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Diffstat (limited to 'Power_Electronics_Principles_and_Applications_by_Jacob')
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diff --git a/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter1.ipynb b/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter1.ipynb new file mode 100644 index 00000000..662bf254 --- /dev/null +++ b/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter1.ipynb @@ -0,0 +1,558 @@ +{ + "cells": [ + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Chapter 1: Advanced Operational Amplifier Principles" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 1.1,Page 6" + ] + }, + { + "cell_type": "code", + "execution_count": 1, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "open output voltage is 0.5 V\n", + "resistance lower loaded is 333.333 ohm\n", + "loaded output voltage is 0.25 V\n" + ] + } + ], + "source": [ + "#finding voltage current resistance\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "R1=1000.0;\n", + "R2=1000.0;\n", + "Rl=500.0#load resistance\n", + "V=1.0#input voltage\n", + "\n", + "#calculation\n", + "Vo=(R2/(R1+R2))*V;\n", + "Rll=1/((1/R2)+(1/Rl))#lower loaded resistance\n", + "Vol=(Rll/(R2+Rll))*V;\n", + "\n", + "#result\n", + "print \"open output voltage is\",round(Vo,3),\"V\"\n", + "print \"resistance lower loaded is\",round(Rll,3),\"ohm\"\n", + "print \"loaded output voltage is\",round(Vol,3),\"V\"\n" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 1.2,Page 11" + ] + }, + { + "cell_type": "code", + "execution_count": 1, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "input resistance is 1.01 Kohm\n" + ] + } + ], + "source": [ + "#finding voltage current resistance\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Rf=100000.0#resistance\n", + "Acl=100.0#amplifier gain\n", + "\n", + "#calculation\n", + "Ri=Rf/(Acl-1);\n", + "\n", + "#result\n", + "print \"input resistance is\",round(Ri/1000,2), \"Kohm\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 1.3,Page 17" + ] + }, + { + "cell_type": "code", + "execution_count": 3, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "current through Ri1 is 178.571 microAmp\n", + "current through Ri2 is 31.915 microAmp\n", + "current through Ri2 is 31.915 microAmp\n", + "current through Rf is 210.486 microAmp\n", + "voltage dropped is 2.105 V\n", + "output voltage 1 is -2.105 V\n", + "output voltage is 2.105 V\n" + ] + } + ], + "source": [ + "#finding voltage current resistance\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Vni=0.0#non inverting voltage\n", + "Vinv=0.0;#inverting voltage\n", + "Vri1=1.0;\n", + "Vri2=15.0;\n", + "Ri1=5600.0#resistance\n", + "Ri2=470000.0;\n", + "Rf=10000.0#load resistance\n", + "\n", + "#calculation\n", + "Ir1=Vri1/Ri1;\n", + "Ir2=Vri2/Ri2;\n", + "Irf=(Vri1/Ri1)+(Vri2/Ri2);\n", + "Vr=Irf*Rf;\n", + "Vo1=-Vr;\n", + "Vo=Irf*Rf;\n", + "\n", + "#result\n", + "print \"current through Ri1 is\",round(Ir1*1e6,3), \"microAmp\"\n", + "print \"current through Ri2 is\",round(Ir2*1e6,3), \"microAmp\"\n", + "print \"current through Ri2 is\",round(Ir2*1e6,3),\"microAmp\"\n", + "print \"current through Rf is\",round(Irf*1e6,3), \"microAmp\"\n", + "print \"voltage dropped is\",round(Vr,3), \"V\"\n", + "print \"output voltage 1 is\",round(Vo1,3), \"V\"\n", + "print \"output voltage is\",round(Vo,3), \"V\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 1.4,Page 25" + ] + }, + { + "cell_type": "code", + "execution_count": 1, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "inverting voltage is 4.955 V\n", + "non inverting voltage is 4.955 V\n", + "current through Rf2 is 42.698 microA\n", + "current through Ri2 is 42.698 microA\n", + "voltage dropped is 4.056 V\n", + "output voltage is 884.897 mV\n" + ] + } + ], + "source": [ + "#finding voltage current resistance\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Ri1=950.00;#ohm\n", + "Ri2=1050.00;\n", + "Rf1=105000.00;#resistance\n", + "Rf2=95000.00;\n", + "Vin=5.00;#voltage\n", + "\n", + "#calculation\n", + "Vinv=(Rf1/(Rf1+Ri1))*Vin;\n", + "Vni=Vinv;\n", + "Irf2=(Vin-Vinv)/Ri2;\n", + "Iri2=Irf2;\n", + "Vrf2=Irf2*Rf2;\n", + "Vo=Vinv-Vrf2-.014;\n", + "\n", + "#result\n", + "print \"inverting voltage is\",round(Vinv,3), \"V\"\n", + "print \"non inverting voltage is\",round (Vni,3), \"V\"\n", + "print \"current through Rf2 is\",round(Irf2*1e6,3), \"microA\"\n", + "print \"current through Ri2 is\",round(Iri2*1e6,3), \"microA\"\n", + "print \"voltage dropped is\",round(Vrf2,3), \"V\"\n", + "print \"output voltage is\",round(Vo*1000,3), \"mV\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 1.5,Page 27" + ] + }, + { + "cell_type": "code", + "execution_count": 5, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "input resistor current is 272.222 microA\n", + "input resistor current is 500.0 microA\n", + "feedback resistor current is 227.778 microAmp\n", + "resistor voltage is 227.778 mV\n", + "1st output voltage is 2.222 V\n", + "input resistor current is 327.778 microA\n", + "input resistor current is 827.778 microA\n", + "feedback resistor voltage is 7.45 V\n", + "2nd output voltage is 10.0 V\n" + ] + } + ], + "source": [ + "#finding voltage current resistance \n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Vniu1=2.45;#V\n", + "Vniu2=2.55;#V\n", + "Vinvu1=2.45;\n", + "Vinvu2=2.55;\n", + "Ri1=9000.0;#ohm\n", + "Ri2=1000.0;#ohm\n", + "Rf1=1000.0;\n", + "Rf2=9000.0;\n", + "Rg=200.0;#load resistance\n", + "\n", + "#calculation\n", + "Iri1=Vniu1/Ri1;\n", + "Irg=(Vniu2-Vniu1)/Rg;\n", + "Irf1=Irg-Iri1;\n", + "Vrf1=Irf1*Rf1;\n", + "Vou1=Vniu1-Vrf1;\n", + "Iri2=(Vniu2-Vou1)/Ri2;\n", + "Irf2=Iri2+Irg;\n", + "Vrf2=Irf2*Rf2#feedback resistor voltage\n", + "Vo=Vrf2+Vniu2;\n", + "\n", + "#result\n", + "print \"input resistor current is\",round(Iri1*1e6,3), \"microA\"\n", + "print \"input resistor current is\",round(Irg*1e6,3), \"microA\"\n", + "print \"feedback resistor current is\",round(Irf1*1e6,3), \"microAmp\"\n", + "print \"resistor voltage is\",round(Vrf1*1000,3), \"mV\"\n", + "print \"1st output voltage is\",round(Vou1,3), \"V\"\n", + "print \"input resistor current is\",round(Iri2*1e6,3), \"microA\"\n", + "print \"input resistor current is\",round(Irf2*1e6,3),\"microA\"\n", + "print \"feedback resistor voltage is\",round(Vrf2,3), \"V\"\n", + "print \"2nd output voltage is\",round(Vo,3), \"V\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 1.6.a,Page 29" + ] + }, + { + "cell_type": "code", + "execution_count": 2, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "input resistor current is 128.0 microA\n", + "feedback resistor current is 128.0 microA\n", + "feedback resistor voltage is 5.018 V\n", + "output resistor voltage is 5.018 V\n", + "output voltage is 3.818 V\n", + "load current is 0.5 A\n", + "load power is 2.5 W\n", + "power dissipated in LM317 is 5.0 W\n" + ] + } + ], + "source": [ + "#finding voltage current resistance\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Vniu1=0;#V\n", + "Vinvu2=0;#V\n", + "Vref=2.56;\n", + "Rl=10000.0;#ohm\n", + "Rf=39200.0;#ohm\n", + "Ro=10.0;#resistance\n", + "Vdc1=5.0;\n", + "Vdc2=15.0;\n", + "Idc=0.5;#current\n", + "\n", + "#calculation\n", + "Iu1=(Vref/Rl)*.5;\n", + "Irf=Iu1;\n", + "Vrf=Irf*Rf;\n", + "Vout=Vrf+Vinvu2;\n", + "Eo=Vout-1.2;\n", + "Iload=Vdc1/Ro;\n", + "Pload=Vdc1**2/Ro;\n", + "Plm317=(Vdc2-Vdc1)*Idc;\n", + "\n", + "#result\n", + "print \"input resistor current is\",round(Iu1*1e6,3), \"microA\"\n", + "print \"feedback resistor current is\",round(Irf*1e6,3), \"microA\"\n", + "print \"feedback resistor voltage is\",round(Vrf,3), \"V\"\n", + "print \"output resistor voltage is\",round(Vout,3), \"V\"\n", + "print \"output voltage is\",round(Eo,3), \"V\"\n", + "print \"load current is\",round(Iload,3), \"A\"\n", + "print \"load power is\",round(Pload,3), \"W\"\n", + "print \"power dissipated in LM317 is\",round(Plm317,3), \"W\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 1.6.b,Page 31" + ] + }, + { + "cell_type": "code", + "execution_count": 7, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "input resistor current is 360.36 microamp\n", + "inverting voltage 1 & 2 is 396.396 mV\n", + "current across Rs is 3.964 A\n", + "emitter voltage is 8.324 V\n", + "output voltage is 10.124 V\n" + ] + } + ], + "source": [ + "#finding voltage current resistance\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Vin=4;#V\n", + "Vs=1.8;#V\n", + "Rf=10000.0;#ohm\n", + "Ri=1100.0;#ohm\n", + "Rl=2.0;#ohm\n", + "Rs=0.1;#ohm\n", + "\n", + "#calculation\n", + "Irf=Vin/(Rf+Ri);\n", + "Vni=Irf*Ri;\n", + "Ir=Vni/Rs;\n", + "Ve=Ir*(Rl+Rs);\n", + "Vo=Ve+Vs;\n", + "\n", + "#result\n", + "print \"input resistor current is\",round(Irf*1e6,3),\"microamp\"\n", + "print \"inverting voltage 1 & 2 is\",round(Vni*1000,3), \"mV\"\n", + "print \"current across Rs is\",round(Ir,3), \"A\"\n", + "print \"emitter voltage is\",round(Ve,3), \"V\"\n", + "print \"output voltage is\",round(Vo,3), \"V\"\n", + "\n" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 1.7,Page 36" + ] + }, + { + "cell_type": "code", + "execution_count": 8, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "rms voltage is 9.899 V\n", + "power delivered is 12.25 W\n", + "load voltage is 28.284 V\n" + ] + } + ], + "source": [ + "#finding voltage and power\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Vs=18.0;#V\n", + "Rl=8.0;#load resistance\n", + "Pll=100.0;#power\n", + "\n", + "#calculation\n", + "Vlp=Vs-4;\n", + "Vlr=Vlp/(2**(.5));\n", + "Pl=(Vlr**2)/Rl;\n", + "Vl=(Pll*Rl)**(.5);\n", + "\n", + "#result\n", + "print \"rms voltage is\",round(Vlr,3), \"V\"\n", + "print \"power delivered is\",round(Pl,3), \"W\"\n", + "print \"load voltage is\",round(Vl,3), \"V\"\n" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 1.9,Page 44" + ] + }, + { + "cell_type": "code", + "execution_count": 2, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "output voltage is 37.34 V\n", + "V+ is 45.34 V ;V- is 29.34 V\n" + ] + } + ], + "source": [ + "#finding output volatage and range \n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "import