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//Chapter-17,Example 9,Page 372
clc();
close();
m1 = 146 //mass of Mg(HCO3)2
m2 = 162 //mass of Ca(HCO3)2
m3 = 111 //mass of CaCl2
m4 = 120 //mass of MgSO4
m5 = 136 //mass of CaSO4
amnt_1 = 12.5 //amount of Mg(HCO3)2 in ppm
amnt_2 = 10.5 //amount of Ca(HCO3)2 in ppm
amnt_3 = 8.2 //amount of CaCl2 in ppm
amnt_4 = 2.6 //amount of MgSO4 in ppm
amnt_5 = 7.5 //amount of CaSO4 in ppm
temp_hard= [(amnt_1*100/m1)+(amnt_2*100/m2)]*0.1
perm_hard= [(amnt_3*100/m3)+(amnt_4*100/m4)+(amnt_5*100/m5)]*0.1
printf("the temporary hardness is = %.4f degree Fr",temp_hard)
printf("\n the permanent hardness is = %.4f degree Fr",perm_hard)
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