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//Ex1_8
clc;
//Given:
e1=1; // in MeV
e2=2; // in MeV
ma=4; // in u(amu)
md=2; // in u(amu)
mp=1; // in u(amu)
// 1u = 1.6*10^-27 Kg
//solution: part a)For alpha particles
v1a=((2*e1*10^6*1.6*10^-19)/(ma*1.6605*10^-27))^.5;
printf("\n The velocity of alpha particles for 1 MeV in m/s is = %f ",v1a)// For 1 MeV
v2a=((2*e2*10^6*1.6*10^-19)/(ma*1.6605*10^-27))^.5;
printf("\n The velocity of alpha particles for 2 MeV in m/s is = %f ",v2a)// For 2 MeV
//solution: part b)For deuteron particles
v1b=((2*e1*10^6*1.6*10^-19)/(md*1.6605*10^-27))^.5;
printf("\n The velocity of deuteron particles for 1 MeV in m/s is = %f ",v1b) // For 1 MeV
v2b=((2*e2*10^6*1.6*10^-19)/(md*1.6605*10^-27))^.5;
printf("\n The velocity of deuteron particles for 2 MeV in m/s is = %f ",v2b) // For 2 MeV
//solution: part c)For proton particles
v1p=((2*e1*10^6*1.6*10^-19)/(mp*1.6605*10^-27))^.5;
printf("\n The velocity of proton particles for 1 MeV in m/s is = %f ",v1p) // For 1 MeV
v2p=((2*e2*10^6*1.6*10^-19)/(mp*1.6605*10^-27))^.5;
printf("\n The velocity of proton particles for 2 MeV in m/s is = %f ",v2p) // For 2 MeV
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