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-rwxr-xr-x2939/CH1/EX1.1/Ex1_1.sce15
-rwxr-xr-x2939/CH1/EX1.10/Ex1_10.sce14
-rwxr-xr-x2939/CH1/EX1.11/Ex1_11.sce25
-rwxr-xr-x2939/CH1/EX1.12/Ex1_12.sce17
-rwxr-xr-x2939/CH1/EX1.13/Ex1_13.sce20
-rwxr-xr-x2939/CH1/EX1.14/Ex1_14.sce18
-rwxr-xr-x2939/CH1/EX1.15/Ex1_15.sce23
-rwxr-xr-x2939/CH1/EX1.16/Ex1_16.sce22
-rwxr-xr-x2939/CH1/EX1.17/Ex1_17.sce15
-rwxr-xr-x2939/CH1/EX1.18/Ex1_18.sce15
-rwxr-xr-x2939/CH1/EX1.19/Ex1_19.sce24
-rwxr-xr-x2939/CH1/EX1.2/Ex1_2.sce9
-rwxr-xr-x2939/CH1/EX1.20/Ex1_20.sce26
-rwxr-xr-x2939/CH1/EX1.21/Ex1_21.sce31
-rwxr-xr-x2939/CH1/EX1.3/Ex1_3.sce23
-rwxr-xr-x2939/CH1/EX1.4/Ex1_4.sce19
-rwxr-xr-x2939/CH1/EX1.5/Ex1_5.sce26
-rwxr-xr-x2939/CH1/EX1.6/Ex1_6.sce16
-rwxr-xr-x2939/CH1/EX1.7/Ex1_7.sce25
-rwxr-xr-x2939/CH1/EX1.8/Ex1_8.sce41
-rwxr-xr-x2939/CH1/EX1.9/Ex1_9.sce16
21 files changed, 440 insertions, 0 deletions
diff --git a/2939/CH1/EX1.1/Ex1_1.sce b/2939/CH1/EX1.1/Ex1_1.sce
new file mode 100755
index 000000000..d809b9bb6
--- /dev/null
+++ b/2939/CH1/EX1.1/Ex1_1.sce
@@ -0,0 +1,15 @@
+//Ex1_1
+
+clc;
+//Given:
+v=1000;// potential
+d=0.05;// distance
+q=3.8*10^-9;// charge
+
+//solution:
+e=v/d;//electric field
+f=e;// force
+f1=f*q;// force on metal sphere
+printf("\n The electric field in V/m is = %f ",e)
+printf("\n The force in N/C is = %f ",f)
+printf("\n The force on metal sphere in N is = %f ",f1)
diff --git a/2939/CH1/EX1.10/Ex1_10.sce b/2939/CH1/EX1.10/Ex1_10.sce
new file mode 100755
index 000000000..ef127ae18
--- /dev/null
+++ b/2939/CH1/EX1.10/Ex1_10.sce
@@ -0,0 +1,14 @@
+
+//Ex1_10
+
+clc;
+
+//Given:
+
+enthalpy=1278; // enthalpy of combustion in kJ/mol
+
+//solution:
+
+energy=(enthalpy*1000)/(6.022*10^23*1.6*10^-19);
+
+printf("The energy in eV is = %f ",energy)
diff --git a/2939/CH1/EX1.11/Ex1_11.sce b/2939/CH1/EX1.11/Ex1_11.sce
new file mode 100755
index 000000000..fc5f3418f
--- /dev/null
+++ b/2939/CH1/EX1.11/Ex1_11.sce
@@ -0,0 +1,25 @@
+//Ex1_11
+
+clc;
+
+//Given:
+mh=1.0078;
+mn=1.0087;
+ma=4.0026;
+mo=15.9949;
+Ah=4.0026; // atomic mass of helium
+Ao=15.9949; // atomic mass of oxygen
+
+//solution:
+
+// part (a)
+
+B1=(2*mh+2*mn-ma)*931; // in MeV
+Bh=B1/Ah;
+printf("\n The mean binding energy of helium atom in MeV is = %f ",Bh)
+
+// part (b)
+
+B2=(8*mh+8*mn-mo)*931; // in MeV
+Bo=B2/Ao;
+printf("\n The mean binding energy of oxygen atom in MeV is = %f ",Bo)
diff --git a/2939/CH1/EX1.12/Ex1_12.sce b/2939/CH1/EX1.12/Ex1_12.sce
new file mode 100755
index 000000000..5f0b5068d
--- /dev/null
+++ b/2939/CH1/EX1.12/Ex1_12.sce
