initial commit / add all books

21 files changed, 440 insertions, 0 deletions

diff --git a/2939/CH1/EX1.1/Ex1_1.sce b/2939/CH1/EX1.1/Ex1_1.sce
new file mode 100755
index 000000000..d809b9bb6
--- /dev/null
+++ b/2939/CH1/EX1.1/Ex1_1.sce
@@ -0,0 +1,15 @@
+//Ex1_1

+

+clc;

+//Given:

+v=1000;// potential

+d=0.05;// distance

+q=3.8*10^-9;// charge

+

+//solution:

+e=v/d;//electric field

+f=e;// force

+f1=f*q;// force on metal sphere

+printf("\n The electric field in V/m is = %f ",e)

+printf("\n The force in N/C is = %f ",f)

+printf("\n The force on metal sphere in N is = %f ",f1)

diff --git a/2939/CH1/EX1.10/Ex1_10.sce b/2939/CH1/EX1.10/Ex1_10.sce
new file mode 100755
index 000000000..ef127ae18
--- /dev/null
+++ b/2939/CH1/EX1.10/Ex1_10.sce
@@ -0,0 +1,14 @@
+

+//Ex1_10

+

+clc;

+

+//Given:

+

+enthalpy=1278; // enthalpy of combustion in kJ/mol

+

+//solution:

+

+energy=(enthalpy*1000)/(6.022*10^23*1.6*10^-19);

+

+printf("The energy in eV is = %f ",energy)

diff --git a/2939/CH1/EX1.11/Ex1_11.sce b/2939/CH1/EX1.11/Ex1_11.sce
new file mode 100755
index 000000000..fc5f3418f
--- /dev/null
+++ b/2939/CH1/EX1.11/Ex1_11.sce
@@ -0,0 +1,25 @@
+//Ex1_11

+

+clc;

+

+//Given:

+mh=1.0078;

+mn=1.0087;

+ma=4.0026;

+mo=15.9949;

+Ah=4.0026; // atomic mass of helium

+Ao=15.9949; // atomic mass of oxygen

+

+//solution:

+

+// part (a)

+

+B1=(2*mh+2*mn-ma)*931; // in MeV

+Bh=B1/Ah;

+printf("\n The mean binding energy of helium atom in MeV is = %f ",Bh)

+

+// part (b)

+

+B2=(8*mh+8*mn-mo)*931; // in MeV

+Bo=B2/Ao;

+printf("\n The mean binding energy of oxygen atom in MeV is = %f ",Bo)

diff --git a/2939/CH1/EX1.12/Ex1_12.sce b/2939/CH1/EX1.12/Ex1_12.sce
new file mode 100755
index 000000000..5f0b5068d
--- /dev/null
+++ b/2939/CH1/EX1.12/Ex1_12.sce
@@ -0,0 +1,17 @@
+

+//Ex1_12

+

+clc;

+

+//Given:

+mh=1.0078;

+mn=1.0087;

+ABe=8.0053; // atomic mass of beryllium

+

+//solution:

+

+B1=(4*mh+4*mn-ABe)*931; // in MeV

+Bh=B1/ABe;

+printf("\n The mean binding energy of Be atom in MeV is = %f ",Bh)

+

+disp("From previous problem we have the avg. binding energy of helium atom is        7.08 MeV, Hence Be is unstable to fission into 2 alphas")

diff --git a/2939/CH1/EX1.13/Ex1_13.sce b/2939/CH1/EX1.13/Ex1_13.sce
new file mode 100755
index 000000000..f21faa004
--- /dev/null
+++ b/2939/CH1/EX1.13/Ex1_13.sce
@@ -0,0 +1,20 @@
+

+//Ex1_13

+

+clc;

+

+//Given:

+

+e=200; // in Mev

+m=0.235; // weight of uranium atom in Kg

+enthalpy=393.5; // in KJ/mol

+Na=6.02*10^23;

+

+

+//solution:

+e1=e*1.6*10^-19*10^6;

