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//Chapter-18,Example 4,Page 406
clc();
close();
V1= 25 //volume of H2SO4
V2 =15 //volumeof NaOH
v= V1*0.1-V2*0.1 //volume of H2SO4 consumed
//100 cc H2SO4 ==17 g NH3 == 14 g N
//1 cc H2SO4 = 14/1000 g N =0.014 g N
//0.014 g N is present in 1 g coal
N= 0.014*100
printf("the percentage of nitrogen is %.2f ",N)
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