@@ -0,0 +1,17 @@
+
+//Ex1_12
+
+clc;
+
+//Given:
+mh=1.0078;
+mn=1.0087;
+ABe=8.0053; // atomic mass of beryllium
+
+//solution:
+
+B1=(4*mh+4*mn-ABe)*931; // in MeV
+Bh=B1/ABe;
+printf("\n The mean binding energy of Be atom in MeV is = %f ",Bh)
+
+disp("From previous problem we have the avg. binding energy of helium atom is 7.08 MeV, Hence Be is unstable to fission into 2 alphas")
diff --git a/2939/CH1/EX1.13/Ex1_13.sce b/2939/CH1/EX1.13/Ex1_13.sce
new file mode 100755
index 000000000..f21faa004
--- /dev/null
+++ b/2939/CH1/EX1.13/Ex1_13.sce
@@ -0,0 +1,20 @@
+
+//Ex1_13
+
+clc;
+
+//Given:
+
+e=200; // in Mev
+m=0.235; // weight of uranium atom in Kg
+enthalpy=393.5; // in KJ/mol
+Na=6.02*10^23;
+
+
+//solution:
+e1=e*1.6*10^-19*10^6;
+atoms=Na/m;
+e2=atoms*e1;//energy released in J
+m1=(e2*12)/(393.5*1000*1000);// in Kg
+m2=m1/1000;// in tons
+printf("\n The amount of coal required in Kg is = %f", m2)
diff --git a/2939/CH1/EX1.14/Ex1_14.sce b/2939/CH1/EX1.14/Ex1_14.sce
new file mode 100755
index 000000000..053af1d33
--- /dev/null
+++ b/2939/CH1/EX1.14/Ex1_14.sce
@@ -0,0 +1,18 @@
+
+//Ex1_14
+
+clc;
+
+//Given:
+H1=241.8; // in KJ/mol
+H2=887.2; // in KJ/mol
+// 1 KJ/mol = 0.0104 eV/atom
+
+//solution: part (a)
+e1=H1*0.0104;
+printf("\n The energy release in part (a) in eV/molecule is = %f ",e1)
+
+//solution: part (b)
+e2=H2*0.0104;
+printf("\n The energy release in part (b) in eV/molecule is = %f ",e2)
+
diff --git a/2939/CH1/EX1.15/Ex1_15.sce b/2939/CH1/EX1.15/Ex1_15.sce
new file mode 100755
index 000000000..e7d30bc57
--- /dev/null
+++ b/2939/CH1/EX1.15/Ex1_15.sce
@@ -0,0 +1,23 @@
+
+//Ex1_15
+
+clc;
+
+//Given:
+H1=4.1; // in eV/molecule
+H2=17.4; // in eV/molecule
+H3=200;// in MeV/atom of U
+
+// 1 eV/atom = 96.32 KJ/mol
+
+//solution: part (a)
+e1=H1*96.32;
+printf("\n The energy release in part (a) in KJ/mol of carbondioxide is = %f ",e1)
+
+//solution: part (b)
+e2=H2*96.32;
+printf("\n The energy release in part (b) in KJ/mol of alumina is = %f ",e2)
+
+//solution: part (c)
+e3=H3*1000*96.32;// in MJ/atom of U(235)
+printf("\n The energy release in part (c) in MJ/atom of U(235) is = %f ",e3)
diff --git a/2939/CH1/EX1.16/Ex1_16.sce b/2939/CH1/EX1.16/Ex1_16.sce
new file mode 100755
index 000000000..5bfb49797
--- /dev/null
+++ b/2939/CH1/EX1.16/Ex1_16.sce
@@ -0,0 +1,22 @@
+
+//Ex1_16
+
+clc;
+
+//Given:
+e=200; //MeV/ atom of U
+// 1 eV = 1.6*10^-19 J
+Na=6.023*10^23;
+M=0.235; // mass in Kg
+
+//solution:
+
+e1=e*1.6*10^-19*10^6;
+A=Na/M;
+e2=A*e1; // energy released in MJ/day
+e3=e2/(24*3600);
