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//Chapter 6: Electrochemistry
//Problem: 13
clc;
//Declaration of Variables
EoSn = 0.15 // V
EoCr = - 0.74 // V
// Solution
mprintf("3Sn+4 + 2Cr --> 3Sn+2 + 2Cr+3\n")
Eo_cell = EoSn - EoCr
n = 6
K = 10 ** (n * Eo_cell / 0.0591)
mprintf(" The equillibrium constant for th reaction is %.2e ",K)
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