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//chapter27
//example27.2
//page575
R1=4 // ohm
R2=4 // ohm
R3=4 // ohm
// for h11 and h21, imagine that output terminals are shorted hence it is clear that input impedence is equal to R1+R2*R3/(R2+R3)
// this is h11 by definition so
h11=R1+R2*R3/(R2+R3)
// now current will divide equally at junction of 4 ohm resistors so output_current/input_current = -0.5
// but this ratio is h21 by definition. Thus
h21=-0.5
// for h12 and h22 imagine a voltage source on output terminals
// this voltage will be divided by a factor 2
// hence input_voltage/output_voltage = 0.5
// but this ratio is h12 by definition. Thus
h12=0.5
// here output impedence looking into output terminals with input terminals open is 8 ohm.
// its reciprocal is h22 by definition. Thus
h22=1/8
printf("h11 = %.3f ohm \n",h11)
printf("h21 = %.3f \n",h21)
printf("h12 = %.3f \n",h12)
printf("h22 = %.3f ohm \n",h22)
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