+printf("\n The rate of energy release in W is %f ",e3)
+
+
+
+
diff --git a/2939/CH1/EX1.17/Ex1_17.sce b/2939/CH1/EX1.17/Ex1_17.sce
new file mode 100755
index 000000000..29f200abf
--- /dev/null
+++ b/2939/CH1/EX1.17/Ex1_17.sce
@@ -0,0 +1,15 @@
+//Ex1_17
+
+clc;
+
+//Given:
+e=26.03; // in MeV
+
+//solution:
+
+loss=e/931; //in atomic mass units (u)
+// 1 u = 1.66*10^-27 Kg
+m=(loss*1.66*10^-27)/(1*10^-27);
+printf("\n The mass loss in 10^-27 Kg/He formed is = %f ",m)
+
+
diff --git a/2939/CH1/EX1.18/Ex1_18.sce b/2939/CH1/EX1.18/Ex1_18.sce
new file mode 100755
index 000000000..89cc0e1dd
--- /dev/null
+++ b/2939/CH1/EX1.18/Ex1_18.sce
@@ -0,0 +1,15 @@
+
+//Ex1_18
+
+clc;
+
+//Given:
+mh=1.007825;
+mt=3.016049;
+md=2.014102;
+
+//solution:
+
+m1=(mh+mt-2*md);
+e=(-m1)*931; // in MeV
+printf("\n The energy loss in MeV is = %f ",e)
diff --git a/2939/CH1/EX1.19/Ex1_19.sce b/2939/CH1/EX1.19/Ex1_19.sce
new file mode 100755
index 000000000..32ca6b7a0
--- /dev/null
+++ b/2939/CH1/EX1.19/Ex1_19.sce
@@ -0,0 +1,24 @@
+
+//Ex1_19
+
+clc;
+
+//Given:
+mh=1.007825;
+mn=1.008665;
+mt=3.016049; // atomic mass of Tritium
+mNi=59.93528; // atomic mass of Nickel
+
+//solution:
+
+// part (a)
+
+B1=(1*mh+2*mn-mt)*931; // in MeV
+Bh=B1/mt;
+printf("\n The mean binding energy of tritium atom in MeV is = %f ",Bh)
+
+// part (b)
+
+B2=(28*mh+32*mn-mNi)*931; // in MeV
+Bo=B2/mNi;
+printf("\n The mean binding energy of nickel atom in MeV is = %f ",Bo)
diff --git a/2939/CH1/EX1.2/Ex1_2.sce b/2939/CH1/EX1.2/Ex1_2.sce
new file mode 100755
index 000000000..692c4b47d
--- /dev/null
+++ b/2939/CH1/EX1.2/Ex1_2.sce
@@ -0,0 +1,9 @@
+//Ex1_2
+
+clc;
+//Given:
+energy=2*10^-6;
+c=2.5*10^-8;// velocity of light
+//solution:
+v=energy/c;// potential
+printf("The potential in V is = %f ",v)
diff --git a/2939/CH1/EX1.20/Ex1_20.sce b/2939/CH1/EX1.20/Ex1_20.sce
new file mode 100755
index 000000000..3934af230
--- /dev/null
+++ b/2939/CH1/EX1.20/Ex1_20.sce
@@ -0,0 +1,26 @@
+
+
+//Ex1_20
+
+clc;
+
+//Given:
+mh=1.00783;
+mn=1.00867;
+m35=34.96885; // atomic mass of Cl (35)
+m37=36.96590; // atomic mass of Cl (37)
+
+//solution:
+
+B1=(17*mh+18*mn-m35)*931; // in MeV
+Bh=B1/m35;
+printf("\n The mean binding energy of Cl (35) atom in MeV is = %f ",Bh)
+
+B2=(17*mh+20*mn-m37)*931; // in MeV
+Bo=B2/m37;
+printf("\n The mean binding energy of Cl (37) atom in MeV is = %f ",Bo)
+
+Bi=Bo-Bh;
+printf("\n The increase in mean binding energy of Cl atom in MeV is = %f ",Bi)
+
+// NOTE: The answer depends upon how much precise value you take for atomic masses.