numpy as np\n", + "Vp=6.0;#V\n", + "Ra=10.0;#Kohm\n", + "Rb=1800.0;#ohm\n", + "V=8.0;\n", + "#solving for Ir & Vo\n", + "a=np.array([[1.0,-124.6e-6],[7800.0,-1.0]])\n", + "b=np.array([134.6e-6,0.0])\n", + "\n", + "#calculation\n", + "x=np.linalg.solve(a,b);\n", + "Vo=x[1];\n", + "Va=Vo+V;\n", + "Vb=Vo-V;\n", + "\n", + "#result\n", + "print \"output voltage is\",round(Vo,2), \"V\"\n", + "print \"V+ is\",round(Va,2), \"V ;V- is\",round(Vb,2), \"V\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 1.11,Page 50" + ] + }, + { + "cell_type": "code", + "execution_count": 1, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "output current is 4.091 mA\n", + "output voltage is 45.409 V\n", + "gain output voltage 1 is 13.356 V\n", + "gain output voltage 2 is 0.38 V\n" + ] + } + ], + "source": [ + "#finding output voltage and gain output voltage \n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Vin=4.5;\n", + "R1=1100.0;\n", + "R2=10000.0;\n", + "\n", + "G1=3.4#gain 1\n", + "G2=120.0#gain 2\n", + "\n", + "#calculation\n", + "Ir=Vin/R1;\n", + "Vo=Ir*(R1+R2);\n", + "Vuo1=Vo/G1;\n", + "Vuo2=Vo/G2;\n", + "\n", + "#result\n", + "print \"output current is\",round(Ir*1000,3),\"mA\"\n", + "print \"output voltage is\",round(Vo,3), \"V\"\n", + "print \"gain output voltage 1 is\",round(Vuo1,3), \"V\"\n", + "print \"gain output voltage 2 is\",round(Vuo2,2),\"V\"" + ] + } + ], + "metadata": { + "kernelspec": { + "display_name": "Python 2", + "language": "python", + "name": "python2" + }, + "language_info": { + "codemirror_mode": { + "name": "ipython", + "version": 2 + }, + "file_extension": ".py", + "mimetype": "text/x-python", + "name": "python", + "nbconvert_exporter": "python", + "pygments_lexer": "ipython2", + "version": "2.7.6" + } + }, + "nbformat": 4, + "nbformat_minor": 0 +} diff --git a/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter2.ipynb b/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter2.ipynb new file mode 100644 index 00000000..9d88fe28 --- /dev/null +++ b/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter2.ipynb @@ -0,0 +1,65 @@ +{ + "cells": [ + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Chapter 2: Power Electronics Circuit Layout" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 2.9,Page 83" + ] + }, + { + "cell_type": "code", + "execution_count": 1, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "load current is 3.75 A\n", + "wiring resistance is 26.67 mohm\n", + "resistance per inch is 1666.67 microohm/inch\n" + ] + } + ], + "source": [ + "#finding an appropriate wire gauge\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "V=15.0;#voltage\n", + "R=4.0;#resistance\n", + "Vl=.1;\n", + "D=8.0;#duty cycle\n", + "\n", + "#calculation\n", + "Il=V/R;\n", + "Rw=Vl/Il#wiring resistance\n", + "Ri=Rw/(2*D);\n", + "\n", + "#result\n", + "print \"load current is\",round(Il,2), \"A\"\n", + "print \"wiring resistance is\",round(Rw*1000,2), \"mohm\"\n", + "print \"resistance per inch is\",round(Ri*1e6,2), \"microohm/inch\"" + ] + } + ], + "metadata": { + "kernelspec": { + "display_name": "Python 2", + "language": "python", + "name": "python2" + } + }, + "nbformat": 4, + "nbformat_minor": 0 +} diff --git a/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter3.ipynb b/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter3.ipynb new file mode 100644 index 00000000..4129f088 --- /dev/null +++ b/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter3.ipynb @@ -0,0 +1,481 @@ +{ + "cells": [ + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Chapter 3 : Power Parameter Calculations" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 3.1,Page 109" + ] + }, + { + "cell_type": "code", + "execution_count": 1, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "ramp current is 450.0 kAt/s\n", + "current at 5 micro sec is 2.25 A\n" + ] + } + ], + "source": [ + "#finding ramp current and current at 5 micro sec\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Ip=3.0;\n", + "f=150000.0;\n", + "t=5.0e-6;\n", + "\n", + "#calculation\n", + "T=1/f;\n", + "It=Ip/T;\n", + "I5=It*t;\n", + "\n", + "#result\n", + "print \"ramp current is\",round(It/1000,3), \"kAt/s\"\n", + "print \"current at 5 micro sec is\",round(I5,3), \"A\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 3.2,Page 110" + ] + }, + { + "cell_type": "code", + "execution_count": 2, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "current in time 0<=t<800ns is 3.575 A\n", + "current in time 800ns<=t<2 microsec is 0.0 A\n", + "current in time 400ns is 1.85 A\n", + "current in time 1 microsec is 0.0 A\n" + ] + } + ], + "source": [ + "#finding current at different time\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Ip=2.0;\n", + "f=500000.0;\n", + "Ir=.3;\n", + "Cd=.4#duty cycle\n", + "t1=4.0e-7;\n", + "t2=1.0e-6;\n", + "I1=0;\n", + "\n", + "#calculation\n", + "T=1/f;\n", + "Im=Ip-Ir;\n", + "I4=(Ip-Im)*t1/(Cd*T)+Im;\n", + "It=(Ip-Im)*t/(Cd*T)+Im;\n", + "It1=0\n", + "\n", + "#resilt\n", + "print \"current in time 0<=t<800ns is\",round(It,3),\"A\"\n", + "print \"current in time 800ns<=t<2 microsec is\",round(It1,2), \"A\"\n", + "print \"current in time 400ns is\",round(I4,2), \"A\"\n", + "print \"current in time 1 microsec is\",round(I1,2), \"A\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 3.3,Page 115" + ] + }, + { + "cell_type": "code", + "execution_count": 3, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "average voltage is 54.02 V\n" + ] + } + ], + "source": [ + "#finding average voltage\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Vr=120;\n", + "\n", + "#calculation\n", + "V=(Vr*2**.5)/pi;\n", + "\n", + "#result\n", + "print \"average voltage is\",round(V,2), \"V\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 3.4,Page 119" + ] + }, + { + "cell_type": "code", + "execution_count": 5, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "average current is 0.98 A\n" + ] + } + ], + "source": [ + "#finding average current\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "f=100000.0;\n", + "Cd=.35#duty cycle\n", + "Ip=3.0;\n", + "Ir=.4;\n", + "\n", + "#calculation\n", + "Im=Ip-Ir;\n", + "T=1/f;\n", + "I=Cd*((Ip-Im)/2+Im)\n", + "\n", + "#result\n", + "print \"average current is\",round(I,2), \"A\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 3.5,Page 124" + ] + }, + { + "cell_type": "code", + "execution_count": 6, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "rms voltage is 8.87 V\n" + ] + } + ], + "source": [ + "#finding rms voltage\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Vp=15.0;\n", + "Cd=.35;\n", + "f=100000.0;\n", + "\n", + "#calculation\n", + "V=Vp*Cd**.5;\n", + "\n", + "#result\n", + "print \"rms voltage is\",round(V,2), \"V\"\n" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 3.6,Page 127" + ] + }, + { + "cell_type": "code", + "execution_count": 7, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "rms current is 1.73 A\n" + ] + } + ], + "source": [ + "#finding rms current\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Ip=3.0;\n", + "f=100000.0;\n", + "\n", + "#calculation\n", + "I=Ip/3**.5;\n", + "\n", + "#result\n", + "print \"rms current is\",round(I,2), \"A\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 3.7,Page 133" + ] + }, + { + "cell_type": "code", + "execution_count": 8, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "rms voltage is 85.0 V\n" + ] + } + ], + "source": [ + "#finding rms voltage\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Vp=170.0;\n", + "f=60.0;\n", + "\n", + "#calculation\n", + "Vr=Vp/2;\n", + "\n", + "#result\n", + "print \"rms voltage is\",round(Vr,2), \"V\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 3.8,Page 140" + ] + }, + { + "cell_type": "code", + "execution_count": 9, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "power required is 2.42 hp\n", + "Pick a 5HP motor\n", + "current required is 18.84 amp\n" + ] + } + ], + "source": [ + "#finding current and power\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "M=1000.0;\n", + "H=40.0;\n", + "T=30.0;\n", + "E1=.9;\n", + "E2=.5;\n", + "V=220.0;\n", + "P1=5.0;\n", + "\n", + "#calculation\n", + "W=M*H;\n", + "P=(W)/(T*550);\n", + "Pe=P1/E1;\n", + "I=(Pe*746)/V;\n", + "\n", + "#result\n", + "print \"power required is\",round(P,2), \"hp\"\n", + "print('Pick a 5HP motor')\n", + "print \"current required is\",round(I,2), \"amp\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 3.9,Page 145" + ] + }, + { + "cell_type": "code", + "execution_count": 10, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "power delivered to the load is 6.36 Watt\n", + "power provided by each supply is 7.23 Watt\n" + ] + } + ], + "source": [ + "#finding power\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Vin=1.0;\n", + "Ri=1100.0;\n", + "Rf=10000.0;\n", + "Rl=8.0;\n", + "Vs=18.0;\n", + "\n", + "#calculation\n", + "Ir=Vin/Ri;\n", + "Vl=Ir*(Ri+Rf);\n", + "Ip=Vl/Rl;\n", + "Pl=(Vl*Ip)/2;\n", + "Ps=(Vs*Ip)/pi;\n", + "\n", + "#result\n", + "print \"power delivered to the load is\",round(Pl,2),\"Watt\"\n", + "print \"power provided by each supply is\",round(Ps,2), \"Watt\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 3.10,Page 149" + ] + }, + { + "cell_type": "code", + "execution_count": 11, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "power delivered is 141.67 Watt\n" + ] + } + ], + "source": [ + "#finding power\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "V=170.0;\n", + "R=51.0;\n", + "\n", + "#calculation\n", + "I=V/R;\n", + "P=(V*I)/4;\n", + "\n", + "#result\n", + "print \"power delivered is\",round(P,2), \"Watt\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 3.11,Page 151" + ] + }, + { + "cell_type": "code", + "execution_count": 12, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "power dissipated is 7.05 watt\n", + "power dissipated when transistor resistance is 0.2 hm is 0.35 watt\n" + ] + } + ], + "source": [ + "#finding power\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "V=7.2;\n", + "Rq=.2;\n", + "Rl=4;\n", + "D=.6;\n", + "\n", + "#calculation\n", + "Ip=V/(Rq+Rl);\n", + "Vl=Ip*Rl;\n", + "P=D*Vl*Ip;\n", + "Vq=Ip*Rq;\n", + "Pq=D*Vq*Ip;\n", + "\n", + "#result\n", + "print \"power dissipated is\",round(P,2), \"watt\"\n", + "print \"power dissipated when transistor resistance is 0.2 hm is\",round(Pq,2), \"watt\"" + ] + } + ], + "metadata": { + "kernelspec": { + "display_name": "Python 2", + "language": "python", + "name": "python2" + } + }, + "nbformat": 4, + "nbformat_minor": 0 +} diff --git a/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter4.ipynb b/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter4.ipynb new file mode 100644 index 00000000..a01cb417 --- /dev/null +++ b/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter4.ipynb @@ -0,0 +1,733 @@ +{ + "cells": [ + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Chapter 4: Linear Power Amplifier Integrated Circuits" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 4.1,Page 162" + ] + }, + { + "cell_type": "code", + "execution_count": 1, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "output voltage is 500.0 mV\n" + ] + } + ], + "source": [ + "#finding voltage \n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Rf=1;\n", + "Ri=10;\n", + "Vi=0;\n", + "Ip=500;\n", + "\n", + "#calculation\n", + "Vrf=Ip*Rf;\n", + "\n", + "#result\n", + "print \"output voltage is\",round(Vrf,2), \"mV\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 4.2,Page 165" + ] + }, + { + "cell_type": "code", + "execution_count": 2, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "frequency of OPA548 is 67.26 KHz\n", + "slew rate of OPA548 is 1.12 Mhz\n", + "the OPA548 can be used\n" + ] + } + ], + "source": [ + "#finding frequency\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Vi=300.0;\n", + "P=35.0;\n", + "R=8.0;\n", + "S=10000.0;\n", + "fh=20.0;\n", + "\n", + "#calculation\n", + "Vl=(P*R)**.5;\n", + "Vp=Vl*2**.5;\n", + "Il=Vl/R;\n", + "f=S/(2*pi*Vp);\n", + "Ao=Vl/Vi;\n", + "G=Ao*fh;\n", + "\n", + "#result\n", + "print \"frequency of OPA548 is\",round(f,2), \"KHz\"\n", + "print \"slew rate of OPA548 is\",round(G,2), \"Mhz\"\n", + "print('the OPA548 can be used')" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 4.3,Page 168" + ] + }, + { + "cell_type": "code", + "execution_count": 3, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "power delivered is 3.5 watt\n" + ] + } + ], + "source": [ + "#finding power\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Rl=10.0;\n", + "V=12.0;\n", + "Vl=5.0;\n", + "\n", + "#calculation\n", + "Pl=Vl**2/Rl;\n", + "I=Vl/Rl;\n", + "Ps=V*I;\n", + "Pic=Ps-Pl;\n", + "\n", + "#result\n", + "print \"power delivered is\",round(Pic,2), \"watt\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 4.4,Page 170" + ] + }, + { + "cell_type": "code", + "execution_count": 1, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "Vload Iload Pload Ps Pic\n", + "0.0 0.0 0.0 0.0 0.0\n", + "0.2 0.0 0.0 0.24 0.24\n", + "0.4 0.0 0.02 0.48 0.46\n", + "0.6 0.1 0.04 0.72 0.68\n", + "0.8 0.1 0.06 0.96 0.9\n", + "4.8 0.5 2.3 5.76 3.46\n", + "5.0 0.5 2.5 6.0 3.5\n", + "5.2 0.5 2.7 6.24 3.54\n", + "5.4 0.5 2.92 6.48 3.56\n", + "5.6 0.6 3.14 6.72 3.58\n", + "5.8 0.6 3.36 6.96 3.6\n", + "6.0 0.6 3.6 7.2 3.6\n", + "6.2 0.6 3.84 7.44 3.6\n", + "6.4 0.6 4.1 7.68 3.58\n", + "11.4 1.1 13.0 13.68 0.68\n", + "11.6 1.2 13.46 13.92 0.46\n", + "11.8 1.2 13.92 14.16 0.24\n", + "12.0 1.2 14.4 14.4 0.0\n" + ] + }, + { + "data": { + "image/png": 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E8BnQNcHzXcifoFaUd4E9RRzjl5FOJbZ3rw2De+IJaNrU62hEyq4uXWzNsC5d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\nREREREREREREREREREREJBn/DwWIrS4GjkBZAAAAAElFTkSuQmCC\n", + "text/plain": [ + "<matplotlib.figure.Figure at 0x7f414b298f90>" + ] + }, + "metadata": {}, + "output_type": "display_data" + } + ], + "source": [ + "#finding Vload vs Pic graph\n", + "\n", + "#initialisation of variable\n", + "%matplotlib inline\n", + "import numpy as np\n", + "import matplotlib.pyplot as plt\n", + "Vload=[0.0, 0.2, 0.4, 0.6, 0.8, 4.8, 5.0, 5.2, 5.4, 5.6, 5.8, 6.0, 6.2, 6.4, 11.4, 11.6, 11.8, 12.0];\n", + "Iload=[0.0, 0.0, 0.0, 0.1, 0.1, 0.5, 0.5, 0.5, 0.5, 0.6, 0.6, 0.6, 0.6, 0.6, 1.1, 1.2, 1.2, 1.2];\n", + "Pload=[0.00, 0.00, 0.02, 0.04, 0.06, 2.30, 2.50, 2.70, 2.92, 3.14, 3.36, 3.60, 3.84, 4.10, 13.00, 13.46, 13.92, 14.40];\n", + "Ps=[0.00, 0.24, 0.48, 0.72, 0.96, 5.76, 6.00, 6.24, 6.48, 6.72, 6.96, 7.20, 7.44, 7.68, 13.68, 13.92, 14.16, 14.40];\n", + "Pic=[0.00, 0.24, 0.46, 0.68, 0.90, 3.46, 3.50, 3.54, 3.56, 3.58, 3.60, 3.60, 3.60, 3.58, 0.68, 0.46, 0.24, 0.00];\n", + "\n", + "#result\n", + "print('Vload Iload Pload Ps Pic');\n", + "for i in range(0,18):\n", + " print Vload[i],\" \",Iload[i],\" \",Pload[i],\" \",Ps[i],\" \", Pic[i]\n", + " \n", + "plt.plot(Vload,Pic);\n", + "plt.xlabel('load voltage (V)')\n", + "plt.ylabel('IC Power(W)')\n", + "plt.title('load voltage vs IC Power')\n", + "plt.show()" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 4.5,Page 173" + ] + }, + { + "cell_type": "code", + "execution_count": 4, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "IC power is 2.57 W\n", + "total power is 3.82 W\n", + "dc supply current is 159.155 mA\n", + "power delivered is 1.25 watt\n" + ] + } + ], + "source": [ + "#finding different power and current\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "V=12.0;\n", + "Vp=5.0;\n", + "R=10.0;\n", + "\n", + "#calculation\n", + "Ip=Vp/R;\n", + "Il=Ip/2**.5;\n", + "Pl=(Vp*Ip)/2;\n", + "Id=Ip/pi;\n", + "Pt=2*V*Ip/pi;\n", + "Pic=Pt-Pl;\n", + "\n", + "#result\n", + "print \"IC power is\",round(Pic,2), \"W\"\n", + "print \"total power is\",round(Pt,2), \"W\"\n", + "print \"dc supply current is\",round(Id*1000,3), \"mA\"\n", + "print \"power delivered is\",round(Pl,2), \"watt\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 4.6,Page 179" + ] + }, + { + "cell_type": "code", + "execution_count": 5, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "thermal resistance is 24.61 C/W\n" + ] + } + ], + "source": [ + "#finding thermal resistance\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Ts=40.0;\n", + "P=2.92;\n", + "Qj=2.5;\n", + "Qc=2.0;\n", + "Tj=125.0;\n", + "\n", + "#calculation\n", + "Qs=(Tj-Ts)/P-Qj-Qc;\n", + "\n", + "#result\n", + "print \"thermal resistance is\",round(Qs,2),\"C/W\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 4.7,Page 180" + ] + }, + { + "cell_type": "code", + "execution_count": 48, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "Vload Iload Pload Ps Pic\n", + "9.4 0.94 4.42 14.36 9.94\n", + "9.6 0.96 4.61 14.67 10.06\n", + "10.0 power delivered by IC in watt\n" + ] + } + ], + "source": [ + "#finding power\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "V=24.0;\n", + "R=10.0;\n", + "Qs=4.0;\n", + "Tj=125.0;\n", + "Ta=40.0;\n", + "Qj=2.5;\n", + "Qc=2.0;\n", + "Vload=[9.4, 9.6];\n", + "Iload=[.94, .96];\n", + "Pload=[4.42, 4.61];\n", + "Ps=[14.36, 14.67];\n", + "Pic=[9.94, 10.06];\n", + "\n", + "#calculation\n", + "P=(Tj-Ta)/(Qj+Qc+Qs);\n", + "\n", + "#result\n", + "print('Vload Iload Pload Ps Pic');\n", + "for i in range(0,2):\n", + " print Vload[i],\" \",Iload[i],\" \",Pload[i],\" \",Ps[i],\" \", Pic[i]\n", + "print round(P,2),\"power delivered by IC in watt\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 4.8,Page 182" + ] + }, + { + "cell_type": "code", + "execution_count": 7, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "gain is 23.0\n", + "limit current is 4.01 A\n", + "output voltage is 46.0 V\n", + "maximum output voltage is 32.0 V\n" + ] + } + ], + "source": [ + "#finding current and voltage\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Rf=22.0;\n", + "Ri=1.0;\n", + "Rs=15.0;\n", + "I=4.75;\n", + "Rc=4.0;\n", + "Vp=2.0;\n", + "Rl=8.0;\n", + "Im=4.0;\n", + "\n", + "#calculation\n", + "Av=1+(Rf/Ri);\n", + "Il=(Rs*I)/(Rc+13.75);\n", + "Vo=Vp*Av;\n", + "V=Im*Rl;\n", + "\n", + "#result\n", + "print \"gain is\",round(Av,2)\n", + "print \"limit current is\",round(Il,2), \"A\"\n", + "print \"output voltage is\",round(Vo,2), \"V\"\n", + "print \"maximum output voltage is\",round(V,2), \"V\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 4.9,Page 185" + ] + }, + { + "cell_type": "code", + "execution_count": 8, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "loudness ofsound is 108.06 dB\n" + ] + } + ], + "source": [ + "#finding loudness\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan,log\n", + "D=8.0;\n", + "d=1.0;\n", + "I=90.0;\n", + "\n", + "#calculation\n", + "Is=20*log(d/D,10);\n", + "Ir=I-Is;\n", + "\n", + "#result\n", + "print \"loudness ofsound is\",round(Ir,2), \"dB\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 4.10,Page 186" + ] + }, + { + "cell_type": "code", + "execution_count": 14, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "19.95 power provided in watt\n" + ] + } + ], + "source": [ + "#finding power\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan,log\n", + "D=1.0;\n", + "I1=108.0;\n", + "I2=95.0;\n", + "P=1.0;\n", + "\n", + "#calculation\n", + "I=I1-I2;\n", + "Pr=P*10**(I/10);\n", + "\n", + "#result\n", + "print \"power provided is\",round(Pr,2), \"watt\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 4.11,Page 188" + ] + }, + { + "cell_type": "code", + "execution_count": 9, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "output voltage is 12.65 V\n", + "gain is 10.28\n" + ] + } + ], + "source": [ + "#finding output voltage and gain\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan,log\n", + "P=20;\n", + "R=8;\n", + "Vi=1.23;\n", + "\n", + "#calculation\n", + "V=(P*R)**.5;\n", + "G=V/Vi;\n", + "\n", + "#result\n", + "print \"output voltage is\",round(V,2), \"V\"\n", + "print \"gain is\",round(G,2)\n" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 4.12,Page 191" + ] + }, + { + "cell_type": "code", + "execution_count": 10, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "resistor b/w pins 1&8 is 600.0 ohm\n", + "thus pick a 620 ohm resistor\n", + "capacitor b/w pins 1&8 is 22.46 microF\n", + "thus pick a 27 microF capacitor\n" + ] + } + ], + "source": [ + "#finding resistor and