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clear
//Given
l = 6 //m -length of the beam
p = 3 //KN-m _ the load applied
R_a = l*p/2 //KN -The reaction at a, Since the system is symmetry
R_b = l*p/2 //KN -The reaction at b
l_s = 10 //mm - The length of the screw
shear_al = 2 //KN - The maximum load the screw can take
I = 2.36*(10**9) //sq.mm The moment of inertia of the whole system
//We will divide this into two parts
l_1 = 50.0 //mm
l_2 = 50.0 //mm
b_1 = 100.0 //mm
b_2 = 200.0 //mm
A_1 = l_1* b_1 //sq.in - area of part_1
y_1 = 200.0 //mm com distance
A_2 =l_2*b_2 //sq.mm - area of part_1
y_2 = 225.0 //in com distance
Q = 2*A_1*y_1 + A_2*y_2 // mm**3 For the whole system
q = R_a*Q*(10**3)/I //N/mm The shear flow
d = shear_al*(10**3)/q //mm The space between the nails
printf("\n The minimal space between the nails %0.0f mm",d)
printf("\n Similar calculation for 4.5 KN gives spacing of 246mm")
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