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+///Chapter No 11 Steam Boilers
+////Example 11.4 Page No 231
+///Find Enthalpy of superheated steam
+//Input data
+clc;
+clear;
+mf=500;                          //Boiler plant consumes of coal in Kg/h
+CV=32000;                        //Calorific value in Kj/Kg
+ms=3200;                         //plant generates in Kg/h
+P=1.2;                           //Absolute pressure MN/m^2
+MN=12;                           
+Tsup=300;                        //Absolute temperature in degree celsius
+Tw=35;                           //Feed water temperature
+Cps=2.3;
+
+//Calculation
+hfw=146.56;                      //In KJ/Kg
+Ts=187.96;                       //In Degree celsius
+hf=798.43;                       //In KJ/Kg
+hfg=1984.3;                      //In KJ/Kg
+hg=2782.7;                       //In KJ/Kg
+hs=hg+Cps*(Tsup-Ts);             //Enthalpy of superheated steam in KJ/Kg
+me=ms/mf;                        //mass of evaporation 
+E=((me*(hs-hfw))/2257);          //Equivalent evaporation in Kg/Kg ofcoal
+etaboiler=((me*(hs-hfw))/CV)*100; //Boiler efficiency in %
+  
+
+///Output
+printf('Enthalpy of superheated steam= %f KJ/Kg\n',hs);
+printf('mass of evaporation=%f \n',me);
+printf('Equivalent evaporation=%f Kg/Kg of coal \n',E);
+printf('Boiler efficiency %f percent \n ',etaboiler);
+