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-rw-r--r--3886/CH22/EX22.10/22_10.sce24
-rw-r--r--3886/CH22/EX22.10/22_10.txt7
-rw-r--r--3886/CH22/EX22.2/22_2.sce20
-rw-r--r--3886/CH22/EX22.2/22_2.txt12
-rw-r--r--3886/CH22/EX22.3/22_3.sce9
-rw-r--r--3886/CH22/EX22.3/22_3.txt6
-rw-r--r--3886/CH22/EX22.4/22_4.sce17
-rw-r--r--3886/CH22/EX22.4/22_4.txt5
-rw-r--r--3886/CH22/EX22.5/22_5.sce13
-rw-r--r--3886/CH22/EX22.5/22_5.txt5
-rw-r--r--3886/CH22/EX22.6/22_6.sce5
-rw-r--r--3886/CH22/EX22.6/22_6.txt4
-rw-r--r--3886/CH22/EX22.7/22_7.sce19
-rw-r--r--3886/CH22/EX22.7/22_7.txt8
-rw-r--r--3886/CH22/EX22.9/22_9.sce12
-rw-r--r--3886/CH22/EX22.9/22_9.txt6
16 files changed, 172 insertions, 0 deletions
diff --git a/3886/CH22/EX22.10/22_10.sce b/3886/CH22/EX22.10/22_10.sce
new file mode 100644
index 000000000..59bab8f89
--- /dev/null
+++ b/3886/CH22/EX22.10/22_10.sce
@@ -0,0 +1,24 @@
+//rotating crank
+//refer fig. 22.16 (a),(b),(c),(d),(e),(f),(g),(h) and (i)
+//from sine rule
+theta=asind((80*sind(60))/(200)) //degree
+//angular velocity of crank
+omega=(2*%pi*1800)/(60) //rad/sec
+vB=0.08*omega //m/sec
+//it is at right angles to BC
+aB=(15.0796^2/0.8) //m/sec^2
+vA=15.8436 //m/sec
+aB=2842.4292 //making 60 degree with horizontal
+alpha=13120.457 //rad/sec^2
+aAB=0.2*alpha
+aA=512.2027 //m/sec^2
+aX=1118.2109 //m/sec^2
+aY=-1174.862 //m/sec^2 downward
+//Consider dynamic equilibrium of piston A
+HA=(4000)-((50*512.2027)/(9.81)) //kN The answer provided in the textbook is wrong
+//Taking moment about B
+vA=813.95 //N
+vB=2001.57 //N
+HB=2598.51 //N
+printf("\nHA=%.2f kN\nHB=%.2f N\nvA=%.2f N\nvB=%.2f N",HA,HB,vA,vB)
+
diff --git a/3886/CH22/EX22.10/22_10.txt b/3886/CH22/EX22.10/22_10.txt
new file mode 100644
index 000000000..127e5fa16
--- /dev/null
+++ b/3886/CH22/EX22.10/22_10.txt
@@ -0,0 +1,7 @@
+
+--> exec('E:\My program EM\22.General plane motion of rigid bodies\22.10.sce', -1)
+
+HA=1389.38 kN
+HB=2598.51 N
+vA=813.95 N
+vB=2001.57 N \ No newline at end of file
diff --git a/3886/CH22/EX22.2/22_2.sce b/3886/CH22/EX22.2/22_2.sce
new file mode 100644
index 000000000..b27f951e3
--- /dev/null
+++ b/3886/CH22/EX22.2/22_2.sce
@@ -0,0 +1,20 @@
+//1 m radius wheel
+//refer fig. 22.4(a),(b),(c),(d),(e) and (f)
+vA=1*5 //m/sec
+aA=1*4 //m/sec^2
+vBA=1*5 //m/sec
+vB=vA+vBA //m/sec
+aBA=1*4 //m/sec^2
+an=5^2 //m/sec^2
+aB=sqrt((8^2)+(25^2)) //m/sec^2
+theta=atand(25/8) //degree
+//Consider rotation of point D
+vDx=5+3*sind(60) //m/sec
+vDy=3*cosd(60) //m/sec
+vD=7.745 //m/sec
+//inclination to horizontal
+theta2=atand(1.5/7.598) //degree
+vDA=0.6*5 //m/sec^2
+aD=sqrt((14.190^2)+(1.422^2)) //m/sec^2
+theta3=atand(14.190/1.422) //degree
+printf("\nAt B\naB=%.3f m/sec^2\ntheta=%.2f degree\nvB=%.3f m/sec\nAt D\nvD=%.3f m/sec^2\ntheta2=%.2f degree\naD=%.3f m/sec^2\ntheta3=%.2f degree",aB,theta,vB,vD,theta2,aD,theta3)
diff --git a/3886/CH22/EX22.2/22_2.txt b/3886/CH22/EX22.2/22_2.txt
new file mode 100644
