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diff --git a/3472/CH35/EX35.2/Example35_2.sce b/3472/CH35/EX35.2/Example35_2.sce
new file mode 100644
index 000000000..b64e07936
--- /dev/null
+++ b/3472/CH35/EX35.2/Example35_2.sce
@@ -0,0 +1,27 @@
+// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION 
+
+// PART III : SWITCHGEAR AND PROTECTION
+// CHAPTER 9: PROTECTION OF TRANSFORMERS
+
+// EXAMPLE : 9.2 :
+// Page number 635-636
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+V_lv = 220.0                 // LV side voltage of transformer(V)
+V_hv = 11000.0               // HV side voltage of transformer(V)
+ratio_CT = 600.0/(5/3**0.5)  // CT ratio on LV side of transformer
+
+// Calculations
+CT_pri = 600.0           // Primary CT
+CT_sec = 5.0/3**0.5      // Secondary CT
+I_1 = V_lv/V_hv*CT_pri   // Line current in secondary of transformer corresponding to primary winding(A)
+I_2 = CT_sec*3**0.5      // Current in secondary of CT(A)
+
+// Results
+disp("PART III - EXAMPLE : 9.2 : SOLUTION :-")
+printf("\nRatio of CTs on 11000 V side = %.f : %.f \n", I_1,I_2)
+printf("\nNOTE: ERROR: Mistake in representing the final answer in textbook solution")
diff --git a/3472/CH35/EX35.3/Example35_3.sce b/3472/CH35/EX35.3/Example35_3.sce
new file mode 100644
index 000000000..94791899b
--- /dev/null
+++ b/3472/CH35/EX35.3/Example35_3.sce
@@ -0,0 +1,28 @@
+// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION 
+
+// PART III : SWITCHGEAR AND PROTECTION
+// CHAPTER 9: PROTECTION OF TRANSFORMERS
+
+// EXAMPLE : 9.3 :
+// Page number 636
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+V_lv = 11.0*10**3       // LV side voltage of transformer(V)
+V_hv = 66.0*10**3       // HV side voltage of transformer(V)
+ratio_CT = 250.0/5      // CT ratio on LV side of transformer
+
+// Calculations
+V_hv_phase = V_hv/3**0.5          // HV side phase voltage(V)
+ratio_main_T = V_hv_phase/V_lv    // Ratio of main transformer
+I_2 = 250.0                       // Primary CT
+I_1 = I_2/(ratio_main_T*3**0.5)   // Primary line current(A)
+CT_sec = 5.0                      // Secondary CT
+secondary_side = CT_sec/3**0.5    // HV side CT secondary
+
+// Results
+disp("PART III - EXAMPLE : 9.3 : SOLUTION :-")
+printf("\nRatio of CTs on high voltage side = %.1f : %.1f = (%.f/%.2f√3) : (%.f/√3) ", I_1,secondary_side,I_2,ratio_main_T,CT_sec)
diff --git a/3472/CH35/EX35.4/Example35_4.sce b/3472/CH35/EX35.4/Example35_4.sce
new file mode 100644
index 000000000..c9ebde03f
--- /dev/null
+++ b/3472/CH35/EX35.4/Example35_4.sce
@@ -0,0 +1,26 @@
+// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION 
+
+// PART III : SWITCHGEAR AND PROTECTION
+// CHAPTER 9: PROTECTION OF TRANSFORMERS
+
+// EXAMPLE : 9.4 :
+// Page number 636
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+V_hv = 33.0           // HV side voltage of transformer(kV)
+V_lv = 6.6            // LV side voltage of transformer(kV)
+ratio_CT = 100.0/1    // CT ratio on LV side of transformer
+
+// Calculations
+CT_pri = 100.0              // Primary CT
+CT_sec = 1.0                // Secondary CT
+I_hv = V_lv/V_hv*CT_pri     // Line current on HV side(A)
+I_lv = CT_sec/3**0.5        // Line current on LV side(A)
+
+// Results
+disp("PART III - EXAMPLE : 9.4 : SOLUTION :-")
+printf("\nRatio of protective CTs on 33 kV side = %.f : %.f/√3 = %.f : %.f ", I_hv,CT_sec,3**0.5*I_hv,I_lv*3**0.5)
diff --git a/3472/CH35/EX35.5/Example35_5.sce b/3472/CH35/EX35.5/Example35_5.sce
new file mode 100644
index 000000000..369e627d8
--- /dev/null
+++ b/3472/CH35/EX35.5/Example35_5.sce
@@ -0,0 +1,30 @@
+// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION 
+
+// PART III : SWITCHGEAR AND PROTECTION
+// CHAPTER 9: PROTECTION OF TRANSFORMERS
+
+// EXAMPLE : 9.5 :
+// Page number 636-637
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+kVA = 200.0          // Transformer rating(kVA)
+E_1 = 11000.0        // HV side voltage of transformer(kV)
+E_2 = 400.0          // LV side voltage of transformer(kV)
+ratio_CT = 500.0/5   // CT ratio on LV side of transformer
+I_f = 750.0          // Fault current(A)
+
+// Calculations
+I_2 = 500.0                   // Primary CT
+I_1 = 5.0                     // Secondary CT
+I_1_T = E_2*I_2/(3**0.5*E_1)  // Primary current in transformer(A)
+I_hv_T = I_1_T*3**0.5         // Equivalent line current on HV side(A)
+I_pilot_lv = I_1*3**0.5       // Pilot current on LV side(A)
+
+// Results
+disp("PART III - EXAMPLE : 9.5 : SOLUTION :-")
+printf("\nCT ratios on high voltage side = %.2f : %.2f \n", I_hv_T,I_pilot_lv)
+printf("\nNOTE: Circulating current is not calculated")
diff --git a/3472/CH35/EX35.6/Example35_6.sce b/3472/CH35/EX35.6/Example35_6.sce
new file mode 100644
index 000000000..27c4f3d26
--- /dev/null
+++ b/3472/CH35/EX35.6/Example35_6.sce
@@ -0,0 +1,27 @@
+// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION 
+
+// PART III : SWITCHGEAR AND PROTECTION
+// CHAPTER 9: PROTECTION OF TRANSFORMERS
+
+// EXAMPLE : 9.6 :
+// Page number 640
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+MVA = 50.0        // Transformer rating(MVA)
+V_hv = 132.0      // HV side voltage of transformer(kV)
+V_lv = 33.0       // LV side voltage of transformer(kV)
+CT_sec = 1.0      // Secondary CT rating
+
+// Calculations
+I_FL = MVA*1000/(3**0.5*V_lv)                       // Full-load current(A)
+CT_ratio_33kV = I_FL/CT_sec                         // CT ratio on 33 kV side
+CT_ratio_132kV = (I_FL*V_lv/V_hv)/(CT_sec/3**0.5)   // CT ratio on 132 kV side
+
+// Results
+disp("PART III - EXAMPLE : 9.6 : SOLUTION :-")
+printf("\nCT ratio on 33 kV side = %.f : 1 ", CT_ratio_33kV)
+printf("\nCT ratio on 132 kV side = %.f : 1 = %.f√3 : 1 ", CT_ratio_132kV,CT_ratio_132kV/3**0.5)