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//Chapter 6: Electrochemistry
//Problem: 11
clc;
//Declaration of Variables
pH = 7 // O2
Eo = 1.229 // V
pO2 = 0.20 // bar
// Solution
mprintf("Nernst equation at 25C is,\n")
mprintf(" E = Eo - (0.0592 / 2) * log(1 / ([H+]^2 * [pO2]^ (1/2)))\n")
E = Eo - (0.0592 / 2) * log10(1.0 / (((10 ** (- 7)) ** 2) * (pO2 ** (1 / 2.0))))
mprintf(" The reduction potential for the reduction is %.3f V",E)
// The answer provided in the textbook is wrong
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