capacitor\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan,log\n", + "G=40.0;\n", + "f=80.0;\n", + "R1=15000.0;\n", + "R2=150.0;\n", + "\n", + "#calculation\n", + "R=2*(R1/G)-R2;\n", + "R11=620;\n", + "C=1/(2*pi*f*R11/7);\n", + "\n", + "#result\n", + "print \"resistor b/w pins 1&8 is\",round(R,2),\"ohm\"\n", + "print('thus pick a 620 ohm resistor')\n", + "print \"capacitor b/w pins 1&8 is\",round(C*1e6,2), \"microF\"\n", + "print('thus pick a 27 microF capacitor')" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 4.13,Page 193" + ] + }, + { + "cell_type": "code", + "execution_count": 11, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "power dissipated is 140.0 mW\n", + "thermal resistance is 628.93 degree C/W\n" + ] + } + ], + "source": [ + "#finding thermal resistance and power\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan,log\n", + "R=8.0#resistance\n", + "V=5.0#voltage\n", + "Tm=150.0#temperature\n", + "Ta=50.0#temperature\n", + "Qa=107.0;\n", + "Qc=37.0;\n", + "Ps=299.0;\n", + "\n", + "#calculation\n", + "Vd=V/2;\n", + "Vm=V-1;\n", + "Vp=Vm-Vd;\n", + "Vr=Vp/2**.5;\n", + "Pl=1000*Vr**2/R;\n", + "Pl=140;\n", + "Pic=Ps-Pl;\n", + "Q=(Tm-Ta)/Pic;\n", + "\n", + "#result\n", + "print \"power dissipated is\",round(Pl,2), \"mW\"\n", + "print \"thermal resistance is\",round(Q*1000,2),\"degree C/W\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 4.14,Page 197" + ] + }, + { + "cell_type": "code", + "execution_count": 12, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "power deliverd is 562.5 mwatt\n" + ] + } + ], + "source": [ + "#finding power delivered\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan,log\n", + "R=8.0#resistance\n", + "V=5.0#voltage\n", + "\n", + "#calculation\n", + "Vl=V-1;\n", + "Vp=Vl-1;\n", + "Vr=Vp/2**.5;\n", + "P=Vr**2/R;\n", + "\n", + "#result\n", + "print \"power deliverd is\",round(P*1000,2), \"mwatt\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 4.15,Page 201" + ] + }, + { + "cell_type": "code", + "execution_count": 13, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "power delivered is 85.56 watt\n", + "thermal resistance is 1.4 degreeC/W\n" + ] + } + ], + "source": [ + "#finding thermal resistance and power\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan,log\n", + "R=8.0#resistance\n", + "Ts=35.0#temperature\n", + "Ta=150.0#temperature\n", + "Vm=42.0#voltage\n", + "\n", + "#calcuation\n", + "Vp=Vm-5;\n", + "Vr=Vp/2**.5;\n", + "Pm=Vr**2/R;\n", + "P=45;\n", + "Qs=(Ta-Ts)/P-1.2;\n", + "\n", + "#result\n", + "print \"power delivered is\",round(Pm,2), \"watt\"\n", + "print \"thermal resistance is\",round(round(Qs*10)/10,2), \"degreeC/W\"" + ] + } + ], + "metadata": { + "kernelspec": { + "display_name": "Python 2", + "language": "python", + "name": "python2" + }, + "language_info": { + "codemirror_mode": { + "name": "ipython", + "version": 2 + }, + "file_extension": ".py", + "mimetype": "text/x-python", + "name": "python", + "nbconvert_exporter": "python", + "pygments_lexer": "ipython2", + "version": "2.7.6" + } + }, + "nbformat": 4, + "nbformat_minor": 0 +} diff --git a/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter5.ipynb b/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter5.ipynb new file mode 100644 index 00000000..58305b46 --- /dev/null +++ b/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter5.ipynb @@ -0,0 +1,647 @@ +{ + "cells": [ + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Chapter 5: Discrete Linear Power Amplifier" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 5.1,Page 215" + ] + }, + { + "cell_type": "code", + "execution_count": 1, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "Id=0 from 0 to 2 so not shown in the graph\n" + ] + }, + { + "data": { + "image/png": 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8oVgLIhWJQSTrtWwJ77xjE+KOO852j7vuOsjLcx2ZZBrVGETS0IoVMGCA7Rg3diy0auU6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\nIiIiIiIiIiIiIiIiIiIiknn+HwC9g+9EmLPsAAAAAElFTkSuQmCC\n", + "text/plain": [ + "<matplotlib.figure.Figure at 0x7fb0a512a8d0>" + ] + }, + "metadata": {}, + "output_type": "display_data" + } + ], + "source": [ + "#finding Id vs Vgs\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "%matplotlib inline\n", + "import numpy as np\n", + "import matplotlib.pyplot as plt\n", + "Vth=3.6;\n", + "Vgs=4;#voltage\n", + "#volt change beyond 3.6 causes a major increase in Id as it is cut off voltage\n", + "\n", + "#result\n", + "print('Id=0 from 0 to 2 so not shown in the graph')\n", + "x=np.linspace(2,3.6,300);\n", + "y=(-2.5*(x-3.6))**.5;\n", + "plt.plot(x,y)\n", + "plt.xlabel('Vgs(volts)');\n", + "plt.ylabel('Id(amps)');\n", + "plt.title('Id vs Vgs');\n" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 5.2,Page 217" + ] + }, + { + "cell_type": "code", + "execution_count": 1, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "drain current is 3.8 A\n", + "Vth=4V is assumed\n" + ] + } + ], + "source": [ + "#finding drain current\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "V=4.5;#voltage\n", + "T=25;#degreeC\n", + "Id=3.8;\n", + "\n", + "#result\n", + "print \"drain current is\",round(Id,2), \"A\"\n", + "print('Vth=4V is assumed')" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 5.3,Page 219" + ] + }, + { + "cell_type": "code", + "execution_count": 2, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "MOSFET is IRF530N\n", + "lower limit of Vth is -4.0 V\n", + "upper limit of Vth is -2.0 V\n", + "current is 2.3 A\n" + ] + } + ], + "source": [ + "#finding drain current of IRF530N\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Vgs=-5;#voltage\n", + "Vthl=-4;\n", + "Vthu=-2;\n", + "Id=2.3;#current\n", + "\n", + "#result\n", + "print('MOSFET is IRF530N')\n", + "print \"lower limit of Vth is\",round(Vthl,2), \"V\"\n", + "print \"upper limit of Vth is\",round(Vthu,2), \"V\"\n", + "print \"current is\",round(Id,2), \"A\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example5.5,Page 225" + ] + }, + { + "cell_type": "code", + "execution_count": 3, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "resistance is 1.51 kohm\n", + "load voltage is 36.68 V\n", + "Pq is 40.02 watt\n", + "Ps is 82.0 watt\n", + "Pl is 41.97 watt\n" + ] + } + ], + "source": [ + "#finding Pq,Pl,Ps,resistance,load voltage\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "R1=22.0;#resistance\n", + "Vg=3.6;#voltage\n", + "Vd=56.0;\n", + "G=.98;#gain\n", + "Vi=40.0;\n", + "Rl=8.0;#load resistance\n", + "Vp=36.5;\n", + "\n", + "#calculation\n", + "Vr=Vd-Vg;\n", + "Ir=Vr/R1;\n", + "R2=Vg/Ir;\n", + "Va=(R1/(R1+R2))*Vi;\n", + "Vl=G*Va;\n", + "Il=Vp/Rl;\n", + "Pl=Vp*4.6/4;\n", + "Ps=Vd*4.6/pi;\n", + "Pq=Ps-Pl;\n", + "\n", + "#result\n", + "print \"resistance is\",round(R2,2), \"kohm\"\n", + "print \"load voltage is\",round(Vl,2), \"V\"\n", + "print \"Pq is\",round(Pq,2), \"watt\"\n", + "print \"Ps is\",round(Ps,2), \"watt\"\n", + "print \"Pl is\",round(Pl,2), \"watt\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 5.6,Page 232" + ] + }, + { + "cell_type": "code", + "execution_count": 4, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "current is 2.45 mA\n", + "resistance2 is 814.815 ohm\n", + "pick R2=R3=820ohm R1=R4=22 kohm\n" + ] + } + ], + "source": [ + "#finding resistance and current \n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "R1=22.0;#resistance\n", + "V1=56.0;#voltage\n", + "V2=2.0;#voltage\n", + "\n", + "#calculation\n", + "I=(V1-V2)/R1;\n", + "R2=V2/I;\n", + "\n", + "#result\n", + "print \"current is\",round(I,2), \"mA\"\n", + "print \"resistance2 is\",round(R2*1000,3), \"ohm\"\n", + "print('pick R2=R3=820ohm R1=R4=22 kohm')" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 5.7,Page 234" + ] + }, + { + "cell_type": "code", + "execution_count": 5, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "load voltage is 10.01 V\n" + ] + } + ], + "source": [ + "#finding load voltage \n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Vi=350.0;#voltage\n", + "f=100.0;#frequency\n", + "Rf=10000.0;#resistance\n", + "Ri=520.0;\n", + "\n", + "#calculation\n", + "Vp=(1+(Rf/Ri))*Vi*2**.5;\n", + "\n", + "#result\n", + "print \"load voltage is\",round(Vp/1000,2), \"V\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 5.8,Page 238" + ] + }, + { + "cell_type": "code", + "execution_count": 6, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "load rms voltage is 20.0 V\n", + "resistance is 54.04 kohm\n", + "current is 1.18 mA\n", + "load current is 4.41 A\n", + "supply power is 39.3 watt\n", + "load power is 38.9 W\n", + "power is 19.552 W\n", + "thermal resistance is 3.01 degreC/W\n" + ] + } + ], + "source": [ + "#designing amplifier\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "P=50.0;#power\n", + "Z=4.7#impedence\n", + "R=4.0;#resistance\n", + "Ta=40.0;#degreeC\n", + "Tj=140.0;#degreeC\n", + "Vd=28.0;\n", + "R2=22.0;\n", + "\n", + "#calculation\n", + "Vr=(P*R)**.5;\n", + "Vp=Vr*2**.5;\n", + "Av=-Vr/1.23;\n", + "Rf=-Av*Z;\n", + "I=(Vd-2)/R2;\n", + "Vm=.63*Vd;\n", + "Ip=Vm/R;\n", + "Ps=Vd*Ip/pi;\n", + "Pl=Ip**2/2*R;\n", + "Pq=round(Ps)-Pl/2;\n", + "Qs=(Tj-Ta)/Pq-2.1;\n", + "\n", + "#result\n", + "print \"load rms voltage is\",round(Vp,2), \"V\"\n", + "print \"resistance is\",round(Rf,2), \"kohm\"\n", + "print \"current is\",round(I,2), \"mA\"\n", + "print \"load current is\",round(Ip,2), \"A\"\n", + "print \"supply power is\",round(Ps,2), \"watt\"\n", + "print \"load power is\",round(Pl,2), \"W\"\n", + "print \"power is\",round(Pq,3), \"W\"\n", + "print \"thermal resistance is\",round(Qs,2), \"degreC/W\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 5.9,Page 243" + ] + }, + { + "cell_type": "code", + "execution_count": 7, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "output voltage is 129.37 mV\n", + "load current is 32.34 mA\n" + ] + } + ], + "source": [ + "#finding load current,output voltage \n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Vi=7.5e-3;#voltage\n", + "Ib=800e-9;#current\n", + "R=53.9e3;#resistance\n", + "\n", + "#calculation\n", + "Vo=11.5*Vi+Ib*R;\n", + "Id=Vo/4;\n", + "\n", + "#result\n", + "print \"output voltage is\",round(Vo*1000,2), \"mV\"\n", + "print \"load current is\",round(Id*1000,2), \"mA\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 5.10,Page 249" + ] + }, + { + "cell_type": "code", + "execution_count": 8, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "resistance is 0.31 ohm\n", + "thus pick a .33ohm rsistance\n", + "voltage is 0.55 V\n", + "power is 0.23 W\n", + "thermal resistance is 8.1 degreeC/W\n" + ] + } + ], + "source": [ + "#finding resistance,voltage,power \n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "G=6.4;#A/V\n", + "I=5.0;#current\n", + "Pq=9.8;#W\n", + "Tj=140.0;\n", + "Ta=40.0;\n", + "R1=.33;\n", + "\n", + "#calculation\n", + "R=2/G;\n", + "Im=I/3;\n", + "Vr=Im*R1;\n", + "P=Vr*Im/4;\n", + "Qs=(Tj-Ta)/Pq-2.1;\n", + "\n", + "#result\n", + "print \"resistance is\",round(R,2), \"ohm\"\n", + "print('thus pick a .33ohm rsistance')\n", + "print \"voltage is\",round(Vr,2), \"V\"\n", + "print \"power is\",round(P,2), \"W\"\n", + "print \"thermal resistance is\",round(Qs,2), \"degreeC/W\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 5.11,Page 251" + ] + }, + { + "cell_type": "code", + "execution_count": 9, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "limit level current is 8.49 A\n" + ] + } + ], + "source": [ + "#finding limit current \n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "P=200;#power\n", + "R=8;#ohm\n", + "\n", + "#calculation\n", + "Il=(P/R)**.5*2**.5;\n", + "Ilm=1.2*Il;\n", + "\n", + "#result\n", + "print \"limit level current is\",round(Ilm,2), \"A\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 5.12,Page 253" + ] + }, + { + "cell_type": "code", + "execution_count": 10, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "resistance is 0.1 ohm\n", + "power is 1.8 W\n", + "MOSFET power is 84.0 W\n", + "temperature is 468.4 degreeC\n" + ] + } + ], + "source": [ + "#finding resistance,power,temperature \n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "I=6;#current\n", + "V=.6;#voltage\n", + "D=.5;#duty cycle\n", + "T=40;#temperature\n", + "\n", + "#calculation\n", + "Rs=V/I;\n", + "Pr=D*V*I;\n", + "Vp=28;\n", + "Pm=D*Vp*I;\n", + "Tj=T+Pm*5.1;\n", + "\n", + "#result\n", + "print \"resistance is\",round(Rs,2), \"ohm\"\n", + "print \"power is\",round(Pr,2), \"W\"\n", + "print \"MOSFET power is\",round(Pm,2), \"W\"\n", + "print \"temperature is\",round(Tj,2), \"degreeC\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 5.13,Page 255" + ] + }, + { + "cell_type": "code", + "execution_count": 11, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "maximum safe temperature is 89.05 degreeC\n" + ] + } + ], + "source": [ + "#finding maximum safe temperature \n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "T=130;#temperature\n", + "P=19.5;#power\n", + "\n", + "#calculation\n", + "Ts=T-P*2.1;\n", + "\n", + "#result\n", + "print \"maximum safe temperature is\",round(Ts,2), \"degreeC\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 5.14,Page 257" + ] + }, + { + "cell_type": "code", + "execution_count": 12, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "reactance is 8.86 ohm\n", + "voltage across resistor is 10.03 V\n", + "-48 is the angle of the voltage in degrees\n", + "power dissipated by load is 12.5 watts\n", + "current across the resistance is 1.77 A\n", + "power supply is 15.8 W\n", + "power dissipated by transistor is 9.55 watts\n" + ] + } + ], + "source": [ + "#finding 3 powers and current across resistance\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "V=15.0;#voltage\n", + "f=300.0;#frequency\n", + "L=4.7;#inductance\n", + "Vdc=28;#V\n", + "Pr=12.5;\n", + "\n", + "#calculation\n", + "Xl=2*pi*f*L;\n", + "Zload=sqrt(8**2+8.9**2);#magnitude of Zload\n", + "Vload=15.0;#msgnitude of Vload\n", + "Vr=Vload*8/Zload;\n", + "I=Vr/8*sqrt(2);\n", + "Psupply=Vdc*I/pi;\n", + "Pq=Psupply-Pr/2;\n", + "\n", + "#result\n", + "print \"reactance is\",round(Xl/1000,2), \"ohm\"\n", + "print \"voltage across resistor is\",round(Vr,2), \"V\"\n", + "print \"-48 is the angle of the voltage in degrees\";\n", + "print \"power dissipated by load is\",round(Pr,2), \"watts\"\n", + "print \"current across the resistance is\",round(I,2), \"A\"\n", + "print \"power supply is\",round(Psupply,2), \"W\"\n", + "print \"power dissipated by transistor is\",round(Pq,2), \"watts\"" + ] + } + ], + "metadata": { + "kernelspec": { + "display_name": "Python 2", + "language": "python", + "name": "python2" + }, + "language_info": { + "codemirror_mode": { + "name": "ipython", + "version": 2 + }, + "file_extension": ".py", + "mimetype": "text/x-python", + "name": "python", + "nbconvert_exporter": "python", + "pygments_lexer": "ipython2", + "version": "2.7.6" + } + }, + "nbformat": 4, + "nbformat_minor": 0 +} diff --git a/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter6.ipynb b/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter6.ipynb new file mode 100644 index 00000000..0c7858a4 --- /dev/null +++ b/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter6.ipynb @@ -0,0 +1,528 @@ +{ + "cells": [ + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Chapter 6: Power Switches" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 6.1,Page 274" + ] + }, + { + "cell_type": "code", + "execution_count": 2, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "collector current is 1.81 A\n", + "load power is 49.32 W\n", + "transistor power is 1.45 W\n", + "least value of base current is 90.67 mA\n", + "max value of base resistance is 4.85 ohm\n", + "thus pick Rb=33ohm\n" + ] + } + ], + "source": [ + "#finding Ic,Pload,Pq,Ibase,Rbase\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Vs=28.0;#V\n", + "Vi=5.0;#V\n", + "Rl=15.0;#ohm\n", + "Vc=.8;#V\n", + "b=20.0;\n", + "\n", + "#calculation\n", + "Ic=(Vs-Vc)/Rl;\n", + "Pl=Ic**2*Rl;\n", + "Pq=Ic*Vc;\n", + "Ib=Ic/b*1000;\n", + "Rb=(Vi-.6)/Ib;\n", + "\n", + "#result\n", + "print \"collector current is\",round(Ic,2), \"A\"\n", + "print \"load power is\",round(Pl,2), \"W\"\n", + "print \"transistor power is\",round(Pq,2), \"W\"\n", + "print \"least value of base current is\",round(Ib,2), \"mA\"\n", + "print \"max value of base resistance is\",round(Rb*100,2), \"ohm\"\n", + "print ('thus pick Rb=33ohm')" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 6.4,Page 282" + ] + }, + { + "cell_type": "code", + "execution_count": 3, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "load resistance is 554.0 ohm\n", + "thus pick Rl=560ohm\n", + "max value of Rb is 3.0 kohm\n", + "thus pick Rb=2.2kohm\n", + "load current is 49.46 mA\n", + "load power is 685.08 mW\n", + "power delivered is 7.42 mW\n" + ] + } + ], + "source": [ + "#finding Pload,Pq,Iload,resistances\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Vd=28.0;#V\n", + "f=100.0;#frequency\n", + "I=50.0;#current\n", + "Rl1=560.0;\n", + "Vp=2.4;\n", + "Ib=500.0;#microAmp\n", + "D=.5;#duty cycle\n", + "\n", + "#calculation\n", + "Rl=(Vd-.3)/I;\n", + "Rb=(Vp-.9)/Ib;\n", + "Vl=Vd-.3;\n", + "Ip=Vl/Rl1;\n", + "Pl=D*Vl*Ip;\n", + "Pq=D*Ip*.3;\n", + "\n", + "#result\n", + "print \"load resistance is\",round(Rl*1000), \"ohm\"\n", + "print('thus pick Rl=560ohm')\n", + "print \"max value of Rb is\",round(Rb*1000,2),\"kohm\"\n", + "print('thus pick Rb=2.2kohm')\n", + "print \"load current is\",round(Ip*1000,2), \"mA\"\n", + "print \"load power is\",round(Pl*1000,2), \"mW\"\n", + "print \"power delivered is\",round(Pq*1000,2), \"mW\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 6.5,Page 286" + ] + }, + { + "cell_type": "code", + "execution_count": 4, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "time of rise is 788.48 ns\n", + "time of rise is 4.65 microsec\n" + ] + } + ], + "source": [ + "#finding time of rise\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "C=640.0;#capacitor\n", + "R1=560.0;#load resistance\n", + "R2=3.3;#kohm\n", + "\n", + "#calculation\n", + "t1=2.2*R1*C;\n", + "t2=2.2*R2*C;\n", + "\n", + "#result\n", + "print \"time of rise is\",round(t1/1000,2), \"ns\"\n", + "print \"time of rise is\",round(t2/1000,2), \"microsec\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 6.6,Page 287" + ] + }, + { + "cell_type": "code", + "execution_count": 2, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "resistance is 682.5 ohm\n", + "pick up resistance=680 ohm\n", + "rise time is 957.44 ns\n" + ] + }, + { + "data": { + "image/png": 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+ "text/plain": [ + "<matplotlib.figure.Figure at 0x7f4e9da3f2d0>" + ] + }, + "metadata": {}, + "output_type": "display_data" + } + ], + "source": [ + "#finding Rpick up,time of rise\n", + "\n", + "#initialisation of variable\n", + "%matplotlib inline\n", + "import numpy as np\n", + "import matplotlib.pyplot as plt\n", + "Vol=0.7;\n", + "Iol=40.0/1000;#current\n", + "Rpullup1=680.0;\n", + "C=640.0;\n", + "Epullup=28.0;\n", + "#for plotting\n", + "x=[0, .1, 1.9, 4.1, 5, 5.1, 5.3, 5.6, 6.0, 9.3];\n", + "y=[27.8, .1, .1, .1, .1, 5, 13.5, 21.0, 27.0, 27.8];\n", + "\n", + "#calculation\n", + "Rpullup=(Epullup-Vol)/Iol;\n", + "trise=2.2*Rpullup1*C;\n", + "plt.plot(x,y,'r');\n", + "plt.xlabel ('time(mus)')\n", + "plt.ylabel ('Vout')\n", + "plt.title ('Vout vs time')\n", + "\n", + "#result\n", + "print \"resistance is\",round(Rpullup,2), \"ohm\"\n", + "print('pick up resistance=680 ohm');\n", + "print \"rise time is\",round(trise/1000,2), \"ns\"\n", + "\n" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 6.7,Page 289" + ] + }, + { + "cell_type": "code", + "execution_count": 5, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "worst case resistance is 0.286 ohm\n", + "load current is 4.45 A\n", + "load voltage is 26.73 V\n", + "load power is 47.62 W\n", + "drop voltage is 1.27 V\n", + "power is 2.27 W\n", + "temperature is 182.6 deg.C\n" + ] + } + ], + "source": [ + "#finding worst case resistance and power characteristics\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "R1=.11;#resistance\n", + "Vd=28.0;#voltage\n", + "R2=6.0;#ohm\n", + "D=.4;#duty