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clear
//Given
hp = 200 //Horse power
stress_sh = 10000 //psi- shear stress
rpm_1 = 20.0 // The rpm at which this shaft1 operates
rpm_2 = 20000.0 // The rpm at which this shaft2 operates
T_1= hp*63000.0/rpm_1 //in-lb Torsion due to rpm1
T_2= hp*63000/rpm_2 //in-lb Torsion due to rpm1
//calculations
//j/c=T/shear_T=K
k_1= T_1/stress_sh //cu.in
//c3=2K/3.14
//c_1= ((2*k_1/3)**0.33) //mm - The radius of the shaft
diamter_1 = (16*k_1/%pi)**(1/3) //mm - The diameter of the shaft
printf("\n The Diameter of the shaft1 is %0.2f in",diamter_1)
//j/c=T/shear_T=K
k_2= T_2/stress_sh //mm3
//c3=2K/3.14
//c_2= ((2*k_2/3)**0.33) //mm - The radius of the shaft
diamter_2 = (16*k_2/%pi)**(1/3) //mm - The diameter of the shaft
printf("\n The Diameter of the shaft2 is %0.3f in",diamter_2)
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