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// A Texbook on POWER SYSTEM ENGINEERING
// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
// DHANPAT RAI & Co.
// SECOND EDITION
// PART III : SWITCHGEAR AND PROTECTION
// CHAPTER 9: PROTECTION OF TRANSFORMERS
// EXAMPLE : 9.2 :
// Page number 635-636
clear ; clc ; close ; // Clear the work space and console
// Given data
V_lv = 220.0 // LV side voltage of transformer(V)
V_hv = 11000.0 // HV side voltage of transformer(V)
ratio_CT = 600.0/(5/3**0.5) // CT ratio on LV side of transformer
// Calculations
CT_pri = 600.0 // Primary CT
CT_sec = 5.0/3**0.5 // Secondary CT
I_1 = V_lv/V_hv*CT_pri // Line current in secondary of transformer corresponding to primary winding(A)
I_2 = CT_sec*3**0.5 // Current in secondary of CT(A)
// Results
disp("PART III - EXAMPLE : 9.2 : SOLUTION :-")
printf("\nRatio of CTs on 11000 V side = %.f : %.f \n", I_1,I_2)
printf("\nNOTE: ERROR: Mistake in representing the final answer in textbook solution")
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