+atoms=Na/m;

+e2=atoms*e1;//energy released in J

+m1=(e2*12)/(393.5*1000*1000);// in Kg

+m2=m1/1000;// in tons

+printf("\n The amount of coal required in Kg is = %f", m2)

diff --git a/2939/CH1/EX1.14/Ex1_14.sce b/2939/CH1/EX1.14/Ex1_14.sce
new file mode 100755
index 000000000..053af1d33
--- /dev/null
+++ b/2939/CH1/EX1.14/Ex1_14.sce
@@ -0,0 +1,18 @@
+

+//Ex1_14

+

+clc;

+

+//Given:

+H1=241.8; // in KJ/mol

+H2=887.2; // in KJ/mol

+// 1 KJ/mol = 0.0104 eV/atom

+

+//solution: part (a)

+e1=H1*0.0104;

+printf("\n The energy release in part (a) in eV/molecule is = %f ",e1)

+

+//solution: part (b)

+e2=H2*0.0104;

+printf("\n The energy release in part (b) in eV/molecule is = %f ",e2)

+

diff --git a/2939/CH1/EX1.15/Ex1_15.sce b/2939/CH1/EX1.15/Ex1_15.sce
new file mode 100755
index 000000000..e7d30bc57
--- /dev/null
+++ b/2939/CH1/EX1.15/Ex1_15.sce
@@ -0,0 +1,23 @@
+

+//Ex1_15

+

+clc;

+

+//Given:

+H1=4.1; // in eV/molecule

+H2=17.4; // in eV/molecule

+H3=200;// in MeV/atom of U

+

+// 1 eV/atom  = 96.32 KJ/mol

+

+//solution: part (a)

+e1=H1*96.32;

+printf("\n The energy release in part (a) in KJ/mol of carbondioxide is = %f ",e1)

+

+//solution: part (b)

+e2=H2*96.32;

+printf("\n The energy release in part (b) in KJ/mol of alumina is = %f ",e2)

+

+//solution: part (c)

+e3=H3*1000*96.32;// in MJ/atom of U(235)

+printf("\n The energy release in part (c) in MJ/atom of U(235) is = %f ",e3)

diff --git a/2939/CH1/EX1.16/Ex1_16.sce b/2939/CH1/EX1.16/Ex1_16.sce
new file mode 100755
index 000000000..5bfb49797
--- /dev/null
+++ b/2939/CH1/EX1.16/Ex1_16.sce
@@ -0,0 +1,22 @@
+

+//Ex1_16

+

+clc;

+

+//Given:

+e=200; //MeV/ atom of U

+// 1 eV = 1.6*10^-19 J

+Na=6.023*10^23;

+M=0.235; // mass in Kg

+

+//solution:

+

+e1=e*1.6*10^-19*10^6;

+A=Na/M;

+e2=A*e1; // energy released in MJ/day

+e3=e2/(24*3600);

+printf("\n The rate of energy release in W is %f ",e3)

+

+

+

+

diff --git a/2939/CH1/EX1.17/Ex1_17.sce b/2939/CH1/EX1.17/Ex1_17.sce
new file mode 100755
index 000000000..29f200abf
--- /dev/null
+++ b/2939/CH1/EX1.17/Ex1_17.sce
@@ -0,0 +1,15 @@
+//Ex1_17

+

+clc;

+

+//Given:

+e=26.03; // in MeV

+

+//solution:

+

+loss=e/931; //in atomic mass units (u)

+// 1 u = 1.66*10^-27 Kg

+m=(loss*1.66*10^-27)/(1*10^-27);

+printf("\n The mass loss in 10^-27 Kg/He formed is = %f ",m)

+

+

diff --git a/2939/CH1/EX1.18/Ex1_18.sce b/2939/CH1/EX1.18/Ex1_18.sce
new file mode 100755
index 000000000..89cc0e1dd
--- /dev/null
+++ b/2939/CH1/EX1.18/Ex1_18.sce
@@ -0,0 +1,15 @@
+