cycle\n", + "Q=62.0;\n", + "\n", + "#calculation\n", + "Ro=2.6*R1;\n", + "Ip=Vd/(R2+Ro);\n", + "Vl=Ip*R2;\n", + "Pl=D*Vl*Ip;\n", + "Vq=Ip*Ro;\n", + "Pq=D*Vq*Ip;\n", + "T=40+round(Pq*10)/10*Q;\n", + "\n", + "#result\n", + "print \"worst case resistance is\",round(Ro,3), \"ohm\"\n", + "print \"load current is\",round(Ip,2),\"A\"\n", + "print \"load voltage is\",round(Vl,2), \"V\"\n", + "print \"load power is\",round(Pl,2), \"W\"\n", + "print \"drop voltage is\",round(Vq,2), \"V\"\n", + "print \"power is\",round(Pq*10,2)/10, \"W\"\n", + "print \"temperature is\",round(T,2), \"deg.C\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 6.8,Page 292" + ] + }, + { + "cell_type": "code", + "execution_count": 6, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "voltage is 150.0 V\n" + ] + } + ], + "source": [ + "#finding voltage\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "L=10.0;#inductor\n", + "I=4.5;#current\n", + "t=300.0#time\n", + "\n", + "#calculation\n", + "V=L*I/t;\n", + "\n", + "#result\n", + "print \"voltage is\",round(V*1000,2), \"V\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 6.9,Page 298" + ] + }, + { + "cell_type": "code", + "execution_count": 1, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "R1+R2 is 682.5 ohm\n", + "pick R1=330ohm & R2=360ohm as they divide Vd setting 8V<Vg<18V\n", + "node voltage for V1 is 28.0 V\n", + "node voltage for V2 is 0.7 V\n", + "gate voltage is 15.31 V\n", + "gate & source diff is -12.69 V\n", + "load voltage is 26.73 V\n", + "load current is 2.23 A\n", + "load power is 47.63 W\n", + "Pq is 2.26 W\n", + "thermal resistance is 44.92 degreeC/W\n" + ] + } + ], + "source": [ + "#finding resistance and power characteristics\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Rl=12.0;#load resistance\n", + "V1=.8;#voltage\n", + "V2=2.4;#voltage\n", + "D=.8;#duty cycle\n", + "Tj=150.0;#degreeC\n", + "Ta=40.0;#degreeC\n", + "Vd=28.0;\n", + "Vo=.7;\n", + "I=40.0;#mA;\n", + "R1=330;\n", + "R2=360;\n", + "Vn1=28;\n", + "Vn2=.7;\n", + "\n", + "#calculation\n", + "k=(Vd-Vo)/I;\n", + "Vg=R2*Vd/(R1+R2)+Vn2;\n", + "Vgs=Vg-Vd;\n", + "Vl=Vd*Rl/(Rl+.57);\n", + "Il=Vl/Rl;\n", + "Pl=D*Vl*Il;\n", + "Vq=Il*.57;\n", + "Pq=D*Vq*Il;\n", + "Q=(Tj-Ta)/Pq-3.7;\n", + "\n", + "#result\n", + "print \"R1+R2 is\",round(k*1000,2), \"ohm\"\n", + "print('pick R1=330ohm & R2=360ohm as they divide Vd setting 8V<Vg<18V')\n", + "print \"node voltage for V1 is\",round(Vn1,2),\"V\"\n", + "print \"node voltage for V2 is\",round(Vn2,2), \"V\"\n", + "print \"gate voltage is\",round(Vg,2), \"V\"\n", + "print \"gate & source diff is\",round(Vgs,2), \"V\"\n", + "print \"load voltage is\",round(Vl,3), \"V\"\n", + "print \"load current is\",round(Il,2), \"A\"\n", + "print \"load power is\",round(Pl,2), \"W\"\n", + "print \"Pq is\",round(Pq,2), \"W\"\n", + "print \"thermal resistance is\",round(Q,2), \"degreeC/W\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 6.10,Page 305" + ] + }, + { + "cell_type": "code", + "execution_count": 8, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "time is 1.1 micro s\n" + ] + } + ], + "source": [ + "#finding time\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "I=40.0;#current\n", + "Q=44.0;#nC\n", + "\n", + "#calculation\n", + "t=Q/I;\n", + "\n", + "#result\n", + "print \"time is\",round(t,2), \"micro s\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 6.11,Page 313" + ] + }, + { + "cell_type": "code", + "execution_count": 9, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "current is 1.8 A\n", + "load voltage is 26.97 V\n", + "power is 40.85 W\n", + "high side voltage is 0.67 V\n", + "high side power is 1.03 W\n", + "low side voltage is 0.36 V\n", + "low side power is 0.55 W\n", + "IC power is 1.56 W\n", + "thermal resistance is 55.49 degreeC/W\n" + ] + } + ], + "source": [ + "#finding different voltages and power\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Rl=15.0;#load resistance\n", + "D=.85;#duty cycle\n", + "Ts=60.0;#degreeC\n", + "Vd=28.0;#voltage\n", + "R1=.375;\n", + "R2=.2;\n", + "\n", + "#calculation\n", + "I=Vd/(R1+R2+Rl);\n", + "Vl1=I*Rl;\n", + "P=D*Vl*I;\n", + "Vh=I*R1;\n", + "Ph=D*Vh*I;\n", + "Vl=I*R2;\n", + "Pl=D*Vl*I;\n", + "Pic=Ph+Pl;\n", + "Pic=1.56;\n", + "Tj=150;\n", + "Ta=60;\n", + "Q=(Tj-Ta)/Pic-2.2;\n", + "\n", + "#result\n", + "print \"current is\",round(I,2), \"A\"\n", + "print \"load voltage is\",round(Vl1,2), \"V\"\n", + "print \"power is\",round(P,2), \"W\"\n", + "print \"high side voltage is\",round(Vh,2), \"V\"\n", + "print \"high side power is\",round(Ph,2), \"W\"\n", + "print \"low side voltage is\",round(Vl,2), \"V\"\n", + "print \"low side power is\",round(Pl,2), \"W\"\n", + "print \"IC power is\",round(Pic,2), \"W\"\n", + "print \"thermal resistance is\",round(Q,2), \"degreeC/W\"" + ] + } + ], + "metadata": { + "kernelspec": { + "display_name": "Python 2", + "language": "python", + "name": "python2" + }, + "language_info": { + "codemirror_mode": { + "name": "ipython", + "version": 2 + }, + "file_extension": ".py", + "mimetype": "text/x-python", + "name": "python", + "nbconvert_exporter": "python", + "pygments_lexer": "ipython2", + "version": "2.7.6" + } + }, + "nbformat": 4, + "nbformat_minor": 0 +} diff --git a/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter7.ipynb b/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter7.ipynb new file mode 100644 index 00000000..45af7d98 --- /dev/null +++ b/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter7.ipynb @@ -0,0 +1,505 @@ +{ + "cells": [ + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Chapter 7: Switiching Power Supplies" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 7.1,Page 326" + ] + }, + { + "cell_type": "code", + "execution_count": 2, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "duty cycle is 0.25\n", + "average voltage is 3.0 V\n" + ] + } + ], + "source": [ + "#finding duty cycle and average voltage\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "T=20.0;#time\n", + "Vp=12.0;#voltage\n", + "t=5.0;\n", + "\n", + "#calculation\n", + "D=t/T;\n", + "Vd=(D*Vp);\n", + "\n", + "#result\n", + "print \"duty cycle is\",round(D,3)\n", + "print \"average voltage is\",round(Vd,3), \"V\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 7.2,Page 238" + ] + }, + { + "cell_type": "code", + "execution_count": 3, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "duty cycle is 42.0 %\n", + "time is 10.0 microsec\n", + "on time is 4.167 microsec\n", + "ripple current is 133.636 mA\n", + "load current is 500.0 mA\n", + "peak inductor current is 566.818 mA\n" + ] + } + ], + "source": [ + "#finding on time ripple,load,peak inductor current\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Vd=12.0;#voltage\n", + "Vl=5.0;#load voltage\n", + "Rl=10.0;#load resistance\n", + "f=100.0;#frequency\n", + "L=220.0;#inductor\n", + "\n", + "#calculation\n", + "D=Vl/Vd;\n", + "T=1/f;\n", + "t=D*T;\n", + "Vr=Vd-Vl;\n", + "I=Vr*round(t*10000)/10/L;\n", + "Il=Vl/Rl;\n", + "Ip=Il+I/2;\n", + "\n", + "#result\n", + "print \"duty cycle is\",round(D*100), \"%\"\n", + "print \"time is\",round(T*1000,3), \"microsec\"\n", + "print \"on time is\",round(t*10000,2)/10, \"microsec\"\n", + "print \"ripple current is\",round(I*1000,3),\"mA\"\n", + "print \"load current is\",round(Il*1000,3), \"mA\"\n", + "print \"peak inductor current is\",round(Ip*1000,3), \"mA\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 7.3,Page 335" + ] + }, + { + "cell_type": "code", + "execution_count": 4, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "rms current is 325.01 mA\n", + "by trapezium method\n", + "rms current is 324.04 mA\n", + "by rectangle method\n", + "\n", + " rectangle method gives good result than trapezium method\n" + ] + } + ], + "source": [ + "#finding rms current\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Id=500.0;#load current\n", + "i=134;#mA\n", + "D=.42;#duty cycle\n", + "\n", + "#calculation\n", + "Ip=Id+i/2;\n", + "Im=Id-i/2;\n", + "I1=((D/3)*(Ip**2+Im*Ip+Im**2))**.5;\n", + "I2=D**.5*Id;\n", + "\n", + "#result\n", + "print \"rms current is\",round(I1,2), \"mA\"\n", + "print('by trapezium method')\n", + "print \"rms current is\",round(I2,2), \"mA\"\n", + "print('by rectangle method')\n", + "print '\\n rectangle method gives good result than trapezium method'" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 7.4,Page 336" + ] + }, + { + "cell_type": "code", + "execution_count": 5, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "voltage is 0.3 V\n", + "dissipated power is 63.0 mW\n" + ] + } + ], + "source": [ + "#finding voltage and power\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "Vp=.3;#voltage\n", + "I=500.0;#current\n", + "D=.42;#duty cycle\n", + "T=150.0;#temperature\n", + "R=.6;#ohm\n", + "\n", + "#calculation\n", + "Vq=I*R;\n", + "Pq=D*Vq*I;\n", + "\n", + "#result\n", + "print \"voltage is\",round(Vq/1000,2), \"V\"\n", + "print \"dissipated power is\",round(Pq/1000,2), \"mW\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 7.5,Page 341" + ] + }, + { + "cell_type": "code", + "execution_count": 7, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "duty cycle is 42.0 %\n", + "time period is 6.667 microsec\n", + "on time is 2.778 microsec\n", + "load current is 500.0 mA\n", + "ripple current is 125.0 mA\n", + "inductor voltage is 7.0 V\n", + "inductor is 155.556 microH\n", + "inductor current is 562.5 mA\n", + "minimum capacitor current is 250.0 mA\n", + "minimum capacitor voltage is 18.0 V\n", + "Rf/Ri is 3.07\n", + "power of LM2595 is 0.33 W\n", + "thermal resistance is 210.998 degreeC/W\n" + ] + } + ], + "source": [ + "#finding all componenets\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "R=10.0;#resistance\n", + "V1=5.0;#V\n", + "V2=12.0;#V\n", + "Ta=80.0;#degreeC\n", + "Tb=150.0;\n", + "f=150.0;#frequency\n", + "\n", + "#calculation\n", + "D=V1/V2;\n", + "T=1/f;\n", + "t=D*T;\n", + "Id=V1/R;\n", + "i=.25*Id;\n", + "Vl=V2-V1;\n", + "L=Vl*t/i;\n", + "Ip=Id+i/2;\n", + "Ic=Id/2;\n", + "Vc=1.5*V2;\n", + "K=V1/1.23-1;\n", + "P=.01*V2+D*Id*1;\n", + "Q=(Tb-Ta)/P-2.2;\n", + "\n", + "#result\n", + "print \"duty cycle