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//Chapter 5: Chemical Kinetics and Catalysis
//Problem: 6
clc;
//Declaration of Constants
R = 1.987 //in cal per K per mol
//Declaration of Variables
T1 = 273.0 //in K
T2 = 303.0 //in K
K1 = 2.45 * 10 ** -5
K2 = 162 * 10 ** -5
// Solution
Ea = log10(K2 / K1) * R * 2.303 / ((T2 - T1) / (T1 * T2))
mprintf("The activation energy of the reaction is %d cal / mol",Ea)
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