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+//Chapter 5: Chemical Kinetics and Catalysis
+//Problem: 6
+clc;
+
+//Declaration of Constants
+R = 1.987 //in cal per K per mol
+
+//Declaration of Variables
+T1 = 273.0 //in K
+T2 = 303.0 //in K
+K1 = 2.45 * 10 ** -5
+K2 = 162 * 10 ** -5
+
+// Solution
+Ea = log10(K2 / K1) * R * 2.303 / ((T2 - T1) / (T1 * T2))
+mprintf("The activation energy of the reaction is %d cal / mol",Ea)