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diff --git a/3472/CH35/EX35.5/Example35_5.sce b/3472/CH35/EX35.5/Example35_5.sce new file mode 100644 index 000000000..369e627d8 --- /dev/null +++ b/3472/CH35/EX35.5/Example35_5.sce @@ -0,0 +1,30 @@ +// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION
+
+// PART III : SWITCHGEAR AND PROTECTION
+// CHAPTER 9: PROTECTION OF TRANSFORMERS
+
+// EXAMPLE : 9.5 :
+// Page number 636-637
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+kVA = 200.0 // Transformer rating(kVA)
+E_1 = 11000.0 // HV side voltage of transformer(kV)
+E_2 = 400.0 // LV side voltage of transformer(kV)
+ratio_CT = 500.0/5 // CT ratio on LV side of transformer
+I_f = 750.0 // Fault current(A)
+
+// Calculations
+I_2 = 500.0 // Primary CT
+I_1 = 5.0 // Secondary CT
+I_1_T = E_2*I_2/(3**0.5*E_1) // Primary current in transformer(A)
+I_hv_T = I_1_T*3**0.5 // Equivalent line current on HV side(A)
+I_pilot_lv = I_1*3**0.5 // Pilot current on LV side(A)
+
+// Results
+disp("PART III - EXAMPLE : 9.5 : SOLUTION :-")
+printf("\nCT ratios on high voltage side = %.2f : %.2f \n", I_hv_T,I_pilot_lv)
+printf("\nNOTE: Circulating current is not calculated")
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