+//Ex1_18

+

+clc;

+

+//Given:

+mh=1.007825;

+mt=3.016049;

+md=2.014102;

+

+//solution:

+

+m1=(mh+mt-2*md);

+e=(-m1)*931; // in MeV

+printf("\n The energy loss in MeV is = %f ",e)

diff --git a/2939/CH1/EX1.19/Ex1_19.sce b/2939/CH1/EX1.19/Ex1_19.sce
new file mode 100755
index 000000000..32ca6b7a0
--- /dev/null
+++ b/2939/CH1/EX1.19/Ex1_19.sce
@@ -0,0 +1,24 @@
+

+//Ex1_19

+

+clc;

+

+//Given:

+mh=1.007825;

+mn=1.008665;

+mt=3.016049; // atomic mass of Tritium

+mNi=59.93528; // atomic mass of Nickel

+

+//solution:

+

+// part (a)

+

+B1=(1*mh+2*mn-mt)*931; // in MeV

+Bh=B1/mt;

+printf("\n The mean binding energy of tritium atom in MeV is = %f ",Bh)

+

+// part (b)

+

+B2=(28*mh+32*mn-mNi)*931; // in MeV

+Bo=B2/mNi;

+printf("\n The mean binding energy of nickel atom in MeV is = %f ",Bo)

diff --git a/2939/CH1/EX1.2/Ex1_2.sce b/2939/CH1/EX1.2/Ex1_2.sce
new file mode 100755
index 000000000..692c4b47d
--- /dev/null
+++ b/2939/CH1/EX1.2/Ex1_2.sce
@@ -0,0 +1,9 @@
+//Ex1_2

+

+clc;

+//Given:

+energy=2*10^-6;

+c=2.5*10^-8;// velocity of light

+//solution:

+v=energy/c;// potential

+printf("The potential in V is = %f ",v)

diff --git a/2939/CH1/EX1.20/Ex1_20.sce b/2939/CH1/EX1.20/Ex1_20.sce
new file mode 100755
index 000000000..3934af230
--- /dev/null
+++ b/2939/CH1/EX1.20/Ex1_20.sce
@@ -0,0 +1,26 @@
+

+

+//Ex1_20

+

+clc;

+

+//Given:

+mh=1.00783;

+mn=1.00867;

+m35=34.96885; // atomic mass of Cl (35)

+m37=36.96590; // atomic mass of Cl (37)

+

+//solution:

+

+B1=(17*mh+18*mn-m35)*931; // in MeV

+Bh=B1/m35;

+printf("\n The mean binding energy of Cl (35) atom in MeV is = %f ",Bh)

+

+B2=(17*mh+20*mn-m37)*931; // in MeV

+Bo=B2/m37;

+printf("\n The mean binding energy of Cl (37) atom in MeV is = %f ",Bo)

+

+Bi=Bo-Bh;

+printf("\n The increase in mean binding energy of Cl atom in MeV is = %f ",Bi)

+

+// NOTE: The answer depends upon how much precise value you take for atomic masses.

diff --git a/2939/CH1/EX1.21/Ex1_21.sce b/2939/CH1/EX1.21/Ex1_21.sce
new file mode 100755
index 000000000..efbf44714
--- /dev/null
+++ b/2939/CH1/EX1.21/Ex1_21.sce
@@ -0,0 +1,31 @@
+

+//EX1_21

+

+clc;

+

+//Given:

+mh=1.0078;

+mn=1.0087;

+m22=21.99431;// atomic mass of Na 22

+m23=22.9898;// atomic mass of Na 23

+m24=23.9909;// atomic mass of Na 24

+

+//solution:

+

+// part (a)

+

+B1=((11*mh+11*mn)-m22)*931; // in MeV

+Bh=B1/m22;

+printf("\n The mean binding energy of Na(22) in MeV is = %f ",Bh)

+

+// part (b)

