diff options
Diffstat (limited to '3776/CH1/EX1.2/Ex1_2.sce')
| -rw-r--r-- | 3776/CH1/EX1.2/Ex1_2.sce | 22 |
1 files changed, 11 insertions, 11 deletions
diff --git a/3776/CH1/EX1.2/Ex1_2.sce b/3776/CH1/EX1.2/Ex1_2.sce index 90d76b556..04492aa43 100644 --- a/3776/CH1/EX1.2/Ex1_2.sce +++ b/3776/CH1/EX1.2/Ex1_2.sce @@ -1,24 +1,24 @@ clear -//Given +//Given load_distributed = 20 //kN/sq.m, This is the load distributed over the pier -H = 2 // m, Total height -h = 1 //m , point of investigation -base = 1.5 //m The length of crossection in side veiw +H = 2 // m, Total height +h = 1 //m , point of investigation +base = 1.5 //m The length of crossection in side view top = 0.5 //m ,The length where load is distributed on top -base_inv = 1 //m , the length at the point of investigation -area = 0.5*1 //m ,The length at a-a crossection +base_inv = 1 //m , the length at the point of investigation +area = 0.5*1 //m ,The length at a-a cross-section density_conc = 25 //kN/sq.m -//caliculation of total weight +//calculation of total weight -v_total = ((top+base)/2)*top*H //sq.m ,The total volume +v_total = ((top+base)/2)*top*H //sq.m ,The total volume w_total = v_total* density_conc //kN , The total weight -R_top = (top**2)*load_distributed //kN , THe reaction force due to load distribution +R_top = (top**2)*load_distributed //kN , THe reaction force due to load distribution reaction_net = w_total + R_top -//caliculation of State of stress at 1m +//calculation of State of stress at 1m v_inv = ((top+base_inv)/2)*top*h //sq.m ,The total volume from 1m to top w_inv = v_inv*density_conc //kN , The total weight from 1m to top reaction_net = w_inv + R_top //kN Stress = reaction_net/area //kN/sq.m printf("\n The total weight of pier is %0.3f kN",w_total) -printf("\n The stress at 1 m above is %0.1f kN/m**2",Stress) +printf("\n The stress at 1 m above is %0.1f kN/sq.m",Stress) |