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//Example 5_16_u1
clc();
clear;
//To calculate the difference between the samples
d=0.2552 //units in nm
a=d*sqrt(2) //units in nm
lamda=0.152 //units in nm
theta=21 //units in degrees
//For sample A
d111=lamda/(2*sin(theta*%pi/180)) //units in nm
h=1
k=1
l=1
a1=d111*sqrt(h^2+k^2+l^2) //units in nm
printf("For sample A a=%.4f nm",a1)
//For sample B
theta=21.38 //units in degrees
d111=lamda/(2*sin(theta*%pi/180)) //units in nm
h=1
k=1
l=1
a2=d111*sqrt(h^2+k^2+l^2) //units in nm
change=((a1-a2)/a2)*100
printf("\nFor sample B a=%.4f nm",a2)
printf("\n Sample B is pure high purity copper as lattice parameter of A is %.2f percent greater than that of pure copper",change)
//Given in text book change in lattice parameter is 1.75% greater but it is 1.73%
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