2465/CH10/EX10.5/Ex10_5.sce


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//Chapter-10,Example 5,Page 253
clc();
close();

E0_Pb=-0.13   

E0_Ni=-0.24   

E0_cell=E0_Pb-E0_Ni

printf('the e.m.f. of cell is %.4f V',E0_cell)
printf('\n the cell reaction is')
printf('\n  Ni + Pb+2 <----> Ni+2 + Pb')