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+//Chapter 6: Electrochemistry
+//Problem: 8
+clc;
+
+//Declaration of Constant
+F = 96500     //in C per mol
+
+//Declaration of Variables
+E1o = - 2.48  //in V
+E2o = 1.61    //in V
+
+// Solution
+delta_G1 = - 3 * F * (- 2.48)
+delta_G2 = - 1 * F * 1.61
+
+mprintf("delta_G3 = delta_G1 + delta_G2\n")
+mprintf(" delta_G3 = - 4 * F * E3o\n")
+
+E3o = (delta_G1 + delta_G2) / (- 4 * F)
+
+mprintf(" The reduction potential for the half-cell Pt/Ce, Ce+4 is %.4f V",E3o)