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-
- Water is flowing through an open channel at a depth of 2 m and a velocity of 3m/s.it then flows through a contracting chute into another channel where the depth i
- s 1 m and the velocity is 10m/s.assuming frictionless flow,determine the difference in the elevation of the channel floors.
-
- Solution:
-
- The points 1 and 2 can be selected on the free surface and therefore p1=p2=0
-
- Therefore by bernoullis equation the difference in the elevation of the channel is y=
-
- 3.6381244
-
- m
-
--->exec('SCI/etc/scilab.quit','errcatch',-1);quit;