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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3718/CH5/EX5.6/Ex5_6.sce | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '3718/CH5/EX5.6/Ex5_6.sce')
-rw-r--r-- | 3718/CH5/EX5.6/Ex5_6.sce | 16 |
1 files changed, 16 insertions, 0 deletions
diff --git a/3718/CH5/EX5.6/Ex5_6.sce b/3718/CH5/EX5.6/Ex5_6.sce new file mode 100644 index 000000000..4bd645e2f --- /dev/null +++ b/3718/CH5/EX5.6/Ex5_6.sce @@ -0,0 +1,16 @@ +//Chapter 5: Chemical Kinetics and Catalysis
+//Problem: 6
+clc;
+
+//Declaration of Constants
+R = 1.987 //in cal per K per mol
+
+//Declaration of Variables
+T1 = 273.0 //in K
+T2 = 303.0 //in K
+K1 = 2.45 * 10 ** -5
+K2 = 162 * 10 ** -5
+
+// Solution
+Ea = log10(K2 / K1) * R * 2.303 / ((T2 - T1) / (T1 * T2))
+mprintf("The activation energy of the reaction is %d cal / mol",Ea)
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