diff --git a/2939/CH1/EX1.21/Ex1_21.sce b/2939/CH1/EX1.21/Ex1_21.sce
new file mode 100755
index 000000000..efbf44714
--- /dev/null
+++ b/2939/CH1/EX1.21/Ex1_21.sce
@@ -0,0 +1,31 @@
+
+//EX1_21
+
+clc;
+
+//Given:
+mh=1.0078;
+mn=1.0087;
+m22=21.99431;// atomic mass of Na 22
+m23=22.9898;// atomic mass of Na 23
+m24=23.9909;// atomic mass of Na 24
+
+//solution:
+
+// part (a)
+
+B1=((11*mh+11*mn)-m22)*931; // in MeV
+Bh=B1/m22;
+printf("\n The mean binding energy of Na(22) in MeV is = %f ",Bh)
+
+// part (b)
+
+B2=((11*mh+12*mn)-m23)*931; // in MeV
+Bo=B2/m23;
+printf("\n The mean binding energy of Na(23)in MeV is = %f ",Bo)
+
+// part (c)
+
+B3=((11*mh+13*mn)-m24)*931; // in MeV
+Bs=B3/m24;
+printf("\n The mean binding energy of Na(24) in MeV is = %f ",Bs)
diff --git a/2939/CH1/EX1.3/Ex1_3.sce b/2939/CH1/EX1.3/Ex1_3.sce
new file mode 100755
index 000000000..1148e33e3
--- /dev/null
+++ b/2939/CH1/EX1.3/Ex1_3.sce
@@ -0,0 +1,23 @@
+//Ex1_3
+
+clc;
+//Given:
+
+energy=10; //in electron volts
+m=9.1*10^-31;// mass of electron in kg
+h=6.626*10^-34;// planck's constant J.s
+c=3*10^8;// speed of light in m/s
+
+//solution (a):
+energy1=energy*1.6*10^-19;// energy in J
+p=(2*m*energy1)^0.5;// momentum
+wavelength=h/p*(10)^10;
+
+printf("The wavelength in Angstroms is = %f ",wavelength)
+
+
+//solution (b):
+wavelength1=h*c/energy1*(10)^10;//photon wavelength
+
+printf("\n The photon wavelength in Angstroms is = %f ",wavelength1)
+
diff --git a/2939/CH1/EX1.4/Ex1_4.sce b/2939/CH1/EX1.4/Ex1_4.sce
new file mode 100755
index 000000000..fe89ed4b1
--- /dev/null
+++ b/2939/CH1/EX1.4/Ex1_4.sce
@@ -0,0 +1,19 @@
+//Ex1_4
+
+clc;
+
+//Given:
+
+wavelength=10^-10;
+m=9.1*10^-31;
+h=6.626*10^-34;
+
+//solution:
+
+p=h/wavelength;
+e=p*p/(2*m); // energy in J
+e1=e/(1.6*10^-19);// energy in eV
+
+printf("The energy in eV is = %f ",e1)
+
+
diff --git a/2939/CH1/EX1.5/Ex1_5.sce b/2939/CH1/EX1.5/Ex1_5.sce
new file mode 100755
index 000000000..64828d812
--- /dev/null
+++ b/2939/CH1/EX1.5/Ex1_5.sce
@@ -0,0 +1,26 @@
+//Ex1_5
+
+clc;
+
+//Given:
+
+m=1.66*10^-27;// 1u=1.66*10^-27 kg
+h=6.6262*10^-34;//planck's constant in J.s
+energy1=120;// in Mev for oxygen
+energy2=140;// in MeV for nitrogen
+
+//solution(a):
+
+p=(2*m*16*energy1*(1.6022*10^-13))^0.5;
+wavelength1=h/p*(10)^15;//wavelength in 10^-5 Angstroms
+
+printf("\n The wavelength in 10^-5 Angstroms is = %f ",wavelength1)
+
+//solution (b):
+
+p=(2*m*14*energy2*(1.6022*10^-13))^0.5;
+wavelength2=h/p*(10)^15;//wavelength in 10^-5 Angstroms
+
+printf("\n The wavelength in 10^-5 Angstroms is = %f ",wavelength2)
+
+// 1 Angstrom = 10^-10 m
diff --git a/2939/CH1/EX1.6/Ex1_6.sce b/2939/CH1/EX1.6/Ex1_6.sce
new file mode 100755
index 000000000..2044888ce
