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diff --git a/3472/CH35/EX35.6/Example35_6.sce b/3472/CH35/EX35.6/Example35_6.sce new file mode 100644 index 000000000..27c4f3d26 --- /dev/null +++ b/3472/CH35/EX35.6/Example35_6.sce @@ -0,0 +1,27 @@ +// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION
+
+// PART III : SWITCHGEAR AND PROTECTION
+// CHAPTER 9: PROTECTION OF TRANSFORMERS
+
+// EXAMPLE : 9.6 :
+// Page number 640
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+MVA = 50.0 // Transformer rating(MVA)
+V_hv = 132.0 // HV side voltage of transformer(kV)
+V_lv = 33.0 // LV side voltage of transformer(kV)
+CT_sec = 1.0 // Secondary CT rating
+
+// Calculations
+I_FL = MVA*1000/(3**0.5*V_lv) // Full-load current(A)
+CT_ratio_33kV = I_FL/CT_sec // CT ratio on 33 kV side
+CT_ratio_132kV = (I_FL*V_lv/V_hv)/(CT_sec/3**0.5) // CT ratio on 132 kV side
+
+// Results
+disp("PART III - EXAMPLE : 9.6 : SOLUTION :-")
+printf("\nCT ratio on 33 kV side = %.f : 1 ", CT_ratio_33kV)
+printf("\nCT ratio on 132 kV side = %.f : 1 = %.f√3 : 1 ", CT_ratio_132kV,CT_ratio_132kV/3**0.5)
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