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//Chapter-3,Example 19,Page 62
clc;
close;
energy= (100*10^6)*24*3600 //energy comsumed in city in a day in Joule
efcy=20/100 //efficiency of reactor
energy_r = energy/efcy //energy required per day
energy_rl=200*1.6*10^-13 //energy released per nuclide
n = energy_r/energy_rl //number of U(235) to be fissioned
//6.023*10^26 atoms of U(235) are present in 235 kg
//n atoms of U(235) are present in
m=235*n/(6.023*10^26)
printf('the amount of fule required for one day operation is %.2f kg',m)
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