3a.jpg>]) +(../24/CH41/EX41.5/Example41_5.sce) (../24/CH41/EX41.6/Example41_6.sce [258]) +[259] Chapter 42. -(../24/CH42/EX42.1/Example42_1.sce) (../24/CH42/EX42.2/Example42_2.sce [255]) -(../24/CH42/EX42.3/Example42_3.sce) [256] (../24/CH42/EX42.4/Example42_4.sce) -(../24/CH42/EX42.5/Example42_5.sce [257]) (../24/CH42/EX42.6/Example42_6.sce) -[258] (../24/CH42/EX42.7/Example42_7.sce) [259] +(../24/CH42/EX42.1/Example42_1.sce) (../24/CH42/EX42.2/Example42_2.sce [260]) +(../24/CH42/EX42.3/Example42_3.sce) [261] (../24/CH42/EX42.4/Example42_4.sce) +(../24/CH42/EX42.5/Example42_5.sce [262]) (../24/CH42/EX42.6/Example42_6.sce) +[263] (../24/CH42/EX42.7/Example42_7.sce) [264] Chapter 43. -(../24/CH43/EX43.1/Example43_1.sce) [260] (../24/CH43/EX43.2/Example43_2.sce) -(../24/CH43/EX43.3/Example43_3.sce) [261] (../24/CH43/EX43.4/Example43_4.sce) -(../24/CH43/EX43.5/Example43_5.sce) [262] (../24/CH43/EX43.6/Example43_6.sce) -[263] (../24/CH43/EX43.7/Example43_7.sce) (../24/CH43/EX43.8/Example43_8.sce) -[264] (../24/CH43/EX43.9/Example43_9.sce) (../24/CH43/EX43.10/Example43_10.sce -[265]) [266] +(../24/CH43/EX43.1/Example43_1.sce) [265] (../24/CH43/EX43.2/Example43_2.sce) +(../24/CH43/EX43.3/Example43_3.sce) [266] (../24/CH43/EX43.4/Example43_4.sce) +(../24/CH43/EX43.5/Example43_5.sce) [267] (../24/CH43/EX43.6/Example43_6.sce) +[268] (../24/CH43/EX43.7/Example43_7.sce) (../24/CH43/EX43.8/Example43_8.sce) +[269] (../24/CH43/EX43.9/Example43_9.sce) (../24/CH43/EX43.10/Example43_10.sce +[270]) [271] Chapter 44. -(../24/CH44/EX44.1/Example44_1.sce) (../24/CH44/EX44.2/Example44_2.sce [267] -[268]) (../24/CH44/EX44.3/Example44_3.sce) (../24/CH44/EX44.4/Example44_4.sce -[269]) (../24/CH44/EX44.5/Example44_5.sce) [270] -(../24/CH44/EX44.6/Example44_6.sce) [271] +(../24/CH44/EX44.1/Example44_1.sce) (../24/CH44/EX44.2/Example44_2.sce [272] +[273]) (../24/CH44/EX44.3/Example44_3.sce) (../24/CH44/EX44.4/Example44_4.sce +[274]) (../24/CH44/EX44.5/Example44_5.sce) [275] +(../24/CH44/EX44.6/Example44_6.sce) [276] Chapter 45. -(../24/CH45/EX45.1/Example45_1.sce [272]) (../24/CH45/EX45.2/Example45_2.sce) -(../24/CH45/EX45.3/Example45_3.sce [273]) (../24/CH45/EX45.6/Example45_6.sce) -[274] (../24/CH45/EX45.7/Example45_7.sce) [275] (../24/DEPENDENCIES/quantum.sci +(../24/CH45/EX45.1/Example45_1.sce [277]) (../24/CH45/EX45.2/Example45_2.sce) +(../24/CH45/EX45.3/Example45_3.sce [278]) (../24/CH45/EX45.6/Example45_6.sce) +[279] (../24/CH45/EX45.7/Example45_7.sce) [280] (../24/DEPENDENCIES/quantum.sci ) ! Missing $ inserted. <inserted text> $ -l.3890 \tcaption {degree_rad}{degree_ +l.3960 \tcaption {degree_rad}{degree_ rad} ! Extra }, or forgotten $. -l.3890 \tcaption {degree_rad}{degree_rad} +l.3960 \tcaption {degree_rad}{degree_rad} ! Missing $ inserted. <inserted text> $ -l.3891 ...sting{../24/DEPENDENCIES/degree_rad.sci} +l.3961 ...sting{../24/DEPENDENCIES/degree_rad.sci} ! Missing } inserted. <inserted text> } -l.3891 ...sting{../24/DEPENDENCIES/degree_rad.sci} +l.3961 ...sting{../24/DEPENDENCIES/degree_rad.sci} ! Missing \endgroup inserted. <inserted text> \endgroup -l.3891 ...sting{../24/DEPENDENCIES/degree_rad.sci} +l.3961 ...sting{../24/DEPENDENCIES/degree_rad.sci} ! Missing \endgroup inserted. <inserted text> \endgroup -l.3891 ...sting{../24/DEPENDENCIES/degree_rad.sci} +l.3961 ...sting{../24/DEPENDENCIES/degree_rad.sci} -[276] +[281] ! Undefined control sequence. \lst@GetLineInterval ...r \lst@GLI \lst@linerange \@nil -l.3891 ...sting{../24/DEPENDENCIES/degree_rad.sci} +l.3961 ...sting{../24/DEPENDENCIES/degree_rad.sci} Runaway argument? \@nil \lst@ifsensitive \else \let \lst@KeywordTest \lst@KEYWORDTEST \let \ETC. ! Paragraph ended before \lst@GLI was complete. <to be read again> \par -l.3893 +l.3963 (../24/DEPENDENCIES/Gravitation.sci) (../24/DEPENDENCIES/electrostatics.sci ! TeX capacity exceeded, sorry [grouping levels=255]. |