index 000000000..cd5aaf0cc
--- /dev/null
+++ b/3886/CH22/EX22.2/22_2.txt
@@ -0,0 +1,12 @@
+
+--> exec('E:\My program EM\22.General plane motion of rigid bodies\22.2.sce', -1)
+
+At B
+aB=26.249 m/sec^2
+theta=72.26 degree
+vB=10.000 m/sec
+At D
+vD=7.745 m/sec^2
+theta2=11.17 degree
+aD=14.261 m/sec^2
+theta3=84.28 degree \ No newline at end of file
diff --git a/3886/CH22/EX22.3/22_3.sce b/3886/CH22/EX22.3/22_3.sce
new file mode 100644
index 000000000..7842cd8d7
--- /dev/null
+++ b/3886/CH22/EX22.3/22_3.sce
@@ -0,0 +1,9 @@
+//slender beam
+//refer fig. 22.5 (a),(b) and (c)
+//from vector diagram
+vB=2*cotd(60) //m/sec
+vBA=(2/sind(60)) //m/sec
+printf("\nvB=%.3f m/sec^2\nvB/A=%.3f m/sec",vB,vBA)
+//acceleration of point B
+aB=(1.778*sind(60))+(3*0.958*sind(30))
+printf("\naB=%.3f m/sec^2",aB)
diff --git a/3886/CH22/EX22.3/22_3.txt b/3886/CH22/EX22.3/22_3.txt
new file mode 100644
index 000000000..4755147cc
--- /dev/null
+++ b/3886/CH22/EX22.3/22_3.txt
@@ -0,0 +1,6 @@
+
+--> exec('E:\My program EM\22.General plane motion of rigid bodies\22.3.sce', -1)
+
+vB=1.155 m/sec^2
+vB/A=2.309 m/sec
+aB=2.977 m/sec^2 \ No newline at end of file
diff --git a/3886/CH22/EX22.4/22_4.sce b/3886/CH22/EX22.4/22_4.sce
new file mode 100644
index 000000000..ec7aa2d40
--- /dev/null
+++ b/3886/CH22/EX22.4/22_4.sce
@@ -0,0 +1,17 @@
+//Length of crank
+//refer fig. 22.6 (a)
+//angular velocity
+omega=(1500*2*%pi)/(60) //rad/sec
+r=0.100
+//Tangential velocity of end B
+vB=r*omega //m/sec
+//Consider motion of connecting rod BC
+theta=asind((100*sind(30))/(250)) //degree
+//Refer fig. 22.6
+//Let omega' be the angular velocity of BC
+omega1=13.6035/0.244 //rad/sec
+//Considering horizontal component of velocities
+vC=15.7080*cosd(60)+0.25*55.547*sind(11.5378) //m/sec
+printf("\nomega1=%.3f rad/sec\nvC=%.2f m/sec",omega1,vC)
+
+
diff --git a/3886/CH22/EX22.4/22_4.txt b/3886/CH22/EX22.4/22_4.txt
new file mode 100644
index 000000000..275ff3aa0
--- /dev/null
+++ b/3886/CH22/EX22.4/22_4.txt
@@ -0,0 +1,5 @@
+
+--> exec('E:\My program EM\22.General plane motion of rigid bodies\22.4.sce', -1)
+
+omega1=55.752 rad/sec
+vC=10.63 m/sec \ No newline at end of file
diff --git a/3886/CH22/EX22.5/22_5.sce b/3886/CH22/EX22.5/22_5.sce
new file mode 100644
index 000000000..ef6f7a228
--- /dev/null
+++ b/3886/CH22/EX22.5/22_5.sce
@@ -0,0 +1,13 @@
+//Velocities of point B and D
+//refer fig. 22.8
+vA=5*1 //m/sec
+//Instantaneous centre in vertically downward direction
+Ic=5/5 //m
+vB=2*5 //m/sec
+CP=1+0.6*sind(60) //m
+PD=0.6*cosd(60) //m
+CD=sqrt((1.520^2)+(0.3^2)) //m
+vD=1.549*5 //m/sec
+//Inclination to horizontal
+theta=atand((0.3)/(1.520)) //degree
+printf("\nvD=%.2f m/sec\ntheta=%.2f degree",vD,theta)
diff --git a/3886/CH22/EX22.5/22_5.txt b/3886/CH22/EX22.5/22_5.txt
new file mode 100644
index 000000000..1ad356b5b
--- /dev/null
+++ b/3886/CH22/EX22.5/22_5.txt
@@ -0,0 +1,5 @@
+
+--> exec('E:\My program EM\22.General plane motion of rigid bodies\22.5.sce', -1)
