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clear
//Given
load_distributed = 20 //kN/sq.m, This is the load distributed over the pier
H = 2 // m, Total height
h = 1 //m , point of investigation
base = 1.5 //m The length of crossection in side veiw
top = 0.5 //m ,The length where load is distributed on top
base_inv = 1 //m , the length at the point of investigation
area = 0.5*1 //m ,The length at a-a crossection
density_conc = 25 //kN/sq.m
//caliculation of total weight
v_total = ((top+base)/2)*top*H //sq.m ,The total volume
w_total = v_total* density_conc //kN , The total weight
R_top = (top**2)*load_distributed //kN , THe reaction force due to load distribution
reaction_net = w_total + R_top
//caliculation of State of stress at 1m
v_inv = ((top+base_inv)/2)*top*h //sq.m ,The total volume from 1m to top
w_inv = v_inv*density_conc //kN , The total weight from 1m to top
reaction_net = w_inv + R_top //kN
Stress = reaction_net/area //kN/sq.m
printf("\n The total weight of pier is %0.3f kN",w_total)
printf("\n The stress at 1 m above is %0.1f kN/m**2",Stress)
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