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///Chapter No 11 Steam Boilers
////Example 11.4 Page No 231
///Find Enthalpy of superheated steam
//Input data
clc;
clear;
mf=500; //Boiler plant consumes of coal in Kg/h
CV=32000; //Calorific value in Kj/Kg
ms=3200; //plant generates in Kg/h
P=1.2; //Absolute pressure MN/m^2
MN=12;
Tsup=300; //Absolute temperature in degree celsius
Tw=35; //Feed water temperature
Cps=2.3;
//Calculation
hfw=146.56; //In KJ/Kg
Ts=187.96; //In Degree celsius
hf=798.43; //In KJ/Kg
hfg=1984.3; //In KJ/Kg
hg=2782.7; //In KJ/Kg
hs=hg+Cps*(Tsup-Ts); //Enthalpy of superheated steam in KJ/Kg
me=ms/mf; //mass of evaporation
E=((me*(hs-hfw))/2257); //Equivalent evaporation in Kg/Kg ofcoal
etaboiler=((me*(hs-hfw))/CV)*100; //Boiler efficiency in %
///Output
printf('Enthalpy of superheated steam= %f KJ/Kg\n',hs);
printf('mass of evaporation=%f \n',me);
printf('Equivalent evaporation=%f Kg/Kg of coal \n',E);
printf('Boiler efficiency %f percent \n ',etaboiler);
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