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Diffstat (limited to '2939/CH9/EX9.8/Ex9_8.sce')
| -rwxr-xr-x | 2939/CH9/EX9.8/Ex9_8.sce | 15 |
1 files changed, 15 insertions, 0 deletions
diff --git a/2939/CH9/EX9.8/Ex9_8.sce b/2939/CH9/EX9.8/Ex9_8.sce new file mode 100755 index 000000000..7e795086c --- /dev/null +++ b/2939/CH9/EX9.8/Ex9_8.sce @@ -0,0 +1,15 @@ +
+// Ex9_8
+
+clc;
+
+// Given:
+a1=0.015;
+a2=0.04;
+
+// Solution: Defining the seperation factor f as approximately equal to (a2/a1) where a1, a2 are the relative abundances of the isotope of interest in the initial and final fractions, we have
+
+f=(a2/a1);
+
+printf("The single stage seperation factor is = %f",f)
+
|