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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1628/CH4 | |
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initial commit / add all books
Diffstat (limited to '1628/CH4')
-rwxr-xr-x | 1628/CH4/EX4.1/Ex4_1.sce | 21 | ||||
-rwxr-xr-x | 1628/CH4/EX4.10/Ex4_10.sce | 29 | ||||
-rwxr-xr-x | 1628/CH4/EX4.11/Ex4_11.sce | 23 | ||||
-rwxr-xr-x | 1628/CH4/EX4.2/Ex4_2.sce | 34 | ||||
-rwxr-xr-x | 1628/CH4/EX4.3/Ex4_3.sce | 27 | ||||
-rwxr-xr-x | 1628/CH4/EX4.4/Ex4_4.sce | 23 | ||||
-rwxr-xr-x | 1628/CH4/EX4.5/Ex4_5.sce | 26 | ||||
-rwxr-xr-x | 1628/CH4/EX4.6/Ex4_6.sce | 23 | ||||
-rwxr-xr-x | 1628/CH4/EX4.7/Ex4_7.sce | 25 | ||||
-rwxr-xr-x | 1628/CH4/EX4.8/Ex4_8.sce | 16 | ||||
-rwxr-xr-x | 1628/CH4/EX4.9/Ex4_9.sce | 25 |
11 files changed, 272 insertions, 0 deletions
diff --git a/1628/CH4/EX4.1/Ex4_1.sce b/1628/CH4/EX4.1/Ex4_1.sce new file mode 100755 index 000000000..78a0055c2 --- /dev/null +++ b/1628/CH4/EX4.1/Ex4_1.sce @@ -0,0 +1,21 @@ + + // Examle 4.1 + + // Reffer the diagram (4.2a) + // Using Superpositon theorem + +I=-0.5; // Source current +I1=I*(0.3/(0.1+0.3)); // When 0.5-A Current source is on { by voltage divider } + +V=80*10^-3; // Voltage source +I2=(V/(0.1+0.3)); // When 80-mV voltage source is on { by ohm's law } + +i=I1+I2; // Current in the circuit { by Superpositon theorem } +disp(' Current in the circuit = '+string(i)+' Amp'); + + + + + + // p 105 4.1 + diff --git a/1628/CH4/EX4.10/Ex4_10.sce b/1628/CH4/EX4.10/Ex4_10.sce new file mode 100755 index 000000000..fbc0b8fa7 --- /dev/null +++ b/1628/CH4/EX4.10/Ex4_10.sce @@ -0,0 +1,29 @@ +
+ // Examle 4.10
+
+ // From Diagram 4.12
+
+P=25; // Power
+Rl=8; // Load resistance
+Vth=P*4*Rl; // Thevenin's equivalent voltage
+
+ // If Load is Short-ckt (RL=0)
+Vo=0; // Voltage
+IL=1; // load current
+Po1=Vo*IL; // O/p power
+
+ // If Load is Open-ckt ( RL=infinity )
+IL1=0; // Load current
+Vo1=1; // Voltage
+Po2=Vo1*IL1; // O/p power
+
+x=[0 2 4 6 8 16 32 ]; // Diffrent value of RL
+y=[0 16 22.22 24.49 25 22.22 16 ] // Value of Power
+
+plot2d(x,y); // To plot graph
+xlabel('RL (in Ohms )--->'); // For X-Label
+ylabel('Po (in W ---->') // For Y-Label
+
+
+
+ // View p 115 4.10
diff --git a/1628/CH4/EX4.11/Ex4_11.sce b/1628/CH4/EX4.11/Ex4_11.sce new file mode 100755 index 000000000..96b356d68 --- /dev/null +++ b/1628/CH4/EX4.11/Ex4_11.sce @@ -0,0 +1,23 @@ + + // Examle 4.11 + + // From the diagram (4.14) + +Req=2+{(12*4)/(12+4)}+4; // Equivalent resistance (for 4.14a ) +v=36; // Voltage source +i=v/Req; // Current supply by the voltage source +I=i*(12/(12+4)); // Current in branch B ==> { by current divider } +disp(' Current in branch B = '+string(I)+' Amp'); + +Req1=3+{(12*6)/(12+6)}+1; // Equivalent resistance (for 4.14b ) +i1=v/Req1; // Current supply by the voltage source +I1=i1*(12/(12+6)); // Current in branch A ==> { by current divider } +disp(' Current in branch A = '+string(I1)+' Amp'); + +Rtr=v/I; // Transfer resistance +disp(' Transfer resistance from Branch A to B = '+string(Rtr)+' Ohm'); + + + + // p 117 4.11 + diff --git a/1628/CH4/EX4.2/Ex4_2.sce b/1628/CH4/EX4.2/Ex4_2.sce new file mode 100755 index 000000000..800cdb97b --- /dev/null +++ b/1628/CH4/EX4.2/Ex4_2.sce @@ -0,0 +1,34 @@ + + + // Examle 4.2 + + // Reffer the diagram (4.3) + // Using Superpositon theorem + +V=10; // Voltage source +I1=(V/(50+150)); // When 10-V voltage source is on { by ohm's law } + +i1=40; // Source current +I2=i1*(150/(50+150)); // When 40-A Current source is on { by current divider } + +i2=-120; // Source current +I3=i2*(50/(50+150)); // When (-120)-A Current source is on { by current divider } + + +I=I1+I2+I3; // Current in the circuit { by Superpositon theorem } +disp(' Current in the circuit = '+string(I)+' Amp'); + + + + + + // p 106 4.2 + + + + + + + + + diff --git a/1628/CH4/EX4.3/Ex4_3.sce b/1628/CH4/EX4.3/Ex4_3.sce new file mode 100755 index 000000000..e616a9549 --- /dev/null +++ b/1628/CH4/EX4.3/Ex4_3.sce @@ -0,0 +1,27 @@ +
+
+ // Example 4.3
+
+ // From the diagram 4.5
+ // Using super position theorem
+ // 4-A current source is active
+
+i=4/{1+(2+3)}; // Current
+R=3; // Rsistance of 3 Ohms
+V4=i*R; // Voltage across 3 Ohms resistance in Case-1
+
+ // 5-A current source is active
+i5=5; // 5-A current source
+V5=(-i5)*{1/[1+(2+3)]*3}; // Voltage across 3 Ohms resistance in Case-2
+
+ // 6-V voltage source is active
+i6=6; // 6-A current source
+V6=i6*{3/[1+(2+3)]}; // Voltage across 3 Ohms resistance in Case-3
+
+V=V4+V5+V6; // Voltage across 3 Ohms resistance
+disp(' Voltage across 3 Ohms resistance is = '+string(V)+' Volt');
+
+
+
+
+ // p 106 4.3
\ No newline at end of file diff --git a/1628/CH4/EX4.4/Ex4_4.sce b/1628/CH4/EX4.4/Ex4_4.sce new file mode 100755 index 000000000..cf12bfb6c --- /dev/null +++ b/1628/CH4/EX4.4/Ex4_4.sce @@ -0,0 +1,23 @@ + + + // Examle 4.4 + + // From the diagram (4.6a) + // Using Superpositon theorem + +V=10; // Voltage source +I1=(V/(2+4+6)); // When 10-V voltage source is on { by ohm's law } + + // we have to find Is= ? + // When Is-A Current source is on + // will have { I2= -(2/3)Is } + // given that I1+I2= 0 + // there for 5/6 - (2/3)Is= 0 +Is=(5*3)/(6*2); // Source current +disp(' The value of source current (Is) = '+string(Is)+' Amp'); + + + + + + // p 108 4.4 diff --git a/1628/CH4/EX4.5/Ex4_5.sce b/1628/CH4/EX4.5/Ex4_5.sce new file mode 100755 index 000000000..4e36b7966 --- /dev/null +++ b/1628/CH4/EX4.5/Ex4_5.sce @@ -0,0 +1,26 @@ + + // Examle 4.5 + + // From the diagram (4.8) + // Using