blob: c9ebde03f0583607f8ac8222145c7a6d3e829724 (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
|
// A Texbook on POWER SYSTEM ENGINEERING
// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
// DHANPAT RAI & Co.
// SECOND EDITION
// PART III : SWITCHGEAR AND PROTECTION
// CHAPTER 9: PROTECTION OF TRANSFORMERS
// EXAMPLE : 9.4 :
// Page number 636
clear ; clc ; close ; // Clear the work space and console
// Given data
V_hv = 33.0 // HV side voltage of transformer(kV)
V_lv = 6.6 // LV side voltage of transformer(kV)
ratio_CT = 100.0/1 // CT ratio on LV side of transformer
// Calculations
CT_pri = 100.0 // Primary CT
CT_sec = 1.0 // Secondary CT
I_hv = V_lv/V_hv*CT_pri // Line current on HV side(A)
I_lv = CT_sec/3**0.5 // Line current on LV side(A)
// Results
disp("PART III - EXAMPLE : 9.4 : SOLUTION :-")
printf("\nRatio of protective CTs on 33 kV side = %.f : %.f/√3 = %.f : %.f ", I_hv,CT_sec,3**0.5*I_hv,I_lv*3**0.5)
|
