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12 files changed, 198 insertions, 0 deletions

diff --git a/3718/CH6/EX6.10/Ex6_10.sce b/3718/CH6/EX6.10/Ex6_10.sce
new file mode 100644
index 000000000..df86e87d4
--- /dev/null
+++ b/3718/CH6/EX6.10/Ex6_10.sce
@@ -0,0 +1,16 @@
+//Chapter 6: Electrochemistry

+//Problem: 10

+clc;

+

+//Declaration of Variables

+T = 25        // C

+Cu = 0.1      // M

+Zn = 0.001    // M

+Eo = 1.1      // V

+

+// Solution

+mprintf("Zn(s) | Zn+2 (0.001M) || Cu+2(0.1M) | Cu(s)\n")

+

+Ecell = Eo + 0.0592 / 2 * log10(Cu / Zn)

+

+mprintf(" The emf of a Daniel cell is %.4f V",Ecell)

diff --git a/3718/CH6/EX6.11/Ex6_11.sce b/3718/CH6/EX6.11/Ex6_11.sce
new file mode 100644
index 000000000..4ecbc9dd0
--- /dev/null
+++ b/3718/CH6/EX6.11/Ex6_11.sce
@@ -0,0 +1,18 @@
+//Chapter 6: Electrochemistry

+//Problem: 11

+clc;

+

+//Declaration of Variables

+pH = 7        // O2

+Eo = 1.229    // V

+pO2 = 0.20    // bar

+

+// Solution

+mprintf("Nernst equation at 25C is,\n")

+mprintf(" E = Eo - (0.0592 / 2) * log(1 / ([H+]^2 * [pO2]^ (1/2)))\n")

+

+E = Eo - (0.0592 / 2) * log10(1.0 / (((10 ** (- 7)) ** 2) * (pO2 ** (1 / 2.0))))

+

+mprintf(" The reduction potential for the reduction is %.3f V",E)

+

+// The answer provided in the textbook is wrong

diff --git a/3718/CH6/EX6.12/Ex6_12.sce b/3718/CH6/EX6.12/Ex6_12.sce
new file mode 100644
index 000000000..7ec96c913
--- /dev/null
+++ b/3718/CH6/EX6.12/Ex6_12.sce
@@ -0,0 +1,23 @@
+//Chapter 6: Electrochemistry

+//Problem: 12

+clc;

+

+//Declaration of Variables

+E_KCl = 0.2415       // V

+E_cell = 0.445       // V

+

+

+// Solution

+mprintf("Emf of the cell is\n")

+mprintf(" At 25C,\n")

+mprintf(" E = Er - El = Eref - ((RT)/ F) * ln H+\n")

+

+pH = (E_cell - E_KCl) / 0.059

+Eo_cell = - 0.8277    // V

+

+mprintf(" Thus, equilibrium constant for the reaction\n")

+mprintf(" 2H2O --> H3O+  + OH- may be calculated as\n")

+

+K = 10 ** (Eo_cell / 0.0591)

+

+mprintf(" K = %.e",K)

diff --git a/3718/CH6/EX6.13/Ex6_13.sce b/3718/CH6/EX6.13/Ex6_13.sce
new file mode 100644
index 000000000..95542167f
--- /dev/null
+++ b/3718/CH6/EX6.13/Ex6_13.sce
@@ -0,0 +1,16 @@
+//Chapter 6: Electrochemistry

+//Problem: 13

+clc;

+

+//Declaration of Variables

+EoSn = 0.15        // V

+EoCr = - 0.74      // V

+

+// Solution

+mprintf("3Sn+4  +  2Cr  -->  3Sn+2 + 2Cr+3\n")

+

+Eo_cell = EoSn - EoCr

+n = 6

+K = 10 ** (n * Eo_cell / 0.0591)

+

+mprintf(" The equillibrium constant for th reaction is %.2e ",K)

diff --git a/3718/CH6/EX6.14/Ex6_14.sce b/3718/CH6/EX6.14/Ex6_14.sce
new file mode 100644
index 000000000..f31642d99
--- /dev/null
+++ b/3718/CH6/EX6.14/Ex6_14.sce
@@ -0,0 +1,14 @@
+//Chapter 6: Electrochemistry

+//Problem: 14

+clc;

+

+//Declaration of Variables

+T = 25           // C

+Eo = - 0.8277    // V

+

+// Solution

+mprintf("The reversible reaction,\n")

+mprintf(" 2H2O  <--> H3O+ + OH-\n")

+mprintf(" May be divided into two parts.\n")

+mprintf(" 2H2O + e- --> 1/2 H2 + OH-    (cathode) Eo = -0.8277 V\n")

+mprintf(" H2O  + 1/2 H2 --> H3O+ + e-   (anode) Eo = 0")

diff --git a/3718/CH6/EX6.15/Ex6_15.sce b/3718/CH6/EX6.15/Ex6_15.sce
new file mode 100644
index 000000000..c0959e1e9
--- /dev/null
+++ b/3718/CH6/EX6.15/Ex6_15.sce
@@ -0,0 +1,16 @@
+//Chapter 6: Electrochemistry

+//Problem: 15

+clc;

+

+//Declaration of Variables

+E = 0.4         // V

+

+// Solution

+

+mprintf( "The cell is Pt(H2) | H+, pH2 = 1 atm\n")

