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clear
//Given
K=5
l=0.2
c=10**-9 //F
b=15.4
a=15
pd=5000 //V
//Calculation
//
C=(K*l*c)/(41.1*log10(b/a))
//Result
printf("\n (i) The capacitance of cylindrical capacitor is %0.1f *10**-9 F",C*10**9)
printf("\n (ii) The potential of the inner cylinder is equal to p.d. between two cylinders i.e potential of inner cylinder is %0.3f V",pd)
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