is\",round(D*100), \"%\"\n", + "print \"time period is\",round(T*1000,3), \"microsec\"\n", + "print \"on time is\",round(t*1000,3), \"microsec\"\n", + "print \"load current is\",round(Id*1000,3), \"mA\"\n", + "print \"ripple current is\",round(i*1000,3), \"mA\"\n", + "print \"inductor voltage is\",round(Vl,2), \"V\"\n", + "print \"inductor is\",round(L*1000,3), \"microH\"\n", + "print \"inductor current is\",round(Ip*1000,2), \"mA\"\n", + "print \"minimum capacitor current is\",round(Ic*1000,2), \"mA\"\n", + "print \"minimum capacitor voltage is\",round(Vc,3), \"V\"\n", + "print \"Rf/Ri is\",round(K,2)\n", + "print \"power of LM2595 is\",round(P,2), \"W\"\n", + "print \"thermal resistance is\",round(Q,3), \"degreeC/W\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 7.6,Page 349" + ] + }, + { + "cell_type": "code", + "execution_count": 9, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "load power is 15.4 W\n", + "supply power is 17.11 W\n", + "dc current is 1.4 A\n", + "inductor current is 1.57 A\n", + "duty cycle is 0.45\n", + "inductor is 154.29 microH\n", + "transistor power is 352.8 mW\n", + "diode power is 385.0 mW\n", + "capacitor is 157.5 microF\n" + ] + } + ], + "source": [ + "#finding different power,inductor current,inductor value\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "V1=12.0#V\n", + "V2=22.0;#V\n", + "I=.7;#A\n", + "f=100.0;#kHz\n", + "R=.4;#ohm\n", + "Vd=.5;\n", + "\n", + "#calculation\n", + "Pl=V2*I;\n", + "Ps=Pl/.9;\n", + "Id=round(Ps/V1*10)/10;\n", + "i=.25*Id;\n", + "Ip=Id+i/2;\n", + "D=round((1-V1/V2)*100)/100;\n", + "t=D/f;\n", + "L=V1*t/i;\n", + "Vp=Id*R;\n", + "Pq=D*Vp*Id;\n", + "Pd=(1-D)*.5*Id;\n", + "C=Id*t/2/20;\n", + "\n", + "#result\n", + "print \"load power is\",round(Pl,2), \"W\"\n", + "print \"supply power is\",round(Ps,2), \"W\"\n", + "print \"dc current is\",round(Id,2), \"A\"\n", + "print \"inductor current is\",round(Ip,2), \"A\"\n", + "print \"duty cycle is\",round(D,2)\n", + "print \"inductor is\",round(L*1000,2), \"microH\"\n", + "print \"transistor power is\",round(Pq*1000,2), \"mW\"\n", + "print \"diode power is\",round(Pd*100,2)*10, \"mW\"\n", + "print \"capacitor is\",round(C*1e6,2), \"microF\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 7.7,Page 355" + ] + }, + { + "cell_type": "code", + "execution_count": 11, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "Rf/Ri is 16.886\n", + "pick Rf=22; Ri=1.3;\n", + "rms current is 1.4 A\n", + "switch power is 132.3 mW\n", + "IC power is 151.2 mW\n", + "total power is 283.5 mW\n", + "IC temperature is 98.43 degreeC\n" + ] + } + ], + "source": [ + "#finding feedback resistor,power,current and temperature\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "V1=12.0;#V\n", + "V2=22.0;#V\n", + "I=.7;#A\n", + "Ta=80.0;#degreeC\n", + "Ps=17.1#supply power\n", + "\n", + "#calculation\n", + "K=V2/1.23-1;\n", + "Id=round(Ps/V1*10)/10;\n", + "D=round((1-(V1/V2))*100)/100;\n", + "Ir=D**.5*Id;\n", + "Ps=Ir**2*.15;\n", + "Pi=D*Id*V1/50;\n", + "P=Ps+Pi;\n", + "T=Ta+P*65;\n", + "\n", + "#result\n", + "print \"Rf/Ri is\",round(K,3)\n", + "print('pick Rf=22; Ri=1.3;')\n", + "print \"rms current is\",round(Id,2), \"A\"\n", + "print \"switch power is\",round(Ps*1000,2), \"mW\"\n", + "print \"IC power is\",round(Pi*1000,2), \"mW\"\n", + "print \"total power is\",round(P*1000,2), \"mW\"\n", + "print \"IC temperature is\",round(T,2), \"degreeC\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 7.8,Page 359" + ] + }, + { + "cell_type": "code", + "execution_count": 13, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "maximum voltage is 18.25 V\n", + "diode voltage is 20.0 V\n", + "duty cycle is 0.34\n", + "power delivered is 5.0 W\n", + "average current is 466.67 mA\n", + "mid primary current is 1.37 A\n", + "rms current is 800.33 mA\n", + "ramp current is 480.0 mA\n", + "maximum transistor current is 1.61 A\n", + "minimum transistor current is 1.13 A\n", + "diode peak current is 2.02 A\n", + "secondary rms current is 1.23 A\n", + "capacitor is 170.0 microF\n" + ] + } + ], + "source": [ + "#designing circuit and finding circuit parameter\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "V1=12.0;#V\n", + "V2=5.0;#V\n", + "Il=1.0;#load current\n", + "T=10.0;#microsec\n", + "K=1.25;#Npri/Nsec\n", + "L=85.0;#microH\n", + "\n", + "#calculation\n", + "Vq=V1+V2*K;\n", + "Vd=V1*K+V2;\n", + "D=round((K*V2)*100/(V1+K*V2))/100;\n", + "Po=V2*Il;\n", + "Pi=round(Po/.09)/10;\n", + "Id=Pi/V1;\n", + "Im=Id/D;\n", + "Ir=(Im*D**.5);\n", + "i=V1*D*T/L;\n", + "IM=Im+.24;\n", + "Imin=Im-.24;\n", + "Ip=K*IM;\n", + "Imid=Il/(1-D);\n", + "Irms=Imid*(1-D)**.5;\n", + "C=D*Il*T/20;\n", + "\n", + "#result\n", + "print \"maximum voltage is\",round(Vq,2), \"V\"\n", + "print \"diode voltage is\",round(Vd,2), \"V\"\n", + "print \"duty cycle is\",round(D,2)\n", + "print \"power delivered is\",round(Po,2), \"W\"\n", + "print \"average current is\",round(Id*1000,2), \"mA\"\n", + "print \"mid primary current is\",round(Im,2), \"A\"\n", + "print \"rms current is\",round(Ir*1000,2),\"mA\"\n", + "print \"ramp current is\",round(i*1000,2), \"mA\"\n", + "print \"maximum transistor current is\",round(IM,2),\"A\"\n", + "print \"minimum transistor current is\",round(Imin,2),\"A\"\n", + "print \"diode peak current is\",round(Ip,2), \"A\"\n", + "print \"secondary rms current is\",round(Irms,2),\"A\"\n", + "print \"capacitor is\",round(C*1000,2), \"microF\"\n" + ] + } + ], + "metadata": { + "kernelspec": { + "display_name": "Python 2", + "language": "python", + "name": "python2" + }, + "language_info": { + "codemirror_mode": { + "name": "ipython", + "version": 2 + }, + "file_extension": ".py", + "mimetype": "text/x-python", + "name": "python", + "nbconvert_exporter": "python", + "pygments_lexer": "ipython2", + "version": "2.7.6" + } + }, + "nbformat": 4, + "nbformat_minor": 0 +} diff --git a/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter8.ipynb b/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter8.ipynb new file mode 100644 index 00000000..7cf6b405 --- /dev/null +++ b/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter8.ipynb @@ -0,0 +1,326 @@ +{ + "cells": [ + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Chapter 8: Thyristors" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 8.3,Page 397" + ] + }, + { + "cell_type": "code", + "execution_count": 1, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "inductance is 6.22 microH\n", + "load impedence at angle 90 degree is 0.00195 ohm\n" + ] + } + ], + "source": [ + "#finding inductance,load impedence\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "V=220.0;#line voltage\n", + "f=50.0;#hertz\n", + "R=80.0;#load resistance\n", + "K=50.0;#di/dt\n", + "\n", + "#calculation\n", + "L=V*2**.5/K;\n", + "Z=2*pi*f*L;\n", + "\n", + "#result\n", + "print \"inductance is\",round(L,2),\"microH\"\n", + "print \"load impedence at angle 90 degree is\",round(Z*1e-6,5), \"ohm\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 8.4,Page 400" + ] + }, + { + "cell_type": "code", + "execution_count": 3, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "minimum value of capacitor is 0.067 micfoF\n", + "\n", + "choose C=.1 micoF\n", + "capacitor impedence at angle -90degree is 31.83 ohm\n", + "Load current in mA at an angle 90 degrees is 6.91\n", + "Potential drop in V at an angle 90 degrees is 0.55\n", + "Power dissipated is 3 mW\n" + ] + } + ], + "source": [ + "#finding capacitor,current\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "V=220.0;#line voltage\n", + "f=50.0;#hertz\n", + "R=80.0;#load resistance\n", + "K=75.0;#dv/dt\n", + "Vd=400.0;#DRM voltage\n", + "\n", + "\n", + "#calculation\n", + "C=Vd/R/K;\n", + "C1=.1;\n", + "Z=1/(2*pi*f*C1);\n", + "Iload=V/1000/(-Z*cos(180*pi/180)+R*round(cos(90*pi/180)));\n", + "Vload=Iload/1000*R;\n", + "P=Vload*Iload;\n", + "\n", + "#result\n", + "print \"minimum value of capacitor is\",round(C,3), \"micfoF\"\n", + "print('\\nchoose C=.1 micoF')\n", + "print \"capacitor impedence at angle -90degree is\",round(Z*1000,2), \"ohm\"\n", + "print \"Load current in mA at an angle 90 degrees is\",round(Iload,2)\n", + "print \"Potential drop in V at an angle 90 degrees is\",round(Vload,2)\n", + "print \"Power dissipated is\",int(P), \"mW\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 8.5,Page 402" + ] + }, + { + "cell_type": "code", + "execution_count": 4, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "snubbing resistnce is 7.39 ohm\n" + ] + } + ], + "source": [ + "#finding snubbing resistance\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "V=220;#line voltage\n", + "f=50;#hertz\n", + "R=80;#load resistance\n", + "I=46;#TSM current\n", + "\n", + "#calculation\n", + "Rs=V*2**.5/(I-V*2**.5/R);\n", + "\n", + "#result\n", + "print \"snubbing resistnce is\",round(Rs,2), \"ohm\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 8.6,Page 414" + ] + }, + { + "cell_type": "code", + "execution_count": 5, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "line period is 16.67 ms\n", + "half-cycle time is 8.333 ms\n", + "no. of cycles is 10.0\n", + "voltage for t1 is 54.0 V\n", + "power for t1 is 291.6 W\n", + "voltage for t2 is 100.0 V\n", + "voltage for t2 is 1000.0 W\n" + ] + } + ], + "source": [ + "#finding voltage , power and cycles\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "R=10.0;#load\n", + "V=120.0;#rms voltage\n", + "f=60.0;#hertz\n", + "T=83.3;#ms\n", + "t1=15;#ms\n", + "t2=55;#ms\n", + "\n", + "#calculation\n", + "Tl=1/f;\n", + "Th=Tl/2;\n", + "C=round(T/Th/100)*100;\n", + "D1=.2;\n", + "V1=round(V*D1**.5);\n", + "P1=V1**2/R;\n", + "D2=.7;\n", + "V2=round(V*D2**.5);\n", + "P2=V2**2/R;\n", + "\n", + "#result\n", + "print \"line period is\",round(Tl*1000,2), \"ms\"\n", + "print \"half-cycle time is\",round(Th*1000,3), \"ms\"\n", + "print \"no. of cycles is\",C/1000\n", + "print \"voltage for t1 is\",round(V1,3), \"V\"\n", + "print \"power for t1 is\",round(P1,3), \"W\"\n", + "print \"voltage for t2 is\",round(V2,3), \"V\"\n", + "print \"voltage for t2 is\",round(P2,3), \"W\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 