thevenin's equivalent theorem + +V1=50; // Voltage source V1 +V2=10; // Voltage source V2 +I1=(V1-V2)/(10+10+20); // Current through the ckt ( when Current source is off ) + +i=1.5; // Current source i +I2=i*(10/(10+(10+20))); // Current through the ckt ( when Current source is active ) +I=I1+I2; // Addition of I1 & I2 +Vth= I*20; // Thevenin's voltage at 20 Ohms R + +Rth=(20*(10+10))/(20+(10+10)); // Thevenin's resistance + +Vl=Vth*(5/(5+10)); // Voltage across Rl +disp(' Voltage across olad resistor (Rl) = '+string(Vl)+' Volt'); + + + + + + + // p 110 4.5 diff --git a/1628/CH4/EX4.6/Ex4_6.sce b/1628/CH4/EX4.6/Ex4_6.sce new file mode 100755 index 000000000..f5f2a4f15 --- /dev/null +++ b/1628/CH4/EX4.6/Ex4_6.sce @@ -0,0 +1,23 @@ + + // Examle 4.6 + + // From the diagram (3.24a) + // Using thevenin's equivalent theorem + +Vth=5; // Thevenin's voltage ==> { by Circuit reduction } + +Rth=3; // Thevenin's resistance ==> { by Circuit reduction } + +Vl=Vth*(3/(3+3)); // Voltage across Rl +disp(' Voltage across olad resistor (Rl) = '+string(Vl)+' Volt'); + + + + + + + // p 111 4.6 + + + + diff --git a/1628/CH4/EX4.7/Ex4_7.sce b/1628/CH4/EX4.7/Ex4_7.sce new file mode 100755 index 000000000..510ae012e --- /dev/null +++ b/1628/CH4/EX4.7/Ex4_7.sce @@ -0,0 +1,25 @@ + + // Examle 4.7 + + // From the diagram (4.11a) + + // Using Nortan's equivalent theorem + +R1=5; // Resistance R1 +R2=10; // Resistance R2 +V1=10; // Voltage source V1 +I1=V1/R1; // Current I1 + +V2=5; // Voltage source V2 +I2=V2/R2; // Current I2 +IN=I1+I2; // Nortan's current + +RN=(R1*R2)/(R1+R2); // Nortan's resistance + +Rl=5; // Load resistance +Il=IN*(RN/(RN+Rl)); // Load current +disp(' Load current (Il) = '+string(Il)+' Amp'); + + + + // p 113 4.7 diff --git a/1628/CH4/EX4.8/Ex4_8.sce b/1628/CH4/EX4.8/Ex4_8.sce new file mode 100755 index 000000000..67b9a7e6f --- /dev/null +++ b/1628/CH4/EX4.8/Ex4_8.sce @@ -0,0 +1,16 @@ + + // Examle 4.8 + +Voc=12.6; // Voltage of car battery +Isc=300; // Short-circuit current +Ro=Voc/Isc; // O/p resistance + + // { P=Vht^2/4Rth } , but here Vth= Voc & Rth= Ro +Pavl=Voc^2/(4*Ro); // Available power +disp(' Available power is = '+string(Pavl)+ ' Watt'); + + + + + + // p 114 4.8
\ No newline at end of file diff --git a/1628/CH4/EX4.9/Ex4_9.sce b/1628/CH4/EX4.9/Ex4_9.sce new file mode 100755 index 000000000..a82126c38 --- /dev/null +++ b/1628/CH4/EX4.9/Ex4_9.sce @@ -0,0 +1,25 @@ + + // Examle 4.9 + +n=8; // No.Of dry cells +E=1.5; // Emf of cell +Voc=n*E; // open-circuit Voltage of battery +r=0.75; // Internal resistance +Ro=r*n; // O/p resistance + + // ==> { P=Vht^2/4Rth } , but here Vth= Voc & Rth= Ro + +Pavl=Voc^2/(4*Ro); // Available power +disp(' Available power is = '+string(Pavl)+ ' Watt'); + + + + + + // p 115 4.9 + + + + + + |