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-//Chapter-4,Example 17,Page 97
-clc();
-close();
-
-q= 300 //heat energy
-
-P= 2 // pressure in atm
-
-V1= 10 // volume in litre
-
-V2= 20 //volume in litre
-
-//since 1 lit.atm = 24.25 cal
-
-W=P*(V2-V1)*24.25 //work done
-
-delta_E= q-W //from the 1st law of thermodynamics
-
-printf('the change in internal energy is %.f cal',delta_E)