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// Ex9_8
clc;
// Given:
a1=0.015;
a2=0.04;
// Solution: Defining the seperation factor f as approximately equal to (a2/a1) where a1, a2 are the relative abundances of the isotope of interest in the initial and final fractions, we have
f=(a2/a1);
printf("The single stage seperation factor is = %f",f)
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