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//Chapter 6: Electrochemistry
//Problem: 15
clc;
//Declaration of Variables
E = 0.4 // V
// Solution
mprintf( "The cell is Pt(H2) | H+, pH2 = 1 atm\n")
mprintf(" The cell reaction is\n")
mprintf(" 1/2 H2 --> H+ + e-\n")
pH = E / 0.0591
mprintf(" pH = %.3f ",pH)
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