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diff --git a/2465/CH17/EX17.4/Ex17_4.sce b/2465/CH17/EX17.4/Ex17_4.sce
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-//Chapter-17,Example 4,Page 370
-clc();
-close();
-
-m1 = 146    //mass of Mg(HCO3)2
-
-m2 = 162    //mass of Ca(HCO3)2
-
-m3 = 111    //mass of CaCl2
-
-m4 = 120    //mass of MgSO4
-
-m5 = 136    //mass of CaSO4
-
-amnt_1 = 12.5     //amount of Mg(HCO3)2 in ppm
-
-amnt_2 = 10.5     //amount of Ca(HCO3)2 in ppm
-
-amnt_3 = 8.2     //amount of CaCl2 in ppm 
-
-amnt_4 = 2.6     //amount of MgSO4 in ppm
-
-amnt_5 = 7.5     //amount of CaSO4 in ppm
-
-temp_hard= (amnt_1*100/m1)+(amnt_2*100/m2)
-
-perm_hard= (amnt_3*100/m3)+(amnt_4*100/m4)+(amnt_5*100/m5)
-
-total= temp_hard +perm_hard
-
-printf("the temporary hardness is = %.3f mg/l",temp_hard)
-
-printf("\n the permanent hardness is = %.3f mg/l",perm_hard)
-
-printf("\n the total  hardness is = %.3f mg/l",total)
-
-v= 100    //volume of sample
-
-v_EDTA = total*v/1000   //volume of EDTA 
-
-printf("\n the volume of M/100 EDTA required is = %.3f ml",v_EDTA)