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+
+//EX1_21
+
+clc;
+
+//Given:
+mh=1.0078;
+mn=1.0087;
+m22=21.99431;// atomic mass of Na 22
+m23=22.9898;// atomic mass of Na 23
+m24=23.9909;// atomic mass of Na 24
+
+//solution:
+
+// part (a)
+
+B1=((11*mh+11*mn)-m22)*931; // in MeV
+Bh=B1/m22;
+printf("\n The mean binding energy of Na(22) in MeV is = %f ",Bh)
+
+// part (b)
+
+B2=((11*mh+12*mn)-m23)*931; // in MeV
+Bo=B2/m23;
+printf("\n The mean binding energy of Na(23)in MeV is = %f ",Bo)
+
+// part (c)
+
+B3=((11*mh+13*mn)-m24)*931; // in MeV
+Bs=B3/m24;
+printf("\n The mean binding energy of Na(24) in MeV is = %f ",Bs)