--- /dev/null
+++ b/2939/CH1/EX1.6/Ex1_6.sce
@@ -0,0 +1,16 @@
+//Ex1_6
+
+clc;
+
+//Given:
+
+wavelength=1.5*10^-10;
+h=6.62*10^-34;
+c=3*10^8;
+
+//solution:
+
+e=(h*c)/wavelength;// energy in J
+e1=e/(1.6*10^-19);// energy in eV
+
+printf("The energy in eV is = %f ",e1)
diff --git a/2939/CH1/EX1.7/Ex1_7.sce b/2939/CH1/EX1.7/Ex1_7.sce
new file mode 100755
index 000000000..5385e245f
--- /dev/null
+++ b/2939/CH1/EX1.7/Ex1_7.sce
@@ -0,0 +1,25 @@
+//Ex1_7
+
+clc;
+
+//Given:
+
+E=5.12*1.6*10^-19// energy in J
+h=6.626*10^-34;
+c=3*10^8;
+wavelength=200*10^-9;
+w=2.3;// in eV
+
+//solution:
+
+tf=E/h;// (part a)
+printf("\n The threshold frequency in s^-1 is = %f ",tf)
+
+tl=c/tf*10^10;// (part b)
+printf("\n The threshold wavelength in Angstroms is = %f ",tl)
+
+e=(h*c)/(wavelength*1.6*10^-19)// photon energy in eV (part c)
+
+pe=e-w;
+
+printf("\n The energy of photoelectrone in eV is = %f ",pe)
diff --git a/2939/CH1/EX1.8/Ex1_8.sce b/2939/CH1/EX1.8/Ex1_8.sce
new file mode 100755
index 000000000..f21b9ee28
--- /dev/null
+++ b/2939/CH1/EX1.8/Ex1_8.sce
@@ -0,0 +1,41 @@
+//Ex1_8
+
+clc;
+
+//Given:
+e1=1; // in MeV
+e2=2; // in MeV
+ma=4; // in u(amu)
+md=2; // in u(amu)
+mp=1; // in u(amu)
+
+// 1u = 1.6*10^-27 Kg
+
+//solution: part a)For alpha particles
+
+v1a=((2*e1*10^6*1.6*10^-19)/(ma*1.6605*10^-27))^.5;
+printf("\n The velocity of alpha particles for 1 MeV in m/s is = %f ",v1a)// For 1 MeV
+
+v2a=((2*e2*10^6*1.6*10^-19)/(ma*1.6605*10^-27))^.5;
+printf("\n The velocity of alpha particles for 2 MeV in m/s is = %f ",v2a)// For 2 MeV
+
+//solution: part b)For deuteron particles
+
+v1b=((2*e1*10^6*1.6*10^-19)/(md*1.6605*10^-27))^.5;
+printf("\n The velocity of deuteron particles for 1 MeV in m/s is = %f ",v1b) // For 1 MeV
+
+
+v2b=((2*e2*10^6*1.6*10^-19)/(md*1.6605*10^-27))^.5;
+printf("\n The velocity of deuteron particles for 2 MeV in m/s is = %f ",v2b) // For 2 MeV
+
+//solution: part c)For proton particles
+
+v1p=((2*e1*10^6*1.6*10^-19)/(mp*1.6605*10^-27))^.5;
+printf("\n The velocity of proton particles for 1 MeV in m/s is = %f ",v1p) // For 1 MeV
+
+
+v2p=((2*e2*10^6*1.6*10^-19)/(mp*1.6605*10^-27))^.5;
+printf("\n The velocity of proton particles for 2 MeV in m/s is = %f ",v2p) // For 2 MeV
+
+
+
diff --git a/2939/CH1/EX1.9/Ex1_9.sce b/2939/CH1/EX1.9/Ex1_9.sce
new file mode 100755
index 000000000..9dfbc191c
--- /dev/null
+++ b/2939/CH1/EX1.9/Ex1_9.sce
@@ -0,0 +1,16 @@
+
+//Ex1_9
+
+clc;
+
+//Given:
+
+m=1/(6.023*10^23);//mass of 1 atom in g
+m1=m*10^-3;//mass of 1 atom in Kg
+c=3*10^8;// velocity in m/s
+//solution:
+
+e=m1*c*c; // energy in J
+e1=e/(1.6*10^-13);// energy in MeV
+
+printf("The energy in MeV is = %f ",e1)
generated by cgit (git 2.34.1) at 2024-12-20 11:44:54 +0000