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-//Chapter-18,Example 6,Page 407
-clc();
-close();
-
-CO =0.46 //composition of CO
-
-CH4 =0.1 //composition of CH4
-
-H2 =0.4 //composition of H2
-
-C2H2 =0.02 //composition of C2H2
-
-N2=0.01 //composition of N2
-
-//for reaction CO + (1/2)O2 = CO2
-
-V1=CO*(1/2) //volume of O2 required
-
-//for reaction CH4 + 2O2 = CO2 + 2H2O
-
-V2=CH4*2 //volume of O2 required
-
-//for reaction H2 + (1/2)O2 = H2O
-
-V3=H2*(1/2) //volume of O2 required
-
-//for reaction C2H2 + (5/2)O2 = 2CO2 +H2O
-
-V4=C2H2*(5/2) //volume of O2 required
-
-total_v= V1+V2+V3+V4
-
-//as air contains 21% of O2 by volume
-
-V_air = total_v*100/21 //volume of air
-
-printf("the volume of air required is %.3f cubicmeter",V_air)