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-//Chapter-3,Example 9,Page 59
-clc;
-close;
-
-mole_U =11.9/238 //mole of Uranium
-
-mole_Pb =10.3/206 //mole of lead
-
-t_half= 4.5*10^9   //half life of Uranium
-
-//  U(238)=(U(238) + Pb(206)) * exp(-lamda*t)
-
-//  1 = (1 + Pb(206)/U(238)) * exp(-lamda*t)
-
-//  1 = (1 + 0.5) * exp(-lamda*t)
-
-lamda = 0.693/t_half
-
-t= log10(1+ mole_Pb/mole_U)/(log10(%e)*lamda)
-
-printf('the age of the ore is ')
-
-disp(t)
-
-printf('    years')