+mprintf(" The cell reaction is\n")

+mprintf(" 1/2 H2 --> H+ + e-\n")

+

+pH = E / 0.0591

+

+mprintf(" pH = %.3f ",pH)

diff --git a/3718/CH6/EX6.2/Ex6_2.sce b/3718/CH6/EX6.2/Ex6_2.sce
new file mode 100644
index 000000000..b99a19e48
--- /dev/null
+++ b/3718/CH6/EX6.2/Ex6_2.sce
@@ -0,0 +1,13 @@
+//Chapter 6: Electrochemistry

+//Problem: 2

+clc;

+

+//Declaration of Variables

+T = 25          // C

+Cu = 0.1        // M

+Zn = 0.001      // M

+Eo = 1.1

+

+// Solution

+E = Eo + 0.0296 * log10(Cu / Zn)

+mprintf("The emf of Daniell cell is %.4f V",E)

diff --git a/3718/CH6/EX6.3/Ex6_3.sce b/3718/CH6/EX6.3/Ex6_3.sce
new file mode 100644
index 000000000..7bedec041
--- /dev/null
+++ b/3718/CH6/EX6.3/Ex6_3.sce
@@ -0,0 +1,17 @@
+//Chapter 6: Electrochemistry

+//Problem: 3

+clc;

+

+//Declaration of Constant

+R = 8.314       //in J per K

+F = 96500       //in C per mol

+

+//Declaration of Variables

+Cu = 0.15      //in M

+Eo = 0.34      //in V

+T = 298        //in K

+n = 2          //in moles

+

+// Solution

+E = Eo + (2.303 * R * T) / (n * F) * log10(Cu)

+mprintf("The single electrode potential for copper metal is %.4f V",E)

diff --git a/3718/CH6/EX6.4/Ex6_4.sce b/3718/CH6/EX6.4/Ex6_4.sce
new file mode 100644
index 000000000..53d63487a
--- /dev/null
+++ b/3718/CH6/EX6.4/Ex6_4.sce
@@ -0,0 +1,13 @@
+//Chapter 6: Electrochemistry

+//Problem: 4

+clc;

+

+//Declaration of Variable

+Eo_Cu = 0.3370      // Cu+2 -> Cu

+Eo_Zn = - 0.7630    // Zn -> Zn +2

+

+// Solution

+Eo_cell = Eo_Cu - Eo_Zn

+

+mprintf("Daniel cell is, Zn | Zn +2 || Cu+2 | Cu\n")

+mprintf(" Eo (cell) is %.1f V", Eo_cell)

diff --git a/3718/CH6/EX6.5/Ex6_5.sce b/3718/CH6/EX6.5/Ex6_5.sce
new file mode 100644
index 000000000..d59a72a09
--- /dev/null
+++ b/3718/CH6/EX6.5/Ex6_5.sce
@@ -0,0 +1,13 @@
+//Chapter 6: Electrochemistry

+//Problem: 5

+clc;

+

+//Declaration of Variable

+Eo_Cu = 0.3370       // Cu+2 -> Cu

+Eo_Cd = - 0.4003     // Cd -> Cd +2

+

+// Solution

+Eo_cell = Eo_Cu - Eo_Cd

+

+mprintf("Cell is, Cd | Cd +2 || Cu+2 | Cu\n")

+mprintf(" Eo (cell) is %.4f V", Eo_cell)

diff --git a/3718/CH6/EX6.6/Ex6_6.sce b/3718/CH6/EX6.6/Ex6_6.sce
new file mode 100644
index 000000000..c0acffd39
--- /dev/null
+++ b/3718/CH6/EX6.6/Ex6_6.sce
@@ -0,0 +1,18 @@
+//Chapter 6: Electrochemistry

+//Problem: 6

+clc;

+

+//Declaration of Constant

+F = 96500        // C / mol

+

+//Declaration of Variables

+n = 2

+T = 25           // C

+Eo_Ag = 0.80     // Ag+ / Ag

+Eo_Ni = - 0.24   // Ni+2 / Ni

+

+// Solution

+Eo_Cell = Eo_Ag - Eo_Ni

+delta_Go = - n * F * Eo_Cell

+

+mprintf("Standard free energy change %d J / mol",delta_Go)

diff --git a/3718/CH6/EX6.8/Ex6_8.sce b/3718/CH6/EX6.8/Ex6_8.sce
new file mode 100644
index 000000000..dd5aa771e
--- /dev/null
+++ b/3718/CH6/EX6.8/Ex6_8.sce
@@ -0,0 +1,21 @@
+//Chapter 6: Electrochemistry

+//Problem: 8

+clc;

+

+//Declaration of Constant

+F = 96500     //in C per mol

+

+//Declaration of Variables

+E1o = - 2.48  //in V

+E2o = 1.61    //in V

+

+// Solution

+delta_G1 = - 3 * F * (- 2.48)

+delta_G2 = - 1 * F * 1.61

+

+mprintf("delta_G3 = delta_G1 + delta_G2\n")

+mprintf(" delta_G3 = - 4 * F * E3o\n")

+

+E3o = (delta_G1 + delta_G2) / (- 4 * F)

+

+mprintf(" The reduction potential for the half-cell Pt/Ce, Ce+4 is %.4f V",E3o)