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k = 24.0*(10**12) //N.mm2 Flexure rigidity
E = 200.0 //Gpa - Youngs modulus of the string
l = 5000.0 //mm - The length of the string
C_A = 300.0 //mm2 - crossection area
P = 50.0 //KN - The force applies at the end
a = 2000.0 //mm - The distance C-F
x = 1//X - let it be a variable X
y_d = x*(a**3)/(3*k) //Xmm The displacement at D, lets keep the variable in units part
y_p = -P*(10**3)*(16*(a**3)-12*(a**3)+(a**3))/(k*6) //mm The displacement due to p
e_rod = l/(C_A*E*(10**3)) //Xmm -deflection, The varible is in units
e_rod
X = y_p/(2*e_rod+y_d) // By equating deflections
y_d_1 = X*(a**3)/(3*k) // the deflection of point D
printf("\n The deflection of point D %0.2f mm",y_d_1)
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