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// Examle 4.5
// From the diagram (4.8)
// Using thevenin's equivalent theorem
V1=50; // Voltage source V1
V2=10; // Voltage source V2
I1=(V1-V2)/(10+10+20); // Current through the ckt ( when Current source is off )
i=1.5; // Current source i
I2=i*(10/(10+(10+20))); // Current through the ckt ( when Current source is active )
I=I1+I2; // Addition of I1 & I2
Vth= I*20; // Thevenin's voltage at 20 Ohms R
Rth=(20*(10+10))/(20+(10+10)); // Thevenin's resistance
Vl=Vth*(5/(5+10)); // Voltage across Rl
disp(' Voltage across olad resistor (Rl) = '+string(Vl)+' Volt');
// p 110 4.5
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