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+
+                             // Examle 4.5
+
+               // From the diagram (4.8)
+               // Using thevenin's equivalent theorem
+
+V1=50;                             // Voltage source V1
+V2=10;                             // Voltage source V2
+I1=(V1-V2)/(10+10+20);             // Current through the ckt ( when Current source is off )
+
+i=1.5;                            // Current source i
+I2=i*(10/(10+(10+20)));           // Current through the ckt ( when Current source is active )
+I=I1+I2;                          // Addition of I1 & I2
+Vth= I*20;                        // Thevenin's voltage at 20 Ohms R
+
+Rth=(20*(10+10))/(20+(10+10));    // Thevenin's resistance 
+
+Vl=Vth*(5/(5+10));                // Voltage across Rl
+disp(' Voltage across olad resistor (Rl) = '+string(Vl)+' Volt');
+
+
+
+
+
+
+                    // p 110         4.5