// Ex9_8

clc;

// Given:
a1=0.015;
a2=0.04;

// Solution: Defining the seperation factor f as approximately equal to (a2/a1) where a1, a2 are the relative abundances of the isotope of interest in the initial and final fractions, we have

f=(a2/a1);

printf("The single stage seperation factor is = %f",f)