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authorprashantsinalkar2017-10-10 12:27:19 +0530
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+///Chapter No 11 Steam Boilers
+////Example 11.4 Page No 231
+///Find Enthalpy of superheated steam
+//Input data
+clc;
+clear;
+mf=500; //Boiler plant consumes of coal in Kg/h
+CV=32000; //Calorific value in Kj/Kg
+ms=3200; //plant generates in Kg/h
+P=1.2; //Absolute pressure MN/m^2
+MN=12;
+Tsup=300; //Absolute temperature in degree celsius
+Tw=35; //Feed water temperature
+Cps=2.3;
+
+//Calculation
+hfw=146.56; //In KJ/Kg
+Ts=187.96; //In Degree celsius
+hf=798.43; //In KJ/Kg
+hfg=1984.3; //In KJ/Kg
+hg=2782.7; //In KJ/Kg
+hs=hg+Cps*(Tsup-Ts); //Enthalpy of superheated steam in KJ/Kg
+me=ms/mf; //mass of evaporation
+E=((me*(hs-hfw))/2257); //Equivalent evaporation in Kg/Kg ofcoal
+etaboiler=((me*(hs-hfw))/CV)*100; //Boiler efficiency in %
+
+
+///Output
+printf('Enthalpy of superheated steam= %f KJ/Kg\n',hs);
+printf('mass of evaporation=%f \n',me);
+printf('Equivalent evaporation=%f Kg/Kg of coal \n',E);
+printf('Boiler efficiency %f percent \n ',etaboiler);
+