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//Chapter-18,Example 6,Page 407
clc();
close();
CO =0.46 //composition of CO
CH4 =0.1 //composition of CH4
H2 =0.4 //composition of H2
C2H2 =0.02 //composition of C2H2
N2=0.01 //composition of N2
//for reaction CO + (1/2)O2 = CO2
V1=CO*(1/2) //volume of O2 required
//for reaction CH4 + 2O2 = CO2 + 2H2O
V2=CH4*2 //volume of O2 required
//for reaction H2 + (1/2)O2 = H2O
V3=H2*(1/2) //volume of O2 required
//for reaction C2H2 + (5/2)O2 = 2CO2 +H2O
V4=C2H2*(5/2) //volume of O2 required
total_v= V1+V2+V3+V4
//as air contains 21% of O2 by volume
V_air = total_v*100/21 //volume of air
printf("the volume of air required is %.3f cubicmeter",V_air)
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