+

+B2=((11*mh+12*mn)-m23)*931; // in MeV

+Bo=B2/m23;

+printf("\n The mean binding energy of Na(23)in MeV is = %f ",Bo)

+

+// part (c)

+

+B3=((11*mh+13*mn)-m24)*931; // in MeV

+Bs=B3/m24;

+printf("\n The mean binding energy of Na(24) in MeV is = %f ",Bs)

diff --git a/2939/CH1/EX1.3/Ex1_3.sce b/2939/CH1/EX1.3/Ex1_3.sce
new file mode 100755
index 000000000..1148e33e3
--- /dev/null
+++ b/2939/CH1/EX1.3/Ex1_3.sce
@@ -0,0 +1,23 @@
+//Ex1_3

+

+clc;

+//Given:

+

+energy=10; //in electron volts

+m=9.1*10^-31;// mass of electron in kg

+h=6.626*10^-34;// planck's constant J.s

+c=3*10^8;// speed of light in m/s

+

+//solution (a):

+energy1=energy*1.6*10^-19;// energy in J

+p=(2*m*energy1)^0.5;// momentum

+wavelength=h/p*(10)^10;

+

+printf("The wavelength in Angstroms is = %f ",wavelength)

+

+

+//solution (b):

+wavelength1=h*c/energy1*(10)^10;//photon wavelength

+

+printf("\n The photon wavelength in Angstroms is = %f ",wavelength1)

+

diff --git a/2939/CH1/EX1.4/Ex1_4.sce b/2939/CH1/EX1.4/Ex1_4.sce
new file mode 100755
index 000000000..fe89ed4b1
--- /dev/null
+++ b/2939/CH1/EX1.4/Ex1_4.sce
@@ -0,0 +1,19 @@
+//Ex1_4

+

+clc;

+

+//Given:

+

+wavelength=10^-10;

+m=9.1*10^-31;

+h=6.626*10^-34;

+

+//solution:

+

+p=h/wavelength;

+e=p*p/(2*m); // energy in J

+e1=e/(1.6*10^-19);// energy in eV

+

+printf("The energy in eV is = %f ",e1)

+

+

diff --git a/2939/CH1/EX1.5/Ex1_5.sce b/2939/CH1/EX1.5/Ex1_5.sce
new file mode 100755
index 000000000..64828d812
--- /dev/null
+++ b/2939/CH1/EX1.5/Ex1_5.sce
@@ -0,0 +1,26 @@
+//Ex1_5

+

+clc;

+

+//Given:

+

+m=1.66*10^-27;// 1u=1.66*10^-27 kg

+h=6.6262*10^-34;//planck's constant in J.s

+energy1=120;// in Mev for oxygen

+energy2=140;// in MeV for nitrogen

+

+//solution(a):

+

+p=(2*m*16*energy1*(1.6022*10^-13))^0.5;

+wavelength1=h/p*(10)^15;//wavelength in 10^-5 Angstroms

+

+printf("\n The wavelength in 10^-5 Angstroms is = %f ",wavelength1)

+

+//solution (b):

+

+p=(2*m*14*energy2*(1.6022*10^-13))^0.5;

+wavelength2=h/p*(10)^15;//wavelength in 10^-5 Angstroms

+

+printf("\n The wavelength in 10^-5 Angstroms is = %f ",wavelength2)

+

+// 1 Angstrom = 10^-10 m

diff --git a/2939/CH1/EX1.6/Ex1_6.sce b/2939/CH1/EX1.6/Ex1_6.sce
new file mode 100755
index 000000000..2044888ce
--- /dev/null
+++ b/2939/CH1/EX1.6/Ex1_6.sce
@@ -0,0 +1,16 @@
+//Ex1_6

+

+clc;

+

+//Given:

+

+wavelength=1.5*10^-10;

+h=6.62*10^-34;

+c=3*10^8;

+

+//solution:

+

+e=(h*c)/wavelength;// energy in J

+e1=e/(1.6*10^-19);// energy in eV

+

+printf("The energy in eV is = %f ",e1)

diff --git a/2939/CH1/EX1.7/Ex1_7.sce b/2939/CH1/EX1.7/Ex1_7.sce
new file mode 100755
index 000000000..5385e245f
--- /dev/null
+++ b/2939/CH1/EX1.7/Ex1_7.sce
@@ -0,0 +1,25 @@
+//Ex1_7

+

+clc;

+

+//Given:

+

+E=5.12*1.6*10^-19// energy in J

+h=6.626*10^-34;

+c=3*10^8;

+wavelength=200*10^-9;

+w=2.3;// in eV

+

+//solution:

+

+tf=E/h;// (part a)

+printf("\n The threshold frequency in s^-1 is = %f ",tf)

+

+tl=c/tf*10^10;// (part b)

+printf("\n The threshold wavelength in Angstroms is = %f ",tl)

+

+e=(h*c)/(wavelength*1.6*10^-19)// photon energy in eV (part c)

+

+pe=e-w;

+

+printf("\n The energy of photoelectrone in eV is = %f ",pe)

diff --git a/2939/CH1/EX1.8/Ex1_8.sce b/2939/CH1/EX1.8/Ex1_8.sce
new file mode 100755
index 000000000..f21b9ee28
--- /dev/null
+++ b/2939/CH1/EX1.8/Ex1_8.sce
@@ -0,0 +1,41 @@
+//Ex1_8

+

+clc;

+

+//Given:

+e1=1; // in MeV

+e2=2; // in MeV

+ma=4; // in u(amu)

+md=2; // in u(amu)

+mp=1; // in u(amu)

+

+// 1u = 1.6*10^-27 Kg

+

+//solution: part a)For alpha particles

+

+v1a=((2*e1*10^6*1.6*10^-19)/(ma*1.6605*10^-27))^.5;

+printf("\n The velocity of alpha particles for 1 MeV in m/s is = %f ",v1a)// For 1 MeV

+

+v2a=((2*e2*10^6*1.6*10^-19)/(ma*1.6605*10^-27))^.5;

+printf("\n The velocity of alpha particles for 2 MeV in m/s is = %f ",v2a)// For 2 MeV

+

+//solution: part b)For deuteron particles

+

+v1b=((2*e1*10^6*1.6*10^-19)/(md*1.6605*10^-27))^.5;

+printf("\n The velocity of deuteron particles for 1 MeV in m/s is = %f ",v1b) // For 1 MeV

+

+

+v2b=((2*e2*10^6*1.6*10^-19)/(md*1.6605*10^-27))^.5;

+printf("\n The velocity of deuteron particles for 2 MeV in m/s is = %f ",v2b) // For 2 MeV

+

+//solution: part c)For proton particles

+

+v1p=((2*e1*10^6*1.6*10^-19)/(mp*1.6605*10^-27))^.5;

+printf("\n The velocity of proton particles for 1 MeV in m/s is = %f ",v1p) // For 1 MeV

+

+

+v2p=((2*e2*10^6*1.6*10^-19)/(mp*1.6605*10^-27))^.5;

+printf("\n The velocity of proton particles for 2 MeV in m/s is = %f ",v2p) // For 2 MeV

+

+

+

diff --git a/2939/CH1/EX1.9/Ex1_9.sce b/2939/CH1/EX1.9/Ex1_9.sce
new file mode 100755
index 000000000..9dfbc191c
--- /dev/null
+++ b/2939/CH1/EX1.9/Ex1_9.sce
@@ -0,0 +1,16 @@
+

+//Ex1_9

+

+clc;

+

+//Given:

+

+m=1/(6.023*10^23);//mass of 1 atom in g

+m1=m*10^-3;//mass of 1 atom in Kg

+c=3*10^8;// velocity in m/s

+//solution:

+

+e=m1*c*c; // energy in J

+e1=e/(1.6*10^-13);// energy in MeV

+

+printf("The energy in MeV is = %f ",e1)