+
+vD=7.74 m/sec
+theta=11.16 degree \ No newline at end of file
diff --git a/3886/CH22/EX22.6/22_6.sce b/3886/CH22/EX22.6/22_6.sce
new file mode 100644
index 000000000..997567380
--- /dev/null
+++ b/3886/CH22/EX22.6/22_6.sce
@@ -0,0 +1,5 @@
+//Velocity of B
+//refer fig.2.9
+omega=(2)/(3*sind(60)) //rad/sec
+vB=3*0.770*cosd(60) //m/sec
+printf("\nvB=%.3f m/sec",vB)
diff --git a/3886/CH22/EX22.6/22_6.txt b/3886/CH22/EX22.6/22_6.txt
new file mode 100644
index 000000000..3e17969aa
--- /dev/null
+++ b/3886/CH22/EX22.6/22_6.txt
@@ -0,0 +1,4 @@
+
+--> exec('E:\My program EM\22.General plane motion of rigid bodies\22.6.sce', -1)
+
+vB=1.155 m/sec \ No newline at end of file
diff --git a/3886/CH22/EX22.7/22_7.sce b/3886/CH22/EX22.7/22_7.sce
new file mode 100644
index 000000000..462153e31
--- /dev/null
+++ b/3886/CH22/EX22.7/22_7.sce
@@ -0,0 +1,19 @@
+//Solid cylinder acted upon by force P
+//refer fig. 22.11 (a) and (b)
+//(1)Maximum Value of P for Rolling without slipping
+//aA=0.8*alpha
+I=(1200*0.8^2)/(2*9.81)
+W=1200 //N
+N=W //N
+//From law of friction
+F=0.2*1200 //N
+//Consider moment equilibrium equation about C
+//on solving
+alpha=(240)/(97.859-73.394) //rad/sec
+P=73.394*9.81 //N
+//(2) When P=1000 N
+F2=0.15*1200 //N
+//Taking moment about A
+alpha2=(1000*0.8-180*0.8)/(39.144) //rad/sec^2
+aA=((1000+180)*9.81)/(1200) //rad/sec^2
+printf("\nMaximum Value of P for Rolling without slipping \nP=%.2f N\nWhen P=1000 N\nalpha=%.2f rad/sec^2\naA=%.3f rad/sec^2",P,alpha2,aA)
diff --git a/3886/CH22/EX22.7/22_7.txt b/3886/CH22/EX22.7/22_7.txt
new file mode 100644
index 000000000..c2d03e256
--- /dev/null
+++ b/3886/CH22/EX22.7/22_7.txt
@@ -0,0 +1,8 @@
+
+--> exec('E:\My program EM\22.General plane motion of rigid bodies\22.7.sce', -1)
+
+Maximum Value of P for Rolling without slipping
+P=720.00 N
+When P=1000 N
+alpha=16.76 rad/sec^2
+aA=9.647 rad/sec^2 \ No newline at end of file
diff --git a/3886/CH22/EX22.9/22_9.sce b/3886/CH22/EX22.9/22_9.sce
new file mode 100644
index 000000000..996d5d633
--- /dev/null
+++ b/3886/CH22/EX22.9/22_9.sce
@@ -0,0 +1,12 @@
+//Uniform bar
+//refer fig. 22.15(a),(b),(c),(d),(e) and (f)
+beta=atand(0.6928/1.7856) //degree
+//aG=alpha*sqrt((1.7856^2)+(0.6928^2))
+I=(300*1.6^2)/(12*9.81)
+//Equating
+alpha=((300*0.6928)/(82.3160)) //rad/sec^2
+//Taking horizontal components of the forces
+NB=(300*1.7856*2.5249)/(9.81*cosd(45)) //N
+//Taking vertical components of the forces
+NA=(300)-(194.98*sind(45))+((300*0.6928*2.5249)/(9.81)) //N (Printing mistake in text book)
+printf("\nNA=%.2f N\nNB=%.2f N\nalpha=%.2f rad/sec^2",NA,NB,alpha)
diff --git a/3886/CH22/EX22.9/22_9.txt b/3886/CH22/EX22.9/22_9.txt
new file mode 100644
index 000000000..cc49cf166
--- /dev/null
+++ b/3886/CH22/EX22.9/22_9.txt
@@ -0,0 +1,6 @@
+
+--> exec('E:\My program EM\22.General plane motion of rigid bodies\22.9.sce', -1)
+
+NA=215.62 N
+NB=194.98 N
+alpha=2.52 rad/sec^2 \ No newline at end of file