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+//chapter27
+//example27.2
+//page575
+
+R1=4 // ohm
+R2=4 // ohm
+R3=4 // ohm
+
+// for h11 and h21, imagine that output terminals are shorted hence it is clear that input impedence is equal to R1+R2*R3/(R2+R3)
+    // this is h11 by definition so
+    h11=R1+R2*R3/(R2+R3)
+
+    // now current will divide equally at junction of 4 ohm resistors so output_current/input_current = -0.5
+    // but this ratio is h21 by definition. Thus
+    h21=-0.5
+
+// for h12 and h22 imagine a voltage source on output terminals
+    // this voltage will be divided by a factor 2
+    // hence input_voltage/output_voltage = 0.5
+    // but this ratio is h12 by definition. Thus
+    h12=0.5
+
+    // here output impedence looking into output terminals with input terminals open is 8 ohm.
+    // its reciprocal is h22 by definition. Thus
+    h22=1/8
+    
+printf("h11 = %.3f ohm \n",h11)
+printf("h21 = %.3f \n",h21)
+printf("h12 = %.3f \n",h12)
+printf("h22 = %.3f ohm \n",h22)