1 files changed, 10 insertions, 8 deletions
diff --git a/3411/CH5/EX5.16.u1/Ex5_16_u1.sce b/3411/CH5/EX5.16.u1/Ex5_16_u1.sce
index 98483f50c..d0535a5fd 100644
--- a/3411/CH5/EX5.16.u1/Ex5_16_u1.sce
+++ b/3411/CH5/EX5.16.u1/Ex5_16_u1.sce
@@ -2,8 +2,8 @@
 clc();
 clear;
 //To calculate the difference between the samples
-d=0.2552
-a=d*sqrt(2)
+d=0.2552       //units in nm
+a=d*sqrt(2)       //units in nm
 lamda=0.152       //units in nm
 theta=21          //units in degrees
 //For sample A
@@ -11,14 +11,16 @@ d111=lamda/(2*sin(theta*%pi/180))      //units in nm
 h=1
 k=1
 l=1
-a=d111*sqrt(h^2+k^2+l^2)            //units in nm
-printf("For sample A a=%.4f nm",a)
+a1=d111*sqrt(h^2+k^2+l^2)            //units in nm
+printf("For sample A a=%.4f nm",a1)
 //For sample B
-theta=21.38
+theta=21.38          //units in degrees
 d111=lamda/(2*sin(theta*%pi/180))      //units in nm
 h=1
 k=1
 l=1
-a=d111*sqrt(h^2+k^2+l^2)            //units in nm
-printf("\nFor sample B a=%.4f nm",a)
-printf("\n Sample B is pure high purity copper as lattice parameter of A is 1.75percent greater than that of pure copper")
+a2=d111*sqrt(h^2+k^2+l^2)            //units in nm
+change=((a1-a2)/a2)*100
+printf("\nFor sample B a=%.4f nm",a2)
+printf("\n Sample B is pure high purity copper as lattice parameter of A is %.2f percent greater than that of pure copper",change)
+//Given in text book change in lattice parameter is 1.75% greater  but it is 1.73%