8.8,Page 427" + ] + }, + { + "cell_type": "code", + "execution_count": 7, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "average voltage is 42.0 V\n", + "dc voltage is 41.0 V\n", + "\n", + "the markers indicae Vp=163V Vave=41\n", + "full-wave rms voltage is 108.0 V\n", + "rms voltage is 108.0 V\n", + "\n", + "the markers indicate Vp=169V ;Vave=106V\n" + ] + } + ], + "source": [ + "#finding dc volatge,average voltage,rms voltage\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "V=120.0;#line voltage\n", + "A=60.0;#degree\n", + "D=0.35;\n", + "\n", + "#calculation\n", + "Va=D*V;\n", + "Vd=V*2**.5*(cos(A*pi/180)+1)/2/pi;\n", + "Vr=.9*V;\n", + "Vrms=V*(2**.5)*(.5*(pi-1.047)+.25*sin(2*A*pi/180))**.5/pi**.5;\n", + "\n", + "#result\n", + "print \"average voltage is\",round(Va,3), \"V\"\n", + "print \"dc voltage is\",round(Vd), \"V\"\n", + "print('\\nthe markers indicae Vp=163V Vave=41')\n", + "print \"full-wave rms voltage is\",round(Vr), \"V\"\n", + "print \"rms voltage is\",round(Vrms), \"V\"\n", + "print('\\nthe markers indicate Vp=169V ;Vave=106V')\n" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 8.9,Page 430" + ] + }, + { + "cell_type": "code", + "execution_count": 8, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "rms voltage is 141.18 V\n", + "double checked value of rms voltage is 141.18 V\n" + ] + } + ], + "source": [ + "#finding rms voltage and double checked rms voltage\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "V=220.0;#line voltage\n", + "P=1.3;#kW\n", + "R=15.0;#ohm\n", + "\n", + "#calculation\n", + "Vr=round((P*1000*R)**.5);\n", + "D=Vr/V;\n", + "Vr=V*2**.5*(.5*(pi-1.710)+sin(196*pi/180)/4)**.5/pi**.5;\n", + "\n", + "#result\n", + "print \"rms voltage is\",round(Vr,2), \"V\"\n", + "print \"double checked value of rms voltage is\",round(Vr,2), \"V\"" + ] + } + ], + "metadata": { + "kernelspec": { + "display_name": "Python 2", + "language": "python", + "name": "python2" + }, + "language_info": { + "codemirror_mode": { + "name": "ipython", + "version": 2 + }, + "file_extension": ".py", + "mimetype": "text/x-python", + "name": "python", + "nbconvert_exporter": "python", + "pygments_lexer": "ipython2", + "version": "2.7.6" + } + }, + "nbformat": 4, + "nbformat_minor": 0 +} diff --git a/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter9.ipynb b/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter9.ipynb new file mode 100644 index 00000000..d50d131a --- /dev/null +++ b/Power_Electronics_Principles_and_Applications_by_Jacob/Chapter9.ipynb @@ -0,0 +1,405 @@ +{ + "cells": [ + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Chapter 9: Power Conversation and Motor Drive Operations" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 9.1,Page 457" + ] + }, + { + "cell_type": "code", + "execution_count": 1, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "peak voltage is 37.6 V\n", + "load voltage is 35.7 V\n", + "ripple voltage is 3.96 V\n", + "approx. load voltage is 35.62 V\n" + ] + } + ], + "source": [ + "#finding peak,load,ripple voltages\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "V=28.0;#V\n", + "C=4700.0;#microF\n", + "R=16.0;#load\n", + "f=120.0;#hertz\n", + "\n", + "#calculation\n", + "Vp=V*2**.5-2;\n", + "Vd=0.95*Vp;\n", + "Id=Vd/R;\n", + "v=Id/f/C;\n", + "#approximation\n", + "Vd1=Vp-v*1e6/2;\n", + "\n", + "#result\n", + "print \"peak voltage is\",round(Vp,2), \"V\"\n", + "print \"load voltage is\",round(Vd,1), \"V\"\n", + "print \"ripple voltage is\",round(v*1e6,2), \"V\"\n", + "print \"approx. load voltage is\",round(Vd1,2), \"V\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 9.2,Page 459" + ] + }, + { + "cell_type": "code", + "execution_count": 2, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "Zth is 1.0 + 1.0 in ohm\n", + "inductor is 2.65 mH\n" + ] + } + ], + "source": [ + "#finding inductor,Zth\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "V1=120.0;#pri voltage\n", + "V2=28.0;#sec voltage\n", + "I=2.0;#pri current\n", + "f=60.0;#Hz\n", + "Vth=28.8;#open voltage\n", + "V3=12.1;#pri-short voltage\n", + "Is=2.0;#short current at 45 degree\n", + "\n", + "#calculation\n", + "Zi=(V2*V3)/V1/Is*cos(45*pi/180);\n", + "Zj=(V2*V3)/V1/Is*sin(45*pi/180);\n", + "L=Zi/(2*pi*f);\n", + "\n", + "#result\n", + "print'Zth is',round(Zi),'+',round(Zj),'in ohm'\n", + "print \"inductor is\",round(L*1000,2), \"mH\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 9.4,Page 463" + ] + }, + { + "cell_type": "code", + "execution_count": 3, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "power factor is 0.32\n" + ] + } + ], + "source": [ + "#finding power factor\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "I1=1.8;#current\n", + "R=16.0;#resistance\n", + "I2=5.7;#A\n", + "V=28.8;#Voltage\n", + "\n", + "#calculation\n", + "P=I1**2*R;\n", + "S=I2*V;\n", + "Pf=P/S;\n", + "\n", + "#result\n", + "print \"power factor is\",round(Pf,2)" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 9.5, Page 468" + ] + }, + { + "cell_type": "code", + "execution_count": 2, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "aparrent power is 8.14 kVA\n", + "dissipated power is 7.84 kW\n", + "power factor is 0.96\n" + ] + } + ], + "source": [ + "#finding power factor\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "I=22.6;#current\n", + "I2=28.00;\n", + "V=120.0;#Voltage\n", + "V2=280.0;\n", + "\n", + "#calculation\n", + "Pt=3*I*V;\n", + "Pl=I2*V2;\n", + "Pf=Pl/Pt;\n", + "\n", + "#result\n", + "print \"aparrent power is\",round(Pt/1000,2),\"kVA\"\n", + "print \"dissipated power is\",round(Pl/1000,2),\"kW\"\n", + "print \"power factor is\",round(Pl/Pt,2)\n", + "\n" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 9.6,Page 474" + ] + }, + { + "cell_type": "code", + "execution_count": 4, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "ratio is 0.72\n", + "firing angle is 58 degrees\n", + "dc voltage is 148.85 V\n", + "time delay is 2.69 ms\n" + ] + } + ], + "source": [ + "#finding firing angle, time delay,Vd\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "V=208.0;#voltage\n", + "R=100.0;#load\n", + "Vd=150.0;#V\n", + "\n", + "#calculation\n", + "r=Vd/V;\n", + "a=58;#degree\n", + "Vd=3*2**.5*208*(cos(pi/3+a*pi/180)-cos(2*pi/3+a*pi/180))/pi;\n", + "t=a*16.7/360;\n", + "\n", + "#result\n", + "print \"ratio is\",round(r,2)\n", + "print('firing angle is 58 degrees');\n", + "print \"dc voltage is\",round(Vd,2), \"V\"\n", + "print \"time delay is\",round(t,2), \"ms\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 9.7,Page 480" + ] + }, + { + "cell_type": "code", + "execution_count": 5, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "max. current is 41.67 A\n", + "dissipated power is 8.68 W\n" + ] + } + ], + "source": [ + "#finding maximum current and power dissipated\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "P=150.0;#power\n", + "V=8.0;#voltage\n", + "R=.01;#resistance\n", + "D=.5;#duty cycle\n", + "\n", + "#calculation\n", + "I=P/.9/D/V;\n", + "Ir=I*D**.5;\n", + "Pq=Ir**2*R;\n", + "\n", + "#result\n", + "print \"max. current is\",round(I,2), \"A\"\n", + "print \"dissipated power is\",round(Pq,2),\"W\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 9.8,Page 489" + ] + }, + { + "cell_type": "code", + "execution_count": 6, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "pwm fundamental frequency is 30.72 kHz\n", + "output voltage is 9.46 V\n" + ] + } + ], + "source": [ + "#finding fundamental frequency and output voltage\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "f1=60.0;#frequency\n", + "V=150.0;#voltage\n", + "f2=31.0;#kHz\n", + "\n", + "#calculation\n", + "f3=f1*4;\n", + "Vo=V*10**(-4.2);\n", + "\n", + "#result\n", + "print \"pwm fundamental frequency is\",round(f3*2**7/1000,2), \"kHz\"\n", + "print \"output voltage is\",round(Vo*1000,2), \"V\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 9.9,Page 491" + ] + }, + { + "cell_type": "code", + "execution_count": 7, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "average voltage is 127.32 V\n", + "\n", + "Va-d @ 200Vin=4.2V\n", + "\n", + "\n", + "pick R1=47kohm\n", + "current through dividers is 2.62 mA\n", + "R2 is 1.6 kohm\n", + "capacitor is 27.01 microF\n" + ] + } + ], + "source": [ + "#finding resistances,capacitor,average voltage\n", + "\n", + "#initialisation of variable\n", + "from math import pi,tan,sqrt,sin,cos,acos,atan\n", + "V=120.0;#load voltage\n", + "f=60.0;#Hz\n", + "Vp=200.0;#V\n", + "Vd=5.0;#V\n", + "\n", + "\n", + "#calculation\n", + "Vdc=2*Vp/pi;\n", + "Va=4.2;\n", + "R1=47.0;\n", + "I=(Vdc-Va)/R1;\n", + "R2=Va/I;\n", + "K=1.0/(1/R1+1/R2)# R1 \\\\ R2\n", + "C=1.0/2/pi/3.8/K;\n", + "\n", + "#result\n", + "print \"average voltage is\",round(Vdc,2), \"V\"\n", + "print('\\nVa-d @ 200Vin=4.2V')\n", + "print('\\n\\npick R1=47kohm')\n", + "print \"current through dividers is\",round(I,2), \"mA\"\n", + "print \"R2 is\",round(R2,2), \"kohm\"\n", + "print \"capacitor is\",round(C*1000,2), \"microF\"" + ] + } + ], + "metadata": { + "kernelspec": { + "display_name": "Python 2", + "language": "python", + "name": "python2" + }, + "language_info": { + "codemirror_mode": { + "name": "ipython", + "version": 2 + }, + "file_extension": ".py", + "mimetype": "text/x-python", + "name": "python", + "nbconvert_exporter": "python", + "pygments_lexer": "ipython2", + "version": "2.7.6" + } + }, + "nbformat": 4, + "nbformat_minor": 0 +} diff --git a/Power_Electronics_Principles_and_Applications_by_Jacob/README.txt b/Power_Electronics_Principles_and_Applications_by_Jacob/README.txt new file mode 100644 index 00000000..274ef8b6 --- /dev/null +++ b/Power_Electronics_Principles_and_Applications_by_Jacob/README.txt @@ -0,0 +1,10 @@ +Contributed By: Amit Kumar Das +Course: btech +College/Institute/Organization: ISM Dhanbad +Department/Designation: Mining Machinery Engineering +Book Title: Power Electronics Principles and Applications +Author: Jacob +Publisher: Cengage Learning, New Delhi +Year of publication: 2009 +Isbn: 9780766823327 +Edition: 4
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