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clear
//given
hp = 63000 //horse power
T = hp*20*(10**-3)/63 //k-in the torsion implies due to horse power
stress_allow_shear = 6 //ksi- The maximum allowable shear stress
M_ver = 6.72/2 //k-in the vertical component of the moment
M_hor = 9.10 //k-in the horizontal component of the moment
//calculations
M = (((M_ver**2)+(M_hor**2))**0.5) //K-in The resultant
d = ((16*(((M**2)+(T**2))**0.5)/(stress_allow_shear*3.14))**0.333) //in** The suggested diameter from derivation
printf("\n The suggested diameter is %0.2f in",d)
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